Why HCL is a Polar Compound ?

Why HCL is a Polar Compound ?
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Hydrogen chloride ( HCl) is formed by covalent bonding of hydrogen and chlorine by sharing electrons with each other. Usually covalent compounds are polar. But since the difference in electronegativity of hydrogen and chlorine is greater, the binding of chlorine bonds attracts the electrons to itself. As a result, hydrogen is charged in a partially positive and chlorine in a partially negative charge. That is, HCl compounds are polar due to the difference in electronegativity of hydrogen and chlorine in the HCl compound.
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HCl is dissolved in solvent A; the solution is non-conducting towards an electric current. Solvent A must be: w) polar x) non-polar y) organic z) more acidic than HCl

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Last Answer : ANSWER: X -- NON-POLAR

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Last Answer : A. Vol of 0 .1M HCl taken = 50ml Vol of .1MNaOH used for neutralization of unused acid=23.2ml Now, 23.2 ml of .1MNaOH =23.2ml of .1MHCl Vol of .1MHCl unused=23.2ml Vol of .1MHCl required ... NH3 solution contain nitrogen = 14*26.8/10*1000 Percentage of Nitrogen=14*26.8*100/10*1000*.257 =14.6%

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Which compound in each of the following pairs will add HCl readily?

Description : Which compound in each of the following pairs will add HCl readily?

Last Answer : Which compound in each of the following pairs will add HCl readily?

Which compound in each of the following pairs will add HCl readily?

Description : Which compound in each of the following pairs will add HCl readily?

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Last Answer : (c) (ii) and (iv) only

When an elemental metal combines with an elemental nonmetal it forms a A covalent compound B binary ionic compound C double salt D polar covalent compound?

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Last Answer : Ghh

The polar bonds existing in III-V compound semiconductor, may be considered as equivalent to

Description : The polar bonds existing in III-V compound semiconductor, may be considered as equivalent to  (a) 1 ionic bond and 3 covalent bonds (b) 1 ionic bond and 4 covalent bonds (c) 2 ionic bonds and 2 covalent bonds (d) 2 ionic bonds and 4 covalent bonds

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Which among the following is used as a catalyst in the production of high octane fuels? (1) HNO3 (2) H2SO4 (3) HCl (4) HF

Description : Which among the following is used as a catalyst in the production of high octane fuels? (1) HNO3 (2) H2SO4 (3) HCl (4) HF

Last Answer : (2) H2SO4 Explanation: Sulfuric acid is used as a catalyst for refining and for producing alkylate, an essential component of highoctane fuel. The hydrocarbon molecules are reformed into more complex molecules with a higher octane rating value.

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Last Answer : (3) dil. HCl and dil. HNO3 Explanation: Aqua regia or nitro-hydrochloric acid is a highly corrosive mixture of acids which is formed by freshly mixing concentrated Nitric acid (HNO3) and Hydrochloric acid (HCl), optimally in a volume ratio of 1:3. It is used in dissolving gold.

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Last Answer : Ans. HCl in the solution provides Clions. This increases the ionic product in NaCl and so the solid NaCl starts separating out.

What happens HCl gas passed through saturated NaCl solution?

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Last Answer : Ans. NaCl will be precipitated out.

Explain why anhydrous HCl is a bad conductor electricity while aqueous HCl is a good conductor of electricity.

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Use the information and data given below to answer the questions • Stronger intermolecular forces result in higher boiling point • Strength of London forces increases with the number of electrons in the molecule • Boiling point of HF ,HCl, HBr and HI are 293K,189K,206K and 238K respectively (a) Which type of intermolecular forces are present in the molecules HCl, HBr and HI? (b) Looking at the trend of boiling points of HCl, HBr and HI, explain, out of dipole interaction and London interaction, which one predominant here? (c) Why is the boiling point of HF highest while that of HCl lowest?

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Last Answer : Ans :( a) In the molecules HCl, HBr and HI, dipole-dipole interaction and London forces are present. (b) Dipole moment of HCl > HBr > HI but boiling point of HCl < HBr

Which type of intermolecular forces exists among the following molecules? (a) H2S molecules (b) H2O (c) Cl2 and CCl4 (d) SiH4 (e) Helium (f) He atoms and HCl molecules

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Last Answer : Ans. (a) Dipole-Dipole interactions. (b)H-Bond. (c)Dispersion forces. (d)Dispersion forces. (e)Dispersion forces. (f)Induced dipole-dipole interactions.

What happen when mango is placed in dilute aqueous soln. of HCl?

Description : What happen when mango is placed in dilute aqueous soln. of HCl?

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Pyridine reacts with HCl to form (a) Pyridinium chloride (b) 2-Chloropyridine (c) 3-Chloropyridine (d) All of these

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Last Answer : Pyridinium chloride

Benzoic acid and diphenyl ketone are both solids insoluble in water. A mixture of these compounds can be separated if we (a) add the mixture to a solution of NaOH in water, and filter. (b) add the mixture to a solution of HCl in water, and filter. (c) dissolve the mixture in benzene and boil off the benzene. (d) It is impossible to separate a mixture of two solids when both are insoluble in water.

Description : Benzoic acid and diphenyl ketone are both solids insoluble in water. A mixture of these compounds can be separated if we (a) add the mixture to a solution of NaOH in water, and filter. (b) add ... benzene. (d) It is impossible to separate a mixture of two solids when both are insoluble in water.

Last Answer : add the mixture to a solution of NaOH in water, and filter

Which of the following compounds is least acidic? (a) HCl (b) Phenol (c) Acetylene (d) Picric acid

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Last Answer : Acetylene

Which of the following reagents is used to prepare benzenediazoniumchloride from aniline?(a) NaNO2 + HCl(b) LiAlH4(c) NH2NH2 + KOH(d) NaOH

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Last Answer : NaNO2 + HCl

Aniline is prepared by (a) the reaction of benzene with ammonia (b) the reduction of nitrobenzene with Sn/HCl (c) the dehydrogenation of nitrobenzene (d) the reaction of nitrobenzene with I2/NaOH

Description : Aniline is prepared by (a) the reaction of benzene with ammonia (b) the reduction of nitrobenzene with Sn/HCl (c) the dehydrogenation of nitrobenzene (d) the reaction of nitrobenzene with I2/NaOH

Last Answer : the reduction of nitrobenzene with Sn/HCl

Which of the following statements is false about aniline? (a) It is a primary aromatic amine. (b) It is a weak base which forms salts with acids. (c) It liberates nitrogen on treatment with ice-cold nitrous acid. (d) It can be prepared by the reduction of nitrobenzene with tin and HCl

Description : Which of the following statements is false about aniline? (a) It is a primary aromatic amine. (b) It is a weak base which forms salts with acids. (c) It liberates nitrogen on treatment with ice-cold nitrous acid. (d) It can be prepared by the reduction of nitrobenzene with tin and HCl

Last Answer : It liberates nitrogen on treatment with ice-cold nitrous acid

Reduction of p-nitrotoluene with Sn + HCl gives : (a) p-methylaniline (b) Toluene (c) m-methylaniline (d) N-Methylaniline

Description : Reduction of p-nitrotoluene with Sn + HCl gives : (a) p-methylaniline (b) Toluene (c) m-methylaniline (d) N-Methylaniline

Last Answer : p-methylaniline

Which of the following statements is False/Incorrect about nitrobenzene? (a) is formed by nitration of benzene at temperatures below 60°C. (b) can be further nitrated to give m-dinitrobenzene. (c) can be oxidized with KMnO4 to give benzoic acid. (d) can be reduced with Sn/HCl to give aniline.

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Last Answer : can be oxidized with KMnO4 to give benzoic acid

Which of the following reagents can be used to distinguish between chlorobenzene and allyl chloride? (a) H2/Ni(b) Br2 in CCl4(c) Zn/HCl(d) NH2NH2

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Last Answer : Br2 in CCl4

Cyclohexanol can be converted into cyclohexene by heating with (a) Zn(Hg) and HCl(b) Concentrated H2SO4(c) SOCl2(d) H2 and Ni

Description : Cyclohexanol can be converted into cyclohexene by heating with (a) Zn(Hg) and HCl (b) Concentrated H2SO4 (c) SOCl2 (d) H2 and Ni

Last Answer : Concentrated H2SO4

A primary amine can be identified by using (a) HCl (b) CHCl3 (c) NaOH (d) CHCl3 + KOH

Description : A primary amine can be identified by using (a) HCl (b) CHCl3 (c) NaOH (d) CHCl3 + KOH

Last Answer : CHCl3 + KOH

Ethyl acetoacetate undergoes acid-hydrolysis with dilute HCl to form (a) Acetoacetic acid (b) Succinic acid (c) Acetic acid (d) Adipic acid

Description : Ethyl acetoacetate undergoes acid-hydrolysis with dilute HCl to form (a) Acetoacetic acid (b) Succinic acid (c) Acetic acid (d) Adipic acid

Last Answer : Acetoacetic acid

Which of the following compounds does not form a salt with dilute HCl? (a) CH3CH2CONH2 (b) (CH3CH2)2NH (c) CH3CH2NH2 (d) (CH3CH2)3N

Description : Which of the following compounds does not form a salt with dilute HCl? (a) CH3CH2CONH2 (b) (CH3CH2)2NH (c) CH3CH2NH2 (d) (CH3CH2)3N

Last Answer : CH3CH2CONH2

Which of the following reagents will convert acetic acid into acetyl chloride? (a) NaCl (b) HCl/ZnCl2 (c) SOCl2 (d) HCl

Description : Which of the following reagents will convert acetic acid into acetyl chloride? (a) NaCl (b) HCl/ZnCl2 (c) SOCl2 (d) HCl

Last Answer : SOCl2

Acetone undergoes reduction with zinc amalgam in HCl to form propane. This reaction is known as (a) Clemmensen reduction (b) Wolf-Kishner reduction (c) Rosenmund reduction(d) Aldol condensation

Description : Acetone undergoes reduction with zinc amalgam in HCl to form propane. This reaction is known as (a) Clemmensen reduction (b) Wolf-Kishner reduction (c) Rosenmund reduction (d) Aldol condensation

Last Answer : Clemmensen reduction

Isopropyl alcohol can be converted to acetone by treatment with (a) HCl/ZnCl2 (b) Na2Cr2O7/H2SO4 (c) NaOH (d) LiAlH4

Description : Isopropyl alcohol can be converted to acetone by treatment with (a) HCl/ZnCl2 (b) Na2Cr2O7/H2SO4 (c) NaOH (d) LiAlH4

Last Answer : Na2Cr2O7/H2SO4

Lucas reagents is (a) HCl/NaNO2 (b) H2/Pd (c) HCl/ZnCl2 (d) H2/Pd/BaSO4

Description : Lucas reagents is (a) HCl/NaNO2 (b) H2/Pd (c) HCl/ZnCl2 (d) H2/Pd/BaSO4

Last Answer : HCl/ZnCl2

Which of the following reagents cannot be used to prepare an alkyl chloride from an alcohol? (a) HCl + ZnCl2 (b) SOCl2 (c) NaCl (d) PCl5

Description : Which of the following reagents cannot be used to prepare an alkyl chloride from an alcohol? (a) HCl + ZnCl2 (b) SOCl2 (c) NaCl (d) PCl5

Last Answer : NaCl

Predict which of the following alkenes reacts the fastest with HCl? (a) CH3CH2CH2CH2CH=CH2 (b) cis-CH3CH2CH=CHCH2CH3 (c) trans-CH3CH2CH=CHCH2CH3 (d) (CH3)2C=CHCH2CH3

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Last Answer : (CH3)2C=CHCH2CH3

Addition of HCl to 3-methyl-1-pentene gives two products. One of these is 2-chloro-3-methylpentane. What is the other product? (a) 1-Chloro-3-methylpentane (b) 3-Chloro-3-methylpentane (c) 3-Chloro-2-methylpentane (d) 2-Chloro-2-methylpentane

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Last Answer : 3-Chloro-3-methylpentane

Addition of two moles of HCl to propyne gives : (a) 2,2-Dichloropropane (b) 1,3-Dichloropropane (c) 1,2-Dichloropropane (d) None of these

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Last Answer : 2,2-Dichloropropane

Lindlar's catalyst is(a) LiAlH4(b) Pd/BaSO4 in Quinoline(c) NH2NH2(d) HCl/ZnCl

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Last Answer : C-1

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Description : Baeyer's reagent is (a) dilute KMnO4 (b) HCl + ZnCl2 (c) Br2 in CCl4 (d) NH2NH2

Last Answer : dilute KMnO4