Show that the equation of the parallel line midway between the parallel lines -Maths 9th

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Answer :

∵ Length of perpendicular from point (x1, y1) to line a\(x\) + by + c = 0 = \(rac{|ax_1+by_1+c|}{\sqrt{a^2+b^2}}\)∴ Length of perpendicular from (0, 0) to \(rac{x}{a}\) + \(rac{y}{b}\) = 1 ⇒ \(rac{\big|rac{1}{a} imes0+rac{1}{b} imes0-1\big|}{\sqrt{rac{1}{a^2}+rac{1}{b^2}}}\) = p⇒ \(rac{|-1|}{\sqrt{rac{1}{a^2}+rac{1}{b^2}}}\) = p⇒ \(rac{1}{p}\) = \(\sqrt{rac{1}{b^2}+rac{1}{b^2}}\) ⇒ \(rac{1}{p^2}\) = \(rac{1}{a^2}\) + \(rac{1}{b^2}\)

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