If a body (coated black) at 600K surrounded by atmosphere at 300K has cooling rate `r_(0)`, the same body at 900K, surrounded by the same atmosphere,

1 Answer

Answer :

If a body (coated black) at 600K surrounded by atmosphere at 300K has cooling rate `r_(0)`, the same body at 900K, ... )//6` C. `16r_(0)` D. `4r_(0)`

Related questions

Description : If a body (coated black) at `600 K` surrounded by atmosphere at `300 K` has cooling rate `r_(0)`, the same body at `900 K`, surrounded by the same atm

Last Answer : If a body (coated black) at `600 K` surrounded by atmosphere at `300 K` has cooling rate `r_(0)`, the same body ... (0)//16` C. `16r_(0)` D. `4r_(0)`

Description : In Dumas’ method for estimation of nitrogen, 0.3g of an organic compound gave 50mL of nitrogen collected at 300K temperature and 715mm pressure. Calculate the percentage composition of nitrogen in the compound. (Aqueous tension at 300K=15 mm).

Last Answer : Volume of nitrogen collected at 300K and 715mm pressure is 50 mL Actual pressure = 715-15 =700 mm Volume of Nitrogen at STP=273*700*50/300*760 =41.9 ml 22400 ml of Nitrogen at STP weighs = 28 g 41.9 ml of Nitrogen weighs = 28*41.9/22400 g % of Nitrogen = 28*41.9*100/22400*0.3 = 17.45 %

Description : Hydrolysis of ester in catalysed by acid. Rate of hydrolysis of ester were obtained initially and after some ester has been hydrolysed as `R_(0)` and

Last Answer : Hydrolysis of ester in catalysed by acid. Rate of hydrolysis of ester were obtained initially and after some ... 0) gt R_(t)` D. Cannot be determined

Description : For a reversible process at T = 300K, the volume is increased from `V_(i)=1L` to `V_(f)=10L`. Calculate `Delta H` if the process is isothermal -

Last Answer : For a reversible process at T = 300K, the volume is increased from `V_(i)=1L` to `V_(f)=10L`. Calculate `Delta H ... kJ B. 4.98 kJ C. 0 D. `-11.47 kJ`

Description : I am going through a divorce, my ex-wife needs to refinance,but we owe more than the house is worth we have a 1st&2nd fixed and never missed a payment in 10 yrs.also have a 740 credit score what can she do need my name off of the house.owe 300k worth 250k?

Last Answer : You cannot get your name off the mortgage unless you refinance. You may be able to have her refinance the home if you sign a note for the difference between what she can finance for and what is owed. You can also contact the first and second lienholders and request a short sale without recourse.

Description : Air enters an adiabatic compressor at 300K. The exit temperature for a compression ratio of 3, assuming air to be an ideal gas (Y = Cp/Cv = 7/5) and the process to be reversible, is (A) 300 × (32/7) (B) 300 × (33/5) (C) 300 × (333/7) (D) 300 × (35/7)

Last Answer : A) 300 × (32/7)

Description : A metal is exposed to the atmosphere for some time. It becomes coated with green carbonate. The metal must be – (1) silver (2) copper (3) aluminium (4) zinc

Last Answer : (2) copper Explanation: Copper forms a rich variety of compounds with oxidation states +1 and +2, which are often called cuprous and cupric, respectively. It does not react with water, but it ... contrast to the oxidation of iron by wet air, this oxide layer stops the further, bulk corrosion.

Description : A metal is exposed to the atmosphere for sometime. It becomes coated with green carbonate. The metal must be (1) silver (2) copper (3) aluminium(4) zinc

Last Answer : copper

Description : Ultra violet radiations of the Sun do not reach the earth because, earth's atmosphere is surrounded by – (1) Carbon dioxide (2) Ammonia (3) Chlorine (4) Ozone

Last Answer : (4) Ozone Explanation: The ozone layer absorbs 97-99% of the Sun's medium-frequency ultraviolet light (from about 200 nm to 315 nm wavelength), which potentially damages exposed life forms on Earth. Ozone ... Earth's atmosphere. In total, ozone makes up only 0.6 parts per million of the atmosphere.

Description : Ultra violet radiations of the Sun do not reach the earth because, earth’s atmosphere is surrounded by (1) Carbon dioxide (2) Ammonia (3) Chlorine (4) Ozone

Last Answer : Ozone

Description : Recall homework 2 in which we calculated emissivity for a single layer atmosphere. If the atmosphere were to suddenly become a perfect emitter (i.e., if e = 1 rather than e = 0.8), ... . (d) There would be initial warming followed by cooling as the planet moves toward radiative equilibrium.

Last Answer : (c) The surface temperature would be higher.

Description : A cell sends a current through a resistance `R_(1)` for time `t`, next the same cell sends current through another resistance `R_(2)` for the time `t`

Last Answer : A cell sends a current through a resistance `R_(1)` for time `t`, next the same cell sends current through another ... r=(1)/(R_(2))+(1)/(R_(2))`

Description : Two cells, having the same emf, are connected in series through an external resistance `R`. Cells have internal resistance `r_(1)` and `r_(2) (r_(1) g

Last Answer : Two cells, having the same emf, are connected in series through an external resistance `R`. Cells have internal resistance ... D. `(r_(1)+r_(2))/(2)`

Description : Assertion : In the circuit shown in figure, battery is ideal. If a resistance `R_(0)` is cannected in parallel with R, then power across R will increa

Last Answer : Assertion : In the circuit shown in figure, battery is ideal. If a resistance `R_(0)` is cannected ... . D. If Assertion is false but Reason is true.

Description : In the circuit diagram shown in Figure E=18V , L=2H, `R_(1)=3Omega , R_(2)=6Omega`. Switch S is closed at t=0 Match the following:

Last Answer : In the circuit diagram shown in Figure E=18V , L=2H, `R_(1)=3Omega , R_(2)=6Omega`. Switch S is closed at t=0 Match the following:

Description : A satellite of mass m orbits the earth in an elliptical orbit having aphelion distance `r_(a)` and perihelion distance `r_(p)`. The period of the orbi

Last Answer : A satellite of mass m orbits the earth in an elliptical orbit having aphelion distance `r_(a)` and perihelion distance ... r_(p)) sqrt(r_(a)r_(p)))/T`

Description : Name the given reaction and enzyme involved in it `underset("Amino donor")(R_(1)-underset(NH_(3)^(+))underset(|)overset(H)overset(|)(C)-COO^(-)+unders

Last Answer : Name the given reaction and enzyme involved in it `underset("Amino donor")(R_(1)-underset(NH_(3)^(+)) ... underset(|)overset(H)overset(|)(C)-COO^(-)`

Description : Determine the voltage drop across the resistance `R_(1)` in the circuit given in Fig. 4.55 with `epsilon=90 V, R_(1)=5 k Omega, R_(2)=5k Omega, R_(3)=

Last Answer : Determine the voltage drop across the resistance `R_(1)` in the circuit given in Fig. 4.55 with `epsilon=90 V, ... k Omega " and " R_(4)=10 k Omega`.

Description : In the figure shown there are two semicircles of radii `r_(1)` and `r_(2)` in which a current `i` is flowing. The magnetic induction at the centre `O`

Last Answer : In the figure shown there are two semicircles of radii `r_(1)` and `r_(2)` in which a current `i` is flowing. The ... 4)[(r_(1)-r_(2))/(r_(1)r_(2))]`

Description : Six resistance each of value `r=5 Omega` are connected between points A, B and C as shown in figure. If `R_(1), R_(2)` and `R_(3)` are the net resista

Last Answer : Six resistance each of value `r=5 Omega` are connected between points A, B and C as shown in figure. If `R_(1), R_(2) ... 1:2:3` C. `5:4:3` D. `4:3:2`

Description : In the circuit shown the cells `A` and `B` have negligible resistance. For `V_(A) = 12 V, R_(1) = 500 Omega` and `R = 100 Omega`, the galvanometer `(G

Last Answer : In the circuit shown the cells `A` and `B` have negligible resistance. For `V_(A) = 12 V, R_(1) = 500 Omega` and ` ... A. 4 V B. 2 V C. 12 V D. 6 V

Description : A metal wire of circular cross-section has a resistance `R_(1)`. The wire is now stretched without breaking, so that its length is doubled and the den

Last Answer : A metal wire of circular cross-section has a resistance `R_(1)`. The wire is now stretched without breaking, so that its ... 2` C. `4 : 1` D. `1 : 4`

Description : the current in resistance `R_(3)` in the given circuit is `2/x A`. Find the value of x.

Last Answer : the current in resistance `R_(3)` in the given circuit is `2/x A`. Find the value of x. A. `1A` B. `2//3A` C. `0.25A` D. `0.50A`

Description : Two batteries of emf `epsilon_(1)` and `epsilon_(2) (epsilon_(2)gtepsilon_(1)` and internal resistances `r_(1)` and `r_(2)` respectively are connected

Last Answer : Two batteries of emf `epsilon_(1)` and `epsilon_(2) (epsilon_(2)gtepsilon_(1)` and internal resistances ... internal resistances `r_(1)` and `r_(2)`

Description : The potential difference in volt across the resistance `R_(3)` in the circuit shown in figure, is `(R_(1)=15Omega,R_(2)=15Omega, R_(3)=30Omega, R_(4)=

Last Answer : The potential difference in volt across the resistance `R_(3)` in the circuit shown in figure, is `(R_(1)=15Omega,R_(2 ... 5 B. `7.5` C. 15 D. `12.5`

Description : You are given two resistances `R_(1)` and `R_(2)`. By using them singly, in series and in parallel, you can obtain four resistances of `1.5Omega, 2Ome

Last Answer : You are given two resistances `R_(1)` and `R_(2)`. By using them singly, in series and in parallel ... .5Omega` C. `3Omega,5Omega` D. `2Omega, 6Omega`

Description : A cell supplies a current `i_(1)` trhough a resistnace `R_(1)` and a current `i_(2)` through a resistance `R_(2)`. The internal resistance of this cel

Last Answer : A cell supplies a current `i_(1)` trhough a resistnace `R_(1)` and a current `i_(2)` through a resistance `R_(2 ... ))/(i_(1)-i_(2)))sqrt(R_(1)R_(2))`

Description : In the circuit shown in figure : `R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega` and `C = (sqrt(3))/(2) mF`. Current in `L - R_(1)` circuit is

Last Answer : In the circuit shown in figure : `R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega` and `C = (sqrt(3)) ... ` B. `90^(@)` C. `180^(@)` D. `60^(@)`

Description : In the circuit shown in figure : `R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega` and `C = (sqrt(3))/(2) mF`. Current in `L - R_(1)` circuit is

Last Answer : In the circuit shown in figure : `R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega` and `C = (sqrt( ... 10 sqrt(2) A` C. `20 sqrt(2) A` D. `25 A`

Description : In the circuit shown in figure : `R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega` and `C = (sqrt(3))/(2) mF`. Current in `L - R_(1)` circuit is

Last Answer : In the circuit shown in figure : `R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega` and `C = (sqrt(3) ... 2) A` C. `5 sqrt(6) A` D. `5 sqrt(3) A`

Description : What are the two faces of the Golgi body? (A) Funny face and goofy face (B) Coated face and non-coated face (C) Saving face and loosing face (D) Cis face and Trans face

Last Answer : (D) Cis face and Trans face

Description : What is the body cavity surrounded by wall called ?

Last Answer : : The body cavity surrounded by a wall is called cilantro.

Description : What is the body of freshwater that is surrounded by land but is bigger than a pond?

Last Answer : a lake

Description : A body of land that is surrounded by water on three sides is called----? A. Strait B. Bay C. Peninsula (Answer) D. Gulf

Last Answer : C. Peninsula (Answer)

Description : Which of the following geographical term related with a body of land surrounded by water on three sides? A. Peninsula B. Gulf C. Strait D. Island

Last Answer : A. Peninsula

Description : What is the cooling of water in the atmosphere that changes gas to liquid?

Last Answer : Condensation

Description : Supercharging is the process of a. supplying the engine with air at a density greater than the density of the surrounding atmosphere b. providing forced cooling air c. injecting excess fuel d. raising the exhaust pressure

Last Answer : ANSWER a. supplying the engine with air at a density greater than the density of the surrounding atmosphere

Description : Air intake for an air compressor should be preferably taken from (A) A site, where cooling towers are located nearby (B) A site, where open coal yard in located nearby (C) An air conditioned room maintained at a temperature of 18°C (D) An outside atmosphere at 10°C

Last Answer : (D) An outside atmosphere at 10°C

Description : Which of the following gives out highest pollutants to the atmosphere 1 cooling tower 2 water tower 3 steam tower 4 fire tower

Last Answer : 3 steam tower

Description : A soil mass coated with a thin layer of paraffin weighs 460 g. When immersed, it displaces 299 cc of water. The weight of paraffin is 10 g. If specific gravity of solids is 2.5 and that of paraffin 0.9, the void ratio of soil, is (A) 0.55 (B) 0.60 (C) 0.65 (D) 0.70

Last Answer : Answer: Option B

Description : Rate of cooling depends on the (1) Temperature difference between the body and the surroundings (2) Nature of the radiating surface (3) Area of the radiating surface (4) All of these

Last Answer : (4) All of these Explanation: Newton's Law of Cooling states that the rate of temperature of the body is proportional to the difference between the temperature of the body and that of the ... Specific heat of the radiating body; Temperature of radiating body and ♦ Temperature of the surrounding.

Description : Which law states, “The rate of loss of heat by a body is directly proportional to the difference in temperature between the body and the surroundings.” (1) Doppler’s Effect (2) Newton’s law of cooling (3) Kirchhoff’s Law (4) Stefan’s Law

Last Answer : (2) Newton’s law of cooling Explanation: Kirchhoff’s Law – Kirchhoff’s Law signifies that good absorbers are good emitters. Stefan’s Law – The radiant energy emitted by a black body per unit area per unit time is directly proportional to the fourth power of its absolute temperature.

Description : Which law states, "The rate of loss of heat by a body is directly proportional to the difference in temperature between the body and the surroundings." (1) Doppler's Effect (2) Newton's law of cooling (3) Kirchhoff's Law (4) Stefan's Law

Last Answer : (2) Newton's law of cooling Explanation: Kirchhoff's Law - Kirchhoff's Law signifies that good absorbers are good emitters. Stefan's Law - The radiant energy emitted by a black body per unit area per unit time is directly proportional to the fourth power of its absolute temperature.

Description : Which law states, "The rate of loss of heat by a body is directly proportional to the difference in temperature between the body and the surroundings"? (1) Doppler's Effect (2) Newton's law of cooling (3) Kirchhoff's Law (4) Stefan's Law

Last Answer : (2) Newton's law of cooling Explanation: Newton's Law of Cooling states that the rate of change of the temperature of an object is proportional to the difference between its own temperature and the ambient temperature.

Description : The force exerted by a moving fluid on an immersed body is directly proportional to the rate of change of momentum due to the presence of the body. This statement is called (A) Newton's law of motion (B) Newton's law of cooling (C) Newton's law of viscosity (D) Newton's law of resistance

Last Answer : Answer: Option D

Description : For a body cooling in a draft, the rate of heat loss is proportional to the difference in temperature between the body and its surroundings.  a. Nemst Effect  b. Caloric Theory  c. Joule’s Law  d. Newton’s Law of Cooling

Last Answer : Newton’s Law of Cooling

Description : Rate of cooling depends on the (1) Temperature difference between the body and the surroundings (2) Nature of the radiating surface (3) Area of the radiating surface (4) All of these

Last Answer : All of these

Description : A circular plate, a cube and a sphere, all made up of same material and having the same mass, are heated to 300°C and left in a room. Which of them will have the slowest rate of cooling? (1) Circular plate (2) Cube (3) Sphere (4) All will cool at the same rate

Last Answer : (3) Sphere Explanation: In the late of 17th century British scientist Isaac Newton studied cooling of bodies. Experiments showed that the cooling rate is approximately proportional to the difference of temperatures between the heated body and the environment.

Description : A hollow sphere and a solid sphere of the same material and equal radii are heated to the same temperature. In this case, (A) The cooling rate will be the same for the two spheres and hence the ... equal amount of radiation from the surrounding in the beginning (D) Both (B) & (C)

Last Answer : (D) Both (B) & (C)

Description : For the same heat load and mass flow rate in the tube side of a shell and tube heat exchanger, one may use multipass on the tube side, because it (A) Decreases the pressure drop (B) ... the outlet temperature of cooling medium (C) Increases the overall heat transfer coefficient (D) None of these

Last Answer : (C) Increases the overall heat transfer coefficient