For the complex [Fe(en)2Cl2], Cl, (en = ethylene diamine), identify (i) the oxidation number of iron, (ii) the hybrid orbitals and the shape of the complex, (iii) the magnetic behaviour of the complex, (iv) the number of geometrical isomers, (v) whether there is an optical isomer also, and (vi) name of the complex. (At. no. of Fe = 26) \ -Chemistry

For the complex [Fe(en)2Cl2], Cl, (en = ethylene diamine), identify (i) the oxidation number of iron, (ii) the hybrid orbitals and the shape of the complex, (iii) the magnetic behaviour of the complex, (iv) the number of geometrical isomers, (v) whether there is an optical isomer also, and (vi) name of the complex. (At. no. of Fe = 26) \ -Chemistry
by

1 Answer

Answer :

i) [Fe(en)2Cl2] Cl or x + 0 + 2 (-1) + (-1) = 0 x + (- 3) = 0 or x = + 3 ∴ Oxidation number of iron, x = + 3 (ii) The complex has two bidentate ligands and two monodentate ligands. Therefore, the coordination number is 6 and hybridization will be d2sp3 and shape will be octahedral. (iii) In the complex 26Fe3+ = 3d5 4s0 4p0 Due to presence of one unpaired electrons in d orbitals the complex is paramagnetic. The number of geometrical isomers are two. (v) In coordination complex of [Fe(en)2Cl2] Cl, only cis-isomer shows optical isomerism. (vi) Name of complex: Dichloridobis (ethane-1, 2- diamine) Iron (III) chloride
by

Related questions

Compare the following complexes with respect to their shape, magnetic behaviour and the hybrid orbitals involved : (i) [CoF4]2- (ii) [Cr(H2O)2(C2O4)2]– (iii) [Ni(CO)4] (Atomic number : Co = 27, Cr = 24, Ni = 28) -Chemistry

Description : Compare the following complexes with respect to their shape, magnetic behaviour and the hybrid orbitals involved : (i) [CoF4]2- (ii) [Cr(H2O)2(C2O4)2]– (iii) [Ni(CO)4] (Atomic number : Co = 27, Cr = 24, Ni = 28) -Chemistry

Last Answer : (i) [COF4]2_ : Tetrafluorido cobalt (III) ion Coordination number = 4 Shape = Tetrahedral Hybridisation = sp3 Important Questions for Class 12 Chemistry Chapter 9 Coordination Compounds Class 12 Important Questions 7

How many isomers are possible for the complex `[Co(en)_(2)Cl_(2)]`(en=ethylene diamine )

Description : How many isomers are possible for the complex `[Co(en)_(2)Cl_(2)]`(en=ethylene diamine )

Last Answer : How many isomers are possible for the complex `[Co(en)_(2)Cl_(2)]`(en=ethylene diamine ) A. 4 B. 2 C. 6 D. 3

Compare the following complexes’ with respect to structural shapes of units, magnetic behaviour and hybrid orbitals involved in units : (i) [Ni(CN)4]2- (ii) [NiCl4]2- (iii) [CoF6]3- [At. Nos. : Ni = 28; Co = 27] -Chemistry

Description : Compare the following complexes’ with respect to structural shapes of units, magnetic behaviour and hybrid orbitals involved in units : (i) [Ni(CN)4]2- (ii) [NiCl4]2- (iii) [CoF6]3- [At. Nos. : Ni = 28; Co = 27] -Chemistry

Last Answer : (i) [Ni(CN)4]2- Shape : Octahedral outer orbital complex Hybridisation : sp3d2 Magnetic behaviour : Paramagnetic (4 unpaired electrons)

Name the following coordination compounds according to IUPAC system of nomenclature :(i) [Co(NH3)4 (H2O)Cl]Cl2 (ii) [CrCl2(en)2]Cl, (en = ethane – 1, 2 – diamine) -Chemistry

Description : Name the following coordination compounds according to IUPAC system of nomenclature :(i) [Co(NH3)4 (H2O)Cl]Cl2 (ii) [CrCl2(en)2]Cl, (en = ethane – 1, 2 – diamine) -Chemistry

Last Answer : (i) [CO(NH3)4 (H2O)Cl]Cl2 Tetraammine aquachlorido cobalt (III) chloride (ii) [CrCl2(en)2]Cl Dichlorobis (ethane-1, 2-diamine) chromium (III) chloride

(i) Write down the IUPAC name of the following complex : [Cr(NH3)2CI3(en)]Cl (en = ethylenediamine) (ii) Write the formula for the following complex : Pentaamminenitrito-o-Cobalt (III) -Chemistry

Description : (i) Write down the IUPAC name of the following complex : [Cr(NH3)2CI3(en)]Cl (en = ethylenediamine) (ii) Write the formula for the following complex : Pentaamminenitrito-o-Cobalt (III) -Chemistry

Last Answer : (I) [Cr(NH3)2Cl3(en)]Cl IUPAC name : Diammine dichlorido ethylenediamine chromium (III) chloride. (ii) [Co(NH3)5(ONO)]2+

Compare the following complexes with respect to structural shapes of units, magnetic behaviour and hybrid orbitals involved in units : [Co(NH3)6]+3, [Cr(NH3)6]3+, Ni(CO)4 (At. nos. : Co = 27, Cr = 24, Ni = 28) -Chemistry

Description : Compare the following complexes with respect to structural shapes of units, magnetic behaviour and hybrid orbitals involved in units : [Co(NH3)6]+3, [Cr(NH3)6]3+, Ni(CO)4 (At. nos. : Co = 27, Cr = 24, Ni = 28) -Chemistry

Last Answer : (i) [Co(NH3)6]+3 → Octahedral shape, d2sp3 hybridisation, diamagnetic Formation of [Co(NH2)6]+3 → oxidation state of Co is +3.

Total number of geometrical isomers for the complex `[Rh Cl (CO) (PPh_(3)) (NH_(3))]` is

Description : Total number of geometrical isomers for the complex `[Rh Cl (CO) (PPh_(3)) (NH_(3))]` is

Last Answer : Total number of geometrical isomers for the complex `[Rh Cl (CO) (PPh_(3)) (NH_(3))]` is

Cold dil. `H_(2)SO_(4)` will completely dissolve : (i) Pb (ii) `Fe_(3)O_(4)` (iii) Fe (iv) Cu (v) Mg (vi) MgO (vii) `CoCO_(3)` (viii) `CuCO_(2)` (ix)

Description : Cold dil. `H_(2)SO_(4)` will completely dissolve : (i) Pb (ii) `Fe_(3)O_(4)` (iii) Fe (iv) Cu (v) Mg (vi) MgO (vii) `CoCO_(3)` (viii) `CuCO_(2)` (ix)

Last Answer : Cold dil. `H_(2)SO_(4)` will completely dissolve : (i) Pb (ii) `Fe_(3)O_(4)` (iii) Fe (iv) Cu (v) ... ) `CoCO_(3)` (viii) `CuCO_(2)` (ix) `SrCO_(3)`

Cold conc. `HNO_(3)` will completely dissolve: (i) Pb (ii) `Pb_(3)O_(4)` (iii) Fe (iv) Sn (v) Mg (vi) MgO (vii) Hg (viii) Au (ix) Ag (x) Pt

Description : Cold conc. `HNO_(3)` will completely dissolve: (i) Pb (ii) `Pb_(3)O_(4)` (iii) Fe (iv) Sn (v) Mg (vi) MgO (vii) Hg (viii) Au (ix) Ag (x) Pt

Last Answer : Cold conc. `HNO_(3)` will completely dissolve: (i) Pb (ii) `Pb_(3)O_(4)` (iii) Fe (iv) Sn (v) Mg (vi) MgO (vii) Hg (viii) Au (ix) Ag (x) Pt

Cold dil. `H_(2)SO_(4)` will completely dissolve : (i) Pb (ii) `Fe_(3)O_(4)` (iii) Fe (iv) Cu (v) Mg (vi) MgO (vii) `CoCO_(3)` (viii) `CuCO_(2)` (ix)

Description : Cold dil. `H_(2)SO_(4)` will completely dissolve : (i) Pb (ii) `Fe_(3)O_(4)` (iii) Fe (iv) Cu (v) Mg (vi) MgO (vii) `CoCO_(3)` (viii) `CuCO_(2)` (ix)

Last Answer : Cold dil. `H_(2)SO_(4)` will completely dissolve : (i) Pb (ii) `Fe_(3)O_(4)` (iii) Fe (iv) Cu (v) ... ) `CoCO_(3)` (viii) `CuCO_(2)` (ix) `SrCO_(3)`

Cold conc. `HNO_(3)` will completely dissolve: (i) Pb (ii) `Pb_(3)O_(4)` (iii) Fe (iv) Sn (v) Mg (vi) MgO (vii) Hg (viii) Au (ix) Ag (x) Pt

Description : Cold conc. `HNO_(3)` will completely dissolve: (i) Pb (ii) `Pb_(3)O_(4)` (iii) Fe (iv) Sn (v) Mg (vi) MgO (vii) Hg (viii) Au (ix) Ag (x) Pt

Last Answer : Cold conc. `HNO_(3)` will completely dissolve: (i) Pb (ii) `Pb_(3)O_(4)` (iii) Fe (iv) Sn (v) Mg (vi) MgO (vii) Hg (viii) Au (ix) Ag (x) Pt

`Na_(2)S + Na_(2)[Fe(CN)_(5)NO]to " X"` (Violet colour) The total number of possible isomers for complex " X" is , provided the ambident behaviour of

Description : `Na_(2)S + Na_(2)[Fe(CN)_(5)NO]to " X"` (Violet colour) The total number of possible isomers for complex " X" is , provided the ambident behaviour of

Last Answer : `Na_(2)S + Na_(2)[Fe(CN)_(5)NO]to " X"` (Violet colour) The total number of possible ... the ambident behaviour of `CN^(-)` is not considered.

Check whether the following are quadratic equations: (i) (x+ 1)2=2(x-3) (ii) x – 2x = (- 2) (3-x) (iii) (x – 2) (x + 1) = (x – 1) (x + 3) (iv) (x – 3) (2x + 1) = x (x + 5) (v) (2x – 1) (x – 3) = (x + 5) (x – 1) (vi) x2 + 3x + 1 = (x – 2)2 (vii) (x + 2)3 = 2x(x2 – 1) (viii) x3 -4x2 -x + 1 = (x-2)3 -Maths 10th

Description : Check whether the following are quadratic equations: (i) (x+ 1)2=2(x-3) (ii) x - 2x = (- 2) (3-x) (iii) (x - 2) (x + 1) = (x - 1) (x + 3) (iv) (x - 3) (2x + 1) = x (x + 5) (v) (2x - 1) (x - 3) = (x ... vi) x2 + 3x + 1 = (x - 2)2 (vii) (x + 2)3 = 2x(x2 - 1) (viii) x3 -4x2 -x + 1 = (x-2)3 -Maths 10th

Last Answer : this is the correct answer!

The complex ion . `[M(en)Br_(2)I_(2)]^(-1)`, has two optical isomers. Their correct configurations are:

Description : The complex ion . `[M(en)Br_(2)I_(2)]^(-1)`, has two optical isomers. Their correct configurations are:

Last Answer : The complex ion . `[M(en)Br_(2)I_(2)]^(-1)`, has two optical isomers. Their correct configurations are: A. B. C. D.

Identify the components labelled A, B, C and D in the diagram below from the list (i) to (viii) given along withComponents : (i) Cristae of mitochondria (ii) Inner membrane of mitochondria (iii) Cytoplasm (iv) Smooth endoplasmic reticulum (v) Rough endoplasmic reticulum (vi) Mitochondrial matrix (vii) Cell vacuole (viii) Nucleus The correct components are: A B C D (a) (v) (iv) (viii) (iii) (b) (i) (iv) (viii) (vi) (c) (vi) (v) (iv) (vii) (d) (v) (i) (iii) (ii)

Description : Identify the components labelled A, B, C and D in the diagram below from the list (i) to (viii) given along with Components : (i) Cristae of mitochondria (ii) Inner membrane of mitochondria (iii) Cytoplasm (iv) Smooth endoplasmic ... viii) (vi) (c) (vi) (v) (iv) (vii) (d) (v) (i) (iii) (ii)

Last Answer : (a) (v) (iv) (viii) (iii)

Identify the sensors for the following : i) Wind speed ii) RPM of generator shaft iii) Temperature in generator iv) Cable untwisting v) Vibration vi) Wind direction

Description : Identify the sensors for the following : i) Wind speed ii) RPM of generator shaft iii) Temperature in generator iv) Cable untwisting v) Vibration vi) Wind direction

Last Answer : i) Wind Speed : Anemometer. ii) RPM of Generator Shaft: Accelerometers. iii) Temperature in Generator: Thermistor, thermocouple, RTD. iv) Cable Untwisting : Cable Twisting sensor. v) Vibration : Accelerometer, piezoelectric. vi) Wind direction: Wind vane.

Identify type of BJT configuration having following features : (i) BJT configuration having the least current gain. (ii) KIT configuration called as voltage follower. (iii) BJT configuration having current gain less than one. (iv) BJT configuration suitable for impedance matching. (v) BIT configuration suitable for voltage amplification. (vi) BJT configuration having the least output impedance.

Description : Identify type of BJT configuration having following features : (i) BJT configuration having the least current gain. (ii) KIT configuration called as voltage follower. (iii) BJT ... configuration suitable for voltage amplification. (vi) BJT configuration having the least output impedance.  

Last Answer : (i) BJT configuration having the least current gain : Common Base Configuration  (ii) KIT configuration called as voltage follower: Common Collector Configuration  (iii) BJT ... Emitter Configuration  (vi) BJT configuration having the least output impedance: Common Collector Configuration

Find the sum of number of geometrical isomers for following complexes. `(a) [CoCl_(2)Br_(2)]^(2-) " " (b) [Rh(en)_(3)]^(3+) " " ( c) [Cr(en)_(2)Br_(2)

Description : Find the sum of number of geometrical isomers for following complexes. `(a) [CoCl_(2)Br_(2)]^(2-) " " (b) [Rh(en)_(3)]^(3+) " " ( c) [Cr(en)_(2)Br_(2)

Last Answer : Find the sum of number of geometrical isomers for following complexes. `(a) [CoCl_(2)Br_(2)]^(2-) " " (b) [Rh(en ... e) [Co(NH_(3))_(3)(NO_(2))_(3)]`

The number of geometrical isomers for octahedral `[CoCl_(4)(NH_(3))_(2)]^(-)`, square planar `[AuBr_(2)Cl_(2)]^(-)` and `[PtCl_(2)(en)]` are

Description : The number of geometrical isomers for octahedral `[CoCl_(4)(NH_(3))_(2)]^(-)`, square planar `[AuBr_(2)Cl_(2)]^(-)` and `[PtCl_(2)(en)]` are

Last Answer : The number of geometrical isomers for octahedral `[CoCl_(4)(NH_(3))_(2)]^(-)`, square planar `[AuBr_(2)Cl_(2)]^(-) ... are A. 4,2 B. 2,2 C. 3,2 D. 2,3

The catalytic activity of transition metals and their compounds is ascribed mainly to (1) their chemical reactivity (2) their magnetic behaviour (3) their unfilled d-orbitals (4) their ability to adopt variable oxidation states

Description : The catalytic activity of transition metals and their compounds is ascribed mainly to (1) their chemical reactivity (2) their magnetic behaviour (3) their unfilled d-orbitals (4) their ability to adopt variable oxidation states

Last Answer : (4) their ability to adopt variable oxidation states

Describe the shape and magnetic behaviour of following complexes : (i) [CO(NH3)6]3+ (ii) [Ni(CN)4]2- (At. No. Co = 27, Ni = 28) -Chemistry

Description : Describe the shape and magnetic behaviour of following complexes : (i) [CO(NH3)6]3+ (ii) [Ni(CN)4]2- (At. No. Co = 27, Ni = 28) -Chemistry

Last Answer : (i) [CO(NH3)6]3+ : Orbitals of CO3+ ion : Hybridization : d2sp3 Shape : Octahedral Magnetic behaviour : Diamagnetic (absence of unpaired electrons) (ii) [Ni(CN)4]2-

Give IUPAC name of the ionization isomer of [Ni(NH3)3NO3]Cl. -Chemistry

Description : Give IUPAC name of the ionization isomer of [Ni(NH3)3NO3]Cl. -Chemistry

Last Answer : IUPAC name : Triammine chlorido nickel (II) nitrate [Ni(NH3)3NO3]Cl

Give IUPAC name of ionization isomer of [Ni(NH3)3NO3]Cl. -Chemistry

Description : Give IUPAC name of ionization isomer of [Ni(NH3)3NO3]Cl. -Chemistry

Last Answer : IUPAC name : Triammine nitrato nickel (III) chloride

Which one of the following has an optical isomer ? (en=ethylenediamine )

Description : Which one of the following has an optical isomer ? (en=ethylenediamine )

Last Answer : Which one of the following has an optical isomer ? (en=ethylenediamine ) A. `[Zn(en)(NH_(3))_(2)]^(2+)` B. `[Co( ... en)]^(3+)` D. `[Zn(en)_(2)]^(2+)`

How many isomers are possible for a compound with formula, `[Rn(en)_(2)Cl(NO_(2))]` ?

Description : How many isomers are possible for a compound with formula, `[Rn(en)_(2)Cl(NO_(2))]` ?

Last Answer : How many isomers are possible for a compound with formula, `[Rn(en)_(2)Cl(NO_(2))]` ? A. 2 B. 4 C. 6 D. 8

Using IUPAC norms write the formulae for the following: (a) Tris(ethane-1,2-diamine) chromium (III) chloride (b) Potassium tetrahydroxozincate(II) -Chemistry

Description : Using IUPAC norms write the formulae for the following: (a) Tris(ethane-1,2-diamine) chromium (III) chloride (b) Potassium tetrahydroxozincate(II) -Chemistry

Last Answer : a) [Cr(en)3] Cl3 (b) K2[Zn(OH)4]

(i) `CH_(2)=CH-CH_(2)-CH=CH_(2)` (ii) `CH_(2)=CH-CH=CH-CH_(3)` (iii) `CH_(3)-CH=CH-CH=CH-CH_(3)` The numbers of possible geometrical isomers for the a

Description : (i) `CH_(2)=CH-CH_(2)-CH=CH_(2)` (ii) `CH_(2)=CH-CH=CH-CH_(3)` (iii) `CH_(3)-CH=CH-CH=CH-CH_(3)` The numbers of possible geometrical isomers for the a

Last Answer : (i) `CH_(2)=CH-CH_(2)-CH=CH_(2)` (ii) `CH_(2)=CH-CH=CH-CH_(3)` (iii) `CH_(3)-CH=CH-CH=CH-CH_(3)` The ... . 0, 2, 4 B. 2, 2 4 C. 0, 3, 3 D. 0,23

(i) `CH_(2)=CH-CH_(2)-CH=CH_(2)` (ii) `CH_(2)=CH-CH=CH-CH_(3)` (iii) `CH_(3)-CH=CH-CH=CH-CH_(3)` The numbers of possible geometrical isomers for the a

Description : (i) `CH_(2)=CH-CH_(2)-CH=CH_(2)` (ii) `CH_(2)=CH-CH=CH-CH_(3)` (iii) `CH_(3)-CH=CH-CH=CH-CH_(3)` The numbers of possible geometrical isomers for the a

Last Answer : (i) `CH_(2)=CH-CH_(2)-CH=CH_(2)` (ii) `CH_(2)=CH-CH=CH-CH_(3)` (iii) `CH_(3)-CH=CH-CH=CH-CH_(3)` The ... . 0, 2, 4 B. 2, 2 4 C. 0, 3, 3 D. 0,23

I have some matchsticks set up like this: I + XI = X. If you do not know Roman numerals, here is a quick starter: I=1 II=2 III=3 IV=4 V=5 VI=6 VII=7 VIII=8 IX=9 X=10 XI=11 XII=12 XIII=13 XIV=14 XV=15...... Of course, I + XI = X is wrong. You are told to move the minimum number of matchsticks to make the question correct. So, how many do you have to move? -Riddles

Description : I have some matchsticks set up like this: I + XI = X. If you do not know Roman numerals, here is a quick starter: I=1 II=2 III=3 IV=4 V=5 VI=6 VII=7 VIII=8 IX=9 X=10 XI=11 ... are told to move the minimum number of matchsticks to make the question correct. So, how many do you have to move? -Riddles

Last Answer : Most people would get to one move at the least, but the real answer is zero moves. If you rotate the whole question around 180 degrees, it will display this: X = IX + I

(i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2)S` (vi) `AsH_(3)` (vii) `SbH_(3)` (viii) `H_(2)Se` (ix) `H_(2)Te` Number of mole

Description : (i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2)S` (vi) `AsH_(3)` (vii) `SbH_(3)` (viii) `H_(2)Se` (ix) `H_(2)Te` Number of mole

Last Answer : (i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2) ... lone pair of electrons on the central atom is present in pure s-orbital

(i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2)S` (vi) `AsH_(3)` (vii) `SbH_(3)` (viii) `H_(2)Se` (ix) `H_(2)Te` Number of mole

Description : (i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2)S` (vi) `AsH_(3)` (vii) `SbH_(3)` (viii) `H_(2)Se` (ix) `H_(2)Te` Number of mole

Last Answer : (i) `NH_(3)` (ii) `N_(2)H_(4)` (iii) `HN_(3)` (iv) `PH_(3)` (v) `H_(2) ... lone pair of electrons on the central atom is present in pure s-orbital

Number of oxide orwesd among , (i) Cassiterite (ii) pyrolusite (iii) Kieserite (iv) Azurite (V) chromite (vi) siderite are.

Description : Number of oxide orwesd among , (i) Cassiterite (ii) pyrolusite (iii) Kieserite (iv) Azurite (V) chromite (vi) siderite are.

Last Answer : Number of oxide orwesd among , (i) Cassiterite (ii) pyrolusite (iii) Kieserite (iv) Azurite (V) chromite (vi) siderite are.

Perform following number system conversion : (i) (589)10 = ( )2 (ii) (101101)2 = ( )16 (iii) (413)8 = ( )2 (iv) (5AF)16 = ( )10 (v) (AC8)16 = ( )2 (vi) (106)8 = ( )10

Description : Perform following number system conversion : (i) (589)10 = ( )2 (ii) (101101)2 = ( )16 (iii) (413)8 = ( )2 (iv) (5AF)16 = ( )10 (v) (AC8)16 = ( )2 (vi) (106)8 = ( )10

Last Answer : (i) (589)10 = (1001001101)2 (ii) (101101)2 = ( 2D )16 (iii) (413)8 = (100001011 )2 (iv) (5AF)16 = (1455 )10 (v) (AC8)16 = (101011001000)2 (vi) (106)8 = (70)10

The possible number of geometrical isomers for the complex `[CoL_(2) Cl_(2)]^(-) (L = H_(2)NCH_(2) CH_(2)O^(-))` is (are)....

Description : The possible number of geometrical isomers for the complex `[CoL_(2) Cl_(2)]^(-) (L = H_(2)NCH_(2) CH_(2)O^(-))` is (are)....

Last Answer : The possible number of geometrical isomers for the complex `[CoL_(2) Cl_(2)]^(-) (L = H_(2)NCH_(2) CH_(2)O^(-))` is (are)....

What type of isomers are the following : `(i) [Mn(CO)_(5)SCN] and [Mn(CO)_(5)NCS]` `(ii) [Co(en)_(3)[Cr(CN)_(6)] and [Cr(en)_(3)][Co(CN)_(6)]` `(iii)

Description : What type of isomers are the following : `(i) [Mn(CO)_(5)SCN] and [Mn(CO)_(5)NCS]` `(ii) [Co(en)_(3)[Cr(CN)_(6)] and [Cr(en)_(3)][Co(CN)_(6)]` `(iii)

Last Answer : What type of isomers are the following : `(i) [Mn(CO)_(5)SCN] and [Mn(CO)_(5)NCS]` `(ii) [Co(en)_(3)[Cr( ... ]Cl and [Co(H_(2)O)Cl_(3)(py)_(2)]H_(2)O`

In ΔABC and ΔDEF, AB = DE, AB || DE, BC = EF and BC || EF. Vertices A, B and C are joined to vertices D, E and F respectively (see Fig. 8.22). Show that (i) quadrilateral ABED is a parallelogram (ii) quadrilateral BEFC is a parallelogram (iii) AD || CF and AD = CF (iv) quadrilateral ACFD is a parallelogram (v) AC = DF (vi) ΔABC ≅ ΔDEF. -Maths 9th

Description : In ΔABC and ΔDEF, AB = DE, AB || DE, BC = EF and BC || EF. Vertices A, B and C are joined to vertices D, E and F respectively (see Fig. 8.22). Show that (i) quadrilateral ABED is a parallelogram ( ... CF and AD = CF (iv) quadrilateral ACFD is a parallelogram (v) AC = DF (vi) ΔABC ≅ ΔDEF. -Maths 9th

Last Answer : . Solution: (i) AB = DE and AB || DE (Given) Two opposite sides of a quadrilateral are equal and parallel to each other. Thus, quadrilateral ABED is a parallelogram (ii) Again BC = EF and BC || EF ... (Given) BC = EF (Given) AC = DF (Opposite sides of a parallelogram) , ΔABC ≅ ΔDEF [SSS congruency]

What percentage is (i) Rs 15 of Rs 120? (ii) 36 minutes of 2 hours? (iii) 8 hours of 2 days (iv) 160 metres of 4 km? (v) 175 mL of 1 litre? (vi) 25 paise of Rs 4? -Maths

Description : What percentage is (i) Rs 15 of Rs 120? (ii) 36 minutes of 2 hours? (iii) 8 hours of 2 days (iv) 160 metres of 4 km? (v) 175 mL of 1 litre? (vi) 25 paise of Rs 4? -Maths

Last Answer : answer:

Find: (i) 25% of Rs 76 (ii) 20% of Rs 132 (iii) 7.5% of 600 m (iv) 313% of 90 km (v) 8.5% of 5 kg (vi) 20% of 12 litres -Maths

Description : Find: (i) 25% of Rs 76 (ii) 20% of Rs 132 (iii) 7.5% of 600 m (iv) 313% of 90 km (v) 8.5% of 5 kg (vi) 20% of 12 litres -Maths

Last Answer : answer:

Find: (i) 32% of 425 (ii) 1623% of 16 (iii) 6.5% of 400 (iv) 136% of 70 (v) 2.8% of 35 (vi) 0.6% of 45 -Maths

Description : Find: (i) 32% of 425 (ii) 1623% of 16 (iii) 6.5% of 400 (iv) 136% of 70 (v) 2.8% of 35 (vi) 0.6% of 45 -Maths

Last Answer : answer:

Convert each of the following fraction into a percentage: (i) 47 100 (ii) 9 20 (iii) 3 8 (iv) 8 125 (v) 19 500 (vi) 4 15 (vii) 2 3 (viii) 1 3 5 -Maths

Description : Convert each of the following fraction into a percentage: (i) 47 100 (ii) 9 20 (iii) 3 8 (iv) 8 125 (v) 19 500 (vi) 4 15 (vii) 2 3 (viii) 1 3 5 -Maths

Last Answer : We have the following: (i) 47100=47100×100% = 47% (ii) 920=920×100% =9×5%= 45% (iii) 38=38×100% =3×252%=752%=3712% (iv) 8125=8125×100%=8×45%=325%=6.4% (v) ... ;203%=803%=2623% (vii) 23=23×100%=2003%=6623% (viii) 135=85=85×100%=(8×20)%=160%

Convert each of the following into a fraction: (i) 32% (ii) 614% (iii) 2623% (iv) 120% (v) 6.25% (vi) 0.8% (vii) 0.06% (viii) 22.75% -Maths

Description : Convert each of the following into a fraction: (i) 32% (ii) 614% (iii) 2623% (iv) 120% (v) 6.25% (vi) 0.8% (vii) 0.06% (viii) 22.75% -Maths

Last Answer : answer:

Evaluate each of the following: (i) (103)3 (ii) (98)3 (iii) (9.9)3 (iv) (10.4)3 (v) (598)3 (vi) (99)3 -Maths 9th

Description : Evaluate each of the following: (i) (103)3 (ii) (98)3 (iii) (9.9)3 (iv) (10.4)3 (v) (598)3 (vi) (99)3 -Maths 9th

Last Answer : answer:

How many of following metals impart a characteristic colour to the Bunsen flame ? `(i) Na " " (ii) Li " " (iii) K " " (iv) Ba` `(v) Sr " " (vi) Mg " "

Description : How many of following metals impart a characteristic colour to the Bunsen flame ? `(i) Na " " (ii) Li " " (iii) K " " (iv) Ba` `(v) Sr " " (vi) Mg " "

Last Answer : How many of following metals impart a characteristic colour to the Bunsen flame ? `(i) Na " " (ii) Li " " (iii) K ... ix) `Be " " (x )Ca " " (x i)Cu`

How many of the following are oxides ores (i) Carnalite (ii) Cuprite (iii) Cassiterite (iv) Chromite (v) Cinnabar (vi) Calamine (vii) Cerussite (Viii)

Description : How many of the following are oxides ores (i) Carnalite (ii) Cuprite (iii) Cassiterite (iv) Chromite (v) Cinnabar (vi) Calamine (vii) Cerussite (Viii)

Last Answer : How many of the following are oxides ores (i) Carnalite (ii) Cuprite (iii) Cassiterite (iv) ... (vii) Cerussite (Viii) Chalocopyrite (ix) Chalcocite

Differentiate between any five of the following. (i) Artery and vein (ii) Hard water and soft water (iii) E-mail and Snail mail (iv) Apes and monkey (v) Hydrostatics and hydrodynamics (vi) Comet and meteor (vii) Barrage and dam (viii) Electron and hole (ix) Isobars and isotopes (x) Autopsy and biopsy

Description : Differentiate between any five of the following. (i) Artery and vein (ii) Hard water and soft water (iii) E-mail and Snail mail (iv) Apes and monkey (v) Hydrostatics and hydrodynamics (vi) Comet and ... (vii) Barrage and dam (viii) Electron and hole (ix) Isobars and isotopes (x) Autopsy and biopsy

Last Answer : Answers: (i) Artery and vein: Arteries: Muscular blood vessels that carry blood away from the heart. All arteries, with the exception of the pulmonary and umbilical arteries, carry oxygenated blood ... to determine cause of death Biopsy: Removal and study of a tissue sample for diagnostic purposes

Name the quantities which are measured by the following units. (i) Newton (ii) Joule (iii) Watt (iv) Volt (v) Light year (vi) Angstrom (vii) Acre-foot (viii) Becquerel (ix) Hertz (x) Cusec

Description : Name the quantities which are measured by the following units. (i) Newton (ii) Joule (iii) Watt (iv) Volt (v) Light year (vi) Angstrom (vii) Acre-foot (viii) Becquerel (ix) Hertz (x) Cusec

Last Answer : Answers: (i) Force (ii) Work Energy (iii) Power of electricity (iv) Potential difference (v) Distance of stars and planets (vi) Length (vii) Volume (viii) Radioactivity (ix) Frequency (x) Rate of flow of water

Which quantity do the following units measure: (i) Volt (ii) Coulomb (iii) Walt (iv) Ohm (v) Mho (vi) Ampere (vii) Dyne (viii) Celsius (ix) Joule (x) Calorie

Description : Which quantity do the following units measure: (i) Volt (ii) Coulomb (iii) Walt (iv) Ohm (v) Mho (vi) Ampere (vii) Dyne (viii) Celsius (ix) Joule (x) Calorie

Last Answer : Answers: (i) Voltage (ii) Charge of Electricity (iii) Power (iv) Resistance (v) Conductivity (vi) Current (vii) Force (viii) Temperature (ix) Energy (x) Heat

Arrange the following steps to form a basic Engineering Process Model.i. Test ii. Design iii. Install iv. Specification v. Manufacture vi. Maintain a) 2, 4, 5, 1, 6, 3 b) 4, 2, 5, 1, 3, 6 c) 2, 4, 5, 1, 3, 6 d) 4, 2, 5, 1, 6, 3

Description : Arrange the following steps to form a basic Engineering  Process Model. i. Test ii. Design iii. Install iv. Specification v. Manufacture vi. Maintain a) 2, 4, 5, 1, 6, 3 b) 4, 2, 5, 1, 3, 6 c) 2, 4, 5, 1, 3, 6 d) 4, 2, 5, 1, 6, 3

Last Answer : a) 2, 4, 5, 1, 6, 3