a -0.8 D b -3.0 D c +0.8 D d +3.0 D Answer : D Solution : Given near point = 100 cm. ∴v=−100cmandu=−25cm∴v=-100cmandu=-25cm 1f=1v−1u=1−100−1−251f=1v-1u=1-100-1-25 1f=1−100+125=−1+4100=3100cm.1f=1-100+125=-1+4100=3100cm. Power, P=1for,100fD=100×3100D=3D