A and B can do a work in 12 days and 17 days respectively and with the help of C they complete the work in 5 days and earn ₹ 238. Find the share of B.

A and B can do a work in 12 days and 17 days respectively and with the help of C they complete the work in 5 days and earn ₹ 238. Find the share of B.
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A and B can do a work in 12 days and 17 days respectively and with the help of C they complete the work in 5 days and earn ₹ 238. Find the share of B.
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Prabu and balaji are two workers. Working together they can complete the whole work in 20 hours. If the Prabu worked for 5 hours and balaji worked for 17 hours, still there was half of the work to be done. In how many hours Prabu working alone, can complete the whole work? a) 17 hours b) 23 hours c) 34 hours d) 37 hours

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Rubika can do the 12 times the actual work in 72 days while sathya can do the one-half of the original work in 6 days. In how many days will both working together complete the 6 times of the original work? a) 20 days b) 25 days c) 30 days d) 35 days

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6 male , 8 female and 12 children can complete a work in 14 days .a female does twice the work of a male does and a child does half the work a male does . how many female alone can complete this work in 14 days? a) 15 b) 10 c) 12 d) 14

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Hanisha can do a work in 25 days, while sudha can do the same work in 50 days. They started the work jointly.Few days sughana also joined them and thus all of them completed the whole work in 12 days. All of them were paid total Rs.900. What is the Share of sughana? a) 252 b) 346 c) 454 d).359

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X,Y and Z can do a certain job in 72,108 and 144 days respectively. They started the job but X left 16 days before the completion of the job while Y left 24 days before the completion. The number of days for which Z worked is. a) 12 days b) 24 days c) 36 days d) 48 days

Description : X,Y and Z can do a certain job in 72,108 and 144 days respectively. They started the job but X left 16 days before the completion of the job while Y left 24 days before the completion. The number of days for which Z worked is. a) 12 days b) 24 days c) 36 days d) 48 days

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P and Q undertake to do a piece of job for Rs.1200. P alone can do it in 12 days while Q alone can do it in 16 days. With the help of R , they finish it in 6 days. Find the share of P,Q & R. a) 400,600,200 b) 200,400,600 c) 450,400,250 d) 600,450,150

Description :  P and Q undertake to do a piece of job for Rs.1200. P alone can do it in 12 days while Q alone can do it in 16 days. With the help of R , they finish it in 6 days. Find the share of P,Q & R. a) 400,600,200 b) 200,400,600 c) 450,400,250 d) 600,450,150

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Rohan and Sohan earn salaries which are in the ratio of `3:4` respectively. Sohan saves `11%` of his salary and Rohan saves `18%` of his salary. If So

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Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is: A.1 : 3 B.3 : 4 C.3 : 2 D.Data inadequate E.None of these

Description : Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and  they cross each other in 23 seconds. The ratio of their speeds is: A.1 : 3 B.3 : 4 C.3 : 2 D.Data inadequate E.None of these

Last Answer : Answer - C (3 : 2) Explanation - Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27x metres, and length of the second train = 17y metres. relative speed = total ... 23x + 23y = 27x + 17 y 27x-23x= 23 y-17y 4x=6y x/y=6/4=3/2= 3:2

Two mail trains Pand Q of 300 m and 600m, run at speed of 130 km/hr and 160 km/hr respectively, in the direction opposite direction to each other. Find the time required to cross each other after the moment they met? A) 11.17 sec B) 12sec C) 9.10sec D) 21sec

Description : Two mail trains Pand Q of 300 m and 600m, run at speed of 130 km/hr and 160 km/hr respectively, in the direction opposite direction to each other. Find the time required to cross each other after the moment they met? A) 11.17 sec B) 12sec C) 9.10sec D) 21sec

Last Answer :  ANSWER:A Explanation:  Length of train P = 300 m  Length of train Q = 600 m  Speed of train p = 130 kmph  Convert km/hr into m/s,  Speed of train p =(130 *5/18)m/s  = 650/18 m/s  = 36.11 m/ ... train B)  = (300+600)m = 900 m We know, time =distance /speed  = 900/ 80.55  = 11.17seconds

Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206))` `t_(1//2)`

Description : Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206))` `t_(1//2)`

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Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206))` `t_(1//2)`

Description : Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206))` `t_(1//2)`

Last Answer : Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha, ... be A. 5.25 B. 0.125 C. 12.5 D. 1.25

Three pipes P, Q and R can fill a tank from empty to full in 40 minutes, 15 minutes, and 30 minutes respectively. When the tank is empty, all the three pipes are opened. P, Q and R discharge chemical solutions X, Y and Z respectively. What is the proportion of the solution Y in the liquid in the tank after 5 minutes? a) 8 / 15 b) 7 / 15 c) 8 / 17 d) 6 / 13 e) 8 / 13

Description : Three pipes P, Q and R can fill a tank from empty to full in 40 minutes, 15 minutes, and 30 minutes respectively. When the tank is empty, all the three pipes are opened. P, Q and R discharge chemical solutions X, Y and Z respectively. ... 5 minutes? a) 8 / 15 b) 7 / 15 c) 8 / 17 d) 6 / 13 e) 8 / 13

Last Answer : a Part of the tank filled by pipe P in 1 minute = 1 / 40 Part of the tank filled by pipe Q in 1 minute = 1 / 15 Part of the tank filled by pipe R in 1 minute = 1/ 30 Here we have to find the proportion of ... together in 5 minute = 5 1/8 = 5/ 8 Required proportion = (1/3) / ( 5/8) = 8 / 15

In a house, there are dogs, cats and parrot in the ratio 3:7:5. If the number of cats was more than the number of dogs by a multiple of both 9 and 7, what is the minimum of pets in the house? A) 945 B) 630 C) 252 D) 238 E) NONE

Description :  In a house, there are dogs, cats and parrot in the ratio 3:7:5. If the number of cats was more than the number of dogs by a multiple of both 9 and 7, what is the minimum of pets in the house? A) 945 B) 630 C) 252 D) 238 E) NONE

Last Answer : Answer: A If three kinds of pets are taken be 3k,7k and 5k respectively, then 7k−3k=63p (where pp is any positive integer). As the number is a multiple of both 9 and 7, it has to be multiple of 63. ... pp for which kk is a natural number is 4. Thus, k =63 Hence, the number of pets =15k= 945