In `(0,6pi)`, the number of solutions of the equation `tantheta+tan2theta+tan3theta=tanthetatan2thetatan3theta` is/are

Question

In `(0,6pi)`, the number of solutions of the equation `tantheta+tan2theta+tan3theta=tanthetatan2thetatan3theta` is/are

In `(0,6pi)`, the number of solutions of the equation `tantheta+tan2theta+tan3theta=tantheta*tan2theta*tan3theta` is/are

asked Jan 20, 2022 by anonymous

1 Answer

Answer :

In `(0,6pi)`, the number of solutions of the equation `tantheta+tan2theta+tan3theta=tantheta*tan2theta*tan3theta` is/are ... B. `17` C. `20` D. `12`

answered Jan 20, 2022 by anonymous

Related questions

The number of real solutions of the equation 2|x|^2 – 5|x| + 2 = 0 is : -Maths 9th

Description : The number of real solutions of the equation 2|x|^2 – 5|x| + 2 = 0 is : -Maths 9th

Last Answer : answer:

The number of distinct solutions of the equation `5/4cos^(2)2x + cos^4 x + sin^4 x+cos^6x+sin^6 x =2` in the interval `[0,2pi] ` is

Description : The number of distinct solutions of the equation `5/4cos^(2)2x + cos^4 x + sin^4 x+cos^6x+sin^6 x =2` in the interval `[0,2pi] ` is

Last Answer : The number of distinct solutions of the equation `5/4cos^(2)2x + cos^4 x + sin^4 x+cos^6x+sin^6 x =2` in the interval `[0,2pi] ` is

If a linear equation has solutions (-2, 2), (0, 0) and (2, – 2), then it is of the form. -Maths 9th

Description : If a linear equation has solutions (-2, 2), (0, 0) and (2, – 2), then it is of the form. -Maths 9th

Last Answer : (b) Let us consider a linear equation ax + by + c = 0 (i) Since, (-2,2), (0, 0) and (2, -2) are the solutions of linear equation therefore it satisfies the Eq. (i), we get At point(-2,2), -2a + 2b + c ... b(x + y)= 0 ⇒ x + y = 0, b ≠ 0 Hence, x + y= 0 is the required form of the linear equation.

The positive solutions of the equation ax + by + c = 0 always lie in the -Maths 9th

Description : The positive solutions of the equation ax + by + c = 0 always lie in the -Maths 9th

Last Answer : (a) We know that, if a line passes through the Ist quadrant, then all solution lying on the line in first quadrant must be positive because the coordinate of all points in the Ist quadrant are positive.

If a linear equation has solutions (-2, 2), (0, 0) and (2, – 2), then it is of the form. -Maths 9th

Description : If a linear equation has solutions (-2, 2), (0, 0) and (2, – 2), then it is of the form. -Maths 9th

Last Answer : (b) Let us consider a linear equation ax + by + c = 0 (i) Since, (-2,2), (0, 0) and (2, -2) are the solutions of linear equation therefore it satisfies the Eq. (i), we get At point(-2,2), -2a + 2b + c ... b(x + y)= 0 ⇒ x + y = 0, b ≠ 0 Hence, x + y= 0 is the required form of the linear equation.

The positive solutions of the equation ax + by + c = 0 always lie in the -Maths 9th

Description : The positive solutions of the equation ax + by + c = 0 always lie in the -Maths 9th

Last Answer : (a) We know that, if a line passes through the Ist quadrant, then all solution lying on the line in first quadrant must be positive because the coordinate of all points in the Ist quadrant are positive.

If the sum of all the solutions of the equation `8 cosx.(cos(pi/6+x)cos(pi/6-x)-1/2)=1` in `[0,pi]` is `k pi` then k is equal to

Description : If the sum of all the solutions of the equation `8 cosx.(cos(pi/6+x)cos(pi/6-x)-1/2)=1` in `[0,pi]` is `k pi` then k is equal to

Last Answer : If the sum of all the solutions of the equation `8 cosx.(cos(pi/6+x)cos(pi/6-x)-1/2)=1` in `[0,pi]` is `k pi` ... (20)/(9)` C. `(2)/(3)` D. `(13)/(9)`

Let `S={xepsilon(-pi,pi):x!=0,+pi/2}`The sum of all distinct solutions of the equation `sqrt3secx+cosecx+2(tan x-cot x)=0` in the set S is equal to

Description : Let `S={xepsilon(-pi,pi):x!=0,+pi/2}`The sum of all distinct solutions of the equation `sqrt3secx+cosecx+2(tan x-cot x)=0` in the set S is equal to

Last Answer : Let `S={xepsilon(-pi,pi):x!=0,+pi/2}`The sum of all distinct solutions of the equation `sqrt3secx+cosecx+2(tan x- ... 2pi)/(9)` C. `0` D. `(5pi)/(9)`

What are both solutions between 0 degrees and 360 degrees of the equation cos theta 911?

Description : What are both solutions between 0 degrees and 360 degrees of the equation cos theta 911?

Last Answer : They are 35.1 and 324.9 degrees.

How many solutions are there to the equation x3 - 7 0?

Description : How many solutions are there to the equation x3 - 7 0?

Last Answer : None because without an equality sign the given expression isnot an equation and so therefore no solutions are possible.

How many solutions are there to the equation x3 - 7 0?

Description : How many solutions are there to the equation x3 - 7 0?

Last Answer : None because without an equality sign the given expression isnot an equation and so therefore no solutions are possible.

The number of solutions satisfying the given equation -Maths 9th

Description : The number of solutions satisfying the given equation -Maths 9th

Last Answer : (d) 3Taking log of both the sides to base 3, we have,$\big[(log_3\,x)^2-rac{9}{2}log_3\,x+5\big]$ log3x = log333/2 = $rac{3}{2}$ (∵ log33 = 1)⇒ 2(log3x)3 - 9(log3x)2 + 10 log3x - 3 = 0 ⇒ ... log3x = 3, 2 log3x = 1 ⇒ x = 31, x = 33, x2 = 31⇒ $x$ = (3, 27, √3)∴ There are three solutions.

What are the number of solutions for real x, which satisfy the equation -Maths 9th

Description : What are the number of solutions for real x, which satisfy the equation -Maths 9th

Last Answer : log2 x>0 2log2 log2 x+log21 log2 (22 x)=1 ⇒2log2 log2 x−log2 log2 (22 x)=1[∵loga1 b=−loga b] $$\Rightarrow \log _{ 2 }{ \left[ \dfrac { { \left( \log _{ 2 }{ x } \right) }^{ 2 } }{ \log_{ 2 } ... log2 (22 )2=log2 8=log2 23=3] ⇒t=3,−1=log2 x ⇒x=2−1or 23 That is x=21 or 8 Hence, the answer is 8.

What happened to the solutions of this logarithmic equation?

Description : What happened to the solutions of this logarithmic equation?

Last Answer : They decided not to use imaginary or complex numbers. Like the square root of + and – 2

Find any four solutions of the equation 4x+3y=12. -Maths 9th

Description : Find any four solutions of the equation 4x+3y=12. -Maths 9th

Last Answer : Given equation is 4x + 3y =12 On putting x = 0 in Eq. (i), we get 4(0) +3y =12 ⇒ 3y =12 ⇒ y = 12 / 3 = 4 So, (0, 4) is a solution of given equation. On putting y = 0 in Eq. (i), we ... given equation. Hence the four solutions of given equation are (0, 4), (3, 0), (1, 8 / 3) and (2,4 / 3).

Draw the graph of the linear equation whose solutions are represented by the points having the sum of the coordinates as 10 units. -Maths 9th

Description : Draw the graph of the linear equation whose solutions are represented by the points having the sum of the coordinates as 10 units. -Maths 9th

Last Answer : As per question, the sum of the coordinates is 10 units. Let x and y be two coordinates, then we get x + y = 10. For x = 5, y = 5, therefore, (5, 5) lies on the graph of x + y = 10. For x = ... and (3, 7) on the graph paper and joining them by a line, we get graph of the linear equation x + y = 10.

How many solutions of the equation 2x + 1 = x – 3 are there on the Cartesian plane? -Maths 9th

Description : How many solutions of the equation 2x + 1 = x – 3 are there on the Cartesian plane? -Maths 9th

Last Answer : 2x + 1 = x - 3 2x-x = -3-1 ∴ x = - 4 ..(i) and it can be written as 1.x + 0. y = - 4 ..(ii) (i) Number line represent the all real values of x on the X ... the equation x + 4 = 0 represent a straight line parallel to Y-axis and infinitely many points lie on a line in the cartesian plane.

Find any four solutions of the equation 4x+3y=12. -Maths 9th

Description : Find any four solutions of the equation 4x+3y=12. -Maths 9th

Last Answer : Given equation is 4x + 3y =12 On putting x = 0 in Eq. (i), we get 4(0) +3y =12 ⇒ 3y =12 ⇒ y = 12 / 3 = 4 So, (0, 4) is a solution of given equation. On putting y = 0 in Eq. (i), we ... given equation. Hence the four solutions of given equation are (0, 4), (3, 0), (1, 8 / 3) and (2,4 / 3).

Draw the graph of the linear equation whose solutions are represented by the points having the sum of the coordinates as 10 units. -Maths 9th

Description : Draw the graph of the linear equation whose solutions are represented by the points having the sum of the coordinates as 10 units. -Maths 9th

Last Answer : As per question, the sum of the coordinates is 10 units. Let x and y be two coordinates, then we get x + y = 10. For x = 5, y = 5, therefore, (5, 5) lies on the graph of x + y = 10. For x = ... and (3, 7) on the graph paper and joining them by a line, we get graph of the linear equation x + y = 10.

How many solutions of the equation 2x + 1 = x – 3 are there on the Cartesian plane? -Maths 9th

Description : How many solutions of the equation 2x + 1 = x – 3 are there on the Cartesian plane? -Maths 9th

Last Answer : 2x + 1 = x - 3 2x-x = -3-1 ∴ x = - 4 ..(i) and it can be written as 1.x + 0. y = - 4 ..(ii) (i) Number line represent the all real values of x on the X ... the equation x + 4 = 0 represent a straight line parallel to Y-axis and infinitely many points lie on a line in the cartesian plane.

How many solutions does the equation 2x +5y=8 has? -Maths 9th

Description : How many solutions does the equation 2x +5y=8 has? -Maths 9th

Last Answer : Solution :- Infinitely many solutions.

Write any two solutions of the linear equation 3x + 2y =9. -Maths 9th

Description : Write any two solutions of the linear equation 3x + 2y =9. -Maths 9th

Last Answer : Solution :-

Write two solutions of the equation 4x -5 y = 15. -Maths 9th

Description : Write two solutions of the equation 4x -5 y = 15. -Maths 9th

Last Answer : Solution :-

NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.1 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.1 -Maths 9th

Last Answer : (i) (x + 4)(x + 10): Using the identity (x + a)(x + b) = x2 + (a + b)x + ab, we have: (x + 4)(x + 10) = x2 + (4 + 10)x + (4 x 10) = x2 + 14x + 40 (ii) (x + 8)(x - 10): Here, a = 8 and b = ( ... have 64m3 - 343n3 = (4m)3 - (7n)3 = (4m - 7n)[(4m)2 + (4m)(7n) + (7n)2] = (4m - 7n)(16m2 + 28mn + 49n2)

NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.2 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.2 -Maths 9th

Last Answer : 1. How will you describe the position of a table lamp on your study table to another person ? To describe the position of a table lamp placed on the table, let us consider the table lamp as P and the table as a plane ... the point A(4, 3). (ii) A unique cross street as shown by the point B(3, 4).

NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.3 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.3 -Maths 9th

Last Answer : 1: Draw the graph of each of the following linear equations in two variables: (i) x + y = 4 (ii) x - y = 2 (iii) y = 3x (iv) 3 = 2x + y Solution: (i)x + y= 4 ⇒ y = 4 - x If ... graph paper and joining them, we get a straight line PQ. Thus, PQ is the required graph of the linear equation y = 5x + 3.

NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.4 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.4 -Maths 9th

Last Answer : 1. Give the geometric representations of y = 3 as an equation (i) in one variable (ii) in two variables (i) y = 3 [An equation in one variable] ∵ y = 3 is an equation in one variable, i.e. y only. ∴ It has ... equation in two variables] We can write 2x + 9 = 0 as 2x + 0y + 9 = 0 or 2x = -9 + 0y

The solutions of a linear equation in two variables always take integral values .True / false -Maths 9th

Description : The solutions of a linear equation in two variables always take integral values .True / false -Maths 9th

Last Answer : answer:

A linear equation in two variables has infinite solutions. True/false. -Maths 9th

Description : A linear equation in two variables has infinite solutions. True/false. -Maths 9th

Last Answer : answer:

Write any four solutions of the linear equation y = 4 x – 11. -Maths 9th

Description : Write any four solutions of the linear equation y = 4 x – 11. -Maths 9th

Last Answer : answer:

What are both solutions between -180 and 180 degrees of the equation (tan theta -7over10)?

Description : What are both solutions between -180 and 180 degrees of the equation (tan theta -7over10)?

Last Answer : They are theta = -34.99 degrees and 145.09 deg.

How many solutions are there to the equation below 11x - 99 11(x - 9)?

Description : How many solutions are there to the equation below 11x - 99 11(x - 9)?

Last Answer : There are infinitely many solutions to 11x - 99 = 11(x - 9)

How many solutions are there to the equation below 4x - 9(x plus 1) 20 - 5x?

Description : How many solutions are there to the equation below 4x - 9(x plus 1) 20 - 5x?