A rectangular plot has a concrete path running inner side of the plot is used as a  lawn, which has an area of 432 sq.m. If the width of the path is 4 m and the length of  the plot is greater than its breadth by 2m, what is the area of the rectangular plot? 1) 980 m^2
2) 975 m^2
3) 984 m^2
4) 960 m^2
5) 965 m^2

1 Answer

Answer :

4) 960 m^2

Related questions

Description : A rectangular park has a concrete footpath running in the middle of the park parallel to the length of the park. The rest of the park is used as a playing ground, which has an area of 253 sq. m. If the width of the path ... m. What is the area of the park? (in sq. m.) (a) 896 (b) 345 (c) 432

Last Answer : (b) 345

Description : A rectangular grassy plot 110 m by 65 m has a gravel path 2.5 m wide all round it on the inside. Find the cost of gravelling the path at 80 paise per sq. Meter 1).Rs.680 2).Rs.860 3).Rs.608 4).None.

Last Answer : 1).Rs.680 Exp: overall area of the grassy plot is 110 x 65 =7150 sq. meters.The area of the grassy plot after applying the gravel path is 105 x 60=6300 sq. meters.Area of the gravel path is 7150 – 6300 = 850 sq.mtrs.Hence x 0.80=Rs.680 .

Description : The width of a rectangular park is 10/21 of its length. If the area of the park is 3360 sq m, then what is the difference between the length and the width of the park? a) 40m b) 44m c) 48m d) 52m e) 56m

Last Answer : Let the length of the park be x metres. Width = x × 10 / 21 = 10x / 21 Area = x × 10x / 21 = 3360 or, x^2 = 3360 × 21 / 10 = 7056 or, x = 84 Hence, length = x = 84m and width = 84 × 10 / 21 = 40 metres Difference = 84 – 40 = 44 metres Answer: b)

Description : The external length, breadth and height of a closed box are 10cm, 9cm and 7cm respectively. The total inner surface area of the box is 262 sq.cm. If the walls of the box are of uniform thickness “t” cm, then “t” equals a) 1cm b) 23/3 cm c) 28/9 cm d) 42.5 cm

Last Answer : a) 1cm

Description : Alternating voltages and phasors (Problem 4)

Last Answer : Alternating voltages and phasors (Problem 4)

Description : Problem on resistance and resistivity 4

Last Answer : Problem on resistance and resistivity 4

Description : Source free RC circuit 4

Last Answer : Source free RC circuit 4

Last Answer : Source free RL circuit 4

Description : The slip of 400 V, three phase, 4 -pole induction motor when rotating at 1440 rpm is 

Last Answer : The slip of 400 V, three phase, 4 -pole induction motor when rotating at 1440 rpm is 4 percent

Description : A cylindrical cable of core radius 1.25cm and impregnated paper insulation of thickness 2.13cm and relative permittivity 3.5. Compute the capacitance of the cable/km (in nF

Last Answer : To calculate the capacitance of the cable per kilometer, you can use the following formula: C = ε * ε0 * A / d where: C is the capacitance of the cable per kilometer (in farads) ε is ... * 10^9 = 644 nF/km So the capacitance of the cable per kilometer would be approximately 644 nanofarads.

Description : While testing a cast iron beam (2.5 cm × 2.5 cm) in section and a metre long simply supported at  the ends failed when a 100 kg weight is applied at the centre. The maximum stress induced is:  (A) 960 kg/cm2 (B) 980 kg/cm2 (C) 1000 kg/cm2 (D) 1200 kg/c

Last Answer : (A) 960 kg/cm

Description : Any good sources for Installer/Cydia?

Last Answer : Look for instructions at modmyiphone.com

Description : When is the 'iPod Touch' 2.0 Software Being Released?

Last Answer : answer:Nobody really knows yet. I have been checking and nothing official is out. http://www.apple.com/itunes/store/appstore.html It still says “Coming Soon” for the app store. edit :: The store is out already. The firmware to install the apps is still unreleased.

Description : State the material used for making (1) Magnetic Core (2) Fuse element  

Last Answer : The material used for making of:  (1) Magnetic Core : Iron, cobalt, Nickel, CRGO, HRGO , silicon steel  (2) Fuse Element: Tin- lead wire, Tinned copper wire 

Description : Nodal Analysis Example 2

Last Answer : Nodal Analysis Example 2

Description : Sinusoidal Steady-State Analysis - nodal analysis super node problem solution 2

Last Answer : Sinusoidal Steady-State Analysis - nodal analysis super node problem solution 2

Description : Alternating voltages and phasors : phasor addition (Problem 2)

Last Answer : Alternating voltages and phasors : phasor addition (Problem 2)

Description : Problem on temperature coefficient of resistance 2

Last Answer : Problem on temperature coefficient of resistance 2

Description : Problem on resistance and resistivity 2

Last Answer : Problem on resistance and resistivity 2

Description : Problem on electrical power and energy 2

Last Answer : Problem on electrical power and energy 2

Description : Source free RC circuit 2

Last Answer : Source free RC circuit 2

Description : Source free RL circuit 2

Last Answer : Source free RL circuit 2

Description : If the length of a rice field is increased by 20% and the breadth is reduced by 20%, the area of the field will be 192 sq. m. What is the area of the original field? (a) 184 sq. m. (b) 196 sq. m. (c) 204 sq. m. (d) 225 sq. m. (e) None of these

Last Answer : (e) None of these

Description : What is the total area of India? (1) 8,511,965 sq. km (2) 3,897,950 sq. km (3) 5,926,780 sq. km (4) 3,287,590 sq. km

Last Answer : (4) 3,287,590 sq. km Explanation: The total geographical area of India is 3.287,590 km2 which makes her the seventh-largest country in the world. India measures 3,214 km from north to south and 2,933 km from east to west. It has a land frontier of 15,200 km and a coastline of 7,517 km.

Description : What is the total area of India ? (1) 8,511,965 sq. km (2) 3,897,950 sq. km (3) 5,926,780 sq. km (4) 3,287,590 sq. km

Last Answer : 3,287,590 sq. km

Description : A goat is tied to one corner of a square plot of side 12 meter by a rope 7 meter long. Find the area it can graze? (a) 38.5 sq.m (b) 155 sq.m (c) 144 sq.m (d) 19.25 sq.m

Last Answer : (a) 38.5 sq.m

Description : If the length of a rectangle is decreased by 3 units and breadth increased by 4 unit, then the area will increase by 9 sq. units. Represent this situation as a linear equation in two variables. -Maths 9th

Last Answer : Solution :-

Description : Area of steel required per metre width of pavement for a length of 20 m for design wheel load 6300 kg and permissible stress in steel 1400 kg/cm2 , is (A) 70 kg/sq cm (B) 80 kg/sq cm (C) 90 kg/sq cm (D) 100 kg/sq cm

Last Answer : Answer: Option C

Description : The length, breadth and height of a rectangular parallelopiped are in the ratios 6 : 3 : 1. If the surface area of a cube is equal -Maths 9th

Last Answer : answer:

Description : If a circular grass lawn of 35 m in radius has a path 7 m wide running around it on the outside, then the area of the path is (a) 1450 m 2 (b) 1576 m 2 (c) 1694 m 2 (d) 3368 m 2

Last Answer : (c) 1694 m 2

Description : For a ribbed slab (A) Clear spacing between ribs shall not be greater than 4.5 cm (B) Width of the rib shall not be less than 7.5 cm (C) Overall depth of the slab shall not exceed four times the breadth of the rib (D) All the above

Last Answer : Answer: Option D

Description : The excavation exceeding 1.5 m in width and 10 sq.m in plan area with a depth not exceeding 30 cm, is termed as (A) Excavation (B) Surface dressing (C) Cutting (D) Surface excavation

Last Answer : (D) Surface excavation

Description : A simply supported uniform rectangular bar breadth b, depth d and length L carries an isolated  load W at its mid-span. The same bar experiences an extension e under same tensile load. The  ratio of the maximum deflection to the ... (A) L/d (B) L/2d (C) (L/2d)² (D) (L/3d)²

Last Answer : (C) (L/2d)

Description : If L, B and D length, breadth and depth of water in a rectangular sedimentation tank of total  discharge Q, the settling velocity, is  (A) Q/H (B) Q/D (C) Q/(D × B)  (D) Q/(L × B) 

Last Answer : (D) Q/(L × B) 

Description : The recommended width of Double line cutting formation for B G is a) 10210 mm b) 10 975 mm c) 11555 mm* d) 10 820 mm

Last Answer : c) 11555 mm*

Description : The dimensions of a rectangular settling tank are: length 24 m, width 6 m and depth 3 m. If 2 hour detention period for tanks is recommended, the rate of flow of sewage per hour, is A. 204 cu.m B. 208 cu.m C. 212 cu.m D. 216 cu.m

Last Answer : ANS: D

Description : What are these in increasing order of length 785 m 884mm 432 cm?

Last Answer : I suggest you convert them all to a common unit (for instance,convert everything to meters). Then you can easily comparethem.

Description : what- the length of a rectangular carpet is 2 times its width. The area of the carpet is 128 square feet.What is the length of the carpet?

Last Answer : 16 ft.

Description : A leaf spring consists of 3 extra full length leaves and 14 graduated length leaves. The maximum force that can act on the spring is 70kN and the distance between eyes of the spring is 1.2m. Width and thickness of the ... close the nip. (a) 4332.2N (b) 4674.1N (c) 4985.4N (d) Can't be determined

Last Answer : (b) 4674.1N

Description : A leaf spring consists of 3 extra full length leaves and 14 graduated length leaves. The maximum force that can act on the spring is 70kN and the distance between eyes of the spring is 1.2m. Width and thickness of the ... /mm², calculate the initial nip. (a) 26.8mm (b) 24.9mm (c) 22.5mm (d)23.1mm

Last Answer : b) 24.9mm

Description : A queen closer is a (A) Brick laid with its length parallel to the face or direction of wall (B) Brick laid with its breadth parallel to the face or direction of wall (C) Brick having the same ... bricks but half the breadth (D) Brick with half the width at one end and full width at the other

Last Answer : Answer: Option C

Description : what- sam has 15 identical rectangular windows in his home. The length of each window is twice the width, and the area of each window is 8 square feet. Sam wants to ...?

Last Answer : 45

Description : What Rectangular pool has an area of 192 square feet. The length of the pool is 15 feet. What is the pool and width rounded to the nearest foot?

Last Answer : 13 feet

Description : In a plot of 18000 sq. m., only 13500 sq. m. is allowed for construction. What percent of the plot is to be left without construction? a) 25 b) 60 c) 45 d) 40 e) 98

Last Answer : Answer: A Percentage of plot allowed for construction = (13500/18000 × 100) = 75 %. Thus, the percentage of plot to be left without construction = 100 % - 75 % = 25 %.

Description : A calf is tied with a rope of length 6 m at the corner of a square grassy lawn of side 20 m. If the length of the rope is increased by 5.5 m, find the increase in area of the grassy lawn in which the calf can graze. -Maths 10th

Last Answer : Given, The initial length of the rope = 6 m Then the rope is said to be increased by 5.5m So, the increased length of the rope = (6 + 5.5) = 11.5 m We know that, the corner of the lawn is a quadrant of a circle. Thus ... – 62) = 1/4 x 22/7 (132.25 – 36) = 1/4 x 22/7 x 96.25 = 75.625 cm2

Description : ABCD is a rectangular plot of land. If the bearing of the side AB is 75°, the bearing of DC is  (A) 75°  (B) 255°  (C) 105°  (D) 285° 

Last Answer : (A) 75° 

Description : To prevent segregation the concrete should to be thrown from a height of more than. (a) ½ m (b) 1m (c) 1.5m (d) 2m

Last Answer : (b) 1m

Description : Is 0.98 greater than .980?

Last Answer : Need answer

Description : If it takes one bag of cement to cover 10 sq. meters of path how many bags of cement will you buy to cover a path that is 21 m long and 2.5 m?

Last Answer : First you need to work out how many square meters are in thepath. To do that multiply 21 by 2.521 X 2.5 = ?sqmYou know one bag of cement will cover 10 sqm so to find out howmany bag are needed for the path divide the answer of 21 X 2.5 by10?/10 =6 bags

Description : A rectangular plot is given for constructing a house having a measurement of 40 m long and 15 m in the front. -Maths 9th

Last Answer : Let ABCD is a rectangular plot having a measurement of 40 m long and 15 m front. ∴ Length of inner-rectangle, EF = 40 - 3 - 3 = 34 m and breadth of inner-rectangle, FG =15 - 2 - 2 = ... [∴ area of a rectangle = length x breadth] Hence, the largest area where the house can be constructed in 374 m2