A bag contains a white and b black balls. Two players A and B alternately draw a ball from the bag -Maths 9th

1 Answer

Answer :

(c) 2 : 1Let W denote the event of drawing a white ball at any draw and B that of drawing a black ball. Then, P (W) = \(rac{a}{a+b},\) P(B) = \(rac{b}{a+b}\)∴ P (A wins the game) = P (W or BBW or BBBBW or ......) = P (W) + P (B) . P (B) . P (W) + P (B) . P (B) . P (B) . P (B) . P (W) + ..... = P (W) (1 + (P (B))2 + (P (B))4 + .....)= \(rac{P(W)}{1-(P(B))^2}\) = \(rac{rac{a}{a+b}}{1-rac{b^2}{(a+b)^2}}\) = \(rac{a(a+b)}{a^2+2ab}\) = \(rac{a+b}{a+2b}\)∴ P (B wins the game) = 1 – P (A wins the game)= \(1-rac{(a+b)}{(a+2b)}\) = \(rac{b}{a+2b}\)According to the given condition,\(rac{a+b}{a+2b}\) = 3. \(rac{b}{a+2b}\) ⇒ a = 2b ⇒ a : b = 2 : 1.

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Last Answer : Number of blue balls = z Total balls = x + y + z therefore P(blue ball)= z /(x+y+z )

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