Express the following in exponential form. (i) 625 (ii) 1024 (iv) 507 (v) 360

Express the following in exponential form. (i) 625 (ii) 1024 (iv) 507 (v) 360
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Express the following in exponential form. (i) 625 (ii) 1024 (iv) 507 (v) 360
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(1) If `5^(n+2)=625 ,f i n d[(n+3)]^(1/3)`: (2) If `(32/243)^n=8/27 ,f i n d((n+0. 4)/1024)^(-n)`

Description : (1) If `5^(n+2)=625 ,f i n d[(n+3)]^(1/3)`: (2) If `(32/243)^n=8/27 ,f i n d((n+0. 4)/1024)^(-n)`

Last Answer : (1) If `5^(n+2)=625 ,f i n d[(n+3)]^(1/3)`: (2) If `(32/243)^n=8/27 ,f i n d((n+0. 4)/1024)^(-n)`

Write the following in exponential form and redical form. (i) Cube root of 729 (ii) Fifth root of 1990 (iii) Square root of 2001 (iv) Seventh root of

Description : Write the following in exponential form and redical form. (i) Cube root of 729 (ii) Fifth root of 1990 (iii) Square root of 2001 (iv) Seventh root of

Last Answer : Write the following in exponential form and redical form. (i) Cube root of 729 (ii) Fifth root of ... ) Square root of 2001 (iv) Seventh root of 777

Find the number which when decreased by 24 % becomes 594. a) 625.8 b) 360.9 c) 465.7 d) 781.5 e) 398.5

Description : Find the number which when decreased by 24 % becomes 594. a) 625.8 b) 360.9 c) 465.7 d) 781.5 e) 398.5

Last Answer : Answer: D Let the number be m. Decrease = 24 % of m  = 24/100 × m = 6m /25 Therefore, decrease number = m – 6m/25 = (25m – 6m)/25 = 19m/25 According to the question 19m/25 = 594  19m = 594 × 25  19m = 14850  m = 14850/19  m =781.5

How many times does 9 go into 507?

Description : How many times does 9 go into 507?

Last Answer : 56 times... with 3 remainder.

If 507 gfecl2 were used up in the reaction fecl2 plus 2naoh feoh2s plus 2nacl how many grams of feoh2 would be formed?

Description : If 507 gfecl2 were used up in the reaction fecl2 plus 2naoh feoh2s plus 2nacl how many grams of feoh2 would be formed?

Last Answer : 359.48 g Fe(OH)2

Express each of the following as a ratio: (i) 43% (ii) 36% (iii) 7.5% (iv) 125% -Maths

Description : Express each of the following as a ratio: (i) 43% (ii) 36% (iii) 7.5% (iv) 125% -Maths

Last Answer : answer:

Express the following as pth power of qth root of x. (i) `(156)^(5/3)` (ii) `(-23)^(3/7)` (iii) `(2/3)^(3/2)` (iv) `(0.61)^(5/9)`

Description : Express the following as pth power of qth root of x. (i) `(156)^(5/3)` (ii) `(-23)^(3/7)` (iii) `(2/3)^(3/2)` (iv) `(0.61)^(5/9)`

Last Answer : Express the following as pth power of qth root of x. (i) `(156)^(5/3)` (ii) `(-23)^(3/7)` (iii) `(2/3)^(3/2)` (iv) `(0.61)^(5/9)`

Why do you think Mr Keesing chose the title - ̳An Incorrigible Chatterbox‘? i) Anne to express her inability to elaborate on such a topic. ii) That this would embarrass Anne and would check her indiscipline. iii) Her to apologise and not repeat her talkative behaviour. iv) Anne to explore her creative writing skills

Description : Why do you think Mr Keesing chose the title - ̳An Incorrigible Chatterbox ? i) Anne to express her inability to elaborate on such a topic. ii) That this would embarrass Anne and would check ... Her to apologise and not repeat her talkative behaviour. iv) Anne to explore her creative writing skills

Last Answer : ii) That this would embarrass Anne and would check her indiscipline.

.Match the terms in column I with their description in column II and choose the correct option. Column I Column II A. Dominance (i) Many genes govern a single character B. Co-dominance (ii) In a heterozygous organism only one allele expresses itself C. Pleiotropy (iii) In a heterozygous organism both alleles express themselves fully D. Polygenic (iv) A single gene inheritance influences many characters A B C D (a) (iv) (i) (ii) (iii) (b) (iv) (iii) (i) (ii) (c) (ii) (i) (iv) (iii) (d) (ii) (iii) (iv) (i)

Description : .Match the terms in column I with their description in column II and choose the correct option. Column I Column II A. Dominance (i) Many genes govern a single character B. Co-dominance (ii) In a heterozygous organism only one allele ... (i) (ii) (c) (ii) (i) (iv) (iii) (d) (ii) (iii) (iv) (i)

Last Answer : (d) (ii) (iii) (iv) (i)

Which is another way to express 360 ÷ 1,000?

Description : Which is another way to express 360 ÷ 1,000?

Last Answer : 360/1000=0.36

which is another way to express 360 divided by 1000?

Description : which is another way to express 360 divided by 1000?

Last Answer : 0.36

What is another way to express 360/1000?

Description : What is another way to express 360/1000?

Last Answer : 0.36

What is another way to express 360/1000?

Description : What is another way to express 360/1000?

Last Answer : 0.36

Arrange the following steps to form a basic Engineering Process Model.i. Test ii. Design iii. Install iv. Specification v. Manufacture vi. Maintain a) 2, 4, 5, 1, 6, 3 b) 4, 2, 5, 1, 3, 6 c) 2, 4, 5, 1, 3, 6 d) 4, 2, 5, 1, 6, 3

Description : Arrange the following steps to form a basic Engineering  Process Model. i. Test ii. Design iii. Install iv. Specification v. Manufacture vi. Maintain a) 2, 4, 5, 1, 6, 3 b) 4, 2, 5, 1, 3, 6 c) 2, 4, 5, 1, 3, 6 d) 4, 2, 5, 1, 6, 3

Last Answer : a) 2, 4, 5, 1, 6, 3

What are some of the things you now know about (i) the people of Coorg? (ii) the main crop of Coorg? (iii) the sports it offers to tourists? (iv) the animals you are likely to see in Coorg? (v) its distance from Bangalore, and how to get ther -Democratic 10th

Description : What are some of the things you now know about (i) the people of Coorg? (ii) the main crop of Coorg? (iii) the sports it offers to tourists? (iv) the animals you are likely to see in Coorg? (v) its distance from Bangalore, and how to get ther -Democratic 10th

Last Answer : The Coorgi or Kodagu people are fiercely independent people comprising martial men and beautiful women who are believed to have descended from the Greeks or the Arabs. They have a strong tradition ... , which is the most frequented one. The other route is via Neelamangal, Kunigal, Chanrayanapatna.

Check whether the following are quadratic equations: (i) (x+ 1)2=2(x-3) (ii) x – 2x = (- 2) (3-x) (iii) (x – 2) (x + 1) = (x – 1) (x + 3) (iv) (x – 3) (2x + 1) = x (x + 5) (v) (2x – 1) (x – 3) = (x + 5) (x – 1) (vi) x2 + 3x + 1 = (x – 2)2 (vii) (x + 2)3 = 2x(x2 – 1) (viii) x3 -4x2 -x + 1 = (x-2)3 -Maths 10th

Description : Check whether the following are quadratic equations: (i) (x+ 1)2=2(x-3) (ii) x - 2x = (- 2) (3-x) (iii) (x - 2) (x + 1) = (x - 1) (x + 3) (iv) (x - 3) (2x + 1) = x (x + 5) (v) (2x - 1) (x - 3) = (x ... vi) x2 + 3x + 1 = (x - 2)2 (vii) (x + 2)3 = 2x(x2 - 1) (viii) x3 -4x2 -x + 1 = (x-2)3 -Maths 10th

Last Answer : this is the correct answer!

I have some matchsticks set up like this: I + XI = X. If you do not know Roman numerals, here is a quick starter: I=1 II=2 III=3 IV=4 V=5 VI=6 VII=7 VIII=8 IX=9 X=10 XI=11 XII=12 XIII=13 XIV=14 XV=15...... Of course, I + XI = X is wrong. You are told to move the minimum number of matchsticks to make the question correct. So, how many do you have to move? -Riddles

Description : I have some matchsticks set up like this: I + XI = X. If you do not know Roman numerals, here is a quick starter: I=1 II=2 III=3 IV=4 V=5 VI=6 VII=7 VIII=8 IX=9 X=10 XI=11 ... are told to move the minimum number of matchsticks to make the question correct. So, how many do you have to move? -Riddles

Last Answer : Most people would get to one move at the least, but the real answer is zero moves. If you rotate the whole question around 180 degrees, it will display this: X = IX + I

In ΔABC and ΔDEF, AB = DE, AB || DE, BC = EF and BC || EF. Vertices A, B and C are joined to vertices D, E and F respectively (see Fig. 8.22). Show that (i) quadrilateral ABED is a parallelogram (ii) quadrilateral BEFC is a parallelogram (iii) AD || CF and AD = CF (iv) quadrilateral ACFD is a parallelogram (v) AC = DF (vi) ΔABC ≅ ΔDEF. -Maths 9th

Description : In ΔABC and ΔDEF, AB = DE, AB || DE, BC = EF and BC || EF. Vertices A, B and C are joined to vertices D, E and F respectively (see Fig. 8.22). Show that (i) quadrilateral ABED is a parallelogram ( ... CF and AD = CF (iv) quadrilateral ACFD is a parallelogram (v) AC = DF (vi) ΔABC ≅ ΔDEF. -Maths 9th

Last Answer : . Solution: (i) AB = DE and AB || DE (Given) Two opposite sides of a quadrilateral are equal and parallel to each other. Thus, quadrilateral ABED is a parallelogram (ii) Again BC = EF and BC || EF ... (Given) BC = EF (Given) AC = DF (Opposite sides of a parallelogram) , ΔABC ≅ ΔDEF [SSS congruency]

Draw the ray diagram in each case to show the position and nature of the image formed when the object is placed: (i) at the centre of curvature of a concave mirror (ii) between the pole P and focus F of a concave mirror (iii) in front of a convex mirror (iv) at 2F of a convex lens (v) in front of a concave lens -Physics

Description : Draw the ray diagram in each case to show the position and nature of the image formed when the object is placed: (i) at the centre of curvature of a concave mirror (ii) between the pole P and focus F of ... front of a convex mirror (iv) at 2F of a convex lens (v) in front of a concave lens -Physics

Last Answer : Answer. Nature of image: Real, inverted and same size image is formed at the centre of curvature. Nature of image: Virtual, enlarged and erect image is formed behind the mirror. Nature of image: Virtual ... : Virtual, erect and diminished image is formed between O and F on the same side of object.

For the complex [Fe(en)2Cl2], Cl, (en = ethylene diamine), identify (i) the oxidation number of iron, (ii) the hybrid orbitals and the shape of the complex, (iii) the magnetic behaviour of the complex, (iv) the number of geometrical isomers, (v) whether there is an optical isomer also, and (vi) name of the complex. (At. no. of Fe = 26) \ -Chemistry

Description : For the complex [Fe(en)2Cl2], Cl, (en = ethylene diamine), identify (i) the oxidation number of iron, (ii) the hybrid orbitals and the shape of the complex, (iii) the magnetic behaviour of the complex, (iv) ... an optical isomer also, and (vi) name of the complex. (At. no. of Fe = 26) \ -Chemistry

Last Answer : i) [Fe(en)2Cl2] Cl or x + 0 + 2 (-1) + (-1) = 0 x + (- 3) = 0 or x = + 3 ∴ Oxidation number of iron, x = + 3 (ii) The complex has two bidentate ligands and two ... )2Cl2] Cl, only cis-isomer shows optical isomerism. (vi) Name of complex: Dichloridobis (ethane-1, 2- diamine) Iron (III) chloride

What percentage is (i) Rs 15 of Rs 120? (ii) 36 minutes of 2 hours? (iii) 8 hours of 2 days (iv) 160 metres of 4 km? (v) 175 mL of 1 litre? (vi) 25 paise of Rs 4? -Maths

Description : What percentage is (i) Rs 15 of Rs 120? (ii) 36 minutes of 2 hours? (iii) 8 hours of 2 days (iv) 160 metres of 4 km? (v) 175 mL of 1 litre? (vi) 25 paise of Rs 4? -Maths

Last Answer : answer:

Find: (i) 25% of Rs 76 (ii) 20% of Rs 132 (iii) 7.5% of 600 m (iv) 313% of 90 km (v) 8.5% of 5 kg (vi) 20% of 12 litres -Maths

Description : Find: (i) 25% of Rs 76 (ii) 20% of Rs 132 (iii) 7.5% of 600 m (iv) 313% of 90 km (v) 8.5% of 5 kg (vi) 20% of 12 litres -Maths

Last Answer : answer:

Find: (i) 32% of 425 (ii) 1623% of 16 (iii) 6.5% of 400 (iv) 136% of 70 (v) 2.8% of 35 (vi) 0.6% of 45 -Maths

Description : Find: (i) 32% of 425 (ii) 1623% of 16 (iii) 6.5% of 400 (iv) 136% of 70 (v) 2.8% of 35 (vi) 0.6% of 45 -Maths

Last Answer : answer:

Convert each of the following fraction into a percentage: (i) 47 100 (ii) 9 20 (iii) 3 8 (iv) 8 125 (v) 19 500 (vi) 4 15 (vii) 2 3 (viii) 1 3 5 -Maths

Description : Convert each of the following fraction into a percentage: (i) 47 100 (ii) 9 20 (iii) 3 8 (iv) 8 125 (v) 19 500 (vi) 4 15 (vii) 2 3 (viii) 1 3 5 -Maths

Last Answer : We have the following: (i) 47100=47100×100% = 47% (ii) 920=920×100% =9×5%= 45% (iii) 38=38×100% =3×252%=752%=3712% (iv) 8125=8125×100%=8×45%=325%=6.4% (v) ... ;203%=803%=2623% (vii) 23=23×100%=2003%=6623% (viii) 135=85=85×100%=(8×20)%=160%

Convert each of the following into a fraction: (i) 32% (ii) 614% (iii) 2623% (iv) 120% (v) 6.25% (vi) 0.8% (vii) 0.06% (viii) 22.75% -Maths

Description : Convert each of the following into a fraction: (i) 32% (ii) 614% (iii) 2623% (iv) 120% (v) 6.25% (vi) 0.8% (vii) 0.06% (viii) 22.75% -Maths

Last Answer : answer:

Evaluate each of the following: (i) (103)3 (ii) (98)3 (iii) (9.9)3 (iv) (10.4)3 (v) (598)3 (vi) (99)3 -Maths 9th

Description : Evaluate each of the following: (i) (103)3 (ii) (98)3 (iii) (9.9)3 (iv) (10.4)3 (v) (598)3 (vi) (99)3 -Maths 9th

Last Answer : answer:

Simplify: (i) (a + b + c)2 + (a – b + c)2 (ii) (a + b + c)2 – (a – b + c)2 (iii) (a + b + c)2 + (a – b + c)2 + (a + b – c)2 (iv) (2x + p – c)2 – (2x – p + c)2 (v) (x2 + y2 – z2)2 – (x2 – y2 + z2)2 -Maths 9th

Description : Simplify: (i) (a + b + c)2 + (a – b + c)2 (ii) (a + b + c)2 – (a – b + c)2 (iii) (a + b + c)2 + (a – b + c)2 + (a + b – c)2 (iv) (2x + p – c)2 – (2x – p + c)2 (v) (x2 + y2 – z2)2 – (x2 – y2 + z2)2 -Maths 9th

Last Answer : answer:

Evaluate each of the following using identities: (i) (2x –1x)2 (ii) (2x + y) (2x – y) (iii) (a2b – b2a)2 (iv) (a – 0.1) (a + 0.1) (v) (1.5.x2 – 0.3y2) (1.5x2 + 0.3y2) -Maths 9th

Description : Evaluate each of the following using identities: (i) (2x –1x)2 (ii) (2x + y) (2x – y) (iii) (a2b – b2a)2 (iv) (a – 0.1) (a + 0.1) (v) (1.5.x2 – 0.3y2) (1.5x2 + 0.3y2) -Maths 9th

Last Answer : (i) (2x - 1/x)2 [Use identity: (a - b)2 = a2 + b2 - 2ab ] (2x - 1/x)2 = (2x) 2 + (1/x)2 - 2 (2x)(1/x) = 4x2 + 1/x2 - 4 (ii) (2x + y) (2x - y) [Use identity: (a - b)(a + b) = a2 - b 2 ] (2x + y) (2x - ... ) = a2 - b 2 ](1.5 x 2 - 0.3y2 ) (1.5x2 + 0.3y2 ) = (1.5 x 2 ) 2 - (0.3y2 ) 2 = 2.25 x4 - 0.09y4

Read the following points `:-` (i) Increase GFR (ii) Increase B.P. (iii) Decreases blood volume (iv) Increases aldosterone secretion (v) Vasoconstrict

Description : Read the following points `:-` (i) Increase GFR (ii) Increase B.P. (iii) Decreases blood volume (iv) Increases aldosterone secretion (v) Vasoconstrict

Last Answer : Read the following points `:-` (i) Increase GFR (ii) Increase B.P. (iii) Decreases blood volume (iv) ... II ? A. Two B. Three C. Four D. Five

Solve the following inequations `(i) (sinx-2)(2sinx-1) lt 0` `(ii) (2cosx-1)(cosx) le 0` `(iii) sinx+sqrt(3)cosx ge 1` `(iv) cos^(2)x+sinx le 2` `(v)

Description : Solve the following inequations `(i) (sinx-2)(2sinx-1) lt 0` `(ii) (2cosx-1)(cosx) le 0` `(iii) sinx+sqrt(3)cosx ge 1` `(iv) cos^(2)x+sinx le 2` `(v)

Last Answer : Solve the following inequations `(i) (sinx-2)(2sinx-1) lt 0` `(ii) (2cosx-1)(cosx) le 0` `(iii) sinx+sqrt(3) ... ^(2)x+sinx le 2` `(v) tan^(2)x gt 3`

Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) |(2x-1)/(x-1)| gt 2` `(v) |x-6| le x^(2)-5x+9

Description : Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) |(2x-1)/(x-1)| gt 2` `(v) |x-6| le x^(2)-5x+9

Last Answer : Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) ... -5) lt 0` `(viii) |x-1|+|x-2|+|x-3| le 6`

Solve for `x` `(i) |x+1|=4x+3` `(ii) |x+1|=|x+3|` `(iii) 7|x-2|-|x-7|=5` `(iv) ||x-1|-2|=6x+8` `(v) |2x^(2)-3x+1|=|x^(2)+x-3|`

Description : Solve for `x` `(i) |x+1|=4x+3` `(ii) |x+1|=|x+3|` `(iii) 7|x-2|-|x-7|=5` `(iv) ||x-1|-2|=6x+8` `(v) |2x^(2)-3x+1|=|x^(2)+x-3|`

Last Answer : Solve for `x` `(i) |x+1|=4x+3` `(ii) |x+1|=|x+3|` `(iii) 7|x-2|-|x-7|=5` `(iv) ||x-1|-2|=6x+8` `(v) |2x^(2)-3x+1|=|x^(2)+x-3|`

Aqueous solution of how many of the following species turn blue limtus red ? (i) `SF_(4)` (ii) `PCl_(3)` (iii) `H_(2)O` (iv) `NO_(2)Cl` (v) `SF_(6)` (

Description : Aqueous solution of how many of the following species turn blue limtus red ? (i) `SF_(4)` (ii) `PCl_(3)` (iii) `H_(2)O` (iv) `NO_(2)Cl` (v) `SF_(6)` (

Last Answer : Aqueous solution of how many of the following species turn blue limtus red ? (i) `SF_(4)` (ii) `PCl_(3)` ( ... )` (xii) `COCl_(2)` (viii) `C Cl_(4)`

Cold dil. `H_(2)SO_(4)` will completely dissolve : (i) Pb (ii) `Fe_(3)O_(4)` (iii) Fe (iv) Cu (v) Mg (vi) MgO (vii) `CoCO_(3)` (viii) `CuCO_(2)` (ix)

Description : Cold dil. `H_(2)SO_(4)` will completely dissolve : (i) Pb (ii) `Fe_(3)O_(4)` (iii) Fe (iv) Cu (v) Mg (vi) MgO (vii) `CoCO_(3)` (viii) `CuCO_(2)` (ix)

Last Answer : Cold dil. `H_(2)SO_(4)` will completely dissolve : (i) Pb (ii) `Fe_(3)O_(4)` (iii) Fe (iv) Cu (v) ... ) `CoCO_(3)` (viii) `CuCO_(2)` (ix) `SrCO_(3)`

Cold conc. `HNO_(3)` will completely dissolve: (i) Pb (ii) `Pb_(3)O_(4)` (iii) Fe (iv) Sn (v) Mg (vi) MgO (vii) Hg (viii) Au (ix) Ag (x) Pt

Description : Cold conc. `HNO_(3)` will completely dissolve: (i) Pb (ii) `Pb_(3)O_(4)` (iii) Fe (iv) Sn (v) Mg (vi) MgO (vii) Hg (viii) Au (ix) Ag (x) Pt

Last Answer : Cold conc. `HNO_(3)` will completely dissolve: (i) Pb (ii) `Pb_(3)O_(4)` (iii) Fe (iv) Sn (v) Mg (vi) MgO (vii) Hg (viii) Au (ix) Ag (x) Pt

(i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2)S` (vi) `AsH_(3)` (vii) `SbH_(3)` (viii) `H_(2)Se` (ix) `H_(2)Te` Number of mole

Description : (i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2)S` (vi) `AsH_(3)` (vii) `SbH_(3)` (viii) `H_(2)Se` (ix) `H_(2)Te` Number of mole

Last Answer : (i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2) ... lone pair of electrons on the central atom is present in pure s-orbital

Aqueous solution of how many of the following species turn blue limtus red ? (i) `SF_(4)` (ii) `PCl_(3)` (iii) `H_(2)O` (iv) `NO_(2)Cl` (v) `SF_(6)` (

Description : Aqueous solution of how many of the following species turn blue limtus red ? (i) `SF_(4)` (ii) `PCl_(3)` (iii) `H_(2)O` (iv) `NO_(2)Cl` (v) `SF_(6)` (

Last Answer : Aqueous solution of how many of the following species turn blue limtus red ? (i) `SF_(4)` (ii) `PCl_(3)` ( ... )` (xii) `COCl_(2)` (viii) `C Cl_(4)`

Cold dil. `H_(2)SO_(4)` will completely dissolve : (i) Pb (ii) `Fe_(3)O_(4)` (iii) Fe (iv) Cu (v) Mg (vi) MgO (vii) `CoCO_(3)` (viii) `CuCO_(2)` (ix)

Description : Cold dil. `H_(2)SO_(4)` will completely dissolve : (i) Pb (ii) `Fe_(3)O_(4)` (iii) Fe (iv) Cu (v) Mg (vi) MgO (vii) `CoCO_(3)` (viii) `CuCO_(2)` (ix)

Last Answer : Cold dil. `H_(2)SO_(4)` will completely dissolve : (i) Pb (ii) `Fe_(3)O_(4)` (iii) Fe (iv) Cu (v) ... ) `CoCO_(3)` (viii) `CuCO_(2)` (ix) `SrCO_(3)`

Cold conc. `HNO_(3)` will completely dissolve: (i) Pb (ii) `Pb_(3)O_(4)` (iii) Fe (iv) Sn (v) Mg (vi) MgO (vii) Hg (viii) Au (ix) Ag (x) Pt

Description : Cold conc. `HNO_(3)` will completely dissolve: (i) Pb (ii) `Pb_(3)O_(4)` (iii) Fe (iv) Sn (v) Mg (vi) MgO (vii) Hg (viii) Au (ix) Ag (x) Pt

Last Answer : Cold conc. `HNO_(3)` will completely dissolve: (i) Pb (ii) `Pb_(3)O_(4)` (iii) Fe (iv) Sn (v) Mg (vi) MgO (vii) Hg (viii) Au (ix) Ag (x) Pt

(i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2)S` (vi) `AsH_(3)` (vii) `SbH_(3)` (viii) `H_(2)Se` (ix) `H_(2)Te` Number of mole

Description : (i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2)S` (vi) `AsH_(3)` (vii) `SbH_(3)` (viii) `H_(2)Se` (ix) `H_(2)Te` Number of mole

Last Answer : (i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2) ... lone pair of electrons on the central atom is present in pure s-orbital

How many anions evolve brownish gas when treated with dil. /con. HCl ? `(i) CO_(3)^(2-) " " (ii)SO_(3)^(2-) " " (iii) NO_(2)^(-) " " (iv)Cl^(-)` `(v)

Description : How many anions evolve brownish gas when treated with dil. /con. HCl ? `(i) CO_(3)^(2-) " " (ii)SO_(3)^(2-) " " (iii) NO_(2)^(-) " " (iv)Cl^(-)` `(v)

Last Answer : How many anions evolve brownish gas when treated with dil. /con. HCl ? `(i) CO_(3)^(2-) " " (ii)SO_(3)^(2-) ... NO_(3)^(-) " " (vii) CH_(3)CO O^(-)`

How many of following metals impart a characteristic colour to the Bunsen flame ? `(i) Na " " (ii) Li " " (iii) K " " (iv) Ba` `(v) Sr " " (vi) Mg " "

Description : How many of following metals impart a characteristic colour to the Bunsen flame ? `(i) Na " " (ii) Li " " (iii) K " " (iv) Ba` `(v) Sr " " (vi) Mg " "

Last Answer : How many of following metals impart a characteristic colour to the Bunsen flame ? `(i) Na " " (ii) Li " " (iii) K ... ix) `Be " " (x )Ca " " (x i)Cu`

Which of the following can undergo nucleophilic substitution under ordinary conditions? I Allyl chloride II Benzyl chloride III n-Propyl chloride IV V

Description : Which of the following can undergo nucleophilic substitution under ordinary conditions? I Allyl chloride II Benzyl chloride III n-Propyl chloride IV V

Last Answer : Which of the following can undergo nucleophilic substitution under ordinary conditions? I Allyl chloride II ... are correct D. I and III are correct

Howmany of the following compounds are dissolve in aqeous solution of `NaOH` (i) Phenol (ii) Cyclohexanol (iii) 2, 4-di nitro phenol (iv) Benzoic (v)

Description : Howmany of the following compounds are dissolve in aqeous solution of `NaOH` (i) Phenol (ii) Cyclohexanol (iii) 2, 4-di nitro phenol (iv) Benzoic (v)

Last Answer : Howmany of the following compounds are dissolve in aqeous solution of `NaOH` (i) Phenol (ii) ... ) `alpha-` naphthol (ix) N-methyl aniline

Number of oxide orwesd among , (i) Cassiterite (ii) pyrolusite (iii) Kieserite (iv) Azurite (V) chromite (vi) siderite are.

Description : Number of oxide orwesd among , (i) Cassiterite (ii) pyrolusite (iii) Kieserite (iv) Azurite (V) chromite (vi) siderite are.

Last Answer : Number of oxide orwesd among , (i) Cassiterite (ii) pyrolusite (iii) Kieserite (iv) Azurite (V) chromite (vi) siderite are.

(i) Copper - Bessemer converter (ii) Iorpn- Blastfurnace (iii) chromium - Aluminothermic process (iv) Tin - Carbon reducaton (v) Zinc -Belgian process

Description : (i) Copper - Bessemer converter (ii) Iorpn- Blastfurnace (iii) chromium - Aluminothermic process (iv) Tin - Carbon reducaton (v) Zinc -Belgian process

Last Answer : (i) Copper - Bessemer converter (ii) Iorpn- Blastfurnace (iii) chromium - Aluminothermic process (iv ... data how many of them are correctly matched ?

How many of the following are oxides ores (i) Carnalite (ii) Cuprite (iii) Cassiterite (iv) Chromite (v) Cinnabar (vi) Calamine (vii) Cerussite (Viii)

Description : How many of the following are oxides ores (i) Carnalite (ii) Cuprite (iii) Cassiterite (iv) Chromite (v) Cinnabar (vi) Calamine (vii) Cerussite (Viii)

Last Answer : How many of the following are oxides ores (i) Carnalite (ii) Cuprite (iii) Cassiterite (iv) ... (vii) Cerussite (Viii) Chalocopyrite (ix) Chalcocite

Which of the following are the components of loamy soils? 1. Red soil 2. Clay soil 3. Alluvial soil 4. Silt soil 5. Sandy soil In d i a n So i l , Se a s o n s a n d N a t u r a l Ve g e t a t i o n (a) I and II (b) I, III and IV (c) II and V (d) II, III and V

Description : Which of the following are the components of loamy soils? 1. Red soil 2. Clay soil 3. Alluvial soil 4. Silt soil 5. Sandy soil In d i a n So i l , Se a s o n s a n d N a t u r a l Ve g e t a t i o n (a) I and II (b) I, III and IV (c) II and V (d) II, III and V

Last Answer : Ans: (c)

Arrange the following religious groups in increasing order of their population in India: 1. Muslims 2. Buddhists 3. Sikhs 4. Jains 5. Christians (a) IV, II, III, V, I (b) IV, II, I, III, V (c) II, IV, III, V, I (d) II, III, IV, I,V

Description : Arrange the following religious groups in increasing order of their population in India: 1. Muslims 2. Buddhists 3. Sikhs 4. Jains 5. Christians (a) IV, II, III, V, I (b) IV, II, I, III, V (c) II, IV, III, V, I (d) II, III, IV, I,V

Last Answer : Ans: (a)

Which states of India have a common border with Pakistan? 1. Jammu and Kashmir 2. Himachal Pradesh 3. Punjab 4. Gujarat 5. Rajasthan (a) I, II, III, V (b) I, II, III, IV (c) I, III, IV (d) I, III, IV, V

Description : Which states of India have a common border with Pakistan? 1. Jammu and Kashmir 2. Himachal Pradesh 3. Punjab 4. Gujarat 5. Rajasthan (a) I, II, III, V (b) I, II, III, IV (c) I, III, IV (d) I, III, IV, V

Last Answer : Ans: (d)