if one end point is at (-5,-6) and the midpoint is at (1,1) whats the endpoint?

1 Answer

Answer :

M = ((x1+x2)/2, (y1+y2)/2)(1,1) = ((-5+x)/2, (-6+y)/2)(-5+x))/2 = 1,  (-6+y)/2 = 1-5 + x = 2, -6+y = 2x = 7, y = 8The end point is (7,8)

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