If `(x)/(2a-3b)=(y)/(3b-4c)=(z)/(4c-2a)`, then find the value of `x^(3)+y^(3)+z^(3)`.

If `(x)/(2a-3b)=(y)/(3b-4c)=(z)/(4c-2a)`, then find the value of `x^(3)+y^(3)+z^(3)`.
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If `(x)/(2a-3b)=(y)/(3b-4c)=(z)/(4c-2a)`, then find the value of `x^(3)+y^(3)+z^(3)`.
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Last Answer : Given, point (2,3) lies on the line. So, the point (2, 3) is the solution of 3x - (a -1) y = 2a - 1 On putting x = 2 and y = 3 in given solution. ∴ 3 2 - (a-1) 3 = 2a - 1 ⇒ 6 - 3a + 3 = 2a - 1 ⇒ - 3a ... 2 2) 3 = 3b ⇒ 10 - 9 = 3b ⇒ 1 = 3b ⇒ 1 / 3 = b Hence, the value of b is 1 / 3.

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Last Answer : Given, point (2,3) lies on the line. So, the point (2, 3) is the solution of 3x - (a -1) y = 2a - 1 On putting x = 2 and y = 3 in given solution. ∴ 3 2 - (a-1) 3 = 2a - 1 ⇒ 6 - 3a + 3 = 2a - 1 ⇒ - 3a ... 2 2) 3 = 3b ⇒ 10 - 9 = 3b ⇒ 1 = 3b ⇒ 1 / 3 = b Hence, the value of b is 1 / 3.

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