what is the correct truth table for -p-> -q?

what is the correct truth table for -p-> -q?
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what is the correct truth table for p V -q?

Description : what is the correct truth table for p V -q?

Last Answer : what is the correct truth table for p V~ q

Match the following `{:(,,"Table-1",,"Table-2"),(,(A),L,(P),[M^(0)L^(0)T^(-2)]),(,(B),"Magnetic Flux",(Q),[ML^(2)T^(-2)A^(-1)]),(,(C),LC,(R),[ML^(2)T^

Description : Match the following `{:(,,"Table-1",,"Table-2"),(,(A),L,(P),[M^(0)L^(0)T^(-2)]),(,(B),"Magnetic Flux",(Q),[ML^(2)T^(-2)A^(-1)]),(,(C),LC,(R),[ML^(2)T^

Last Answer : Match the following `{:(,,"Table-1",,"Table-2"),(,(A),L,(P),[M^(0)L^(0)T^(-2)]),(,(B),"Magnetic Flux",(Q) ... (-2)A^(-2)]),(,(D),CR^(2),(S),"None"):}`

The table gives the populations (in thousands) of ten species (A-J) in four areas (p-s) consisting of the number of habitats given within brackets against each. Study the table and answer the question which follows. Which area out of p - s shows maximum species diversity? (a) s (b) p (c) q (d) r

Description : The table gives the populations (in thousands) of ten species (A-J) in four areas (p-s) consisting of the number of habitats given within brackets against each. Study the table and answer the question which follows. ... out of p - s shows maximum species diversity? (a) s (b) p (c) q (d) r

Last Answer : (a) s

What is Minterm in Truth Table ?

Description : What is Minterm in Truth Table ?

Last Answer : : The value of the variables in a given row of a true table is only the value for which the output of the Boolean sum is 1 is called the minterm of that particular row. For example , if a true table has three inputs A, B, C and the value of ABC is 1 , then this would be a minterm of ABC .

What is Truth Table ?

Description : What is Truth Table ?

Last Answer : A table with input / output symbols of logic gates is called a table.

Why is the Truth Table used ?

Description : Why is the Truth Table used ?

Last Answer : Truth table is used to display the input and output of the gate.

Which set of truth table input signals will result in an output signal value of 1 from the 'AND' gate as shown in the illustration? EL-0035 A. 1-Jan B. Jan-00 C. 0-1 D. 0-0

Description : Which set of truth table input signals will result in an output signal value of 1 from the 'AND' gate as shown in the illustration? EL-0035 A. 1-Jan B. Jan-00 C. 0-1 D. 0-0

Last Answer : Answer: A

As shown in the illustration, which set of truth table input signals will result in an output signal at point 'Y'? EL-0035 A. 0-0 B. 0-1 C. Jan-00 D. 1-Jan

Description : As shown in the illustration, which set of truth table input signals will result in an output signal at point 'Y'? EL-0035 A. 0-0 B. 0-1 C. Jan-00 D. 1-Jan

Last Answer : Answer: D

What type of logic circuit is indicated by the truth table shown in the illustration? EL-0072 A. OR B. AND C. NOR D. NAND

Description : What type of logic circuit is indicated by the truth table shown in the illustration? EL-0072 A. OR B. AND C. NOR D. NAND

Last Answer : Answer: A

Simplified Boolean equation for the following truth table is: Image(A) F = yz’ + y’z (B) F = xy’ + x’y (C) F = x’z + xz’ (D) F = x’z + xz’ + xyz

Description : Simplified Boolean equation for the following truth table is: (A) F = yz’ + y’z (B) F = xy’ + x’y (C) F = x’z + xz’ (D) F = x’z + xz’ + xyz 

Last Answer : (C) F = x’z + xz’ 

Function of OR Gate its logical symbol and truth table.

Description : Function of OR Gate its logical symbol and truth table.

Last Answer : Function: - OR gate is used to perform logical addition. So used in adder subtractor and logic circuits where logical Oring is required. Used to implement SOP form equations. Also used in PLA logic. Logical symbol of OR gate :- Truth table:- 

Define multiplexer. Draw logical symbol of 4:1 multiplexer with truth table and output logical equation

Description : Define multiplexer. Draw logical symbol of 4:1 multiplexer with truth table and output logical equation

Last Answer : Multiplexer - it is a combinational circuit which selects one input from several inputs and connects it to the output.  It is a circuit which has N-input and single output is called as multiplexer.

State Demorgan's theorem's and prove both theorems using truth table.

Description : State Demorgan's theorem's and prove both theorems using truth table.

Last Answer : De Morgan's 1st theorem states that when the OR sum of two variables is inverted, this is the same as inverting each variable individually and then ANDing these inverted variables. De Morgan's 2nd ... individually and then ORing them. In Boolean equation form it can be written as

Describe block diagram of digital comparator and write truth table of 2 bit comparator.

Description : Describe block diagram of digital comparator and write truth table of 2 bit comparator.

Last Answer : Digital comparator is a combinational circuit which compares two numbers, A and B; and evaluates their relative magnitudes. The outcome of the comparison is given by three binary variables which indicate whether A ... Depending on the result of comparison one of these outputs will go high.

Draw logic diagram of T flip-flop and give its truth table.

Description : Draw logic diagram of T flip-flop and give its truth table.

Last Answer : Logic Diagram:  

Draw the symbol, logic expression and truth table of NOR gate.

Description : Draw the symbol, logic expression and truth table of NOR gate.

Last Answer : symbol, logic expression and truth table of NOR gate

The sum of product expression for a Boolean function can be derived from its truth table by

Description : The sum of product expression for a Boolean function can be derived from its truth table by (a) AND operation of the product terms. (b) NOR operation of the product terms. (c) OR operation of the product terms. (d) NAND operation of the product terms.

Last Answer : C. OR operation of the product terms

An OR gate has 6 inputs. The number of input words in its truth table are

Last Answer : An OR gate has 6 inputs. The number of input words in its truth table are 64.

Consider the table Student(stuid, name, course, marks). Which one of the following two queries is correct to find the highest marks student in course 5? Q.1. Select S.stuid From student S Where not exists (select * from student e where e course='5' and e marks ≥ s marks) Q.2. Select S.stuid From student S Where s.marks > any (select distinct marks from student S where s.couse = 5) (A) Q.1 (B) Q.2 (C) Both Q.1 and Q.2 (D) Neither Q.1 nor Q.2

Description : Consider the table Student(stuid, name, course, marks). Which one of the following two queries is correct to find the highest marks student in course 5? Q.1. Select S.stuid From student S Where not exists (select * from student ... ) Q.1 (B) Q.2 (C) Both Q.1 and Q.2 (D) Neither Q.1 nor Q.2

Last Answer : (B) Q.2 Explanation: First query gives stuid of students whose marks are greater than all students taking course 5. Second query gives stuid of students whose marks are greater than any student taking ... comparison is between maximum of marks by any student in course 5. So the answer is option D.

Let P(m,n) be the statement “m divides n” where the Universe of discourse for both the variables is the set of positive integers. Determine the truth values of the following propositions. (a) ∃m ∀n P(m,n) (b) ∀n P(1,n) (c) ∀m ∀n P(m,n) (A) (a)-True; (b)-True; (c)-False (B) (a)-True; (b)-False; (c)-False (C) (a)-False; (b)-False; (c)-False (D) (a)-True; (b)-True; (c)-True

Description : Let P(m,n) be the statement m divides n where the Universe of discourse for both the variables is the set of positive integers. Determine the truth values of the following propositions. (a) ∃m ∀n P(m,n) (b) ∀n P(1,n) ( ... -False (C) (a)-False; (b)-False; (c)-False (D) (a)-True; (b)-True; (c)-True

Last Answer : Answer: A

If x^3 + px + q and x^3 + qx + p have a common factor, then which of the following is correct ? -Maths 9th

Description : If x^3 + px + q and x^3 + qx + p have a common factor, then which of the following is correct ? -Maths 9th

Last Answer : x3+px+q 3x2+p have common root Let common root =a a3+ap+q=0 a2=3−p​a=3−p​​4p3+27q2=? a3(a2+p)+q=0 ⇒3−p​​[(3−p​)+p]+q=0 3−p​​(3+2p​)=−q ⇒27−p(4p2)​=q2

Match the columns and choose the correct options `{:(,I,,II),((p),"e-waste",(i),"Waste clothing"),((q),"Biodegradable waste",(ii),"Dirt"),((r),"Inert

Description : Match the columns and choose the correct options `{:(,I,,II),((p),"e-waste",(i),"Waste clothing"),((q),"Biodegradable waste",(ii),"Dirt"),((r),"Inert

Last Answer : Match the columns and choose the correct options `{:(,I,,II),((p),"e-waste",(i),"Waste clothing"),((q)," ... iv,r-I,s-ii D. p-iv,q-iii,r-I,s-ii

Match the column and find correct combination: `{:(,"Column I",,"Column II"),((a),"Drawub",p,"Mutation theory"),((b),"De Vries",q,"Protobiosis"),((c),

Description : Match the column and find correct combination: `{:(,"Column I",,"Column II"),((a),"Drawub",p,"Mutation theory"),((b),"De Vries",q,"Protobiosis"),((c),

Last Answer : Match the column and find correct combination: `{:(,"Column I",,"Column II"),((a),"Drawub",p,"Mutation theory"),((b), ... q, d=p D. a=r, b=t, c=p, d=q

Consider the follwing complexes ion `P,Q` and `R` `P =[FeF_(6)]^(3-), Q=[V(H_(2)O)_(6)]^(2+)` and `R=[Fe(H_(2)O)_(6)]^(2+)` The correct order of the c

Description : Consider the follwing complexes ion `P,Q` and `R` `P =[FeF_(6)]^(3-), Q=[V(H_(2)O)_(6)]^(2+)` and `R=[Fe(H_(2)O)_(6)]^(2+)` The correct order of the c

Last Answer : Consider the follwing complexes ion `P,Q` and `R` `P =[FeF_(6)]^(3-), Q=[V(H_(2)O)_(6)]^(2+)` and `R=[Fe( ... lt P` C. `R lt P lt Q` D. `Q lt P lt R`

`P+Q rarr Anisol e overset(HI)rarrR+S` Correct statement among the following is

Description : `P+Q rarr Anisol e overset(HI)rarrR+S` Correct statement among the following is

Last Answer : `P+Q rarr Anisol e overset(HI)rarrR+S` Correct statement among the following is A. P and Q are `C_(6)H_(5)` ... Q are `C_(6)H_(5)C1` and `CH_(3)` Ona

In the following diagram, the path of a ray of light passing through a glass prism is shown: In this diagram the angle of incidence, the angle of emergence and the angle of deviation respectively are (select the correct option): (a) X, R and T (b) Y, Q and T (c) X, Q and P (d) Y, Q and P

Description : In the following diagram, the path of a ray of light passing through a glass prism is shown: In this diagram the angle of incidence, the angle of emergence and the angle of deviation respectively are (select the correct option): (a) X, R and T (b) Y, Q and T (c) X, Q and P (d) Y, Q and P

Last Answer : (d) Y, Q and P

Eight persons P, Q, R, S, W, X, Y and Z in which 4 females are facing towards and 4 males facing away from the center. Males and females are seated alternately. I. X is male, W position is 3rd to the right of X and exactly opposite to Q. II. P is 2nd to the left of W. III. S and R are facing each other as well R & Y are neighbors. Which of the following is correct for neighbors? a) X, W b) R, X c) S, W d) P, S

Description : Eight persons P, Q, R, S, W, X, Y and Z in which 4 females are facing towards and 4 males facing away from the center. Males and females are seated alternately. I. X is male, W position is 3rd to the right of X ... . Which of the following is correct for neighbors? a) X, W b) R, X c) S, W d) P, S

Last Answer : Ans: option (d)

Image P shows a portion of a larger photograph. Some operations have been done on that photograph using an image manipulation software. Image Q shows a portion of the resulting photograph. Identify the option(s) that specifies/specify the correct operations.

Description : Image P shows a portion of a larger photograph. Some operations have been done on that photograph using an image manipulation software. Image Q shows a portion of the resulting photograph. Identify ... D. Rotate clockwise by 90 degrees, flip horizontally, then rotate clockwise by 45 degrees 

Last Answer : A C

How much energy is required to vaporize kg of aluminum use the table below and this equation Q equals ml vapor?

Description : How much energy is required to vaporize kg of aluminum use the table below and this equation Q equals ml vapor?

Last Answer : 2200 kj

How much energy is required to vaporize kg of aluminum use the table below and this equation Q equals ml vapor?

Description : How much energy is required to vaporize kg of aluminum use the table below and this equation Q equals ml vapor?

Last Answer : 2200 kj

Q.What is the major advantage of a hash table?

Description : Q.What is the major advantage of a hash table?

Last Answer : The major advantage of a hash table is its speed. Because the hash function is to take a range of key values and transform them into index values in such a way that the key values are distributed randomly across all the indices of a hash table.

Select the correct statement from the ones given below. (a) Barbiturates, when given to criminals, make them tell the truth. (b) Morphine is often given to persons, who have undergone surgery, as a pain killer. (c) Chewing tobacco lowers blood pressure and heart rate. (d) Cocaine is given to patients after surgery as it stimulates recovery.

Description : Select the correct statement from the ones given below. (a) Barbiturates, when given to criminals, make them tell the truth. (b) Morphine is often given to persons, who have undergone surgery, ... pressure and heart rate. (d) Cocaine is given to patients after surgery as it stimulates recovery.

Last Answer : (b) Morphine is often given to persons, who have undergone surgery, as a pain killer.

In Epistemology, the following problem can be solved Options: A) What is known to the brain beyond the knowledge of its own ideas B) How do the knowledge 'becomes objective as well as subjective simultaneously C) What is the criteria of judgement of Truth and False D) All the above are correct

Description : In Epistemology, the following problem can be solved Options: A) What is known to the brain beyond the knowledge of its own ideas B) How do the knowledge 'becomes objective as well as subjective simultaneously C) What is the criteria of judgement of Truth and False D) All the above are correct

Last Answer : D) All the above are correct 

I want to put "S.P.Q.R." on something. Any suggestions?

Description : I want to put "S.P.Q.R." on something. Any suggestions?

Last Answer : Put it in your profile.

Match the following: NC code DefinitionP. M05 1. Absolute coordinate system Q. G01 2. Dwell R. G04 3. Spindle stop S. G09 4. Linear interpolation a.P-2, Q-3, R-4, S-1 b.P-3, Q-4, R-1, S-2 c.P-3, Q-4, R-2, S-1 d.P-4, Q-3, R-2, S-1

Description : Match the following: NC code DefinitionP. M05 1. Absolute coordinate system Q. G01 2. Dwell R. G04 3. Spindle stop S. G09 4. Linear interpolation a.P-2, Q-3, R-4, S-1 b.P-3, Q-4, R-1, S-2 c.P-3, Q-4, R-2, S-1 d.P-4, Q-3, R-2, S-1

Last Answer : c.P-3, Q-4, R-2, S-1

When two concurrent and coplaner forces P and Q act at an angle of 180?, their resultant will be a a.moment equal to PQ b.couple c.(P-Q) d.107 dynes e.zero

Description : When two concurrent and coplaner forces P and Q act at an angle of 180?, their resultant will be a a.moment equal to PQ b.couple c.(P-Q) d.107 dynes e.zero

Last Answer : c. (P-Q)

Write the given sets in roster form: (a). P = {y: y is an integer and -4 < y < 6}. (b). Q = {y: y is a natural number which is <8} (c). R = {y: y is a 2 digit natural number in which the sum of its digits is 9} -Other

Description : Write the given sets in roster form: (a). P = {y: y is an integer and -4 < y < 6}. (b). Q = {y: y is a natural number which is

Last Answer : (i) A = {x: x is an integer and †3 < x < 7} The elements of this set are †2, †1, 0, 1, 2, 3, 4, 5, and 6 only. Therefore, the given set can be written in roster form as A = {†2, †... and 80 only. Therefore, this set can be written in roster form as C = {17, 26, 35, 44, 53, 62, 71, 80}}.

3. ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus. -Maths 9th

Description : 3. ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus. -Maths 9th

Last Answer : Solution: Given in the question, ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Construction, Join AC and BD. To Prove, PQRS is a rhombus. Proof: In ΔABC P and Q ... (ii), (iii), (iv) and (v), PQ = QR = SR = PS So, PQRS is a rhombus. Hence Proved

2. ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rectangle. -Maths 9th

Description : 2. ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rectangle. -Maths 9th

Last Answer : Solution: Given in the question, ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. To Prove, PQRS is a rectangle. Construction, Join AC and BD. Proof: In ΔDRS and ... , In PQRS, RS = PQ and RQ = SP from (i) and (ii) ∠Q = 90° , PQRS is a rectangle.

ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see Fig 8.29). AC is a diagonal. Show that: (i) SR || AC and SR = 1/2 AC (ii) PQ = SR (iii) PQRS is a parallelogram. -Maths 9th

Description : ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see Fig 8.29). AC is a diagonal. Show that: (i) SR || AC and SR = 1/2 AC (ii) PQ = SR (iii) PQRS is a parallelogram. -Maths 9th

Last Answer : . Solution: (i) In ΔDAC, R is the mid point of DC and S is the mid point of DA. Thus by mid point theorem, SR || AC and SR = ½ AC (ii) In ΔBAC, P is the mid point of AB and Q is the mid point of BC. ... ----- from question (ii) ⇒ SR || PQ - from (i) and (ii) also, PQ = SR , PQRS is a parallelogram.

Express 1.27 bar in p/q form. -Maths 9th

Description : Express 1.27 bar in p/q form. -Maths 9th

Last Answer : (1) x = 1.2727272727......... (2) 100x = 127.27272727......... From subtracting (1) and (2 ) We get : 99x = 126.0000000 x = 126/99 = 14/11.

Points P and Q have been taken on opposite sides AB and CD, respectively of a parallelogram ABCD such that AP = CQ . -Maths 9th

Description : Points P and Q have been taken on opposite sides AB and CD, respectively of a parallelogram ABCD such that AP = CQ . -Maths 9th

Last Answer : Join AQ and PC . Since ABCD is a parallelogram . ⇒ AB | | DC ⇒ AP | | QC ∵ AP and QC are parts of AB and DC respectively] Also, AP = CQ [given] Thus, APCQ is a parallelogram . We know that diagonals of a parallelogram bisect each other . Hence AC and PQ bisect each other .

l, m and n are three parallel lines intersected by transversals p and q such that l, m and n cut off equal intercepts AB and BC on p (see figure). -Maths 9th

Description : l, m and n are three parallel lines intersected by transversals p and q such that l, m and n cut off equal intercepts AB and BC on p (see figure). -Maths 9th

Last Answer : Though E, draw a line parallel to p intersecting L at G and n at H respectively. Since l | | m ⇒ AG | | BE and AB | | GE [by construction] ∴ Opposite sides of quadrilateral AGEB are ... ∠DGE = ∠FHE [alternate interior angles] By ASA congruence axiom, we have △DEG ≅ △FEH Hence, DE = EF

P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Description : P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Last Answer : (i) In △ARB,P is the mid point of AB and PD || BR. ∴ D is a mid - point of AR [converse of mid - point theorem] ∴ AR = 2AD But BC = AD [opp sides of ||gm ABCD] Thus, AR = 2BC (ii) ∴ ABCD is a ... a mid - point of AR and DQ || AB ∴ Q is a mid point of BR [converse of mid - point theorem] ⇒ BR = 2BQ

If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Description : If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Last Answer : Join PR. ∵ △PSR and ||gm APRD are on the same base and between same parallel lines. ar(△PSR) = 1/2 ar(||gm APRD) Similarly, ar(△PQR) = 1/2 ar(||gm PBCR) ar(△PQRS) = ar(△PSR) + △(PQR) = 1/2 ar(||gm APRD) + 1 ... |gm PBCR) = 1/2 ar(||gm ABCD) ⇒ ar(||gm ABCD) = 2 ar(||gm PQRS) = 2 32.5 = 65cm2

A farmer was having a field in the form of a parallelogram PQRS. She took any point A on RS and joined it to points P and Q. In how many parts the field is divided ? -Maths 9th

Description : A farmer was having a field in the form of a parallelogram PQRS. She took any point A on RS and joined it to points P and Q. In how many parts the field is divided ? -Maths 9th

Last Answer : From the adjoining figure, we have The field PQRS is divided into three parts △PAQ, △APS and △AQR. Now, △PAQ and ||gm PQRS are on the same base and lie between the same parallels. ∴ ar(△PAQ) = 1 / 2 ar(||gm ... , she can sow wheat in △APS and △AQR, pulses in △PAQ or vice - versa .

The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q, then parallelogram PBQR is completed (see figure). -Maths 9th

Description : The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q, then parallelogram PBQR is completed (see figure). -Maths 9th

Last Answer : Join AC and QP, also it is given that AQ || CP ∴ △ACQ and △APQ are on the same base AQ and lie between the same parallels AQ || CP. ∴ ar(△ACQ) = ar(△APQ) or ar(△ABC) + ar(△ABQ) = ar(△BPQ) + ar(△ABQ) or ar(△ABC) = ar( △BPQ) or 1/2 ar(||gm ABCD) = 1/2 ar(||gm PBQR) or ar(||gm ABCD) = ar(||gm PBQR)

In the given figure, ABCD is a square. Side AB is produced to points P and Q in such a way that PA = AB = BQ. Prove that DQ = CP. -Maths 9th

Description : In the given figure, ABCD is a square. Side AB is produced to points P and Q in such a way that PA = AB = BQ. Prove that DQ = CP. -Maths 9th

Last Answer : In △PAD, ∠A = 90° and DA = PA = PB ⇒ ∠ADP = ∠APD = 90° / 2 = 45° Similarly, in △QBC, ∠B = 90° and BQ = BC = AB ⇒∠BCQ = ∠BQC = 90° / 2 = 45° In △PAD and △QBC , we have PA = QB [given] ∠A = ... [each = 90° + 45° = 135°] ⇒ △PDC = △QCD [by SAS congruence rule] ⇒ PC = QD or DQ = CP