What is the area of a circle when the radius is 5.5 cm?

1 Answer

Answer :

Using 3.14 as Pi the area of circle is: 94.985

Related questions

Description : (i) The radius of a circle is increasing at the rate of 5 cm/sec. Find the rate of increasing of its perimeter. (ii) If the area of a circle increases

Last Answer : (i) The radius of a circle is increasing at the rate of 5 cm/sec. Find the rate ... to its circumference is iversely proportional to its radius.

Description : A chord of a circle of radius 20 cm subtends an angle of 90° at the centre. Find the area of the corresponding major segment of the circle. -Maths 10th

Last Answer : Area of the minor segment = { pi × 90 /360 - sin 45 × cos 45 } × r × r ={ 3.14 ×1/4 - 1÷√2 ×1÷√2 } × 20 × 20 = { 3.14 ... Area of major segment = area of circle - area of minor segment = 1256 - 114 = 1142 HOPE IT HELPS YOU

Description : The area of a circle (A) varies directly as the square of its radius. The area of the circle of radius 7 cm is 154 `cm^(2)`. What is the area of the c

Last Answer : The area of a circle (A) varies directly as the square of its radius. The area of the circle of ... What is the area of the circle of radius 35 cm?

Description : What is the area of the corresponding major sector of a circle of radius 28 cm and the central angle 45 o ? (a) 4312 cm 2 (b) 2156 cm 2 (c) 1256 cm 2 (d) 3412 cm 2

Last Answer : (b) 2156 cm 2

Description : In a circle of radius 14 cm, an arc subtends an angle of 45 O at the centre, then the area of the sector is (a) 71 cm 2(b) 76 cm 2 (c) 77 cm 2 (d) 154 cm 2

Last Answer : (c) 77 cm 2

Description : A wire can be bent to form a circle of radius 56 cm. if it is instead bent in the form of a square, then its area will be: a) 6400 sq.cm b) 2025 sq.cm c) 7744 sq.cm d) 6561 sq.cm e) none of these

Last Answer : Length of the wire = circumference of the circle 2 × (22/7) × 56 = 2 × 22 × 8 = 352 cm side of square = 352/4 = 88cm area of square = 88 × 88 = 7744 sq.cm Answer: c)

Description : A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th

Last Answer : ∵ PM = MQ = 1/2 = PQ = 45 cm and OP = 7.5 cm In right angled ΔOMP, using phthagoras theorem OM2 = OP2 - PM2 ⇒OM2 = 7.52 - 4.52 ⇒OM2 = 56.25 - 20.25 ⇒OM2 = 36 ∴ OM = √36 = 6 cm

Description : A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th

Last Answer : ∵ PM = MQ = 1/2 = PQ = 45 cm and OP = 7.5 cm In right angled ΔOMP, using phthagoras theorem OM2 = OP2 - PM2 ⇒OM2 = 7.52 - 4.52 ⇒OM2 = 56.25 - 20.25 ⇒OM2 = 36 ∴ OM = √36 = 6 cm

Description : Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the A distance between AB and CD is 6 cm, find the radius of the circle. -Maths 9th

Last Answer : Join OA and OC. Let the radius of the circle be r cm and O be the centre Draw OP⊥AB and OQ⊥CD. We know, OQ⊥CD, OP⊥AB and AB∥CD. Therefore, points P,O and Q are collinear. So, PQ=6 cm. Let OP=x. Then, ... r2=52+(2.5)2=25+6.25=31.25 ⇒r2=31.25⇒r=5.6 Hence, the radius of the circle is 5.6 cm

Description : If the sides of a triangle are 3 cm, 4 cm and 5 cm, then what is the radius of the circum-circle? -Maths 9th

Last Answer : Semi-perimeter of triangle (s) = \(rac{3+4+5}{2}\)cm = 6 cm∴ Area of triangle A = \(\sqrt{s(s-a)(s-b)(s-c)}\) = \(\sqrt{6 imes3 imes2 imes1}\) cm2 = 6 cm2∴ Radius of circum-circle = \(rac{abc}{4( ext{Area of}\,\Delta)}\) = \(rac{3+4+5}{4 imes60}\) cm = 2.5 cm

Description : Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th

Last Answer : STEP1: Draw a circle with centre at point O and radius 5 cm. STEP2: Draw its cord AB. STEP3: With centre A as centre and radius more than half of AB, draw two arcs, one on each side ... is perpendicular bisector of AB which is chord of circle, Hence, it passes through the centre of the circle.

Last Answer : I determined and what next? A circle inscribed in a triangle This is a circle that touches all sides of the triangle. The center of the circle inscribed in the triangle ABC is the intersection of the axes of the ... the 2nd series of the summer part of KMS 2009 / 2010.pdf example no.6" in Slovak

Description : From a circular plate of diameter 6 cm is cut out a circle whose diameter is a radius of the plate. Find the e.g. of the remainder from the center of circular plate (A) 0.5 cm (B) 1.0 cm (C) 1.5 cm (D) 2.5 cm

Last Answer : (A) 0.5 cm

Description : The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm

Description : If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is -Maths 9th

Last Answer : According to question the radius of the circle passing through the points A, B and C .

Description : The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm

Description : If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is -Maths 9th

Last Answer : According to question the radius of the circle passing through the points A, B and C .

Description : Find the length of a chord which is at a distance of 12 cm from the centre of a circle of radius 13 cm. -Maths 9th

Last Answer : Let AB be a chord of circle with centre O and radius 13cm. Draw OM perpendicular AB and join OA. In the right triangle OMA, we have OA2 = OM2 + AM2 ⇒ 132 = 122 + AM2 ⇒ AM2 = 169 - 144 ... . As the perpendicular from the centre of a chord bisects the chord.Therefore, AB = 2AM = 2 x 5 = 10cm.

Description : The radius of a circle is 13 cm and the length of one of its chords is 24 cm. Find the distance of the chord from the centre. -Maths 9th

Last Answer : Let PQ be a chord of a circle with centre O and radius 13cm such that PQ = 24cm. From O, draw OM perpendicular PQ and join OP. As, the perpendicular from the centre of a circle to a chord bisects the chord. ∴ PM ... Hence, the distance of the chord from the centre is 5cm.

Description : A circle has radius √2 cm. It is divided into two segments by a chord of length 2cm.Prove that the angle subtended by the chord at a point in major segment is 45 degree . -Maths 9th

Last Answer : Given radius =2 cm Therefore AO=2 cm Let OD be the perpendicular from O on AB And AB =2cm Therefore AD=1cm (perpendicular from the centre bisects the chord) Now in triangle AOD, AO=2 cm ... by a chord at the centre is double of the angle made by the chord at any poin on the circumference)

Description : What is the radius of a circle inscribed in a triangle having side lengths 35 cm, 44 cm and 75 cm? -Maths 9th

Last Answer : (d) 6 cmLet a = 35 cm, b = 44 cm, c = 75 cm. Thens = \(rac{a+b+c}{2}\) = \(rac{34+44+75}{2}\) cm = 77 cm∴ Area if triangle = \(\sqrt{77(77-35)(77-44)(77-75)}\) cm2= \(\sqrt{77 imes42 ... ) cm2 = 462 cm2∴ Radius of incircle = \(rac{ ext{Area}}{ ext{semi-perimeter}}\) = \(rac{462}{77}\) cm = 6 cm.

Description : In the figure below, CD is a chord of the semi circle with centre O. OA is the radius of the circle. If `CD=10` cm, `AB=2` cm and `bar(OA)_|_bar(CD)`

Last Answer : In the figure below, CD is a chord of the semi circle with centre O. OA is the radius of the ... |_bar(CD)` the length of OB is `"_____________"`

Description : The radius of a circle is 10cm. The length of a chord is 12 cm. Then the distance of the chord from the centre is `"__________________"`.

Last Answer : The radius of a circle is 10cm. The length of a chord is 12 cm. Then the distance of the chord from the centre is `"__________________"`.

Description : What is the approximate circumference of a circle with 17.4 cm radius?

Last Answer : Circumference of circle: 2*pi*17.4 = 109 cm approximately

Description : In the given figure, OACB is a quadrant of a circle of radius 7 cm. The perimeter of the quadrant is (a) 11 cm (b) 18 cm (c) 25 cm (d) 36 cm

Last Answer : (c) 25 cm

Description : A thin wire is in the shape of a circle of radius 77 cm. It is bent into a square. What is the side of the square? (a) 168 cm (b) 242 cm (c) 121 cm (d) 336 cm

Last Answer : (c) 121 cm

Description : If the radius of a circle that is 5 what is the area?

Last Answer : It is 78.5 square units.

Description : An isosceles triangle of vertical angle `2theta` is inscribed in a circle of radius `a` . Show that the area of the triangle is maximum when `theta=pi

Last Answer : An isosceles triangle of vertical angle `2theta` is inscribed in a circle of radius `a` . Show that the area of ... pi/4` C. `pi/6` D. None of these.

Description : A is the area of a circle with radius r units. Write the formula of area, making r as the subject.

Last Answer : A is the area of a circle with radius r units. Write the formula of area, making r as the subject.

Description : If The exact area of a circle is 81pi square inches what are the radius and diameter of the circle explain?

Last Answer : The radius is 9 inches because area of circle is pi*9 squared =81pi square inches and the diameter is twice the radius which is2*9 = 18 inches

Description : What is a polynomial for the area of a circle with radius(x plus 2) feet?

Last Answer : A = pi()*(x2 + 4x +4) square feet.

Description : What is The area of a circle depending on the radius. Use the equation A(r) r2 to compute A(7). Round your answer to the nearest hundredth.?

Last Answer : The area of a circle is: pi times radius squared

Description : What is the area in feet of a circle with a radius of 9?

Last Answer : Area of circle: pi times 9 squared = 254.469 square feet roundedto 3 decimal places

Description : What is The area of a circle depending on the radius. Use the equation A(r) r2 to compute A(7). Round your answer to the nearest hundredth.?

Last Answer : The area of a circle is: pi times radius squared

Description : What is the area in feet of a circle with a radius of 9?

Last Answer : Area of circle: pi times 9 squared = 254.469 square feet roundedto 3 decimal places

Description : What is a polynomial for the area of a circle with radius(x plus 2) feet?

Last Answer : A = pi()*(x2 + 4x +4) square feet.

Description : What is the area of a circle radius equal to 2?

Last Answer : Using 3.14 as Pi the area of circle is: 12.56

Description : What is the area of a circle with a radius of 4mm use 3.14 for pi?

Last Answer : A)12.56mm2 B)25.12mm2 C)50.24mm2 D)502.4mm2

Description : What is the area of a circle if the radius is 15.35 in?

Last Answer : Using 3.14 as Pi the area of circle is: 739.85465

Description : What is the area of a circle with the radius of 20 inches?

Last Answer : Using 3.14 as Pi the area of circle is: 1256.0

Description : If the radius of a circle is doubled, what about its area?(a) Area is 2 times (b) Area is 4 times (c) Area is half (d) does not change

Last Answer : (b) Area is 4 times

Description : What is the radius of the circle/ I.Ratio of its area to circumference is >7. II.Diameter of the circle is ≤ 32. If the question can be answered with the help of statement I alone, If ... the statements. If the data in either statement I or statement II alone is sufficient to answer the question.

Last Answer : Let the radius of the circle be r units From statement 1: [πr^2]/ [ 2 πr ] > 7 or r > 14 From statement II: 2r≤32 R ≤ 16 Hence, r can be 15 or 16 units Hence, Answer : d

Description : Area of a rectangle is equal to the area of circle whose radius is 14 cms. If the breadth of the rectangle is 22 cms. What is its length? a) 27 cms b) 28 cms c) 25 cms. d) 29 cms e) None of these

Last Answer : According to question, l×b = ¶r2 l ×22 = 22/7 ×14 × 14 l = 22/7 ×14 × 14/22 cms = 28 cms. Answer: b)

Description : Write a C++ program to declare a class ‘circle’ with data members as radius and area. Declare a function getdata to accept radius and putdata to calculate and display area of circle.

Last Answer : #include<iostream.h> #include<conio.h> class circle { float radius,area; public: void getdata() { cout<<"Enter radius:"; cin>>radius; } void putdata() { area=3 ... { circle c; clrscr(); c.getdata(); c.putdata(); getch(); }

Description : Define a class circle having data members pi and radius. Initialize and display values of data members also calculate area of circle and display it.

Last Answer : class abc {  float pi,radius; abc(float p, float r) { pi=p; radius=r; } void area() { float ar=pi*radius*radius; System.out.println("Area="+ar); } void display() { System.out.println("Pi="+pi ... void main(String args[]) { abc a=new abc(3.14f,5.0f); a.display(); a.area(); } }

Description : If the radius of a circle is increased by 50 per cent. Its area is increased by: (A) 125 per cent (B) 100 per cent (C) 75 per cent (D) 50 per cent

Last Answer : Answer: A Area of circle = pie * Radius *Radius. Suppose radius is 100 Hence Area= 3.14 *100 *100 =31400 Radius increase by 50% i.e 150 Therefore Area = 3.14 *150 *150 =70650 which is 125 % of original

Description : The surface area of a sphere of radius 5 cm -Maths 9th

Last Answer : Radius of the sphere (r1) = 5 cm Radius of the base of cone (r2) = 4 cm Let r сm be the height of the cone. Surface area of sphere = 4 πr2 ⇒ 4 π(5)2 = 100 π cm2 Curved surface area of cone = πrl = 4 πl ... ∴ Volume of cone = 1/3 πr2h = 1/3 x 22/7 x 42 x 3 = 352/7 cm3 = 50.29 cm3 (Approximately)

Description : If the circumference of a circle measures 1.5 pi cm what is the area of the circle in terms of pi?

Last Answer : circumference = 2πr→ r = circumference/2πarea = πr²= π(circumference/2π)²= circumference²/4π= (1.5π cm)²/4π= (3π/2 cm)²/4π= (9π²/4)/4π cm²= 9π/16 cm²= 0.5625π cm²

Description : Find the total surface area of a hemisphere of radius 10 cm -Maths 9th

Last Answer : Radius of hemisphere, r = 10cm Formula: Total surface area of hemisphere = 3πr2 = 3×3.14×102 = 942 The total surface area of given hemisphere is 942 cm2.

Description : A joker’s cap is in the form of right circular cone of base radius 7 cm and height 24cm. Find the area of the sheet required to make 10 such caps. -Maths 9th

Last Answer : Radius of conical cap, r = 7 cm Height of conical cap, h = 24cm Slant height, l2 = (r2+h2) = (72+242) = (49+576) = (625) Or l = 25 cm CSA of 1 conical cap = πrl = (22/7)×7×24 = 550 CSA of 10 caps = (10×550) cm2 = 5500 cm2 Therefore, the area of the sheet required to make 10 such caps is 5500 cm2.