what is 56 x 23?

what is 56 x 23?
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1288
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Since there are 23 Hours, 56 Minuets & 4.1 Seconds in a day, what happens to the extra 3 Minuets & 56.9 Seconds?

Description : Since there are 23 Hours, 56 Minuets & 4.1 Seconds in a day, what happens to the extra 3 Minuets & 56.9 Seconds?

Last Answer : shut down

How many 23 go in 56?

Description : How many 23 go in 56?

Last Answer : 23 goes into 56 2 times

The earth completes one rotation on its axis in : (1) 23 hrs. 56 min. 4.9 sec (2) 23 hrs. 10 min. 2 sec (3) 23 hrs. 30 min. (4) 24 hrs.

Description : The earth completes one rotation on its axis in : (1) 23 hrs. 56 min. 4.9 sec (2) 23 hrs. 10 min. 2 sec (3) 23 hrs. 30 min. (4) 24 hrs.

Last Answer : (1) 23 hrs. 56 min. 4.9 sec Explanation: The Earth rotates around its axis once in about 24 hours with respect to the sun and once every 23 hours 56 minutes and 4 seconds with respect to the stars. The Earth rotates from the west towards east. Seasons are caused by Earth's rotation around its axis.

Which of the following couldnot be an Ethernet multicast destination? A) B7:7B:6C:DE:10:00 B) 7B:AA:C1:23:45:32 C) 7C:56:21:1A:DE:F4 D) 83:32:21:21:4D:34

Description : Which of the following couldnot be an Ethernet multicast destination? A) B7:7B:6C:DE:10:00 B) 7B:AA:C1:23:45:32 C) 7C:56:21:1A:DE:F4 D) 83:32:21:21:4D:34

Last Answer : 7C:56:21:1A:DE:F4

Which of the following couldnot be an Ethernet unicast destination? A) 43:7B:6C:DE:10:00 B) 44:AA:C1:23:45:32 C) 46:56:21:1A:DE:F4 D) 48:32:21:21:4D:34

Description : Which of the following couldnot be an Ethernet unicast destination? A) 43:7B:6C:DE:10:00 B) 44:AA:C1:23:45:32 C) 46:56:21:1A:DE:F4 D) 48:32:21:21:4D:34

Last Answer : 43:7B:6C:DE:10:0

Number of human live lost during 1980-2010 due to natural and induced hazards in India? a. 1,42,265 b. 1,56,897 c. 1,43,039 d. 1,23,987

Description : Number of human live lost during 1980-2010 due to natural and induced hazards in India? a. 1,42,265 b. 1,56,897 c. 1,43,039 d. 1,23,987

Last Answer : c. 1,43,039

Calculate the attenuation constant of a conductor of conductivity 200 units, frequency 1M radian/s in air. a) 11.2 b) 1.12 c) 56.23 d) 5.62

Description : Calculate the attenuation constant of a conductor of conductivity 200 units, frequency 1M radian/s in air. a) 11.2 b) 1.12 c) 56.23 d) 5.62

Last Answer : a) 11.2

The earth completes one rotation on its axis in : (1) 23 hrs. 56 min. 4.9 sec (2) 23 hrs. 10 min. 2 sec (3) 23 hrs. 30 min. (4) 24 hrs.

Description : The earth completes one rotation on its axis in : (1) 23 hrs. 56 min. 4.9 sec (2) 23 hrs. 10 min. 2 sec (3) 23 hrs. 30 min. (4) 24 hrs.

Last Answer : 23 hrs. 56 min. 4.9 sec

If 7:15=56:x, then what is the value of x?

Description : If 7:15=56:x, then what is the value of x?

Last Answer : If 7:15=56:x, then what is the value of x?

What is 56 x 36?

Description : What is 56 x 36?

Last Answer : Use your calculator b*tch

H2S is being absorbed in a gas absorber unit. The height of the transfer unit based on the overall mass transfer coefficient on the gas side is 0.4 m. The equilibrium data is given by, y = 1.5 x. The bulk concentration of H2S has to be reduced from 0.05 to 0.001 mole fraction in the gas side. The height of the tower (in metres) corresponding to an operating line given by, y = 5x + 0.001 is (A) 2.0 (B) 1.56 (C) 1.0

Description : H2S is being absorbed in a gas absorber unit. The height of the transfer unit based on the overall mass transfer coefficient on the gas side is 0.4 m. The equilibrium data is given by, y = 1.5 x. The bulk concentration of H2S ... by, y = 5x + 0.001 is (A) 2.0 (B) 1.56 (C) 1.0

Last Answer : (A) 2.0

There are 312, 260 and 156 students in class X, XI and XII respectively. Buses are to be hired to take these students to a picnic. Find the maximum number of students who can sit in a bus if each bus takes equal number of students (a) 52 (b) 56 (c) 48 (d) 63

Description : There are 312, 260 and 156 students in class X, XI and XII respectively. Buses are to be hired to take these students to a picnic. Find the maximum number of students who can sit in a bus if each bus takes equal number of students (a) 52 (b) 56 (c) 48 (d) 63

Last Answer : (a) 52

Find the pressure due to a column of mercury 74.0 cm high.  a. 91.80 x 10^3 N/m^2  b. 73.56 x 10^2 N/m^2  c. 9.86 x 10^4 N/m^2  d. 87.2 x 10^4 N/m^2

Description : Find the pressure due to a column of mercury 74.0 cm high.  a. 91.80 x 10^3 N/m^2  b. 73.56 x 10^2 N/m^2  c. 9.86 x 10^4 N/m^2  d. 87.2 x 10^4 N/m^2

Last Answer : 9.86 x 10^4 N/m^2

19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)

34.8% x 950 – 33.2% of 850 = ? a) 58.4 b) 48.4 c) 56.4 d) 68.9 e) 76.3

Description : 34.8% x 950 – 33.2% of 850 = ? a) 58.4 b) 48.4 c) 56.4 d) 68.9 e) 76.3

Last Answer : 34.8% x 950 – 33.2% of 850 = ? Sol: 0.348 x 950 – 0.332 x 850=? 330.6 – 282.2=? ?= 48.4 Answer: b)

An animal drawn seed drill has k number of furrow openers 180mm apart. If the speed of operation is 2.0kmph, the area covered (ha), in 8-11day is given by: A. 1.85/1000k B. 28.8 x 10-2k C. k/6.56 D. 1.762k

Description : An animal drawn seed drill has k number of furrow openers 180mm apart. If the speed of operation is 2.0kmph, the area covered (ha), in 8-11day is given by: A. 1.85/1000k B. 28.8 x 10-2k C. k/6.56 D. 1.762k

Last Answer : B. 28.8 x 10-2k

The acceleration due to gravity on the moon is 1.6 meters per second squared. If a pendulum is whose length is 6.4 meters is placed on the moon, its period will be: w) 1.57 seconds x) 3.14 seconds y) 12.56 seconds z) 25.12 seconds

Description : The acceleration due to gravity on the moon is 1.6 meters per second squared. If a pendulum is whose length is 6.4 meters is placed on the moon, its period will be: w) 1.57 seconds x) 3.14 seconds y) 12.56 seconds z) 25.12 seconds

Last Answer : not real

X invested 13% more than Y's investment. Y invested 18% less than investment of Z. X's investment is what percent of investment made by both Y and Z? A) 47.5. B) 50.9. C) 56.5 D) None

Description : X invested 13% more than Y's investment. Y invested 18% less than investment of Z. X's investment is what percent of investment made by both Y and Z? A) 47.5. B) 50.9. C) 56.5 D) None

Last Answer : Answer: B)  Let investment of Z be 100%  Let Y’s investment is 82%  Also A’s investment is 92.66%  Required % =92.66/182*100= 50.9%