Description : In a circle , chord AB subtends an angle of `60^(@)` at the centre and chord CD subtends `120^(@)`, at it. Then which chord is longer ?
Last Answer : In a circle , chord AB subtends an angle of `60^(@)` at the centre and chord CD subtends `120^(@)`, at it. Then which chord is longer ?
Description : A chord of a circle of radius 20 cm subtends an angle of 90° at the centre. Find the area of the corresponding major segment of the circle. -Maths 10th
Last Answer : Area of the minor segment = { pi × 90 /360 - sin 45 × cos 45 } × r × r ={ 3.14 ×1/4 - 1÷√2 ×1÷√2 } × 20 × 20 = { 3.14 ... Area of major segment = area of circle - area of minor segment = 1256 - 114 = 1142 HOPE IT HELPS YOU
Description : The locus of the middle points of the focal chords of the parabola, `y^2=4x` is:
Last Answer : The locus of the middle points of the focal chords of the parabola, `y^2=4x` is: A. `y^2=x-1` B. `y^2=2(x-1)` C. `y^2=2(1-x)` D. None
Description : What is the vertex of the quadratic y -2x2 plus 4x-1?
Last Answer : It is (1, 1).
Description : Path followed by water jet issuing from the bottom of a water tank will be a (A) Parabola (vertex being at the opening) (B) Hyperbola (C) Horizontal straight line (D) Zig-zag path (which is geometrically undefined)
Last Answer : (A) Parabola (vertex being at the opening)
Description : An arc of a circle of raduis `R` subtends an angle `(pi)/2` at the centre. It carriers a current `i`. The magnetic field at the centre will be
Last Answer : An arc of a circle of raduis `R` subtends an angle `(pi)/2` at the centre. It carriers a current `i`. The ... (0)i)/(4R)` D. `(2mu_(0)i)/(5R)`
Description : In a circle of radius 14 cm, an arc subtends an angle of 45 O at the centre, then the area of the sector is (a) 71 cm 2(b) 76 cm 2 (c) 77 cm 2 (d) 154 cm 2
Last Answer : (c) 77 cm 2
Description : Find the equation of the normal to the curve `y = 5x + x^2` which makes an angle `45^@` with x axis.
Last Answer : Find the equation of the normal to the curve `y = 5x + x^2` which makes an angle `45^@` with x axis.
Description : A circle has radius √2 cm. It is divided into two segments by a chord of length 2cm.Prove that the angle subtended by the chord at a point in major segment is 45 degree . -Maths 9th
Last Answer : Given radius =2 cm Therefore AO=2 cm Let OD be the perpendicular from O on AB And AB =2cm Therefore AD=1cm (perpendicular from the centre bisects the chord) Now in triangle AOD, AO=2 cm ... by a chord at the centre is double of the angle made by the chord at any poin on the circumference)
Description : Designation of a curve is made by: (A) Angle subtended by a chord of any length (B) Angle subtended by an arc of specified length (C) Radius of the curve (D) Curvature of the curve
Last Answer : (C) Radius of the curve
Description : If is the length of a sub-chord and is the radius of simple curve, the angle of deflection between its tangent and sub-chord, in minutes, is equal to (A) 573 S/R (B) 573 R/S (C) 1718.9 R/S (D) 1718.9 S/R
Last Answer : (D) 1718.9 S/R
Description : If the long chord and tangent length of a circular curve of radius R are equal the angle of deflection, is (A) 30° (B) 60° (C) 90° (D) 120°
Last Answer : D
Description : Rankine's deflection angle in minutes is obtained by multiplying the length of the chord by (A) Degree of the curve (B) Square of the degree of the curve (C) Inverse of the degree of the curve (D) None of these
Last Answer : (A) Degree of the curve
Description : For a curve of radius 100 m and normal chord 10 m, the Rankine's deflection angle, is (A) 0°25'.95 (B) 0°35'.95 (C) 1°25'.53 (D) 2°51'.53
Last Answer : (D) 2°51'.53
Description : Write the coordinates of the vertices of a rectangle whose length and breadth are 6 and 3 units respectively, one vertex at the origin, the longer side lies on the y-axis and one of the vertices lies in the second quadrant. -Maths 9th
Last Answer : Solution :-
Description : A portion of an embankment having a uniform up-gradient 1 in 500 is circular with radius 1000 m of the centre line. It subtends 180° at the centre. If the height of the bank is 1 m at the lower end, and side slopes 2 ... earth work involved. (A) 26,000 m3 (B) 26,500 m3 (C) 27,000 m3 (D) 27,500 m
Last Answer : (D) 27,500 m3
Description : Find the point on the curve` y^(2) = x` at which the tangent drawn makes an angle of `45^(@)` from X-axis.
Last Answer : Find the point on the curve` y^(2) = x` at which the tangent drawn makes an angle of `45^(@)` from X-axis.
Description : When a graph is plotted between log x/m and log p, it is straight line with an angle `45^(@)` and intercept 0.3010 on y - axis. If initial pressure is
Last Answer : When a graph is plotted between log x/m and log p, it is straight line with an angle `45 ... adsorbent : (Report your answer after multiplying by 10)
Description : The angle between two altitudes of a parallelogram through the vertex of an obtuse angle of the parallelogram is 60°. -Maths 9th
Last Answer : Let the parallelogram be ABCD, in which ∠ADC and ∠ABC are obtuse angles. Now, DE and DF are two altitudes of parallelogram and angle between them is 60°.
Description : Let the vertex of an angle ABC be located outside a circle -Maths 9th
Last Answer : Given: AD = CE To prove: ∠ABC = 1/2(∠DOE - ∠AOC) In △AOD and △COE AD = CE (Given) AO = OC and DO = OE (Radii of same circle) ∴ △AOD ≅ △COE (By SSS congruence criterion) ⇒ ∠1 = ∠3, ∠2 = ∠4 (CPCT) ... = 1/2(4z + 4x - 360°) ....(vii) From (iv) and (vii), we have ∠BAC = 1/2(∠DOE - ∠AOC)
Description : a square is inscribed in an isosceles triangle so that the square and the triangle have one angle common. show that the vertex of the square opposite the vertex of the common angle bisect the hypotenuse. -Maths 9th
Last Answer : This answer was deleted by our moderators...
Description : (i) Find the co-ordinates of the points on the curve xy = 16 at which the normal drawn meet at origin. (ii) Find the points on the curve`4x^(2)+9 y^(2
Last Answer : (i) Find the co-ordinates of the points on the curve xy = 16 at which the normal drawn meet at ... ` at which the normal drawn is parallel to X-axis.
Description : A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment. -Maths 9th
Last Answer : Given, AB is a chord of a circle, which is equal to the radius of the circle, i.e., AB = BO …(i) Join OA, AC and BC. Since, OA = OB= Radius of circle OA = AS = BO
Description : The angle of intersection of a curve is the angle between (A) Back tangent and forward tangent (B) Prolongation of back tangent and forward tangent (C) Forward tangent and long chord (D) Back tangent and long chord
Last Answer : (A) Back tangent and forward tangent
Description : Derive length of parabola
Last Answer : Derive length of parabola class 11
Description : Shear force for a cantilever carrying a uniformly distributed load over its length, is (A) Triangle (B) Rectangle (C) Parabola (D) Cubic parabola
Last Answer : (B) Rectangle
Description : The locus of the end point of the resultant of the normal and tangential components of the stress on an inclined plane, is (A) Circle (B) Parabola (C) Ellipse (D) Straight line
Last Answer : (C) Ellipse
Description : Find the area of a parallelogram given in the figure. Also, find the length of the altitude from vertex A on the side DC. -Maths 9th
Last Answer : Weknowthatthediagonalofaparallelogram(∥gm)dividesitintotwocongruenttriangles.SoAreaof∥gmABCD=2 Areaof△BCD.AccordingtoHeron′sformulathearea(A)oftrianglewithsidesa,b&cisgivenasA=2[s(s−a)(s−b) ... 90=180Areaof∥gm=base heightHeightofaltitudefromvertexAonsideCDoftheof∥gm=baseCDareaof∥gmABCD =12180 =15cm
Last Answer : =3 x 3 x 5 x 2 cm2 Area of parallelogram ABCD = 2 x 90 = 180 cm2 (ii) Let altitude of a parallelogram be h. Also, area of parallelogram ABCD =Base x Altitude ⇒ 180 = DC x h [from Eq. (ii)] ... h ∴ h = 180/12= 15 cm Hence, the area of parallelogram is 180 cm2 and the length of altitude is 15 cm.
Description : Perpendiculars are drawn from the vertex of the obtuse angles of a rhombus to its sides. The length of each perpendicular is equal to a units. -Maths 9th
Last Answer : answer:
Description : If A (-2, 4), B (0, 0) and C (4, 2) are the vertices of triangle ABC, then find the length of the median through the vertex A. -Maths 9th
Last Answer : D=slid ht of BC D≅(20+4,20+2) =(2,1) ∴ Length of median = Light of AD =root(−2−2)2+(4−1)2=root42+32=5 hope it helps thank u
Description : What is the length of a perpendicular line drawn from one vertex to the opposite side?
Last Answer : What is the answer ?
Description : In the figure below ( not to scale) `bar(CD)||bar(RS) /_EMG=90^(@),/_GMD= gamma^(@),/_CME= x^(@) ` and `gamma^(@)=(x^(@))/(2)`. `/_ FNS : /_FNR `is
Last Answer : In the figure below ( not to scale) `bar(CD)||bar(RS) /_EMG=90^(@),/_GMD= gamma^(@),/_CME= x^(@) ` and `gamma^(@)=(x^(@))/(2)`. `/_ FNS : /_FNR `is
Description : A ray incident normally on one face of a right-angled isosceles glass prism in air is deviated through `90^(@)`. What can you say about the refractive
Last Answer : A ray incident normally on one face of a right-angled isosceles glass prism in air is deviated ... you say about the refractive index of glass ?
Description : If the length of a transition curve to be introduced between a straight and a circular curve of radius 500 m is 90 m, the maximum deflection angle to locate its junction point, is (A) 1°43' 08" (B) 1°43' 18" (C) 1°43' 28" (D) 1°43' 38"
Last Answer : (C) 1°43' 28"
Description : The y-coordinate of the centroid of the area bounded by the x-axis, the line x = 3 and the parabola y = x2 will be a.2.7 b.2.55 c.107 dynes d.2.6 e.2.65
Last Answer : a. 2.7
Description : The coordinates of the focus of the parabola described parametrically by `x=5t^2+2.y=10t+4` are
Last Answer : The coordinates of the focus of the parabola described parametrically by `x=5t^2+2.y=10t+4` are A. (7,4) B. (3,4) C. (3,-4) D. (-7,4)
Description : A parabola is drawn through two given points `A(1,0)` and `B(-1,0)` such that its directrix always touches the circle `x² + y^2 = 4.` Then, The locus
Last Answer : A parabola is drawn through two given points `A(1,0)` and `B(-1,0)` such that its directrix always touches the circle ... `(x^(2))/(5)+(y^(2))/(4)=1`
Description : What is the perpendicular bisector equation of the line y equals 5x plus 10 spanning the parabola y equals x squared plus 4?
Last Answer : If: y = 5x +10 and y = x^2 +4Then: x^2 +4 = 5x +10Transposing terms: x^2 -5x -6 = 0Factorizing the above: (x-6)(X+1) = 0 meaning x = 6 or x =-1Therefore by substitution endpoints of the line are ... .5 = -1/5(x-2.25) => 5y= -x+114.75Perpendicular bisector equation in its general form: x+5y-114.75= 0
Description : Assuming constant gravity and no air resistance, the path of a cannonball fired from a cannon is: w) a semi-circle x) an ellipse y) a parabola z) a hyperbola
Last Answer : ANSWER: Y -- A PARABOLA
Description : To a person standing on shore, an object dropped from the mast of a passing sailboat will trace what path, assuming negligible air resistance. Is it: w) vertical straight line x) slanted straight line y) parabola z) hyperbola
Last Answer : ANSWER: Y -- PARABOLA
Description : If the incident ray falls directly on the normal. What will be the angle of incidence .? a ) 0 b)30 c)60 d)90
Last Answer : a ) 0
Description : In STL files when chord length decrease then accuracy _______ a.increase b.decrease c.may increase or may decrease d.remains constant
Last Answer : a.increase
Description : A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th
Last Answer : ∵ PM = MQ = 1/2 = PQ = 45 cm and OP = 7.5 cm In right angled ΔOMP, using phthagoras theorem OM2 = OP2 - PM2 ⇒OM2 = 7.52 - 4.52 ⇒OM2 = 56.25 - 20.25 ⇒OM2 = 36 ∴ OM = √36 = 6 cm
Description : Find the length of a chord which is at a distance of 12 cm from the centre of a circle of radius 13 cm. -Maths 9th
Last Answer : Let AB be a chord of circle with centre O and radius 13cm. Draw OM perpendicular AB and join OA. In the right triangle OMA, we have OA2 = OM2 + AM2 ⇒ 132 = 122 + AM2 ⇒ AM2 = 169 - 144 ... . As the perpendicular from the centre of a chord bisects the chord.Therefore, AB = 2AM = 2 x 5 = 10cm.
Description : The radius of a circle is 13 cm and the length of one of its chords is 24 cm. Find the distance of the chord from the centre. -Maths 9th
Last Answer : Let PQ be a chord of a circle with centre O and radius 13cm such that PQ = 24cm. From O, draw OM perpendicular PQ and join OP. As, the perpendicular from the centre of a circle to a chord bisects the chord. ∴ PM ... Hence, the distance of the chord from the centre is 5cm.
Description : Point A(5, 1) is the centre of the circle with radius 13 units. AB ⊥ chord PQ. B is (2, –3). The length of chord PQ is -Maths 9th
Last Answer : (c) ParallelogramAB = \(\sqrt{(4-7)^2+(5-6)^2}\) = \(\sqrt{9+1}\) = \(\sqrt{10}\)BC = \(\sqrt{(7-4)^2+(6-3)^2}\) = \(\sqrt{9+9}\) = \(3\sqrt2\)CD =\(\sqrt{(4-1)^2+(3-2) ... = \(2\sqrt{13}\)AB = CD, BC = AD and AC ≠ BD ⇒ opposite sides are equal and diagonals are not equal. ⇒ ABCD is a parallelogram.