If a = log12m and b = log18m, then (a-2b)/(b-2a) equals -Maths 9th

If a = log12m and b = log18m, then (a-2b)/(b-2a) equals -Maths 9th
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Answer :

(a) log32\(rac{a-2b}{b-2a}\) = \(rac{ ext{log}_{12}\,m-\,2 ext{log}_{18}\,m}{ ext{log}_{18}\,m-\,2 ext{log}_{12}\,m}\)
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