A and B can do a work in 30 days and 10 days respectively. If they work on alternate days beginning with A, in how many days will the work be complete

A and B can do a work in 30 days and 10 days respectively. If they work on alternate days beginning with A, in how many days will the work be complete
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A and B can do a work in 30 days and 10 days respectively. If they work on alternate days ... A, in how many days will the work be completed?
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Nandhu, naren and abishek can do a piece of work in 10,15, and 30 days respectively. In how many days can Nandhu do the work if he is assisted by naren and abishek on alternate days? a) 6.6 days b) 7.5 days c) 8.4 days d) 9.1 days

Description : Nandhu, naren and abishek can do a piece of work in 10,15, and 30 days respectively. In how many days can Nandhu do the work if he is assisted by naren and abishek on alternate days? a) 6.6 days b) 7.5 days c) 8.4 days d) 9.1 days 

Last Answer : B Nandhu's 1 day work = 1/10 Naren's 1 day work = 1/15 Abishek's 1 day work =1/30 Nandhu's 2 day's work =(1/10*2) =1/5 (nandhu + naren+abishek)'s 1 day work = 1/10+1/15+1/30 =3+2+1/30 =6/30 ... +1/5 = 2/5 Now 2/5 work is done in 3 days Whole work will be done in 3 *5/2 = 15/2 = 7.5 days

A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

X and Y can do a piece of work in 20 days and 30 days respectively. The time they take to complete the work by working together is ……………

Description : X and Y can do a piece of work in 20 days and 30 days respectively. The time they take to complete the work by working together is ……………

Last Answer : X and Y can do a piece of work in 20 days and 30 days respectively. The time they take to complete the work by working together is ……………

Consider three CPU intensive processes P1, P2, P3 which require 20, 10 and 30 units of time, arrive at times 1, 3 and 7 respectively. Suppose operating system is implementing Shortest Remaining Time first (preemptive scheduling) algorithm, then .............. context switches are required (suppose context switch at the beginning of Ready queue and at the end of Ready queue are not counted). (A) 3 (B) 2 (C) 4 (D) 5

Description : Consider three CPU intensive processes P1, P2, P3 which require 20, 10 and 30 units of time, arrive at times 1, 3 and 7 respectively. Suppose operating system is implementing Shortest Remaining Time first (preemptive scheduling) ... end of Ready queue are not counted). (A) 3 (B) 2 (C) 4 (D) 5

Last Answer : (A) 3

A and B can do a work in 12 days and 17 days respectively and with the help of C they complete the work in 5 days and earn ₹ 238. Find the share of B.

Description : A and B can do a work in 12 days and 17 days respectively and with the help of C they complete the work in 5 days and earn ₹ 238. Find the share of B.

Last Answer : A and B can do a work in 12 days and 17 days respectively and with the help of C they complete the work in 5 days and earn ₹ 238. Find the share of B.

What is the alternate beginning for Stalked at 17?

Description : What is the alternate beginning for Stalked at 17?

Last Answer : Sixteen-year-old Angela, a high school student, meets a college student (Chad), and he asks her and her friend, Tenaya, to invite them at his fraternity house, and they politely refuse, walking ... . After she finished high school and college, she got married and had children about 10 years later.

Two faucet A and Bcan fill a cistern in 6 hours and 2 hours respectively. If they are opened on alternate hours and if faucet A is opened first, in how many hours will the cistern be full? A) 4 hours B) 5 hours C) 7 hours D) 6 hours

Description : Two faucet A and Bcan fill a cistern in 6 hours and 2 hours respectively. If they are opened on alternate hours and if faucet A is opened first, in how many hours will the cistern be full? A) 4 hours B) 5 hours C) 7 hours D) 6 hours

Last Answer : A Faucet A can fill = 1/6 faucet B can fill = 1/2 For every two hour, 1/6 + 1/2 = 1+3/6 =>4/6=2/3 Part filled Total filled in 3 hours = 2/3+1/6= 5/6 In next hour it will be fille full. So total time will be 4 hours.

Twenty workers can complete a piece of work in 30 days. After how many days should 5 workers leave the job so that the work is completed in 35 days? a) 5 days b) 10 days c) 15 days d) 20 days

Description : Twenty workers can complete a piece of work in 30 days. After how many days should 5 workers leave the job so that the work is completed in 35 days? a) 5 days b) 10 days c) 15 days d) 20 days

Last Answer : c) 15 days

The disease of dry rot in timber is caused by (A) Lack of ventilation (B) Alternate wet and dry conditions (C) Complete submergence in water (D) None of the above

Description : The disease of dry rot in timber is caused by (A) Lack of ventilation (B) Alternate wet and dry conditions (C) Complete submergence in water (D) None of the above

Last Answer : Answer: Option A

If Ramesh can complete 2/5th of a work in 24 days and Satish can complete 1/3rd of the work in 30 days, then in how many days can they complete the wo

Description : If Ramesh can complete 2/5th of a work in 24 days and Satish can complete 1/3rd of the work in 30 days, then in how many days can they complete the wo

Last Answer : If Ramesh can complete 2/5th of a work in 24 days and Satish can complete 1/3rd of the work ... days can they complete the work if they work together?

Rishwi can finish a work in 6 days working 4 hours a day. Dhiviksha can complete the same work in 4 days working 5 hrs a day. If both rishwi and dhiviksha work together, working 4 hrs a day, in how many days can they finished the work? a) 30/11 b) 11/120 c) 11/30 d) 30/13

Description : Rishwi can finish a work in 6 days working 4 hours a day. Dhiviksha can complete the same work in 4 days working 5 hrs a day. If both rishwi and dhiviksha work together, working 4 hrs a day, in how many days can they finished the work? a) 30/11 b) 11/120 c) 11/30 d) 30/13

Last Answer : A Rishwi can complete the work in (6*4) = 24 hrs Dhiviksha can complete the work in (4*5) = 20 hrs Rishwi's 1 hr work = 1/24 Dhiviksh's 1 hr work = 1/20(Rishwi and dhivikasha)'s 1 hr work = (1/24 ... fininsh the work in (120/11)hrs Number of days of 4 hrs each = 120/11*1/4 =120/44 =30/11 days

A zoo has an average of 1020 visitors on Sundays and 480 on other days. The average number visitors per day in a month of 30 days beginning with a Sunday is. A) 5200 B) 570 C) 530 D) 450

Description : A zoo has an average of 1020 visitors on Sundays and 480 on other days. The average number visitors per day in a month of 30 days beginning with a Sunday is. A) 5200 B) 570 C) 530 D) 450

Last Answer : B)  Since the month begins with a Sunday So there will be 5 Sundays I the month Therefore required average = [(1020*5)+(480*25)/30] =(5100+12000)/30 =17100/30 = 570

For complete stabilisation of organic matter in polluted water, it takes (A) 5 days (B) 10 days (C) 20 days (D) 30 days

Description : For complete stabilisation of organic matter in polluted water, it takes  (A) 5 days  (B) 10 days  (C) 20 days  (D) 30 days 

Last Answer : (D) 30 days 

Kathir and Anand can do a work in 20 days and 30 days respectively. Kathir started the work and left after 4 days. Anand took over and completed the work. In how many days was the total work completed? a) 28 days b) 20 days c) 23 days d) 25 days e) 26 days

Description : Kathir and Anand can do a work in 20 days and 30 days respectively. Kathir started the work and left after 4 days. Anand took over and completed the work. In how many days was the total work completed? a) 28 days b) 20 days c) 23 days d) 25 days e) 26 days 

Last Answer : a Kathir’s one day’s work= 1/20 Kathir’s 4 day’s work =4* (1/20) = 1/5 Work left= 1-1/5 = 4 /5 Anand’s one day’s work= 1/30 Anand can do work in = (4/5) *(30/ 1) = 24 days So total days = 24+4 = 28 days

Rubika can do the 12 times the actual work in 72 days while sathya can do the one-half of the original work in 6 days. In how many days will both working together complete the 6 times of the original work? a) 20 days b) 25 days c) 30 days d) 35 days

Description : Rubika can do the 12 times the actual work in 72 days while sathya can do the one-half of the original work in 6 days. In how many days will both working together complete the 6 times of the original work? a) 20 days b) 25 days c) 30 days d) 35 days

Last Answer :  C Efficiency of Rubika = 16.666% Efficiency of sathya = 4.166% Total efficiency of rubika and sathya =(16+4) =20% Actual work 100/20=5 So, they can do actual work in 5 days So, 6 times work requires 30 days.

P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Description : P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Last Answer : B Work done by P,Q & R in 8 days = 1/20 * 8 =2/5 Remaining work = (1 - 2/5) = 3/5 Now 3/5 work is done by Q & R in 20 days Whole work will be done by Q & R in(20*5/3) =100/3 days (P+Q+R ... (Q+R)'s 1 day work =1/20 - 3/100 =5-3/100 =2/100 =1/50 P alone could complete the work in 50 days..

In the multidrug therapy of leprosy, rifampicin is given: A. Daily B. On alternate days C. Weekly D. Monthly

Description : In the multidrug therapy of leprosy, rifampicin is given: A. Daily B. On alternate days C. Weekly D. Monthly

Last Answer : D. Monthly

For the treatment of female infertility, clomiphene citrate is used in the following manner: A. Daily from 5th to 10th day of menstrual cycle B. On alternate days over the last two weeks of menstrual cycle C. Cyclically for 3 weeks with one week gap D. Continuously till conception occurs

Description : For the treatment of female infertility, clomiphene citrate is used in the following manner: A. Daily from 5th to 10th day of menstrual cycle B. On alternate days over the last two weeks of menstrual cycle C. Cyclically for 3 weeks with one week gap D. Continuously till conception occurs

Last Answer : A. Daily from 5th to 10th day of menstrual cycle

The following measure can minimise pituitary-adrenal suppression during long-term corticosteroid therapy: A. Use of betamethasone in place of prednisolone B. Use of prednisolone on alternate days C. Division of the daily dose in three equal 8 hourly doses D. Administration of the total daily dose at bed time

Description : The following measure can minimise pituitary-adrenal suppression during long-term corticosteroid therapy: A. Use of betamethasone in place of prednisolone B. Use of prednisolone on alternate days C. Division of ... in three equal 8 hourly doses D. Administration of the total daily dose at bed time

Last Answer : B. Use of prednisolone on alternate days

Audit programs are modified to suit the circumstances on particular engagements. A complete audit program for an engagement generally should be developed a. Prior to beginning the actual audit work. b. After the auditor has completed an evaluation of the existing internal accounting control. c. After reviewing the client's accounting records and procedures. d. When the audit engagement letter is prepared

Description : Audit programs are modified to suit the circumstances on particular engagements. A complete audit program for an engagement generally should be developed a. Prior to beginning the actual audit work. ... the client's accounting records and procedures. d. When the audit engagement letter is prepared

Last Answer : After the auditor has completed an evaluation of the existing internal accounting contro

The length of line measured with a chain was found to be 250m. Calculate the true length of line if i) The length was measured with 30 m chain and the chain was 10cm too long and ii) The length of chain was 30 m in the beginning and 30.10 m at the end of the work.

Description : The length of line measured with a chain was found to be 250m. Calculate the true length of line if i) The length was measured with 30 m chain and the chain was 10cm too long and ii) The length of chain was 30 m in the beginning and 30.10 m at the end of the work. 

Last Answer : Given Data: L = 30 m Measured Length = 250 m Solution: Case i) The length was measured with 30 m chain and the chain was 10cm too long L' = 30 + 0.1 = 30.1 m Correct Distance = (L'/L) x Measured Length ... = 30.05 m Correct Distance = (L'/L) x Measured Length  = (30.05/30) x 250  = 250.42 m

At the alternate aerodrome, the commander of a turbojet engine aeroplane should have a fuel quantity (final reserve) sufficient for flying during: a. 30 minutes at holding flight speed at 1,500 ft b. 45 minutes at holding flight speed at 1,500 ft c. 30 minutes at cruising speed d. 45 minutes at cruising speed

Description : At the alternate aerodrome, the commander of a turbojet engine aeroplane should have a fuel quantity (final reserve) sufficient for flying during: a. 30 minutes at holding flight speed at 1,500 ft b. 45 ... speed at 1,500 ft c. 30 minutes at cruising speed d. 45 minutes at cruising speed

Last Answer : a. 30 minutes at holding flight speed at 1,500 ft

Refer to CAP697 MRJT1 Fig. 4.3.1 Given: Estimated zero fuel mass 50t; estimated landing mass at destination 52t; final reserve fuel 2t; alternate fuel 1t; flight to destination distance 720nm, true course 030, W/V 340/30; cruise: LRC, at FL330 outside air temperature -30C. Find estimated trip fuel and time. a. 4,800kg / 01hr 45min b. 4,400kg / 02hr 02min c. 4,750kg / 02hr 00min d. 4,600kg / 02hr 05min

Description : Refer to CAP697 MRJT1 Fig. 4.3.1 Given: Estimated zero fuel mass 50t; estimated landing mass at destination 52t; final reserve fuel 2t; alternate fuel 1t; flight to destination distance 720nm, true course 030, W/V ... b. 4,400kg / 02hr 02min c. 4,750kg / 02hr 00min d. 4,600kg / 02hr 05min

Last Answer : a. 4,800kg / 01hr 45min

A,B and C can do a work in 20,45 and 120 days respectively.They started the work. A left 10 days before and B left 5 days before the completion of wor

Description : A,B and C can do a work in 20,45 and 120 days respectively.They started the work. A left 10 days before and B left 5 days before the completion of wor

Last Answer : A,B and C can do a work in 20,45 and 120 days respectively.They started the work. A left 10 ... work. In how many days is the total work completed ?

The APO shall submit its nominations with complete documentation to the Commission not later than ______ prior to the expiry of the term of an incumbent chairman or member. a. 30 days b. 60 days c. 90 days d. 120 days

Description : The APO shall submit its nominations with complete documentation to the Commission not later than ______ prior to the expiry of the term of an incumbent chairman or member. a. 30 days b. 60 days c. 90 days d. 120 days

Last Answer : 60 days

P and Q together can complete a job in 30 days. Q and R together can complete the same job in 40 days. P and R together can complete the same job in 40 days. What is the respective ratio of the number of days taken by P when completing the same job alone to the number of days taken by R when completing the same job alone? a) A.2:5 b) B.1:2 c) C.3:4 d) D.2:3

Description : P and Q together can complete a job in 30 days. Q and R together can complete the same job in 40 days. P and R together can complete the same job in 40 days. What is the respective ratio of the number of days taken by P ... R when completing the same job alone? a) A.2:5 b) B.1:2 c) C.3:4 d) D.2:3

Last Answer : B Efficiency of P and Q= 1/30 per day ___________1 ⇒ Efficiency of Q and R = 1/40 per day_________2 ⇒ Efficiency of R and P = 1/40 per day _________3 Taking equation 2 and 3 together ⇒ Q + R = ... 120 days he they work alone. ⇒ Ratio of number of days in which P and R can complete the job 1:2.

90 persons can complete a job in 32 days. 12 days after they started working, 60 more persons joined them. How many days will they now take to complete the remaining work? a) 10 days b) 12 days c) 14 days d) 16 days

Description : 90 persons can complete a job in 32 days. 12 days after they started working, 60 more persons joined them. How many days will they now take to complete the remaining work? a) 10 days b) 12 days c) 14 days d) 16 days

Last Answer : B (90 * 32) persons can complete the work in 1 day. 1 person 1 day's work = 1/(90 *32) i.e., 1/2880 90 person's 12 day's work = 1/32 * 12 = 3/8 Remaining work =(1- 3/8) = 5/8 150 persons 1 ... 5/96 work is done by them in 1 day . Therefore 5/8 work is done by them, = (96/5*5/8) =12 days.

If the purchases made during the year were Rs. 60,000, the balance of stock in trade at the beginning and at the end of the year were Rs. 12,000 and Rs. 9,000 respectively and the gross profit on sales was 1/5th, when which one of the following represents the figure of gross profit for the year ? (A) Rs. 15,750 (B) Rs. 14,000 (C) Rs. 12,500 (D) Rs. 17,250

Description : If the purchases made during the year were Rs. 60,000, the balance of stock in trade at the beginning and at the end of the year were Rs. 12,000 and Rs. 9,000 respectively and the gross profit on sales was 1/5th, when which ... year ? (A) Rs. 15,750 (B) Rs. 14,000 (C) Rs. 12,500 (D) Rs. 17,250

Last Answer : Answer: Rs. 12,500

Two pumps P & Q can fill a tank in 12 mins and 15 mins respectively while a third pipe R can empty the full tank in 6 mins. P & Q kept open for 5 mins in the beginning and then R is also opened. In what time is tank emptied? A) 30mins B) 35mins C) 40mins D) 45 mins

Description : Two pumps P & Q can fill a tank in 12 mins and 15 mins respectively while a third pipe R can empty the full tank in 6 mins. P & Q kept open for 5 mins in the beginning and then R is also opened. In what time is tank emptied? A) 30mins B) 35mins C) 40mins D) 45 mins

Last Answer : D Part filled in 5 min = 5(1/12 +1/15) = 5*9/60 = ¾ Part emptied in 1 min when all the pumps are opened, = 1/6 – (1/12 + 1/15) = 1/6 – 3/20 = 1/60 Now 1/60 is part emptied in 1 min Therefore ¾ part will be emptied in 60 * ¾ = 45 mins

In humans, ovarian follicles reach maturity from the beginning of a menstrual cycle in (a) 5 to 7 days (b) 7 to 9 days (c) 10 to 14 days (d) 14 to 16 days

Description : In humans, ovarian follicles reach maturity from the beginning of a menstrual cycle in (a) 5 to 7 days (b) 7 to 9 days (c) 10 to 14 days (d) 14 to 16 days

Last Answer : Ans:(c)

Can you complete the following beginning to a joke?

Description : Can you complete the following beginning to a joke?

Last Answer : The boxer said “you guys are so mean – you’re treating me like a dog!”

Complete the concept map: Beginning of urabanisation

Description : Complete the concept map: Beginning of urabanisation

Last Answer : Complete the concept map:

Fifteen men can complete a piece of work in 10 days, working 8 hours per day. How many persons are required to complete double the work in 25 days, wo

Description : Fifteen men can complete a piece of work in 10 days, working 8 hours per day. How many persons are required to complete double the work in 25 days, wo

Last Answer : Fifteen men can complete a piece of work in 10 days, working 8 hours per day. How many persons are ... work in 25 days, working 6 hours per day ?

A can complete a piece of work working along with B in 20 days. If he can complete the same work working along with C in 10 days, then between B and C

Description : A can complete a piece of work working along with B in 20 days. If he can complete the same work working along with C in 10 days, then between B and C

Last Answer : A can complete a piece of work working along with B in 20 days. If he can complete the same work ... , then between B and C who is more efficient ?

X, Y and Z can complete a piece of work in 10 days. X and Y can do it in 20 days. Then Z alone can complete the work in ……………… days.

Description : X, Y and Z can complete a piece of work in 10 days. X and Y can do it in 20 days. Then Z alone can complete the work in ……………… days.

Last Answer : X, Y and Z can complete a piece of work in 10 days. X and Y can do it in 20 days. Then Z alone can complete the work in ……………… days.

6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish the same work in 2 days. 15 men and 20 women can do the same work in - days. a) 4 days b) 6 days c) 2 days d) 8 days e) 7 days

Description : 6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish the same work in 2 days. 15 men and 20 women can do the same work in - days. a) 4 days b) 6 days c) 2 days d) 8 days e) 7 days

Last Answer : Let work done by 1 man in 1 day = m and work done by 1 woman in 1 day = b Work done by 6 men and 8 women in 1 day = 1/10 => 6m + 8b = 1/10 => 60m + 80b = 1 --- (1) Work done by 26 men and 48 ... 1 day = 15/100 + 20/200 =1/4 => Time taken by 15 men and 20 women in doing the work = 4 days Answer: a)

6 male , 8 female and 12 children can complete a work in 14 days .a female does twice the work of a male does and a child does half the work a male does . how many female alone can complete this work in 14 days? a) 15 b) 10 c) 12 d) 14

Description :  6 male , 8 female and 12 children can complete a work in 14 days .a female does twice the work of a male does and a child does half the work a male does . how many female alone can complete this work in 14 days? a) 15 b) 10 c) 12 d) 14

Last Answer :  D Let 1 female ‘s 1 day work= x Then 1 male’s 1 day work =x/2 And 1 child’s 1 day work =x/4 So 6x/2 + 8x +12x/4 =1/14 3x+8x+3x = 1/14 14x = 1/14 X=196 1 female alone can complete the work in 196 days So, to complete the work in 14 days number of female required = 14.

Sai and Ram working together completed a job in 10 days. If sai worked twice as efficiently as he actually did and ram worked 2/3 as efficiently as he actually did, the work would have been completed in 6 days. Sai alone could complete the work in. a) 40/3 days b) 42/4 days c) 44/6 days d) 43/3 days

Description : Sai and Ram working together completed a job in 10 days. If sai worked twice as efficiently as he actually did and ram worked 2/3 as efficiently as he actually did, the work would have been completed in 6 days. Sai alone could complete the work in. a) 40/3 days b) 42/4 days c) 44/6 days d) 43/3 days

Last Answer : A Let sai's 1 day work = x Ram's 1 day work = y Then x+y = 1/10 ===>1 and 2x +2y /3 = 1/6 (6x+2y )/3 = 1/6 6x + 2y =1/2 ====>2 Multiply 1 by 6 =>6x+6y = 6/10 2 = ... /10 - 1/40 = 4-1/10 =3/40 Sai's 1 day work = 3/40 So sai alone could complete the work in 40/3 days.

Satish, Goel and Khan can do a particular job in 24,36 and 48 days respectively. If they start working together and are paid ₹ 5200 for their work, th

Description : Satish, Goel and Khan can do a particular job in 24,36 and 48 days respectively. If they start working together and are paid ₹ 5200 for their work, th

Last Answer : Satish, Goel and Khan can do a particular job in 24,36 and 48 days respectively. If they ... 5200 for their work, then find their individual shares.

A and B working alone can finish a job in 5 days and 7 days respectively. They work at it alternately for a day. If A starts the work, find in how many days the job will be finished? a) 29/5 b) 11/5 c) 24/5 d) 21/5 e) None of these

Description : A and B working alone can finish a job in 5 days and 7 days respectively. They work at it alternately for a day. If A starts the work, find in how many days the job will be finished? a) 29/5 b) 11/5 c) 24/5 d) 21/5 e) None of these

Last Answer : Work done by A in one day = 1/5 and work done by B in one day = 1/7 They are working alternately. Therefore, Work done in first two day = (1/5 + 1/7) = 12/35 Work done in first four day = 24/35 Work done in ... = 4/35/1/7 = 4/5 of the day. Therefore Total days taken = 5 + 4/5 = 29/5 days Answer: b)

Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of theseSix bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of these

Description : Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of these

Last Answer : Answer – D (16) Explanation – L.C.M. of 2, 4, 6, 8, 10, 12 is 120.So, the bells will toll together after every 120 seconds, i.e, 2 minutes.In 30 minutes, they will toll together 30/2 + 1 = 16

A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m.? A.15 B.8 C.7 D.10 E.None of these

Description : A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m.? A.15 B.8 C.7 D.10 E.None of these

Last Answer : Answer – C (7) Explanation – Relative speed = (2 + 3) = 5 rounds per hourSo, they cross each other 5 times in an hour and 2 times in half an hourHence, they cross each other 7 times before 9.30 a.m.

Six bells commencing tolling together toll at intervals of 2, 3, 6, 8 , 10 and 12 seconds respectively.In 30 minutes how many times do they toll together?

Description : Six bells commencing tolling together toll at intervals of 2, 3, 6, 8 , 10 and 12 seconds respectively.In 30 minutes how many times do they toll together?

Last Answer : Ans 1. L.C.M of 2, 4, 6, 8, 10 and 12 is 120. so, the bells will toll together after 120 seconds i.e. 2 minutes . In 30 minutes the bells toll together 30/2 + 1 times i.e. times.

One method of troubleshooting digital circuits in a console is to ___________. A. supply alternate logic levels at the input(s) and test for change of state conditions at the output B. ground all inputs and test for a logic '1' at the output C. open all inputs and test for a logic '0' at the output D. vary each input smoothly from 0-10 volts and test for similar variance at the output

Description : One method of troubleshooting digital circuits in a console is to ___________. A. supply alternate logic levels at the input(s) and test for change of state conditions at the output B. ground all ... output D. vary each input smoothly from 0-10 volts and test for similar variance at the output

Last Answer : Answer: A

Twenty two men cann complete a piece of work in 17 days. They work for 2 days. How many more men should now be employed so as to complete the work in

Description : Twenty two men cann complete a piece of work in 17 days. They work for 2 days. How many more men should now be employed so as to complete the work in

Last Answer : Twenty two men cann complete a piece of work in 17 days. They work for 2 days. How many more men should now be ... A. 11 B. 22 C. 33 D. none of these

A is twice as fast as B and together they can complete a work in 20 days. In how many days can A alone complete the work?

Description : A is twice as fast as B and together they can complete a work in 20 days. In how many days can A alone complete the work?

Last Answer : A is twice as fast as B and together they can complete a work in 20 days. In how many days can A alone complete the work?

A is thrice as fast as B. If B can do a piece of work in 60 days, the number of days they take to complete the work is ……..

Description : A is thrice as fast as B. If B can do a piece of work in 60 days, the number of days they take to complete the work is ……..

Last Answer : A is thrice as fast as B. If B can do a piece of work in 60 days, the number of days they take to complete the work is ……..

48 boys complete a work in 36 days. After they have worked for 24 days, 24 more boys join them. How many days will they take to complete the remaining work? a) 8 days b) 6 days c) 4 days d) 3 days

Description : 48 boys complete a work in 36 days. After they have worked for 24 days, 24 more boys join them. How many days will they take to complete the remaining work? a) 8 days b) 6 days c) 4 days d) 3 days

Last Answer : A 1 boy’s 1 day’s work = 1/(36*48) =1/1728 48 boy’s 24 day’s work=48*24/1728=2/3 Remaining work = 1-2/3=1/3 72 boy’s 1 day’s work =72/1728=1/24 1/24 work is done by them in 1 day. So, 1/3 work is done by them in 24/3= 8 days