If vertices of a triangles are (1, k), (4, -3) and (-9, 7) and its area is 15 sq. units then find then the value of k. -Maths 9th

If vertices of a triangles are (1, k), (4, -3) and (-9, 7) and its area is 15 sq. units then find then the value of k. -Maths 9th
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 hope it helps if the vertices of a triangle are (1,k),(4,−3)(−9,7) area = 15 sq.units. find the value of k. Area of △  21​[x1​(y2​−y3​)+x2​(y3​−y1​)+x3​(y1​−y2​)]=15 21​[1(−3−7)+4(7−k)+(−9)(k−(−3)]=15 21​(−10+8−4k−9(k+3)]=15 21​[(−10+28−4k−9k−27)]=15 −10+28−4k−9k−27=30 −10+28−13k−27=30 −13k=30+10+27−28 −13k=39 k=1339​k=−3 thank u
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