The arithmetic mean of 10 observations is 45. If one of the obsservations, 54, is deleted, then find the mean of the remaining observations.

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The arithmetic mean of 10 observations is 45. If one of the obsservations, 54, is deleted, then find the mean of the remaining observations.

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Description : A shopkeeper bought 30 kg of wheat at the rate of Rs 45 per Kg. He sold 40% of the total quantity at the rate of Rs 50 per Kg. Approximately, at what price per Kg should he sell the remaining quantity to make 25 per cent overall profit? 1. Rs 54 2. Rs 52 3. Rs 50 4. Rs 60

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Description : The mean of the data set comprising of 16 observation is 16. If one of the observation valued 16 is deleted and three new observations 3, 4, & 5 are a

Last Answer : The mean of the data set comprising of 16 observation is 16. If one of the observation valued 16 is deleted and three ... B. 16.8 C. `14.0` D. `16.0`

Description : The number of observations in a group is 40. The average of the first 10 members is 4.5 and the average of the remaining 30 members is 3.5. The average of the whole group is (A) 4 (B) 15/2 (C) 15/4 (D) 6

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Description :  on analyzing the result of an competitive exam the teacher found that the average for the entire the class was 69 marks. If we say that average of 10 % of the students scored 77 marks and average of 28 % of the ... marks of the remaining students of the class A) 67.54 B) 68.26 C) 66.91 D) 69.06 

Last Answer : D) average of entire class = 69marks average of 28 % of the students = 66 marks average of 10% of the students = 77 marks then % of remaining students = (100- 10 - 28) = 62% let the average of 62% of the ... (62*x)+770+1848= 6900 62 * x = 6900-770-1848 62*x = 4282 x = 69.06

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Description : A group of students of arithmetic mean of the marks in a test was 63. The brightest 30% of them secured a mean score of 70 and the dullest 15% a mean score of 41. The mean score of remaining 55 % is A) 63.675 B) 61.785 C) 65.181 D) 66.67

Last Answer : C) Let the requird mean score be ‘x’ Then (30*70)+(15*41)+55x = 63*100 2100+615+55x=6300 2715+55x=6300 55x=3585 X=65.181

Description : M do a piece of work in 45 days and N can finish it in 40 days. They work together for 5 days and then M leaves. In how many days will N finish the remaining work? a) 30 5/9 b) 29 4/9 c) 31 3/5 d) 29 5/9

Last Answer : A Time taken by M to finish the work = 45 days. M's 1 day's work = 1/45 Time taken by N to finish the work = 40 days. N's 1 day's work = 1/40 (M + N)'s 1 day's work = (1/40+1/45) = ... be done by N in (55/72*40) days = 30and 5/9 days. Hence, the remaining work is done by B in 30 and 5/9 days.

Description : A officer undertakes to complete a job in 250 days. He employs 300 male for 50 days and they complete 1/2 of the work . He then reduces the number of male to 100, who work for 120 days, after which there ... male must be employed for the remaining period to finish the work? a) 25 b) 50 c) 45 d) 35

Last Answer : B 300 male in 50 days do = 1/2work 1 male in 1 day does = ½*1/50*1/300 work 100 male in 120 days do = ½ *1/50*1/300 *100*120 =2/5 work Total work done = ½ + 2/5 =(5+4)/10=9/10 ... is done in 50 days by 300 male 1/10 work is done in 60 days by =300*50*1*2/10*60 =50 male

Description : In a cross joint tensile test the following observations were made: Specimen width 20mm, Material thickness 20mm, Max Load: 180kN, Break position: Parent Plate. What is the UTS? a) 45 kN/mm b) 450 N/mm2c) 39 kN/mm2d) 39 N/mm2

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Description : The 2 digit number which becomes (5/6)th of itself when its digits are reversed. The difference in the digits of the number being 1, then the two digits number is (a) 45 (b) 54 (c) 36 (d) None of these

Last Answer : (b) 54

Description : The 2 digit number which becomes (5/6)th of itself when its digits are reversed. The difference in the digits of the number being 1, then the two digits number is (a) 45 (b) 54 (c) 36 (d) None of these

Last Answer : (b) 54

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Last Answer : (i) 42 nd

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Description : 10 years ago the average age of all the 25 teachers of a college was 45 years. 4 years ago, a teacher retired from the post at the age of 60 years, and was replaced by a new teacher whose age was 54 years. ... 53 b) Between 53 and 54 c) Between 54 and 55 d) Between 55 and 56 e) None of the above

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Last Answer : (2) 173

Description : The mean marks obtained by a class of 40 students is 65. The mean marks of half of the students is found to be 45. The mean marks of the remaining students is (A) 85 (B) 60 (C) 70 (D) 65

Last Answer : Answer: A

Description : If the mean of the observations x, x + 3, x + 5, x + 7and x + 10 is 9, then mean of the last three observations is -Maths 9th

Last Answer : NEED ANSWER

Description : If the mean of the observations x, x + 3, x + 5, x + 7and x + 10 is 9, then mean of the last three observations is -Maths 9th

Last Answer : According to question find the mean of the last three observations

Description : If the sum of 10 observations is 95, then their mean is ______.

Last Answer : If the sum of 10 observations is 95, then their mean is ______.

Description : If the average of 4 observations x, x+1, x+2, x+3 is 12 then the average of last 2 observations is A) 10 B) 11 C) 12 D) 13

Last Answer :  D) We have (x+x+1+x+2x+3/40=12 4x+6=48 4x=42 x=10.5 so the numbers are 10.5,11.5, 12.5, 13.5 required average = 12.5+13.5/2 =26/2 =13.

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : NEED ANSWER

Description : The median of the data 78, 56, 22, 34, 45, 54, 39, 68, 54 and 84 is -Maths 9th

Last Answer : NEED ANSWER

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : (b) We arrange the given data into groups like 13-22,23-32 103-112. (since, our data is from 14 to 112). The class width in this case is 9. Now, the given data can be arranged in tabular form as follows. Hence, the number of classes in distribution will be 10.

Description : The median of the data 78, 56, 22, 34, 45, 54, 39, 68, 54 and 84 is -Maths 9th

Last Answer : According to question find the median of the data

Description : Which number does not fit in the row:12,27,36,45,49,54?

Last Answer : 12

Description : Find the missing number in the series: 60 59 57 54 50 _________. A. 45 B. 47 C. 44 D. 43

Last Answer : ANSWER: A

Description : Find the missing number in the series: 60 59 57 54 50 _________. A. 45 B. 47 C. 44 D. 43

Last Answer : ANSWER: A

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Last Answer : a) 48.59

Description : Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Last Answer : Let the age of Ram be R, brother be B R=3B And (R + 9 ) =1.5(B + 9) 3B + 9 =1.5B + 13.5 1.5B =4.5 or B = 3 years R= 9 years. Father current age = 4R(Since father is 3 times older than Ram, his ... R + 3 R, and not 3R) Father age when Ram is 1.5 times the age of his brother = 4R + 9 = 45. Answer : c

Description : Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Last Answer : Let the age of Ram be R, brother be B R=3B And (R + 9 ) =1.5(B + 9) 3B + 9 =1.5B + 13.5 1.5B =4.5 or B = 3 years R= 9 years. Father current age = 4R(Since father is 3 times older than Ram, his ... R + 3 R, and not 3R) Father age when Ram is 1.5 times the age of his brother = 4R + 9 = 45. Answer : c

Description : A certain thing is thrown twice from a place with the gap of 45 minutes between the two shots. A girl approaching this point in a train heard the second shot 44 minutes after she heard the first shot. What is the speed of train ... travels at 660 m/s? a) 62 km/hr b) 54 km/hr c) 48 km/hr d) 27 km/hr

Last Answer : B Actual time between the two shots being fired = 45 minutes. If a girl was stationary she would have heard the shots after 44 minutes. But since the train was moving towards the source, she heard the second shot after ... = (15 *18/5) km/hr =54 km/hr Hence the speed of the train is 54 km/hr

Description : Two faucet can separately fill a cistern 30minutes and 45 minutes respectively and when the waste faucet is open, they can together fill it in 54 minutes. The waste faucet can empty the full cistern in? A) 27 min B) 23 min C) 23 min D) 29 min 

Last Answer : A 1/30 + 1/45 - 1/x = 1/54 1/x=1/30+1/45-1/54 1/x=9+6-5/270 1/x=10/270 1/x=1/27 x = 27

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Description : Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41 

Last Answer :  Answer: A (i) Percentage scored in Mathematics = 120/180 100  = 12000/180  =1200/18  = 66 2 /3 % (ii) Total maximum of all the three subjects = 150 + 160 + 200 = 510 and Total score in the ... percentage on the whole = (400/510 100)  = (40000/510)  = 4000/51  = 78 22/51 %

Description : If the arithmetic mean of 150 numbers is calculated 70. If each number is increased by 10, then mean of new number is. A) 70 B) 80 C) 90 D) 60

Last Answer : B) Arithmetic mean of numbers = 70 Sum of 150 numbers = (70 * 150) =10500 Total increase = (150 * 10) = 1500 Increased sum = 10500 + 1500 = 12000 Increased average = 12000/150 =80

Description : If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th

Last Answer : x + x + 2 + x + 4 + x + 6 + x + 8 / 5 = 11 5x + 20 = 55 5x = 35 ⇒ x = 7

Description : The mean of 8 observations is 40. If 5 is added to each observation, then what will be the new mean ? -Maths 9th

Last Answer : Let the 8 observations are x1, x2, x3, x4, x5, x6, x7, x8 ∴ x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = 40 × 8 = 320 New mean = 320 + 5 × 8 = 360 / 8 = 45

Description : If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th

Last Answer : x + x + 2 + x + 4 + x + 6 + x + 8 / 5 = 11 5x + 20 = 55 5x = 35 ⇒ x = 7

Description : The mean of 8 observations is 40. If 5 is added to each observation, then what will be the new mean ? -Maths 9th

Last Answer : Let the 8 observations are x1, x2, x3, x4, x5, x6, x7, x8 ∴ x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = 40 × 8 = 320 New mean = 320 + 5 × 8 = 360 / 8 = 45

Description : The range of 12 observations is 60. If the least observation is 90, then find the greatest observation.

Last Answer : The range of 12 observations is 60. If the least observation is 90, then find the greatest observation. A. 130 B. 140 C. 150 D. 160

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Last Answer : (A) Rs. 48,000

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Last Answer : (A) 3

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Last Answer : Total actual CP = Rs. (1000*10+4000)=Rs. 14000 Total Sp = Rs.(5* 1500+5*1100) =Rs. 13000 Loss= cp-sp=1000 Loss %= (1000/14000)*100 = 7.14%

Description : If the arithmetic mean of the roots of the equation `4cos^(3)x-4cos^(2)x-cos(pi+x)-1=0` in the interval `[0,315]` is equal to `kpi`, then the value of

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Last Answer : Yes, it will produce a complete image of the object, as shown in the figure. This can be verified experimentally by observing the image of a distant object like a tree on a screen when the ... the lens is covered with a black paper. However, the intensity or brightness of the image will reduce.

Description : Rotary drilling (A) Is not suitable for deposits containing very coarse gravel (B) Hinders the ground water observations and permeability test (C) Is not economical for holes of less than 10 cm (D) All the above

Last Answer : Answer: Option D

Description : P,Q, R enter into a partnership.P initially invests Rs 54 lakh and withdraws Rs 18 lakhs after 4 years. Q initially Rs 72 lakh ans adds another Rs 18 lakhs after 6 years and R invests Rs 108 lakh and adds another ... Then for how many years did R invests Rs 126 lakh per annum A) 5 B) 7 C) 8 D) 11 

Last Answer : Answer: C) Ratio of their profit P, Q, R is 54*4+36*6:72*6+90*4:108*x+126*(10-x) =12:22:35 - 0.5x Profit of R=profit of P +profit of Q 35-0.5x=12+22 X=2 year The number of years for R invests Rs 126 lakh =10-2=8years

Description : The mean of four numbers a, b, c, d is 100. If c = 70, then the mean of the remaining numbers is (A) 30 (B) 85/2 (C) 170/3 (D) 110

Last Answer : Answer: D 

Description : Mean of 20 observations is 17. If in the observations, observation 40 is replaced by 12, find the new mean. -Maths 9th

Last Answer : Since mean of 20 observations is 17 Sum of the 20 observations = 17 x 20 = 340 New sum of 20 observations = 340 – 40 + 12 = 312 New mean=312 / 20 =15.6