If 7:15=56:x, then what is the value of x?

If 7:15=56:x, then what is the value of x?
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If 7:15=56:x, then what is the value of x?
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A sample of natural gas containing 80% methane (CH4 ) and rest nitrogen (N2 ) is burnt with 20% excess air. With 80% of the combustibles producing CO2 and the remainder going to CO, the Orsat analysis in volume percent is (A) CO2 : 6.26, CO : 1.56, O2 : 3.91, H2O :15.66, N2 : 72.60 (B) CO2 : 7.42, CO : 1.86, O2 : 4.64, N2 :86.02 (C) CO2 : 6.39, CO : 1.60, O2 : 3.99, H2O:25.96, N2 :72.06 (D) CO2 : 7.60, CO : 1.90, O2 : 4.75, N2 : 85.74

Description : A sample of natural gas containing 80% methane (CH4 ) and rest nitrogen (N2 ) is burnt with 20% excess air. With 80% of the combustibles producing CO2 and the remainder going to CO, the Orsat analysis in volume percent is (A) CO2 : 6 ... 96, N2 :72.06 (D) CO2 : 7.60, CO : 1.90, O2 : 4.75, N2 : 85.74

Last Answer : (B) CO2 : 7.42, CO : 1.86, O2 : 4.64, N2 :86.02

If one root of the quadratic equation `ax^(2) + bx + c = 0` is `15 + 2sqrt(56)` and `a,b` and c are rational, then find the quadratic equation.

Description : If one root of the quadratic equation `ax^(2) + bx + c = 0` is `15 + 2sqrt(56)` and `a,b` and c are rational, then find the quadratic equation.

Last Answer : If one root of the quadratic equation `ax^(2) + bx + c = 0` is `15 + 2sqrt(56)` and `a,b` and c are rational, then find the quadratic equation.

Compute the value of adding the following two fuzzy integers: A = {(0.3,1), (0.6,2), (1,3), (0.7,4), (0.2,5)} B = {(0.5,11), (1,12), (0.5,13)} Where fuzzy addition is defined as μA+B(z) = maxx+y=z (min(μA(x), μB(x))) Then, f(A+B) is equal to (A) {(0.5,12), (0.6,13), (1,14), (0.7,15), (0.7,16), (1,17), (1,18)} (B) {(0.5,12), (0.6,13), (1,14), (1,15), (1,16), (1,17), (1,18)} (C) {(0.3,12), (0.5,13), (0.5,14), (1,15), (0.7,16), (0.5,17), (0.2,18)} (D) {(0.3,12), (0.5,13), (0.6,14), (1,15), (0.7,16), (0.5,17), (0.2,18)}

Description : Compute the value of adding the following two fuzzy integers: A = {(0.3,1), (0.6,2), (1,3), (0.7,4), (0.2,5)} B = {(0.5,11), (1,12), (0.5,13)} Where fuzzy addition is defined as μA+B(z) = maxx+y=z (min(μA(x), μB( ... ,18)} (D) {(0.3,12), (0.5,13), (0.6,14), (1,15), (0.7,16), (0.5,17), (0.2,18)}

Last Answer : (D) {(0.3,12), (0.5,13), (0.6,14), (1,15), (0.7,16), (0.5,17), (0.2,18)} 

i weigh about 180 pounds im 5'6 size 15 jeans and im 16 years old how much should i weigh for my age and height?

Description : i weigh about 180 pounds im 5'6 size 15 jeans and im 16 years old how much should i weigh for my age and height?

Last Answer : 130-144 lbs according to this chart > http://www.buzzle.com/articles/height-weight-ratio-chart.html There is no safe fast way to lose weight. Diet and exercise. Walk, eun, swim. Eat foods ... the sweets, the sodas and sugary juice drinks. Eat smaller portions at meal time. Make fruit your dessert.

A car is travelling at 15 m s-1, the distance it will travel in 1 hour is A. 54 km B. 55 km C. 56 km D. 57 km

Description : A car is travelling at 15 m s-1, the distance it will travel in 1 hour is A. 54 km B. 55 km C. 56 km D. 57 km

Last Answer : 54 km

Find the magnetization of the field which has a magnetic moment 16 units in a volume of 1.2 units. a) 16.67 b) 13.33 c) 15.56 d) 18.87

Description : Find the magnetization of the field which has a magnetic moment 16 units in a volume of 1.2 units. a) 16.67 b) 13.33 c) 15.56 d) 18.87

Last Answer : b) 13.33

A car covers a distance of 1120 metres in 1 minute whereas a bus covers a distance of 56 kms in 44 minutes. What is the ratio of their speed? a) 22:25 b) 25:22 c) 11:15 d) 15:11

Description : A car covers a distance of 1120 metres in 1 minute whereas a bus covers a distance of 56 kms in 44 minutes. What is the ratio of their speed? a) 22:25 b) 25:22 c) 11:15 d) 15:11

Last Answer : A Speed of the Car = 1120 m/minute Speed of the bus=56 kms in 44 minutes =56/44 km/m =56000/44 m/mints Speed of the car : Speed of the bus, =1120:56000/44 =280:14000/44 =20:1000/44 =880:1000 =88:100 Required ratio =22:25

kajal rides his scooter 14km at an average speed of 16 km/hr and again travels 16km at an average speed of 14 km/hr. What is her average speed for the entire trip approximately? a) 15.36 km/hr b) 17.46 km/hr c) 13.56 km/hr d) 14.86 km/hr

Description : kajal rides his scooter 14km at an average speed of 16 km/hr and again travels 16km at an average speed of 14 km/hr. What is her average speed for the entire trip approximately? a) 15.36 km/hr b) 17.46 km/hr c) 13.56 km/hr d) 14.86 km/hr

Last Answer : D Total distance travelled =14+16=30Km Time taken to travel 14 km at an average speed of 16 km/hr =14/16=7/8 Hr Time taken to travel 16 km at an average speed of 14 km/hr =16/14=8/7 hr Total time taken = ... /Total time taken =30/(7/8+8/7) =30/(113/56) =30*56/113=1680/113 =14.86 km/hr

The average age of Mr and Mrs Rahim at the time of their marriage in 1981 was 56 yrs. On the occasion of their anniversary in 1986, they observed that the average age of their family had come down by 15 yrs compared to their age at the time of their marriage. This was due to the fact that their daughter varshini was born. What was the age of varshini in 1990? A) 6 B) 5 C) 4 D) 1

Description : The average age of Mr and Mrs Rahim at the time of their marriage in 1981 was 56 yrs. On the occasion of their anniversary in 1986, they observed that the average age of their family had come down by 15 yrs compared to ... varshini was born. What was the age of varshini in 1990? A) 6 B) 5 C) 4 D) 1

Last Answer : B) Sum of the ages of Mr and Mrs Rahim=56×2=112years Sum of the ages in 1986=41×3=123 years Sum of the ages of Mr and Mrs Rahim =112+10=122 Daughters age in 1986=123-122=1 years  Daughters age in 1990 =1+4=5 years.

Have you heard the news? 12:34:56 7 8 9?

Description : Have you heard the news? 12:34:56 7 8 9?

Last Answer : you’re missing the 2000 from the last number.

Two cars A and B race each other. The Car A ran for 2 minute at a speed of 7.5 km/h, slept for 56 minute and again ran for 2 minute at a speed of 7.5 km/h. find the average speed of the car A in the race. -Science

Description : Two cars A and B race each other. The Car A ran for 2 minute at a speed of 7.5 km/h, slept for 56 minute and again ran for 2 minute at a speed of 7.5 km/h. find the average speed of the car A in the race. -Science

Last Answer : We know that Distance=speed×timeDistance=speed×time Distance travelled in first 2 minute = 7.5×2607.5×260 = 0.25 km Distance travelled in last 2 minute = 7.5×2607.5×260= 0.25 km Total distance = .25+.25 = 0.5 km Total time = 2+2+56 = 60 minute = 1 hr Average speed = 0.5/1 = 0.5 km/hr

What is the unit rate of 4 pounds of green peppers costs 7.56?

Description : What is the unit rate of 4 pounds of green peppers costs 7.56?

Last Answer : What is the answer ?

What is 13/56 + 5/7 =?

Description : What is 13/56 + 5/7 =?

Last Answer : 30/56

In a solution having a pH of 7.4, the hydrogen ion concentration is (A) 7.4 nmol/L (B) 40 nmol/L (C) 56 nmol/L (D) 80 nmol/L

Description : In a solution having a pH of 7.4, the hydrogen ion concentration is (A) 7.4 nmol/L (B) 40 nmol/L (C) 56 nmol/L (D) 80 nmol/L

Last Answer : Answer : B

You are measuring noise in a voice channel at 7 dB test point level. The meter reads -56 dBm (FIA weighted). What is the reading in dBrnc? A. 20 B. 32 C. 35 D. 25

Description : You are measuring noise in a voice channel at 7 dB test point level. The meter reads -56 dBm (FIA weighted). What is the reading in dBrnc? A. 20 B. 32 C. 35 D. 25

Last Answer : C. 35

Find the torque of a loop with magnetic moment 12.5 and magnetic flux density 7.65 units is a) 95.625 b) 65.925 c) 56.525 d) 65.235

Description : Find the torque of a loop with magnetic moment 12.5 and magnetic flux density 7.65 units is a) 95.625 b) 65.925 c) 56.525 d) 65.235

Last Answer : a) 95.625

Calculate the energy in an electric field with permittivity of 56 and field intensity of 36π(in μJ) a) 3.16 b) 5.16 c) 7.16 d) 9.16

Description : Calculate the energy in an electric field with permittivity of 56 and field intensity of 36π(in μJ) a) 3.16 b) 5.16 c) 7.16 d) 9.16

Last Answer : a) 3.16

The maximum efficiency of transmission through a pipe is (A) 50 % (B) 56.7 %C) 66.67 % (D) 76.66 %

Description : The maximum efficiency of transmission through a pipe is (A) 50 % (B) 56.7 % C) 66.67 % (D) 76.66 %

Last Answer : Answer: Option C

The maximum comfortable retardation applied to moving vehicles, is (A) 3.42 m/sec2 (B) 4.42 m/sec2 (C) 5.56 m/sec2 (D) 7.80 m/sec2

Description : The maximum comfortable retardation applied to moving vehicles, is (A) 3.42 m/sec2 (B) 4.42 m/sec2 (C) 5.56 m/sec2 (D) 7.80 m/sec2

Last Answer : Answer: Option A

Reshma purchased 120 chairs at price of Rs. 110 per chair. He sold 30 chairsat a profit of Rs. 12 per chair and 75 chairs at profit of Rs. 14 per chairs. The remaining chairs were sold at a loss of Rs. 7 per chairs. What is the average profit per table? A. Rs 10.56 B. Rs 10.87 C. Rs 12.123 D. Rs 12.67

Description : Reshma purchased 120 chairs at price of Rs. 110 per chair. He sold 30 chairsat a profit of Rs. 12 per chair and 75 chairs at profit of Rs. 14 per chairs. The remaining chairs were sold at a loss of Rs. 7 per chairs ... the average profit per table? A. Rs 10.56 B. Rs 10.87 C. Rs 12.123 D. Rs 12.67 

Last Answer : Answer – B (Rs 10.875) Explanation – Total C.P = Rs. (120 x 110) =Rs. 13200. Total S.P = Rs.[(30 x 110 + 30 x 12) + (75 x 110 + 75 x 14) + (15 x 110 – 15 x 7) =Rs..14505 Average profit = Rs. (14505 – 13200) /120 = Rs. 1305/120= 10.875

On dividing a number by 56, we get 29 as remainder. On dividing the same number by 8, what is the remainder ? 1) 2 2) 3 3) 4 4) 5 5) 7

Description : On dividing a number by 56, we get 29 as remainder. On dividing the same number by 8, what is the remainder ? 1) 2 2) 3 3) 4 4) 5 5) 7

Last Answer : 4) 5

What is the value of 5 in 56.13?

Description : What is the value of 5 in 56.13?

Last Answer : 5/100

For the reaction `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` the value of `Delta H=30.56 KJ mol^(_1)` and `Delta S = 66 JK^(-1)mol^(-1)`. The temperature at

Description : For the reaction `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` the value of `Delta H=30.56 KJ mol^(_1)` and `Delta S = 66 JK^(-1)mol^(-1)`. The temperature at

Last Answer : For the reaction `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` the value of `Delta H=30.56 KJ mol^(_1)` and `Delta ... :- A. 373 K B. 413 K C. 463 K D. 493 K

What is the value of 5 in 56.13?

Description : What is the value of 5 in 56.13?

Last Answer : 5/100

In the equation 8b plus 4b 56 - 16b what is the value of b?

Description : In the equation 8b plus 4b 56 - 16b what is the value of b?

Last Answer : Without an equality sign the given expression is not an equationand so therefore no solution is possible.

What is the value of the 9 in the number 56.279 in fractions?

Description : What is the value of the 9 in the number 56.279 in fractions?

Last Answer : 9/1000

An excavator costs Rs. 20,00,000 and has an estimated life of 8 years. It has no salvage value at the end of 8 years. The book value of the excavator at the end of 3 years using general double declining balance method is (A) Rs. 8,43,750 (B) Rs. 8,75,000 (C) Rs. 10,50,000 (D) Rs. 11,56,250

Description : An excavator costs Rs. 20,00,000 and has an estimated life of 8 years. It has no salvage value at the end of 8 years. The book value of the excavator at the end of 3 years using general double declining balance method is (A) Rs. 8,43,750 (B) Rs. 8,75,000 (C) Rs. 10,50,000 (D) Rs. 11,56,250

Last Answer : (A) Rs. 8,43,750

What is the decimal value of 26? 56) A) 128 B) 36 C) 32 D) 64

Description : What is the decimal value of 26? A) 128 B) 36 C) 32 D) 64

Last Answer : D) 64

Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, 49, 50, 74, 75, 99,100 B. 10, 50, 75,100, 250, 1000 C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Description : Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, ... C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Last Answer : C. 0, 1,10,11, 50, 51, 75, 76,100,101

A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Description : A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Last Answer : since curved surface of half of the spherical ball = 56.57 cm2 ∴ 2πr2 = 56.57 ⇒ r2 = 56.57 / 2 × 3.14 = 9 ⇒ r = 3 cm Now, volume of spherical ball = 4 / 3 πr3 = 4 / 3 × 3.14 × 3 × 3 × 3 = 113.04 cm3

The median of the data 26,56,32,33,60,17,34,29,45 is 33. If 26 is replaced by 62, then find the new median. -Maths 9th

Description : The median of the data 26,56,32,33,60,17,34,29,45 is 33. If 26 is replaced by 62, then find the new median. -Maths 9th

Last Answer : Here, the given data in ascending order is 17, 29, 32, 33, 34, 45, 56, 60, 62 Now median is (9 + 1 / 2)th term i.e. , 5th term Hence, new median is 34.

A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Description : A spherical ball is divided into two equal halves. If the curved surface area of each half is 56.57 cm?, find the volume of the spherical ball.11531/cylinder-radius-halved-and-height-doubled-then-find-volume-with-respect-original-volume -Maths 9th

Last Answer : since curved surface of half of the spherical ball = 56.57 cm2 ∴ 2πr2 = 56.57 ⇒ r2 = 56.57 / 2 × 3.14 = 9 ⇒ r = 3 cm Now, volume of spherical ball = 4 / 3 πr3 = 4 / 3 × 3.14 × 3 × 3 × 3 = 113.04 cm3

The median of the data 26,56,32,33,60,17,34,29,45 is 33. If 26 is replaced by 62, then find the new median. -Maths 9th

Description : The median of the data 26,56,32,33,60,17,34,29,45 is 33. If 26 is replaced by 62, then find the new median. -Maths 9th

Last Answer : Here, the given data in ascending order is 17, 29, 32, 33, 34, 45, 56, 60, 62 Now median is (9 + 1 / 2)th term i.e. , 5th term Hence, new median is 34.

The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then, the area of the triangle is -Maths 9th

Description : The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then, the area of the triangle is -Maths 9th

Last Answer : The area of the triangle is

The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then, the area of the triangle is -Maths 9th

Description : The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then, the area of the triangle is -Maths 9th

Last Answer : The area of the triangle is

In the following reaction: `3Fe+4H_(2)OrarrFe_(3)O_(4)+4H_(2)`, if the atomic weight of iron is `56`, then its equivalent weight will be

Description : In the following reaction: `3Fe+4H_(2)OrarrFe_(3)O_(4)+4H_(2)`, if the atomic weight of iron is `56`, then its equivalent weight will be

Last Answer : In the following reaction: `3Fe+4H_(2)OrarrFe_(3)O_(4)+4H_(2)`, if the atomic weight of iron is `56`, then its equivalent weight will be

A wire can be bent to form a circle of radius 56 cm. if it is instead bent in the form of a square, then its area will be: a) 6400 sq.cm b) 2025 sq.cm c) 7744 sq.cm d) 6561 sq.cm e) none of these

Description : A wire can be bent to form a circle of radius 56 cm. if it is instead bent in the form of a square, then its area will be: a) 6400 sq.cm b) 2025 sq.cm c) 7744 sq.cm d) 6561 sq.cm e) none of these

Last Answer : Length of the wire = circumference of the circle 2 × (22/7) × 56 = 2 × 22 × 8 = 352 cm side of square = 352/4 = 88cm area of square = 88 × 88 = 7744 sq.cm Answer: c)

Five persons M, N, O, P and Q request a bank for safety lockers. There are only 6 lockers available which are numbered from 52 to 57. The conditions are as follows: I. M’s locker number is 2 less than O’s lockers number. II. Lockers of N and P are next to each other. 14. If Q’s locker number is 54 and N’s locker number is greater than Q’s locker number, then which locker number is not allocated? a) locker 52 b) locker 53 c) locker 54 d)locker 56

Description : Five persons M, N, O, P and Q request a bank for safety lockers. There are only 6 lockers available which are numbered from 52 to 57. The conditions are as follows: I. M's locker number is 2 less ... , then which locker number is not allocated? a) locker 52 b) locker 53 c) locker 54 d)locker 56

Last Answer : a) locker 52

The sum of three numbers is 210. If the ratio between the first and second number be 2:3 and that between the second and third be 4:5, then the difference between the first and third number? a) 21 b) 35 c) 42 d) 56 e) None of these

Description : The sum of three numbers is 210. If the ratio between the first and second number be 2:3 and that between the second and third be 4:5, then the difference between the first and third number? a) 21 b) 35 c) 42 d) 56 e) None of these

Last Answer : Answer: C a: b = 2:3 and b:c = 4:5 a:b:c = 8:12:15 Difference between first and third number = (7/35)*210 = 42

A tank can be filled by a tap in 8 hrs while it can be emptied by another tap in 18 hrs. if both the taps are opened simultaneously, then after how much time will the cistern get filled? A) 14hrs 24mins B) 14 hrs 12 mins C) 14hrs 56 mins D) 14hrs 30mins

Description : A tank can be filled by a tap in 8 hrs while it can be emptied by another tap in 18 hrs. if both the taps are opened simultaneously, then after how much time will the cistern get filled? A) 14hrs 24mins B) 14 hrs 12 mins C) 14hrs 56 mins D) 14hrs 30mins

Last Answer : A Net part filled in 1hr = (1/8 – 1/18) = 9 – 4/72 = 5/72 Therefore the tank will be filled in 72/5 hrs i.e., 14 hrs 24mins

A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98

Description : A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98 

Last Answer : Answer: D Let the number be 100. Increase in the number = 70 % = 40 % of 100  = (40/100 100)  = 70 Therefore, increased number = 100 + 70 = 170 This number is decreased by 70 % Therefore, decrease ... = 100 - 51 = 49 Hence, net percentage decrease = (49/100 100)  = (4900/100)  = 49 %

If vertices of a triangles are (1, k), (4, -3) and (-9, 7) and its area is 15 sq. units then find then the value of k. -Maths 9th

Description : If vertices of a triangles are (1, k), (4, -3) and (-9, 7) and its area is 15 sq. units then find then the value of k. -Maths 9th

Last Answer : hope it helps if the vertices of a triangle are (1,k),(4,−3)(−9,7) area = 15 sq.units. find the value of k. Area of △ 21 [x1 (y2 −y3 )+x2 (y3 −y1 )+x3 (y1 −y2 )]=15 21 [1(−3−7)+ ... k+3)]=15 21 [(−10+28−4k−9k−27)]=15 −10+28−4k−9k−27=30 −10+28−13k−27=30 −13k=30+10+27−28 −13k=39 k=1339 k=−3 thank u

what is 56 x 23?

Description : what is 56 x 23?

Last Answer : 1288

What is 56 x 36?

Description : What is 56 x 36?

Last Answer : Use your calculator b*tch

H2S is being absorbed in a gas absorber unit. The height of the transfer unit based on the overall mass transfer coefficient on the gas side is 0.4 m. The equilibrium data is given by, y = 1.5 x. The bulk concentration of H2S has to be reduced from 0.05 to 0.001 mole fraction in the gas side. The height of the tower (in metres) corresponding to an operating line given by, y = 5x + 0.001 is (A) 2.0 (B) 1.56 (C) 1.0

Description : H2S is being absorbed in a gas absorber unit. The height of the transfer unit based on the overall mass transfer coefficient on the gas side is 0.4 m. The equilibrium data is given by, y = 1.5 x. The bulk concentration of H2S ... by, y = 5x + 0.001 is (A) 2.0 (B) 1.56 (C) 1.0

Last Answer : (A) 2.0

There are 312, 260 and 156 students in class X, XI and XII respectively. Buses are to be hired to take these students to a picnic. Find the maximum number of students who can sit in a bus if each bus takes equal number of students (a) 52 (b) 56 (c) 48 (d) 63

Description : There are 312, 260 and 156 students in class X, XI and XII respectively. Buses are to be hired to take these students to a picnic. Find the maximum number of students who can sit in a bus if each bus takes equal number of students (a) 52 (b) 56 (c) 48 (d) 63

Last Answer : (a) 52

Find the pressure due to a column of mercury 74.0 cm high.  a. 91.80 x 10^3 N/m^2  b. 73.56 x 10^2 N/m^2  c. 9.86 x 10^4 N/m^2  d. 87.2 x 10^4 N/m^2

Description : Find the pressure due to a column of mercury 74.0 cm high.  a. 91.80 x 10^3 N/m^2  b. 73.56 x 10^2 N/m^2  c. 9.86 x 10^4 N/m^2  d. 87.2 x 10^4 N/m^2

Last Answer : 9.86 x 10^4 N/m^2

19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)

34.8% x 950 – 33.2% of 850 = ? a) 58.4 b) 48.4 c) 56.4 d) 68.9 e) 76.3

Description : 34.8% x 950 – 33.2% of 850 = ? a) 58.4 b) 48.4 c) 56.4 d) 68.9 e) 76.3

Last Answer : 34.8% x 950 – 33.2% of 850 = ? Sol: 0.348 x 950 – 0.332 x 850=? 330.6 – 282.2=? ?= 48.4 Answer: b)

An animal drawn seed drill has k number of furrow openers 180mm apart. If the speed of operation is 2.0kmph, the area covered (ha), in 8-11day is given by: A. 1.85/1000k B. 28.8 x 10-2k C. k/6.56 D. 1.762k

Description : An animal drawn seed drill has k number of furrow openers 180mm apart. If the speed of operation is 2.0kmph, the area covered (ha), in 8-11day is given by: A. 1.85/1000k B. 28.8 x 10-2k C. k/6.56 D. 1.762k

Last Answer : B. 28.8 x 10-2k