If `(m + 2) sintheta + (2m-1) costheta = 2m+1`, then

If `(m + 2) sintheta + (2m-1) costheta = 2m+1`, then
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If `(m + 2) sintheta + (2m-1) costheta = 2m+1`, then A. `tantheta=(3)/(4)` B. `tantheta=(2m)/(m^(2 ... `tantheta=(2m)/(m^(2)-1)` D. `tantheta=(4)/(3)`
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