Find the angle of intersection of the curves `x y=a^2a n dx^2+y^2=2a^2`

Find the angle of intersection of the curves `x y=a^2a n dx^2+y^2=2a^2`
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Find the angle of intersection of the curves `x y=a^2a n dx^2+y^2=2a^2`
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Last Answer : (a) 45º 3x + y - 7 = 0 ⇒ y = -3x + 7 ⇒ Slope (m1) = -3 x + 2y + 9 = 0 ⇒ y = \(rac{-x}{2}\) - \(rac{9}{2}\) ⇒ Slope (m2) = \(-rac{1}{2}\)If θ is the angle between the given lines, then tan θ = \(\ ... \bigg|rac{-rac{5}{2}}{1+rac{3}{2}}\bigg|\)= \(\bigg|rac{-rac{5}{2}}{rac{5}{2}}\bigg|\) = 1∴ θ = 45°.

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