Description : Given that the area of a figure varies as square of mean ordinate. The area of the figure is 154 sq. cm when the mean ordinate is 7 cm. The area of the figure when mean ordinate is 10.5 cm will be a.364.9 cm b.364.5 cm c.360.6 cm d.346.5 cm e.356.3 cm
Last Answer : d. 346.5 cm
Description : In a circle of radius 14 cm, an arc subtends an angle of 45 O at the centre, then the area of the sector is (a) 71 cm 2(b) 76 cm 2 (c) 77 cm 2 (d) 154 cm 2
Last Answer : (c) 77 cm 2
Description : Find the radius of a sphere whose surface area is 154 cm square. -Maths 9th
Last Answer : Let 'r' be the radius of sphere Surface area of sphere = 4 πr2 ⇒ 154 = 4 πr2 ⇒ 154 = 4 x 22/7 x r2 ⇒ r 2 = 154 x 7/4 x 22 = 49/4 ⇒ r = 7/2 cm = 3.5 cm
Description : The area of a circle is 154 sq cm. Its circumference is a) 44cm b) 88cm c) 154cm d) 176cm e) 164 cm
Last Answer : a) 44cm
Description : The volume of a sphere (V) varies directly as the cube of its radius. The volume of the sphere of radius 3 cm is ` 36 pi cm^(3)`. What is the volume o
Last Answer : The volume of a sphere (V) varies directly as the cube of its radius. The volume of the sphere of ... What is the volume of a sphere of radius 15 cm?
Description : A wire can be bent to form a circle of radius 56 cm. if it is instead bent in the form of a square, then its area will be: a) 6400 sq.cm b) 2025 sq.cm c) 7744 sq.cm d) 6561 sq.cm e) none of these
Last Answer : Length of the wire = circumference of the circle 2 × (22/7) × 56 = 2 × 22 × 8 = 352 cm side of square = 352/4 = 88cm area of square = 88 × 88 = 7744 sq.cm Answer: c)
Description : A cylindrical vessel can hold 154 g of water. If the radius of its base is 3.5 cm, and 1 cm3 of water weighs lg,find the depth of water. -Maths 9th
Last Answer : Since 1 cm3 of water weighs 1 g. ∴ Volume of cyclinder vessel = 154 cm3 πr2h = 154 h = 154 × 7 / 22 × 3.5 × 3.5 h ;= 4 cm Hence, the depth of water is 4 cm.
Description : In a heat exchanger, the rate of heat transfer from the hot fluid to the cold fluid (A) Varies directly as the area and the LMTD (B) Directly proportional to LMTD and inversely proportional to the area (C) Varies as square of the area (D) None of these
Last Answer : (A) Varies directly as the area and the LMTD
Description : A thin wire is in the shape of a circle of radius 77 cm. It is bent into a square. What is the side of the square? (a) 168 cm (b) 242 cm (c) 121 cm (d) 336 cm
Last Answer : (c) 121 cm
Description : With a constant diameter impeller of a centrifugal pump (A) Its capacity varies directly as the square of speed (B) Head varies as the square of speed (C) Horsepower input varies as the square of speed (D) Head varies as the speed
Last Answer : (B) Head varies as the square of speed
Description : At a constant speed of the centrifugal pump, it’s __________ the impeller diameter. (A) Capacity varies directly with (B) Head varies as the square of (C) Horsepower varies as the cube of (D) All (A), (B) and (C)
Last Answer : (D) All (A), (B) and (C)
Description : The terminal velocity of a sphere setting in a viscous fluid varies as : (a) The Reynolds number (b) The square of its diameter (c) Directly proportional to the viscosity of the fluid (d) Its diameter
Last Answer : (b) The square of its diameter
Description : The gravitational potential energy of an object close to the ground varies: w) inversely as its distance from the ground x) directly as its distance from the ground y) inversely as the square of its distance from the ground z) directly as the square of its distance from the ground
Last Answer : ANSWER: X -- DIRECTLY AS ITS DISTANCE FROM THE GROUND
Description : the curved surface area of a cylinder is 154 cm. the total surface area of the cylinder is three times its curved surface area. find the volume of the cylinder. -Maths 9th
Last Answer : T.S.A = 3*154 = 462 cm² C.S.A = 154 cm² C.S.A = 2πrh T.S.A = 2πr(r+h) Now, In T.S.A = 2πrr + 2πrh 462 = 2πrr + 2πrh 462 = 2*22/7*r*r + 154 462 - 154 = 2*22/7*r*r 308*7/2*22 = r*r 49 = r*r R = 7 cm ... 7*h 154/44 = h 7/2 =h H = 3.5 cm or 7/2 cm Now volume = πrrh = 22/7 * 7* 7 *7/2 = 11*49 = 539 cm³
Description : Discharge in laminar flow through a pipe varies (A) As the square of the radius (B) Inversely as the pressure drop (C) Inversely as the viscosity (D) As the square of the diameter
Last Answer : (A) As the square of the radius
Description : In laminar flow through a round tube, the discharge varies (A) Linearly as the viscosity (B) Inversely as the pressure drop (C) Inversely as the viscosity (D) As the square of the radius
Last Answer : (C) Inversely as the viscosity
Description : The mass of a liquid (in grams ) varies directly with its volume (in `cm^(3)`). A liquid would have a mass of 20 grams if its volume is 10 `cm^(3)`).
Last Answer : The mass of a liquid (in grams ) varies directly with its volume (in `cm^(3)`). A liquid would have a ... in grams, if its volume is 8 ` cm^(3)`).
Description : Given that x varies directly with the square of y. when x is 2,y is also 2. find y when x is 8. given that it is positive.
Last Answer : Given that x varies directly with the square of y. when x is 2,y is also 2. find y when x is 8. given that it is positive. A. 8 B. 6 C. 4 D. 2
Description : The rated life of a bearing varies (a) directly as load (b) inversely as the square of the load (c) inversely as the cube of the load
Last Answer : (c) inversely as the cube of the load
Description : The rated life of a bearing varies A. Directly as load B. Inversely as square of load C. Inversely as cube of load D. Inversely as fourth power of load
Last Answer : C. Inversely as cube of load
Description : The rated life of a bearing varies (A) Directly as load (B) Inversely as square of load (C) Inversely as cube of load (D) Inversely as fourth power of load
Last Answer : (C) Inversely as cube of load
Description : The head loss in turbulent flow in a pipe varies (A) Directly as the velocity (B) Inversely as the square of the velocity (C) Approximately as the square of the velocity (D) Inversely as the square of the diameter
Last Answer : (C) Approximately as the square of the velocity
Description : Power requirement of fans having constant wheel diameter varies __________ fan speed. (A) As square of (B) Directly as (C) As cube of (D) None of these
Last Answer : (C) As cube of
Description : . The pressure and power requirement of a gas fan at constant speed & capacity varies __________ the gas density. (A) Directly as (B) Inversely as square root of (C) Inversely as (D) As square of
Last Answer : (A) Directly as
Description : Consider the following statements in respect of steady laminar flow through a circular pipe: 1. Shear stress is zero on the central axis of the pipe 2. Discharge varies directly with the viscosity of the fluid 3. Velocity is maximum at the ... 2 , 3 & 4 (b) 1 & 3 only (c) 2 & 4 only (d)3 & 4 only
Last Answer : (b) 1 & 3 only
Description : Permeability of soil varies a) Inversely as square of grain size b) Inversely as grain size c) Directly as grain size d) Square of grain size*
Last Answer : d) Square of grain size*
Description : Find the volume of a sphere whose surface area is 154 cm sq. -Maths 9th
Last Answer : Let r cm be the radius of sphere. Surface area of the sphere = 4 πr2 ⇒ 154 = 4 πr2 ⇒ 4 x 22/7 x r2 = 154 r 2 = 154 x 7/4 x 22 = 72/22 ⇒ r = 7/2 Volume of sphere = 4/3 πr3 = 4/3 x 22/7 x 7/2 x 7/2 x 7/2 cm3 = 539/3 cm3 = 179.2/3 cm3
Description : A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th
Last Answer : ∵ PM = MQ = 1/2 = PQ = 45 cm and OP = 7.5 cm In right angled ΔOMP, using phthagoras theorem OM2 = OP2 - PM2 ⇒OM2 = 7.52 - 4.52 ⇒OM2 = 56.25 - 20.25 ⇒OM2 = 36 ∴ OM = √36 = 6 cm
Description : (i) The radius of a circle is increasing at the rate of 5 cm/sec. Find the rate of increasing of its perimeter. (ii) If the area of a circle increases
Last Answer : (i) The radius of a circle is increasing at the rate of 5 cm/sec. Find the rate ... to its circumference is iversely proportional to its radius.
Description : If The exact area of a circle is 81pi square inches what are the radius and diameter of the circle explain?
Last Answer : The radius is 9 inches because area of circle is pi*9 squared =81pi square inches and the diameter is twice the radius which is2*9 = 18 inches
Description : In the given figure, OACB is a quadrant of a circle of radius 7 cm. The perimeter of the quadrant is (a) 11 cm (b) 18 cm (c) 25 cm (d) 36 cm
Last Answer : (c) 25 cm
Description : A chord of a circle of radius 20 cm subtends an angle of 90° at the centre. Find the area of the corresponding major segment of the circle. -Maths 10th
Last Answer : Area of the minor segment = { pi × 90 /360 - sin 45 × cos 45 } × r × r ={ 3.14 ×1/4 - 1÷√2 ×1÷√2 } × 20 × 20 = { 3.14 ... Area of major segment = area of circle - area of minor segment = 1256 - 114 = 1142 HOPE IT HELPS YOU
Description : What is the area of a circle when the radius is 5.5 cm?
Last Answer : Using 3.14 as Pi the area of circle is: 94.985
Description : What is the area of the corresponding major sector of a circle of radius 28 cm and the central angle 45 o ? (a) 4312 cm 2 (b) 2156 cm 2 (c) 1256 cm 2 (d) 3412 cm 2
Last Answer : (b) 2156 cm 2
Description : The area of the circle that can be inscribed in a square of side 6 cm is (a) 36 π cm 2 (b) 18 π cm 2 (c) 12 π cm 2 (d) 9 π cm 2
Last Answer : (d) 9 π cm 2
Description : The resistance of a conductor varies _____________. A. directly as its length and inversely as its cross-sectional area B. inversely as its length and directly as its cross-sectional area C. directly ... as its cross-sectional area D. inversely as its length and inversely as its cross-sectional area
Last Answer : Answer: A
Description : What is the radius of the circle/ I.Ratio of its area to circumference is >7. II.Diameter of the circle is ≤ 32. If the question can be answered with the help of statement I alone, If ... the statements. If the data in either statement I or statement II alone is sufficient to answer the question.
Last Answer : Let the radius of the circle be r units From statement 1: [πr^2]/ [ 2 πr ] > 7 or r > 14 From statement II: 2r≤32 R ≤ 16 Hence, r can be 15 or 16 units Hence, Answer : d
Description : The radius of a circle is 13 cm and the length of one of its chords is 24 cm. Find the distance of the chord from the centre. -Maths 9th
Last Answer : Let PQ be a chord of a circle with centre O and radius 13cm such that PQ = 24cm. From O, draw OM perpendicular PQ and join OP. As, the perpendicular from the centre of a circle to a chord bisects the chord. ∴ PM ... Hence, the distance of the chord from the centre is 5cm.
Description : Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the A distance between AB and CD is 6 cm, find the radius of the circle. -Maths 9th
Last Answer : Join OA and OC. Let the radius of the circle be r cm and O be the centre Draw OP⊥AB and OQ⊥CD. We know, OQ⊥CD, OP⊥AB and AB∥CD. Therefore, points P,O and Q are collinear. So, PQ=6 cm. Let OP=x. Then, ... r2=52+(2.5)2=25+6.25=31.25 ⇒r2=31.25⇒r=5.6 Hence, the radius of the circle is 5.6 cm
Description : Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th
Last Answer : STEP1: Draw a circle with centre at point O and radius 5 cm. STEP2: Draw its cord AB. STEP3: With centre A as centre and radius more than half of AB, draw two arcs, one on each side ... is perpendicular bisector of AB which is chord of circle, Hence, it passes through the centre of the circle.
Description : he Radius (or diameter) of bright rings in Newton's rings is (a) Directly proportional to the square root of odd numbers (b) Inversely proportional to the square root of natural numbers (c) ... to the square root of even numbers (d) Directly proportional to the square root of natural numbers
Last Answer : (a) Directly proportional to the square root of odd numbers
Description : What is The area of a circle depending on the radius. Use the equation A(r) r2 to compute A(7). Round your answer to the nearest hundredth.?
Last Answer : The area of a circle is: pi times radius squared
Description : The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th
Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm
Description : If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is -Maths 9th
Last Answer : According to question the radius of the circle passing through the points A, B and C .