Description : 20 gram of caustic soda are dissolved in water to prepare 500 ml of solution. Find the normality and molarity of solution.
Last Answer : Basis: 500 ml solution. Weight of solute = 20 gm Molecular weight of NaOH = 40 Gram moles of solute = 20/40 = 0.5 Molarity = Gram moles/ Volume of solution in lit 0.5/0.5 = 1 M Normality = gram equivalent of solute/ volume of solution in lit = 0.5/0.5 = 1N
Description : Hydrogen peroxide solution `(20 mL)` reacts quantitatively with a solution of `KMnO_(4) (20 mL)` acidified with dilute of `H_(2)SO_(4)`. The same volu
Last Answer : Hydrogen peroxide solution `(20 mL)` reacts quantitatively with a solution of `KMnO_(4) (20 mL)` ... calculate the molarity of `H_(2)O_(2)`.
Description : If 25mL of a `H_(2)SO_(4)` solution reacts completely with `1.06g` of pure `Na_(2)CO_(3)` , what is the normality of this acid sotution :
Last Answer : If 25mL of a `H_(2)SO_(4)` solution reacts completely with `1.06g` of pure `Na_(2)CO_(3)` , what is the normality of ... N B. 0.5 N C. 1.8 N D. 0.8 N
Description : Battery acid `(H_(2)SO_(4))` has density 1.285 g `cm^(-3)` , 10.0 `cm^(3)` of this acid is diluted to 1L . 25.0 `cm^(3)` of this diluted solution requ
Last Answer : Battery acid `(H_(2)SO_(4))` has density 1.285 g `cm^(-3)` , 10.0 `cm^(3)` of this acid is diluted ... the battery acid is : A. 98 B. 38 C. 19 D. 49
Description : For a solution of volatile liquids, the partial vapour pressure of each component in solution is directly proportional to its (a) Molarity (b) Mole fraction (c) Molality (d) Normality
Last Answer : Ans:(b)
Description : One of the following ways of expressing the concentration of a solution does not depend on temperature. It is-----? A. Molarity B. Molality (Answer) C. Normality D. Formality
Last Answer : B. Molality (Answer)
Description : The comple `[Fe(H_(2)O)_(6)NO]^(2+)` is formed in the brown ring test fro nitrates when freshly prepared `FesO_(4)` solution is added to aqueous solut
Last Answer : The comple `[Fe(H_(2)O)_(6)NO]^(2+)` is formed in the brown ring test fro nitrates when ... electrons is Fe. D. All the above are correct statement.
Description : When 0.50 liter of a 12M solution is diluted to 1.0 liters the molarity of this new solution is?
Last Answer : 6.0 M when you multiply 12M by the .50 liters you will get the6.0 M
Last Answer : : Molarity: The number of moles of dissolved solution per liter of a solution is called molarity of that solution. Molality: The number of moles of dissolved solution per solvent is called molality ... normal solution. The concentration of a normal solution is called normality. It is expressed by N.
Description : The number of moles of solute present in 1 kg of a solvent is called its (a) Molality (b) Molarity (c) Normality (d) Formality
Last Answer : Ans:(a)
Description : Which of the following modes of expressing concentration is independent of temperature - (1) Molarity (2) Molality (3) Normality (4) Formality
Last Answer : (2) Molality
Description : Which of the following concentration expressions is defined as the number of moles of solute per kilogram of solvent: w) molarity x) molality y) normality z) equivalents
Last Answer : ANSWER: X -- MOLALITY
Description : When `H_(2)O_(2)` is reacted with `K_(2)Cr_(2)O_(7)" in dilute "H_(2)SO_(4)` and then ether is added. The ether layer gets -colour
Last Answer : When `H_(2)O_(2)` is reacted with `K_(2)Cr_(2)O_(7)" in dilute "H_(2)SO_(4)` and then ether ... layer gets -colour A. Red B. Yellow C. Blue D. Green
Description : Which anion does not liberate any gas with dilute as well as conc. `H_(2)SO_(4)`.
Last Answer : Which anion does not liberate any gas with dilute as well as conc. `H_(2)SO_(4)`. A. `NO_(2)^(-)` B. `NO_(3)^(-)` C. `SO_(3)^(2-)` D. `SO_(4)^(2-)`
Description : Radium is a radioactive substance. It dissolves in dilute `H_(2)SO_(4)` and forms a compound radium sulphate. The compound is a)No longer radioactive
Last Answer : Radium is a radioactive substance. It dissolves in dilute `H_(2)SO_(4)` and forms a compound ... content D. twice as radioactive as the radium content
Description : What is the molarity of 5.60 mol of sodium carbonate in 1500 ml of solution?
Last Answer : Molarity = moles of solute/Liters of solution ( 1500 mL = 1.5 Liters ) Molarity = 0.800 moles NaOH/1.5 Liters = 0.533 M sodium hydroxide ...
Description : The relation between molarity (M) and molarity (m) is given by : (`rho` = density of solution (g/mL), `M_(1)` = molecular weight of solute) :-
Last Answer : The relation between molarity (M) and molarity (m) is given by : (`rho` = density of solution (g/mL), `M_(1 ... ))` D. `m = (1000M)/(1000rho -MM_(1))`
Description : In the titration of `K_(2)Cr_(2)O_(7)` and ferrous sulphate, following data is obtained: `V_(1)` mL of `K_(2)Cr_(2)O_(7)` solution of molarity `M_(1)`
Last Answer : In the titration of `K_(2)Cr_(2)O_(7)` and ferrous sulphate, following data is obtained: `V_(1)` mL of `K_(2)Cr_ ... V_(2)` D. `M_(1)V_(1)=M_(2)V_(2)`
Description : `{:("column I","column II"),("(A)"4.1gH_(2)SO_(3),"(p) 200 mL of 0.5 N base is used for complete neutralization"),("(B)" 4.9 g H_(3)PO_(4),"(q) 200 mi
Last Answer : `{:("column I","column II"),("(A)"4.1gH_(2)SO_(3),"(p) 200 mL of 0.5 N base is used for ... Na_(2)CO_(3),"(s)May react with an oxidising agent"):}`
Description : Titer refers to a. The most concentrated antigen-antibody concentration showing a reaction. b. The first diluted antigen-antibody concentration showing a reaction. c. The precipitation line ... antigen-antibody reaction. d. The most dilute antigen-antibody concentration showing a reaction.
Last Answer : d. The most dilute antigen-antibody concentration showing a reaction.
Description : Which of the following compounds does not form a salt with dilute HCl? (a) CH3CH2CONH2 (b) (CH3CH2)2NH (c) CH3CH2NH2 (d) (CH3CH2)3N
Last Answer : CH3CH2CONH2
Description : 3.0 ml of raw sewage is diluted to 300 ml. The D.O. concentration of the diluted sample at the beginning of the test was 8 mg/l. After 5 dayincubation at 20°C, the D.O. concentration was 5 mg/l. The BOD of raw sewerage is A. 100 mg/l B. 200 mg/l C. 300 mg/l D. 400 mg/l
Last Answer : ANS: C
Description : If the depletion of oxygen is found to be 2.5 mg/litre after incubating 2.5 ml of sewage diluted to 250 ml for 5 days at 20°C, B.O.D. of the sewage is A. 50 mg/l B. 100 mg/l C. 150 mg/l D. 250 mg/l
Last Answer : ANS: D
Description : Concentrated sulphuric acid is always diluted by adding which thing? -Do You Know?
Last Answer : answer:
Description : Concentrated sulphuric acid is always diluted by adding which thing?
Last Answer : Acid to water
Description : 1 g of complex `[Cr(H_(2)O)_(5)Cl]Cl_(2).H_(2)O` was passed through a cation exchanger to produce HCl. The acid liberated was diluted to 1 litre. What
Last Answer : 1 g of complex `[Cr(H_(2)O)_(5)Cl]Cl_(2).H_(2)O` was passed through a cation ... molarity of acid solution [Molecular weight of complex=266.5]?
Description : If a dilute solution of aqueous `NH_(3)` is saturated with `H_(2)S` then the product formed is :
Last Answer : If a dilute solution of aqueous `NH_(3)` is saturated with `H_(2)S` then the product formed is : A. `(NH_(4))_( ... (NH_(4))_(2)S_(x)` D. `NH_(4)OH+S`
Description : What is the molarity of a soloution which contains 22.41 grams of NaCl in 50.0 mL of soloutuon?
Last Answer : 0.4482
Description : By adding 1 ml of Orthotolidine solution to 100 ml chlorinated water taken after contact period, the residual chlorine makes the colour of solution (A) Yellowish (B) Greenish (C) Bluish (D) Reddish
Last Answer : (A) Yellowish
Description : Amount of oxalic acid present in a solution can be determined by its titration with `KMnO_(4)` solution in the presence of `H_(2)SO_(4)`. The titratio
Last Answer : Amount of oxalic acid present in a solution can be determined by its titration with `KMnO_(4)` ... . D. gets oxidised by oxalic acid to chlorine.
Description : What volume at NTP of gaseous ammonia will be required to be passed into `30 cm^(3)` of 1 N `H_(2)SO_(4)` solution to bring down the acid strength of
Last Answer : What volume at NTP of gaseous ammonia will be required to be passed into `30 cm^(3)` of 1 N `H_(2 ... down the acid strength of the latter of 0.2 N ?
Description : `[X]+H_(2)SO_(4) rarr [Y]` a colourless gas with irritating smell `[Y] + K_(2)Cr_(2)O_(7) + H_(2)SO_(4) rarr` green solution `[X]` and `[Y]` are
Last Answer : `[X]+H_(2)SO_(4) rarr [Y]` a colourless gas with irritating smell `[Y] + K_(2)Cr_(2)O_(7) + H_(2)SO_(4) rarr ... 2-), H_(2)S` D. `CO_(3)^(2-), CO_(2)`
Description : Assertion : A white turbidity is obtained by passing `H_(2)S` through aq solution of `SO_(2)` Reason: Aq solution of `SO_(2)` and `H_(2)S` undergoes r
Last Answer : Assertion : A white turbidity is obtained by passing `H_(2)S` through aq solution of `SO_(2 ... Statement-I is not correct and Statement-II is correct
Description : When `SO_(2)` is passed through acidified solution of `H_(2)S`
Last Answer : When `SO_(2)` is passed through acidified solution of `H_(2)S` A. `H_(2)SO_(3)` is formed B. ... . Sulphur is precipitated D. `H_(2)SO_(5)` is formed
Description : The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is
Last Answer : The volume (in ml) of 0.5 M NaOH required for the complete reaction with 150 ml of 1.5M `H_(3)PO_(3)` solution is A. 1350 B. 900 C. 1250 D. 1150
Description : Hydrazine `N_(2)H_(4)` acts as a reducing agent. To prepare 100 ml of 2 N hydrazine solution, the weight required will be
Last Answer : Hydrazine `N_(2)H_(4)` acts as a reducing agent. To prepare 100 ml of 2 N hydrazine solution, the weight required will ... B. 1.6 g C. 3.2 g D. 0.8 g
Description : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required 200 mL of 0.1 N `Na_(2)S_(2)O_(3)
Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated ... 56 mL B. 112 mL C. 168 mL D. 224 mL
Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required ... . 0.8 g C. 4.2 g D. 0.98 g
Last Answer : Some amount of "20V" `H_(2)O_(2)` is mixed with excess of acidified solution of Kl. The iodine so liberated required ... 37.2 mL C. 5.6 mL D. 22.4 mL
Description : To a 25 mL `H_(2)O_(2)` solution excess acidified solution of Kl was added. The iodine liberated 20 ml of 0.3 N sodium thiosulphate solution. Use thes
Last Answer : To a 25 mL `H_(2)O_(2)` solution excess acidified solution of Kl was added. The iodine liberated 20 ml of ... strength of `H_(2)O_(2)` is 1.344 L
Description : The volume of 3 M `Ba(OH)^(2)` solution required to neutralize completely 120 mL of 1.5M `H_(3)PO_(4)` solution is :
Last Answer : The volume of 3 M `Ba(OH)^(2)` solution required to neutralize completely 120 mL of 1.5M `H_(3)PO_(4)` solution is :
Description : If 1 mL of a `KMnO_(4)` solution react with 0.140g `Fe^(2+)` and if 1 mL of `KHV_(2)O_(4)`. `H_(2C_(2)O_(4)` solution react with o.1 mL of previous `K
Last Answer : If 1 mL of a `KMnO_(4)` solution react with 0.140g `Fe^(2+)` and if 1 mL of `KHV_(2)O_(4)`. `H_(2C_( ... 15/6 mL B. 13/16 C. `11/14` D. None of these
Description : The volume (in `mL`) of `0.1M Ag NO_(3)` required for complete precipitation of chloride ions present in `30 mL` of `0.01M` solution of `[Cr(H_(2)O)_(
Last Answer : The volume (in `mL`) of `0.1M Ag NO_(3)` required for complete precipitation of chloride ions present ... Cl]Cl_(2)`, as silver chloride is close to:
Description : You are given a solution of an alkali. In order to estimate its concentration in terms of normality , you need to know
Last Answer : You are given a solution of an alkali. In order to estimate its concentration in terms of ... the alkali present in it and its equivalent weight.
Description : How many grams per liter would there be in a 0.35 N (Normality) Citric acid solution?
Last Answer : The normality of a solution is the number of gram-equivalent weights of the dissolved substance per liter of solution. The gram-equivalent weight of the dissolved substance is the molecular weight of the dissolved ... would have (0.35)(64.4) = 22.41 grams of citric acid per liter of solution.
Description : Define normality of solution.
Last Answer : Normality of solution: It is defines as the number of gram equivalent of solute per liter of solution Normality = Gram equivant of solute/ volume of solution in liter
Description : Normality is defined as the number of: w) moles of solute per 1000 grams of solvent x) equivalent weights of solute per liter of solution y) kilograms of solute per liter of solution z) moles of solute per 1000 grams of solution
Last Answer : ANSWER: X -- EQUIVALENT WEIGHTS OF SOLUTE PER LITER OF SOLUTION
Description : What is the molarity of a solution made by dissolving 6 moles of naoh in 3 kg?
Last Answer : Need answer
Description : If addition of conc. `H_(2)SO_(4)` is made to an unknown salt, a colourless and odouriess gas is produced then which of the following can be present ?
Last Answer : If addition of conc. `H_(2)SO_(4)` is made to an unknown salt, a colourless and odouriess gas is produced then which ... C. `Cl^(-)` D. `NO_(3)^(-)`
Description : If 1.8 L of water is added to 2.5 L of a 7.0 M KOH solution what is the molarity of the new solution?
Last Answer : If 1.8 L of water is added to 2.5 L of a 7.0 M KOH solution,what is the molarity of the new solution?