What is the value of gravitational acceleration g ?

What is the value of gravitational acceleration g ?
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Answer :

Gravitational acceleration g has a value of 9.8 m / s.
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What is the value of gravitational acceleration ( g) in the center of the earth ?

Description : What is the value of gravitational acceleration ( g) in the center of the earth ?

Last Answer : The value of gravitational acceleration ( g) in the center of the earth is zero (0).

Where is the highest value of gravitational acceleration 'g ' ?

Description : Where is the highest value of gravitational acceleration 'g ' ?

Last Answer : The value of gravitational acceleration 'g' is highest in the polar region

What is meant by gravitational acceleration value of 9.8ms 2 ?

Description : What is meant by gravitational acceleration value of 9.8ms 2 ?

Last Answer : The acceleration that occurs in a freely falling object under the influence of gravity is called gravitational acceleration , which is an excellent natural example of balanced acceleration. The value of gravitational ... of any object falling freely on the earth 's surface is 9.8ms − 2 .

What is the standard value of gravitational acceleration ?

Last Answer : The standard value of gravitational acceleration is 9.8 m / s.

The average person passes out at an acceleration of 7g (that is, seven times the gravitational acceleration on Earth). Suppose a car is designed to accelerate at this rate. How much time (in seconds) would be required for the car to accelerate from rest to 56.3 miles per hour?

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Last Answer : I think the Fluther policy is not to help students with their homework, but I always hate this kind of problem and it seems to me that the g is just in there to provide some background and to confuse you.

what is the acceleration of a 1.4 kg object if the gravitational force pulls downward on it , but air resistance pushes upward on it with a force of 2.5 N?

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Last Answer : if g = 10(m/s)/s then force down = ma = 10*1.4=14n14n-2.5n=11.5na=f/m = 11.5/1.4 = 8.21 (m/s/)s

What would a swing be without gravitational acceleration ?

Description : What would a swing be without gravitational acceleration ?

Last Answer : Without gravitational acceleration the oscillation will continue to oscillate at the same speed for life.

What is meant by gravitational acceleration of the moon 1.63ms-2 ?

Description : What is meant by gravitational acceleration of the moon 1.63ms-2 ?

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What is gravitational acceleration ?

Description : What is gravitational acceleration ?

Last Answer : Gravitational acceleration: The rate of increase in the velocity of an object falling freely on the surface of the earth under the influence of a gravitational ball is called gravitational acceleration. It is ... with g . This is equal to the dimension and the unit of acceleration and the unit.

What is gravitational acceleration ?

Description : What is gravitational acceleration ?

Last Answer : Gravitational acceleration is the rate of increase in the velocity of an object falling freely on the surface under the influence of a gravitational ball .

What is the degree of gravitational acceleration ?

Description : What is the degree of gravitational acceleration ?

Last Answer : Gravitational acceleration is a type of acceleration , so its magnitude will be LT −2

What does gravitational acceleration mean ?

Description : What does gravitational acceleration mean ?

Last Answer : Gravitational acceleration is the rate of increase of velocity of an object falling from above. Gravity causes an object released from above to run towards the surface, and the closer it gets ... at which velocity increases per second during a fall is called 'gravitational acceleration' in physics.

At which place on the Earth surface the gravitational acceleration minimum? Why?

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Last Answer : At which place on the Earth surface the gravitational acceleration minimum? Why?

Draw a graph showing the variation of gravitational acceleration due to the depth and altitude from the Earth’s surface.

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Last Answer : Draw a graph showing the variation of gravitational acceleration due to the depth and altitude from the Earth’s surface.

At which place on the Earth’s surface is the gravitational acceleration maximum? Why?

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Last Answer : At which place on the Earth’s surface is the gravitational acceleration maximum? Why?

If the gravitational force between the earth and object always causes the same acceleration why does a feather fall more slowly than a hammer does?

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Last Answer : Need answer

What is gravitational acceleration?

Description : What is gravitational acceleration?

Last Answer : Standing at surface radius its = 9.82 (m/s)/sbut double the radius and the acceleration drops to 9.82 / ((2 / 1)2) = 2.455 (m/s)/s

What is the value of the gravitational constant G ?

Description : What is the value of the gravitational constant G ?

Last Answer : : The value of the gravitational constant G is 6.67384 10-11 Nm2kg-2

What is the value of gravitational constant G?

Description : What is the value of gravitational constant G?

Last Answer : 1

The value of the universal gravitational constant, G is (a) 6.67 × 1011 Nm2/kg2 (b) 6.67 × 10+9 Nm2/kg2 (c) 6.67 × 10–9 Nm2/kg2 (d) 6.67 × 10–11 Nm2/kg2

Description : The value of the universal gravitational constant, G is (a) 6.67 × 1011 Nm2/kg2 (b) 6.67 × 10+9 Nm2/kg2 (c) 6.67 × 10–9 Nm2/kg2 (d) 6.67 × 10–11 Nm2/kg2

Last Answer : Ans:(d)

The value of G, the universal gravitational constant, was measured experimentally by: w) Newton x) Cavendish y) Copernicus z) Kepler

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As we go from Equator to North pole the value of ‘g’, the acceleration due to gravity (1) remains the same (2) decreases (3) increases (4) None of the above

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The dimensions of gravitational constant G a.MLT-2 b.M-1L3T-2 c.Ellipsc d.ML2T-1 e.MLT-1

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What is the unit of gravitational constant G ?

Description : What is the unit of gravitational constant G ?

Last Answer : The unit of gravitational constant G is Nm ^ 2kg ^ -2

Calculate the mass and mean density of the earth from the following data : `{:(,"Gravitational constant",(G),=6.6xx10^(-11)Nm^(2)kg^(-2)),(,"Radius of

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Calculate the mass and mean density of the earth from the following data : `{:(,"Gravitational constant",(G),=6.6xx10^(-11)Nm^(2)kg^(-2)),(,"Radius of

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Gravitational constant (G) is an example of (a) Non-dimensional constant (b) Dimensional constant (c) Numeric constant (d) Quantity without dimensions

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Last Answer : Ans:(b)

Dimensions of gravitational constant ‘G’ are: A. [M]-1 [L]3 [T]-2 B. [M] [L]3 [T]-2 C. [M]-1 [L]2 [T]-1 D. [M] [L]-1 [T]2

Description : Dimensions of gravitational constant ‘G’ are: A. [M]-1 [L]3 [T]-2 B. [M] [L]3 [T]-2 C. [M]-1 [L]2 [T]-1 D. [M] [L]-1 [T]2

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Velocity of escape is equal to A. r × √(2g); where r: radius of Earth or any other planet for that matter, g: gravitational field strength B. g × √(2r); where r: radius of Earth or any other planet for that matter, g: gravitational field strength C. √(2g) ⁄ r; where r: radius of Earth or any other planet for that matter, g: gravitational field strength D. √(2gr); where r: radius of Earth or any other planet for that matter, g: gravitational field strength

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A mass of 5kg is 100m above a given datum where local g = 9.75 m/s2 . Find the gravitational force in newtons. (Formula: Fg= mg/k )  a. 48.75 N  b. 50 N  c. 45 N  d. None of the above

Description : A mass of 5kg is 100m above a given datum where local g = 9.75 m/s2 . Find the gravitational force in newtons. (Formula: Fg= mg/k )  a. 48.75 N  b. 50 N  c. 45 N  d. None of the above

Last Answer : 48.75 N

A weight of 4.9 N rests on a rough horizontal floor that has a coefficient of friction of 0.5. If g = 9.8 m/s2, the smallest horizontal force that gives the weight an acceleration of 4m/s2 is most nearly a.2.5 N b.3 N c.2 N d.4.5 N e.4.9 N

Description : A weight of 4.9 N rests on a rough horizontal floor that has a coefficient of friction of 0.5. If g = 9.8 m/s2, the smallest horizontal force that gives the weight an acceleration of 4m/s2 is most nearly a.2.5 N b.3 N c.2 N d.4.5 N e.4.9 N

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Show that acceleration due to gravity at height h above the Earth’s surface is gh = g(R/R + h)^2

Description : Show that acceleration due to gravity at height h above the Earth’s surface is gh = g(R/R + h)^2

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Acceleration due to gravity (g) is mini- mum at?

Description : Acceleration due to gravity (g) is mini- mum at?

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Acceleration due to gravity (g) is maxi- mum at?

Description : Acceleration due to gravity (g) is maxi- mum at?

Last Answer : polar regions

At the Center of earth Acceleration due to gravity (g) is?

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Critical speed of rotation, N (in rps - rotation per second) of a trammel is equal to (where, g = acceleration due to gravity = 9.81 m/sec 2 and, r = radius of trammel, metre.) (A) (1/2π). √(g/r) (B) (1/π). √(g/r) (C) ½ √(g/r) (D) 2π. √(g/r)

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Last Answer : (A) (1/2π). √(g/r)

Force that acts on a mass of 1 g and gives it an acceleration of 1 cm s-2 is defined asA. 1 newtonB. 1 dyneC. 1 pound-forceD. 1 pa-force

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The static deflection of a spring under gravity, when a mass of 1 kg is suspended from it, is 1 mm. Assume the acceleration due to gravity g = 10 m/s^2. The natural frequency of this spring-mass system (in rad/s) is A 100 B 150 C 200 D 250

Description : The static deflection of a spring under gravity, when a mass of 1 kg is suspended from it, is 1 mm. Assume the acceleration due to gravity g = 10 m/s^2. The natural frequency of this spring-mass system (in rad/s) is A 100 B 150 C 200 D 250

Last Answer : A 100

A lift of weight W is lifted by a rope with an acceleration f. If the area of cross-section of the rope is A, the stress in the rope is (A) [W (1 + f/G)]/A (B) (1 - g/f)/A (C) [W (2 + f/G)]/A (D) [W (2 + g/f)]/A

Description : A lift of weight W is lifted by a rope with an acceleration f. If the area of cross-section of the rope  is A, the stress in the rope is  (A) [W (1 + f/G)]/A (B) (1 - g/f)/A (C) [W (2 + f/G)]/A (D) [W (2 + g/f)]/A

Last Answer : (A) [W (1 + f/G)]/A

If is the speed of a locomotive in km per hour, g is the acceleration due to gravity, is the distance between running faces of the rails and is the radius of the circular curve, the required super elevation is (A) gV²/GR (B) Rg/GV² (C) GR/gV² (D) GV²/gR

Description : If is the speed of a locomotive in km per hour, g is the acceleration due to gravity, is the distance between running faces of the rails and is the radius of the circular curve, the required super elevation is (A) gV²/GR (B) Rg/GV² (C) GR/gV² (D) GV²/gR

Last Answer : (D) GV²/gR

If V is speed of a moving vehicle, r is radius of the curve, g is the acceleration due to gravity, W is the width of the carriageway, the super elevation is (A) WV/gr (B) W²V/gr (C) WV²/gr (D) WV/gr²

Description : If V is speed of a moving vehicle, r is radius of the curve, g is the acceleration due to gravity, W is the width of the carriageway, the super elevation is (A) WV/gr (B) W²V/gr (C) WV²/gr (D) WV/gr²

Last Answer : Answer: Option C

The earth's gravitational force field is said to be conservative force field because a.The work acted by the earth's gravitational field on a particle is independent on the path traced out by the particle b.The work acted by the erth's gravitational field will cause same path for all particles irrespective of their mass c.The direction of gravitational force is fixed d.The gravitational field has only single directional component always acting normal to a body e.The value of gravitational force rise is fixed

Description : The earth's gravitational force field is said to be conservative force field because a.The work acted by the earth's gravitational field on a particle is independent on the path traced out by ... directional component always acting normal to a body e.The value of gravitational force rise is fixed

Last Answer : a. The work acted by the earth's gravitational field on a particle is independent on the path traced out by the particle

Calculate the value of the universal gravitational constant from the given data. Mass of the Earth = 6 × 10^24 kg,

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As distance increases, value of gravitational field strength A. also increases B. decreases C. remains constant D. may increase or decrease

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Last Answer : decreases

The value of acceleration due to gravity is 980 cm/sec2. Its value in meter per (hour)2 will be a.1.27 x 108 b.127 c.1270 d.1.27 x 107 e.1270000

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Last Answer : a. 1.27 x 108

Calculate the value of acceleration due to gravity on the surface of Mars if the radius of Mars = 3.4 × 10^3 km and its mass is 6.4 × 10^23 kg.

Description : Calculate the value of acceleration due to gravity on the surface of Mars if the radius of Mars = 3.4 × 10^3 km and its mass is 6.4 × 10^23 kg.

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At what distance below the surface of the Earth, the acceleration due to gravity decreases by 10% of its value at the surface,

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The value of acceleration due to gravity is maximum at

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What is the value in meter per second of the acceleration of gravity?

Description : What is the value in meter per second of the acceleration of gravity?

Last Answer : 9.8

What is the value in meter per second of the acceleration of gravity?

Description : What is the value in meter per second of the acceleration of gravity?

Last Answer : 9.8