An urn contains nine balls, of which three are red, four are blue and two are green. -Maths 9th

An urn contains nine balls, of which three are red, four are blue and two are green. -Maths 9th
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1 Answer

Answer :

(b) \(rac{2}{7}\)Let S be the sample space having 9 balls (3R + 4B + 2G) Then n(S) = Total number of ways in which 3 balls can be drawn out of the 9 balls= \(rac{9 imes8 imes7}{3 imes2}\) = 84Let A : Event of drawing three balls of different colours from the urn.⇒ A = Event of drawing 1 red ball out of 3 red balls, 1 blue ball out of 4 blue balls and 1 green ball out of 2 green balls ⇒ n(A) = 3C1 × 4C1 × 2C1 = 3 × 4 × 2 = 24.∴ P(A) = \(rac{n(A)}{n(S)}\) = \(rac{24}{84}\) = \(rac{2}{7}\).
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An urn contains 3 white and 5 blue balls and a second urn contains 4 white and 4 blue balls. If one ball is drawn from each urn, -Maths 9th

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