The temperature of O2 is changed from -48.03 °C to 235.59 °C. If its new volume is 29.164 L, what was its original volume in liters ______ L?

The temperature of O2 is changed from -48.03 °C to 235.59 °C. If its new volume is 29.164 L, what was its original volume in liters ______ L?
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1 Answer

Answer :

12.90(Explanation): use charle's law for this one. V/T=V/T. we know the temperatures in both scenarios, and we're trying to solve for the volume in the beginning. Remember temperature in Kelvin! So, plug in what we know to get V/224.97K =29.164/508.59K. Now, cross-mulitply to solve for V. Equation now looks like this 508.59V=6561.02508. Now, divide by 508.59 on both sides to get 12.90042093. Round to 4 sig figs, 12.90 DONE!
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