How many grams per liter would there be in a 0.35 N (Normality) Citric acid solution?

How many grams per liter would there be in a 0.35 N (Normality) Citric acid solution?
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The normality of a solution is the number of gram-equivalent weights of the dissolved substance per  liter of solution. The gram-equivalent weight of the dissolved substance is the molecular weight of the  dissolved substance divided by the hydrogen equivalent of the dissolved substance. Citric acid has a  molecular weight of 192.12 and it contains three hydrogen equivalents (i.e., three COOH groups). Thus,  the gram equivalent weight of the citric acid dissolved in water is 192.12/3 = 64.04 grams. Therefore  0.35 Normal citric acid would have (0.35)(64.4) = 22.41 grams of citric acid per liter of solution.
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