What do you call a maj7 chord on the iii degree Roman numeral?

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Description : Why on clocks and watches is the Roman Numeral 4 written IIII instead of IV?

Last Answer : According to Wikipedia, using IIII instead of IV creates a visual symmetry with the VIII on the other side, which the two-character IV would not. The article also says that using IIII keeps the total ... five Is, and an X in order to make the correct number of numerals for their clocks: VIIIIIX.

Description : I am a four-digit number and when converted to a Roman numeral I become a common 3 letter word meaning 'Blend.' What number am I? -Riddles

Last Answer : 1009 means MIX IX=9 M=1000.

Description : What number is this roman numeral Mcmlii?

Last Answer : In modern (shorthand) notation, M = 1000, CM = 900, L = 50, II = 2 the sum is 1952.In the ancient Roman (full) notation, M = 1000, C = 100, M = 1000, L = 50, II = 2 ... letters. Monks in the Middle Ages created the modern (shorthand) notation with place order to save time and ink when making copies.

Description : What is CCXLVII in roman numeral?

Last Answer : Under the rules now governing the Roman numeral system 247 isdeemed to be CCXLVII but the ancient Romans would have notated itas CCXXXXVII

Description : What does MCMXLIX the roman numeral for what number?

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Description : What is 927 as a roman numeral?

Last Answer : 927 as a Roman numeral is CMXXVII or as DCCCCXXVII

Description : What is the value of the Roman numeral VC?

Last Answer : V=5C = 100so VC is 5 before a 100 or "95".CV would be 105

Description : What is V in Roman numeral numbers?

Last Answer : V = 5

Description : What does the Roman numeral above the group tell us about the structure of the atom?

Last Answer : If you are referring to GROUP NUMBER when you say "Roman numeralabove the group", it tells you the number of valence electrons, orthe number of outermost electrons, with transition metals being ... the number of valenceelectrons is the group number minus 10 (minus 10 for the 10transition groups).

Description : What is CCLXXVI in Roman numeral number?

Last Answer : 276200 + 50 + 20 + 6

Description : How would you write 116 as a Roman numeral?

Last Answer : 100 + 10 + 5 + 1C + X + V + ICXVI

Description : What does the roman numeral MCMLI mean?

Last Answer : Under today's rules now governing the Roman numeral system MCMLIis equivalent to 1951

Description : What the number for the Roman numeral Llll?

Last Answer : 53 = 50 + 1 + 1 + 1

Description : What does roman numeral v111?

Last Answer : 5 + 1 + 1 + 1 = 8

Description : How would you write 825 as a Roman numeral?

Last Answer : 825 as a Roman numeral is DCCCXXV meaning 800+20+5 = 825

Description : What Roman numeral is MCMXXLII?

Last Answer : It is an invalid arrangement of Roman numerals

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Last Answer : It is: XI XXV MMII in Roman numerals

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Description : A circle has radius √2 cm. It is divided into two segments by a chord of length 2cm.Prove that the angle subtended by the chord at a point in major segment is 45 degree . -Maths 9th

Last Answer : Given radius =2 cm Therefore AO=2 cm Let OD be the perpendicular from O on AB And AB =2cm Therefore AD=1cm (perpendicular from the centre bisects the chord) Now in triangle AOD, AO=2 cm ... by a chord at the centre is double of the angle made by the chord at any poin on the circumference)

Description : The radius of a simple circular curve is 300 m and length of its specified chord is 30 m. The degree of the curve is (A) 5.73° (B) 5.37° (C) 3.57° (D) 3.75°

Last Answer : (A) 5.73°

Description : If D is the degree of the curve of radius R, the exact length of its specified chord, is (A) Radius of the curve sine of half the degree (B) Diameter of the curve sine of half the ... Diameter of the curve cosine of half the degree (D) Diameter of the curve tangent of half the degree

Last Answer : (B) Diameter of the curve × sine of half the degree

Description : Rankine's deflection angle in minutes is obtained by multiplying the length of the chord by (A) Degree of the curve (B) Square of the degree of the curve (C) Inverse of the degree of the curve (D) None of these

Last Answer : (A) Degree of the curve

Description : State the meaning of degree of curve and long chord.

Last Answer : Degree of curve : The angle subtended at the centre by a standard chord of 30 m length, is known as degree of curve. Long Chord : The straight line joining rear tangent point and forward tangent point is called as long chord of curve.

Description : What does romon numeral M mean?

Last Answer : The Roman numeral of M is equivalent to 1000 = one thousand

Description : What is 5.75 million in numeral form?

Last Answer : What is the answer ?

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Last Answer : (1) 8 Explanation: The octal numeral system is the base-8 number system and uses the digits 0 to 7. As it uses only eight digits (0 through 7) there are no numbers or letters used above 8.

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Last Answer : d. Binary

Description : What is the minimum thickness of hub at the welding end per ASME B16.5? a) The numeral pipe thickness. b) 87 ½% of the pipe thickness. c) 112 ½% of the pipe thickness. d) .25".

Last Answer : b) 87 ½% of the pipe thickness.

Description : The popular search engine “Google” derives its name from the word “Googol”. What does the word mean ? (1) To search (2) To index (3) To crawl (4) The numeral one followed by a hundred zeros

Last Answer : The numeral one followed by a hundred zeros

Description : 1. What is the main constituent of haemoglobin? 2. By whom is the Prime Minister appointed? 3. Which substance is a bad conductor of electricity but a good conductor of heat? 4. When it is noon ... maps of India? 20. By whom the Mahatma Gandhi was referred to Father of the Nation' first?

Last Answer : Answer : 1. Iron 2. President 3. Mica 4. 0°E or W 5. Gandhara 6. National income 7. Faiz Ahmed Faiz 8. 8 9. Divergent movement 10. Shahjahan 11. The President 12. Black 13. Amir ... Ram Das 16. Prime Minister 17. Artery 18. Defence Minister 19. Geographical Survey of India 20. Subhash Chandra Bose

Description : I have some matchsticks set up like this: I + XI = X. If you do not know Roman numerals, here is a quick starter: I=1 II=2 III=3 IV=4 V=5 VI=6 VII=7 VIII=8 IX=9 X=10 XI=11 ... are told to move the minimum number of matchsticks to make the question correct. So, how many do you have to move? -Riddles

Last Answer : Most people would get to one move at the least, but the real answer is zero moves. If you rotate the whole question around 180 degrees, it will display this: X = IX + I

Description : Have you lately run across any quotes, pieces of literature, poetry, etc., that have struck a chord with you that you would like to share?

Last Answer : answer:I referred to the essay that this came from in an earlier topic - not hard to find if you're interested - this was another part of the same essay: Contemplate the power of the phrase, ... remember the number correctly, and it was then approved. 3 The #3 footnote: This is the sober truth.

Description : Just how bad is it to plug a power strip into an extension chord into the wall?

Last Answer : Not at all. Your circuit breakers will pop before anything happens, but what you have shouldn’t cause any problems.

Description : In STL files when chord length decrease then accuracy _______ a.increase b.decrease c.may increase or may decrease d.remains constant

Last Answer : a.increase

Description : A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th

Last Answer : ∵ PM = MQ = 1/2 = PQ = 45 cm and OP = 7.5 cm In right angled ΔOMP, using phthagoras theorem OM2 = OP2 - PM2 ⇒OM2 = 7.52 - 4.52 ⇒OM2 = 56.25 - 20.25 ⇒OM2 = 36 ∴ OM = √36 = 6 cm

Description : A circle with centre O and diameter COB is given. If AB and CD are parallel, then show that chord AC is equal to chord BD. -Maths 9th

Last Answer : O Join AC and BD. Given, COB is the diameter of circle. ∠CAB = ∠BDC = 90° [angle in a semi-circle] Also, AB II CD ∠ABC = ∠DCB (alternate angles] Now, ∠ACB = 90° - ∠ABC and ∠DBC = 90° - ∠DCB = ... = ∠DBC BC = BC [common sides] ΔABC = ΔDCB [by ASA congruency] ∴ AC = BD [by CPCT] Hence Proved.

Description : The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm

Description : AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, then find the distance of AB from the centre of the circle. -Maths 9th

Last Answer : ∵ The perpendicular drawn from the centre to the chord bisects it. ∴ AM = 1/2 AB = 1/2 × 30 cm = 15 cm Also, OA = 1/2 AD = 1/2 × 34 cm = 17 cm In rt. △OAM, we have OA2 = OM2 + AM2 172 = OM2 + 152 ⇒ 289 = OM2 + 225 ⇒ OM2 = 289 - 225 ⇒ OM2 = 64 ⇒ OM = √64 = 8 cm

Description : In the figure, chord AB of circle with centre O, is produced to C such that BC = OB. CO is joined and produced to meet the circle in D. -Maths 9th

Last Answer : In △OBC, OB = BC ⇒ ∠BOC = ∠BCO = y ...[angles opp. to equal sides are equal] ∠OBA is the exterior angle of △BOC So, ∠ABO = 2y ...[ext. angle is equal to the sum of int. opp. angles] Similarly, ∠AOD is the exterior angle of △AOC ∴ x = 2y + y = 3y

Description : AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, the distance of AB from the centre of the circle is -Maths 9th

Last Answer : (d) Given, AD = 34 cm and AB = 30 cm In figure, draw OL ⊥ AB. Since, the perpendicular from the centre of a circle to a chord bisects the chord.

Description : If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, prove that arc PXA = arc PYB. -Maths 9th

Last Answer : Let AB be a chord of a circle having centre at OPQ be the perpendicular bisector of the chord AB, which intersects at M and it always passes through O. To prove arc PXA ≅ arc PYB Construction Join AP and BP. Proof In ... ΔBPM, AM = MB ∠PMA = ∠PMB PM = PM ∴ ΔAPM s ΔBPM ∴PA = PB ⇒arc PXA ≅ arc PYB

Description : A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment. -Maths 9th

Last Answer : Given, AB is a chord of a circle, which is equal to the radius of the circle, i.e., AB = BO …(i) Join OA, AC and BC. Since, OA = OB= Radius of circle OA = AS = BO

Description : If two equal chords of a circle intersect, prove that the parts of one chord are separately equal to the parts of the other chord. -Maths 9th

Last Answer : Explanation of this question

Description : A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th

Last Answer : ∵ PM = MQ = 1/2 = PQ = 45 cm and OP = 7.5 cm In right angled ΔOMP, using phthagoras theorem OM2 = OP2 - PM2 ⇒OM2 = 7.52 - 4.52 ⇒OM2 = 56.25 - 20.25 ⇒OM2 = 36 ∴ OM = √36 = 6 cm

Description : A circle with centre O and diameter COB is given. If AB and CD are parallel, then show that chord AC is equal to chord BD. -Maths 9th

Last Answer : O Join AC and BD. Given, COB is the diameter of circle. ∠CAB = ∠BDC = 90° [angle in a semi-circle] Also, AB II CD ∠ABC = ∠DCB (alternate angles] Now, ∠ACB = 90° - ∠ABC and ∠DBC = 90° - ∠DCB = ... = ∠DBC BC = BC [common sides] ΔABC = ΔDCB [by ASA congruency] ∴ AC = BD [by CPCT] Hence Proved.

Description : The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm

Description : AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, then find the distance of AB from the centre of the circle. -Maths 9th

Last Answer : ∵ The perpendicular drawn from the centre to the chord bisects it. ∴ AM = 1/2 AB = 1/2 × 30 cm = 15 cm Also, OA = 1/2 AD = 1/2 × 34 cm = 17 cm In rt. △OAM, we have OA2 = OM2 + AM2 172 = OM2 + 152 ⇒ 289 = OM2 + 225 ⇒ OM2 = 289 - 225 ⇒ OM2 = 64 ⇒ OM = √64 = 8 cm

Description : In the figure, chord AB of circle with centre O, is produced to C such that BC = OB. CO is joined and produced to meet the circle in D. -Maths 9th

Last Answer : In △OBC, OB = BC ⇒ ∠BOC = ∠BCO = y ...[angles opp. to equal sides are equal] ∠OBA is the exterior angle of △BOC So, ∠ABO = 2y ...[ext. angle is equal to the sum of int. opp. angles] Similarly, ∠AOD is the exterior angle of △AOC ∴ x = 2y + y = 3y

Description : AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, the distance of AB from the centre of the circle is -Maths 9th

Last Answer : (d) Given, AD = 34 cm and AB = 30 cm In figure, draw OL ⊥ AB. Since, the perpendicular from the centre of a circle to a chord bisects the chord.

Description : If the perpendicular bisector of a chord AB of a circle PXAQBY intersects the circle at P and Q, prove that arc PXA = arc PYB. -Maths 9th

Last Answer : Let AB be a chord of a circle having centre at OPQ be the perpendicular bisector of the chord AB, which intersects at M and it always passes through O. To prove arc PXA ≅ arc PYB Construction Join AP and BP. Proof In ... ΔBPM, AM = MB ∠PMA = ∠PMB PM = PM ∴ ΔAPM s ΔBPM ∴PA = PB ⇒arc PXA ≅ arc PYB