What is the greatest remainder you could have with the divisor 5?

What is the greatest remainder you could have with the divisor 5?
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Last Answer : Remainder = 145 Again, we should evaluate p(5) Let p(y) = y3 + y2 - 2y + 5 ∴ p(5) = 53 + 52 - 2 x 5 + 5 = 125 + 25 - 10 + 5 = 145 Thus , we find that p(5) is the remainder when p(y) is divided by y - 5 .

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Determine the remainder when polynomial p(x) is divided by x - 2 . -Maths 9th

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If x51 + 51 is divided by x + 1, then the remainder is -Maths 9th

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By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial x4 + 1 and x-1. -Maths 9th

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