Description : The scores of an English test out of 100 of 20 students are given below : 75, 69, 88, 55, 95, 88, 73, 64, 75, 98, 88, 95, 90, 95, 88, 44, 59, 67, 88, 99. -Maths 9th
Last Answer : Median=n=even =n/2=20/2=10th observation =98 Mode =88
Description : Consider the following JAVA program: public class First { public static int CBSE (int x) { if (x < 100) x = CBSE (x +10); return (x - 1); } public static void main (String[] args){ System.out.print(First.CBSE(60)); } } What does this program print? (1) 59 (2) 95 (3) 69 (4) 99
Last Answer : (2) 95
Description : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598
Last Answer : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? Sol: 27.75 x 1764 ÷ 64 – 2 = 8 x ? 27.75 x 27.5625 – 2 = 8 x ? 762.859/8=? ? = 95.357 Answer: a)
Description : In a diagnostic test in mathematics given to students, the following marks (out of 100) are recorded 46, 52, 48, 11, 41, 62, 54, 53, 96, 40, 98 and 44. -Maths 9th
Last Answer : NEED ANSWER
Last Answer : Median will be a good representative of the data, because 1.each value occurs once. 2.the data is influenced by extreme values.
Description : Find the median of the following observations: 46,64,87,41,58,77,35,90,55,92,33. If 92 is replaced by 99 and 41 by 43. find the new median -Maths 9th
Last Answer : Here's ur answer Hope it has helped u..
Description : Given are the scores (out of 25) of 9 students in a Monday test : 14, 25, 17, 22, 20, 19, 10, 8 and 23 -Maths 9th
Last Answer : Ascending orders of scores is : 8, 10, 14, 17, 19, 20, 22, 23, 25 Now, new score = 8 + 10 + 14 + 17 + 19 + 20 + 22 + 23 + 25 / 9 = 158 / 9 = 17.5 marks Median = (n + 1 / 2)th observation because n is odd = (9 + 1 / 2)th observation = 5th observation = 19 marks.
Description : The average score in a bank examination of 13 students of a class is 50. If the scores of the top five students are not considered, the average score of the remaining students falls by 5. The pass mark ... integral scores, the maximum possible score of the topper is. A) 85 B) 90 C) 95 D) 100
Last Answer : D Average = Sum of observations/Number of observations Given, average score in a bank examination of 13 students of a class is 50. Sum of total scores = 13 50= 650 Given, if the scores of the top five students are not ... b + c + d + e = 290 ⇒46+ 47 + 48+ 49 +e = 290 ⇒e = 100
Description : Nandita scores 60% marks in five subjects together, viz., Hindi, Science, Mathematics, English and Sanskrit, where in the maximum marks of each subject were 105. How many marks did Nandita score in Science, if she scored 69 ... and 51 marks in English? a) 66 b) 68 c) 55 d) 65 e) None of these
Last Answer : Answer: D Total of maximum marks of all subjects=105×5=525 75% of 525=525 ×60/100= 315 Obtained marks of foru subjects (Hindi, Sanskrit, mathematics and English) =69+62+68+51=250 So, the obtained marks in Science=315-250=65
Description : Given the following data pairs (x, y), find the regression equation. (1, 1.24), (2, 5.23), (3, 7.24), (4, 7.60), (5, 9.97), (6, 14.31), (7, 13.99), (8, 14.88), (9, 18.04), (10, 20.70) a. y = 0.490 x - 0.053 b. y = 2.04 x c. y = 1.98 x + 0.436 d. y = 0.49 x
Last Answer : c. y = 1.98 x + 0.436
Description : The sag in a tape 100 ft long held between two supports 99.8 ft aprat at the same level is a.3.32 ft b.0.98 ft c.2.73 ft d.1.87 ft e.107 dynes
Last Answer : c. 2.73 ft
Description : Water comprises approximately ____ percent of cleaning and sanitizing solutions. a. 80 to 89 c. 90 to 95 b. 95 to 99 d. 75 to 85
Last Answer : b. 95 to 99
Description : The energy consumption and production patterns in a chemical plant over a 9 month period is provided in the table below; Month 1 2 3 4 5 6 7 8 9 Production in Tonnes / month 493 ... and give your inference on the result ? ( consider 9 month data for evaluation for predicted energy consumption)
Last Answer : It is required to use the equations Y= mX + C and nC + mΣX = ΣY cΣX + mΣX2 = ΣXY Month X = Production in Tonnes / month Y =Energy Consumption MWh /month X 2 XY 1 493 78.2 ... 73.7 54756 17240.63 8 239 64.4 57121 15402.96 9 239 72.1 57121 17228.98 3387 665.3 1410683 253221
Description : Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, ... C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56
Last Answer : C. 0, 1,10,11, 50, 51, 75, 76,100,101
Description : A sample of natural gas containing 80% methane (CH4 ) and rest nitrogen (N2 ) is burnt with 20% excess air. With 80% of the combustibles producing CO2 and the remainder going to CO, the Orsat analysis in volume percent is (A) CO2 : 6 ... 96, N2 :72.06 (D) CO2 : 7.60, CO : 1.90, O2 : 4.75, N2 : 85.74
Last Answer : (B) CO2 : 7.42, CO : 1.86, O2 : 4.64, N2 :86.02
Description : Make a stem-and-leaf plot for this set of data. Find the range,median,and mode of the data. : 47 54 70 62 59 62 82 66 62 73 55 82 59?
Last Answer : nevermind- i figured it out
Description : Evaluate each of the following: (i) (103)3 (ii) (98)3 (iii) (9.9)3 (iv) (10.4)3 (v) (598)3 (vi) (99)3 -Maths 9th
Last Answer : answer:
Description : PROBLEM GThe moist unit weights of the soil are 105.73 pcf and 112.67 pcf, and the respective degree of saturation are 50.0% and 75.0%, compute the values of thevoid ratio, porosity, and specific gravity of the given soil?
Last Answer : Pressuron theory (2013) by Olivier Minazzoli and Aurélien Hees
Description : 79.93 × 35.02 -59.93 × 85.08 + 74.98 × 44.04 =? a) 1420 b) 1000 c) 1580 d) 870 e) 1260
Last Answer : ? ≈ 80 × 35-60 × 85 + 75 × 44 =2800 – 5100 + 3300 = 1000 Answer: b)
Description : My ex wife owe over $20,000.00 in back taxes. Years owed 95,98,99, and 2000.I recently filed this missing years and now have a fairly accurate assessment of what we owe. Unable to pay without filing Chapter 7 or 13.Income is stretched to the limit. ?
Last Answer : If she is your ex-wife, you probably aren't liable for her back taxes. Usually, your legal separation agreement will stipulate that you are each responsible for your own taxes. If so, I would think you're off the hook for this.
Description : If total income of company B in 2008 was Rs.140 crore, what was the total expenditure of that company in the same year? (approx) a) Rs.100.66 cr. b) Rs.110.33 cr. c) Rs.98.22 cr. d) Rs.94.90 cr. e) Rs.96.55 cr.
Last Answer : e) Rs.96.55 cr.
Description : A class consists of 80 students, 25 of them are girls and 55 boys. 10 of them are rich and 20 are fair complexioned. -Maths 9th
Last Answer : Let P (A) = Probability of selecting a fair complexioned person. ThenP(A) = \(rac{20}{80}\) = \(rac{1}{4}\)Let P(B) = Probability of selecting a rich person. Then P(B) = \(rac{10}{80}\) = \(rac{1}{8}\)Let P (C) = ... ) = \(rac{1}{4}\)x \(rac{1}{8}\)x \(rac{5}{16}\) = \(rac{5}{512}\) = 0.009.
Description : The class marks of a continuous distribution are 1.04, 1.14, 1.24, 1.34, 1.44,1.54 and 1.64. -Maths 9th
Last Answer : It is not correct. Because the difference between two consecutive class marks should be equal to the class size. Here, difference between two consecutive marks is 0.1 and class size of 1.55-1.73 is 0.18, which are not equal.
Description : Under normal conditions, food proteins are generally readily digested upto the present (A) 67 to 73 (B) 74 to 81 (C) 82 to 89 (D) 90 to 97
Last Answer : Answer : D
Description : The marks obtained (out of 100) by a class of 80 students are given below: -Maths 9th
Last Answer : In the given frequency distribution, the class intervals are not of equal width. Therefore, we would make modification in the lengths of the rectangle in the histogram so that the areas of rectangle ... draw rectangles with lengths as given in the last column. The histogram of data is given below:
Description : A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is: a) 35.55 km/hr b) 36 km/hr c) 71.11 km/hr d) 71 km/hr e) 69.69km/hr
Last Answer : Total time taken = (160/64) + (160/80) = 9/2 hrs. Avg Speed – 320 × (2/9) km/hr = 71.11km/hr Answer: c)
Description : The sound power level of a jet plane flying at a height of 1 km is 160 dB. What is the maximum sound pressure level on the ground directly below the plane assuming that the aircraft radiates sound equally in all directions? A. 59.1 dB B. 69.1 dB C. 79.1 dB D. 89.1 dB
Last Answer : D. 89.1 dB
Description : on analyzing the result of an competitive exam the teacher found that the average for the entire the class was 69 marks. If we say that average of 10 % of the students scored 77 marks and average of 28 % of the ... marks of the remaining students of the class A) 67.54 B) 68.26 C) 66.91 D) 69.06
Last Answer : D) average of entire class = 69marks average of 28 % of the students = 66 marks average of 10% of the students = 77 marks then % of remaining students = (100- 10 - 28) = 62% let the average of 62% of the ... (62*x)+770+1848= 6900 62 * x = 6900-770-1848 62*x = 4282 x = 69.06
Description : A group of students of arithmetic mean of the marks in a test was 63. The brightest 30% of them secured a mean score of 70 and the dullest 15% a mean score of 41. The mean score of remaining 55 % is A) 63.675 B) 61.785 C) 65.181 D) 66.67
Last Answer : C) Let the requird mean score be ‘x’ Then (30*70)+(15*41)+55x = 63*100 2100+615+55x=6300 2715+55x=6300 55x=3585 X=65.181
Description : What are the next two numbers in this pattern 88 44 64 32 52?
Last Answer : 26 46 . alternating numbers, difference halved each time 88 - 64 = 24 44 - 32 = 12 = 64 - 52 12/2 = 6 = 32 - 26 = 52 - 46 last is 6/2 = 3 (nothing after that as 3/2 is not a whole number) 26 - 23 = 3 = 46 - 43 . 88 44 64 32 52 26 46 23 43
Description : When testing a grade calculation system, a tester determines that all scores from 90 to 100 will yield a grade of A, but scores below 90 will not. This analysis is known as: A. Equivalence partitioning B. Boundary value analysis C. Decision table D. Hybrid analysis
Last Answer : A. Equivalence partitioning
Last Answer : B. Boundary value analysis
Description : In a mathematics test given to 15 students, the following marks (out of 100) are recorded : -Maths 9th
Last Answer : For Mean : As we know that ⇒ x̅ = 41 + 39 + 48 + 52 + 46 + 62 + 54 + 40 + 96 + 52 + 98 + 40 + 42 + 52 + 60 / 15 x̅ = 822 / 15 = 54.8 ⇒ x̅ = 54.8 For Median : First of ... 52 For Mode : Make a frequency table for given data : Here, the marks 52 has the maximum frequency '3'. ∴ Mode = 52
Description : What is the radius of a circle inscribed in a triangle having side lengths 35 cm, 44 cm and 75 cm? -Maths 9th
Last Answer : (d) 6 cmLet a = 35 cm, b = 44 cm, c = 75 cm. Thens = \(rac{a+b+c}{2}\) = \(rac{34+44+75}{2}\) cm = 77 cm∴ Area if triangle = \(\sqrt{77(77-35)(77-44)(77-75)}\) cm2= \(\sqrt{77 imes42 ... ) cm2 = 462 cm2∴ Radius of incircle = \(rac{ ext{Area}}{ ext{semi-perimeter}}\) = \(rac{462}{77}\) cm = 6 cm.
Description : 95 students each from 102 schools participated -Maths 9th
Last Answer : 95 x 102 = (100 - 5)(100 + 2) 1002 + (- 5 + 2) x 100 + (- 5 x 2) = 10,000 - 300 – 10 = 9,690 Fraternity, patriotism.
Description : Water content of sewage is about A. 90 % B. 95 % C. 99 % D. 9.9 %
Last Answer : ANS: D
Description : Purity of electrical grade aluminium should be ≥ __________ percent. (A) 95 (B) 99.5 (C) 85 (D) 90
Last Answer : (B) 99.5
Description : At what percentage (by volume) of alcohol composition, it forms anazeotrope with water? (A) 90 (B) 91.5 (C) 95 (D) 99
Last Answer : (C) 95
Description : Super Profit is Rs.9,167 and the Normal Rate of Return is 10% Goodwill as per capitalization of Super Profit method is equal to A Rs.91,670 B Rs.90,600 C Rs.67,910 D Rs.95,000
Last Answer : ANS: Rs 91670
Description : According to the United Nations’ publication, Ending Hunger: An Idea Whose Time Has Come, in the last 88 years, ____ countries have done away with hunger; 41 of these countries have done it since ____. a. 80, 1970 c. 95, 1980 b. 70, 1955 d. 75, 1960
Last Answer : d. 75, 1960
Description : If the fare of Rajdhani Exp is Rs. 350 and that of Sapt Kranti Exp is Rs. 450 for all classes of passenger then what is the total income of both the trains during 2011 to 2013? 1) Rs. 95 crore 2) Rs. 98 crore 3) Rs. 90 crore 4) Rs. 89 crore 5) Rs. 92.5 crore
Last Answer : 5) Rs. 92.5 crore
Description : ‘X’ has given a data on a person age, which should be between 1 to 99. Using BVA which is the appropriate one A. 0,1,2,99 B. 1, 99, 100, 98 C. 0, 1, 99, 100 D. –1, 0, 1, 99
Last Answer : C. 0, 1, 99, 100
Description : The average weight of a group of 75 women was calculated as 47 kg. It was later discovered that the weight of one of the women was read as 45 kg, whereas her actual weight was 25kg. What is the actual average weight ... kg (b) 46.64 kg (c) 45.96 kg (d) Cannot be determined (e) None of these
Last Answer : (a) 46.73 kg
Description : Mithun went to a shop and bought things worth Rs. 75, out of which 90 Paise went on sales tax on taxable purchases. If the tax rate was 18%, then what was the cost of the tax free items? a) 12.5 b) 69.80 c) 19.7 d) 34.5 e) 69.1
Last Answer : Answer: E Total cost of the items he purchased = Rs.75 Given that out of this Rs.75, 90 Paise is given as tax => Total tax incurred = 90 Paise = Rs.90/100 Let the cost of the tax free items = x Given that tax rate = ... −0.9 −x) = 90 ⇒ (75 − 0.9 − x) = 5 x = 75 − 0.9 - 5 X=69.1
Description : The mean weight per student in a group of 7 students is 55 kg. -Maths 9th
Last Answer : x̅ = 1 / n (Σxi) ⇒ 55 = x1 + x2 + .......+ ⇒ x7 / 7 ⇒ x1 + x2 + ...... + x7 = 55 × 7 = 385 x1 + x2 + ...... + x6 = 52 + 54 + 55 + 53 + 56 + 54 = 324 ∴ x7 = 385 - 324 = 61 kg ∴ weight of the seventh student is 61 kg.