What is 34 over 11 as a mixed number?

What is 34 over 11 as a mixed number?
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It is 3 and 1/11 as a mixed number
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If you weighed 138 pounds on Earth you would wait a hundred twenty eight decimal point 34 lb on Saturn. Write the weight on Saturn as a mixed number in simplest form?

Description : If you weighed 138 pounds on Earth you would wait a hundred twenty eight decimal point 34 lb on Saturn. Write the weight on Saturn as a mixed number in simplest form?

Last Answer : The number in question is 128.34However, a pound is a measure of mass, not weight: weight is measured in pounds-force. Also "you would wait . . on Saturn" makes no sense at all!

How do you write 34.75 as a mixed number?

Description : How do you write 34.75 as a mixed number?

Last Answer : 34 and 3 over 4.

How much is 128.34 in mixed numbers in simplest form?

Description : How much is 128.34 in mixed numbers in simplest form?

Last Answer : It is 128 and 17/50 in its simplest form

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

The largest number that will divide 398,436 and 542 leaving remainders 7,11 and 15 respectively is(a) 17 (b) 11 (c) 34 (d) 45

Description : The largest number that will divide 398,436 and 542 leaving remainders 7,11 and 15 respectively is(a) 17 (b) 11 (c) 34 (d) 45

Last Answer : (a) 17

What is a mixed number of 11 over 4?

Description : What is a mixed number of 11 over 4?

Last Answer : It is 2 3/4.

how many times does 11 go into 34?

Description : how many times does 11 go into 34?

Last Answer : 3.09 times

Calculate the radius of the first and second orbit of sodium atom `(Z=11)`. `(h=6.6xx10^(-34) J s, e=1.6xx10^(-19) C` and `m=9.1xx10^(-31) kg.)`

Description : Calculate the radius of the first and second orbit of sodium atom `(Z=11)`. `(h=6.6xx10^(-34) J s, e=1.6xx10^(-19) C` and `m=9.1xx10^(-31) kg.)`

Last Answer : Calculate the radius of the first and second orbit of sodium atom `(Z=11)`. `(h=6.6xx10^(-34) J s, e=1.6xx10^(-19) C` and `m=9.1xx10^(-31) kg.)`

Momentum of electron having mass 9.1 × 10-31 kg and velocity 2.0 × 107 is A. 1.91 × 10-23 B. 2.34 × 10-23 C. 3.11 × 10-19 D. 7.88 × 10-34

Description : Momentum of electron having mass 9.1 × 10-31 kg and velocity 2.0 × 107 is A. 1.91 × 10-23 B. 2.34 × 10-23 C. 3.11 × 10-19 D. 7.88 × 10-34

Last Answer : 1.91 × 10-23

Find the natural frequency in Hz of the free longitudinal vibrations if the displacement is 2mm. a) 11.14 b) 12.38 c) 11.43 d) 11.34

Description : Find the natural frequency in Hz of the free longitudinal vibrations if the displacement is 2mm. a) 11.14 b) 12.38 c) 11.43 d) 11.34

Last Answer : a) 11.14

Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Description : Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these

Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)

(37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Description : (37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Last Answer : (37÷44) + (78÷34) x (480÷85) = ? Sol: 0.841 + 2.29412 x 5.64706 =? 0.841 + 12.955 =? ? = 13.796 Answer: c)

(37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Description : (37÷44) + (78÷34) x (480÷85) = ? a) 11.769 b) 12.756 c) 13.796 d) 12.796 e) none

Last Answer : (37÷44) + (78÷34) x (480÷85) = ? Sol: 0.841 + 2.29412 x 5.64706 =? 0.841 + 12.955 =? ? = 13.796 Answer: c)

Eight years ago, the ratio of the ages of micky and Donald was 6:5, 12years hence, the ratio of their ages will be 11:10. What is Donald age at present a) 30 years b) 28 years c) 34 years d) 36 years

Description : Eight years ago, the ratio of the ages of micky and Donald was 6:5, 12years hence, the ratio of their ages will be 11:10. What is Donald age at present a) 30 years b) 28 years c) 34 years d) 36 years

Last Answer : B Let 8 years ago the age of Micky and Donald be 6x and 5x resp. then, ((6x+8)+12) / ((5x+8)+12) = 11/10 10(6x+20) = 11(5x+20) 5x = 20 => x = 4 So Donald age is (5x+8) = 28

What is 11.8 as a mixed number?

Description : What is 11.8 as a mixed number?

Last Answer : It is 11 and 4/5 as a mixed number in its simplest form

How do you write 11.4 as a mixed number in simplest form?

Description : How do you write 11.4 as a mixed number in simplest form?

Last Answer : It is 11 and 2/5 as a mixed number in its simplest form

Tickets numbered 1 to 37 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 4 or 10? A) 11/37 B) 37/11 C) 12/37 D) 37/12

Description : Tickets numbered 1 to 37 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 4 or 10? A) 11/37 B) 37/11 C) 12/37 D) 37/12

Last Answer : Answer: A) Here, S = {1, 2, 3, 4, ...., 36,37}. Let E = event of getting a multiple of 4 or 10= {4,8,12,16,20,24,28,32,36,10, 30}. P(E) = n(E)/n(S) = 11/37

When 22.4 litres of `H_(2)(g)` is mixed with 11.2 litres of `CI_(2)(g)`, eacg at STP, the moles of HCI(g) formed is equal to :-

Description : When 22.4 litres of `H_(2)(g)` is mixed with 11.2 litres of `CI_(2)(g)`, eacg at STP, the moles of HCI(g) formed is equal to :-

Last Answer : When 22.4 litres of `H_(2)(g)` is mixed with 11.2 litres of `CI_(2)(g)`, eacg at STP, the moles of HCI(g ... ) C. 1 mol of HCI (g) D. 2 mol of HCI (g)

Saturated steam at 1 atm is discharged from a turbine at 1200 kg/h. Superheated steam at 300 0C and 1 atm is needed as a feed to a heat exchanger. To produce it, the turbine discharge stream is mixed with superheated steam at 400 0C, 1 atm and specific volume of 3.11 m 3 /kg. Calculate the amount of superheated steam at 300 0C produced and the volumetric flow rate of the 400 0C steam.

Description : Saturated steam at 1 atm is discharged from a turbine at 1200 kg/h. Superheated steam at 300 0C  and 1 atm is needed as a feed to a heat exchanger. To produce it, the turbine discharge ... amount of superheated steam at 300 0C produced and the volumetric flow rate of the  400 0C steam.

Last Answer : Solution 1. Mass balance of water 1200 + m1 = m2 ………………………………………… (1) …………………….1 mark 2. Energy balance (1200 kg/h)(2676 kJ/kg) + m1(3278 kJ/kg)

Consider two alloys A and B. 50 kg of alloy A is mixed with 70 kg of alloy B. A contains brass and copper in the ratio 3 : 2, and B contains them in the ratio 4 : 3 respectively. What is the ratio of copper to brass in the mixture? A) 8 : 5 B) 7 : 5 C) 5 : 11 D) 4 : 9 E) 5 : 7

Description : Consider two alloys A and B. 50 kg of alloy A is mixed with 70 kg of alloy B. A contains brass and copper in the ratio 3 : 2, and B contains them in the ratio 4 : 3 respectively. What is the ratio of copper to brass in the mixture? A) 8 : 5 B) 7 : 5 C) 5 : 11 D) 4 : 9 E) 5 : 7

Last Answer : Answer: E Brass in A = 3/5 * 50 = 30 kg, Brass in B = 4/7 * 70 = 40 kg Total brass = 30+40 = 70 kg So copper in mixture is (50+70) – 70 = 50 kg So copper to brass = 50 : 70=5:7

Two vessels contains equal quantity of solution contains milk and water in the ratio of 7:2 and 4:5 respectively. Now the solutions are mixed with each other then find the ratio of milk and water in the final solution? A) 11:7 B) 11:6 C) 11:5 D) 11:9 E) None of these

Description : Two vessels contains equal quantity of solution contains milk and water in the ratio of 7:2 and 4:5 respectively. Now the solutions are mixed with each other then find the ratio of milk and water in the final solution? A) 11:7 B) 11:6 C) 11:5 D) 11:9 E) None of these

Last Answer : Answer: A milk = 7/9 and water = 2/9 – in 1st vessel milk = 4/9 and water = 5/9 – in 2nd vessel (7/9 + 4/9)/ (2/9 + 5/9) = 11:7