Which of the following points lie on the x-axis ? -Maths 9th

1 Answer

Answer :

B (1,0) , D(0,0), E(-1,0) and G(4,0) lies on the x - axis .

Related questions

Description : Which of the points P(0, 3), Q(l, 0), R(0, – 1), S(-5, 0) and T(1, 2) do not lie on the X-axis ? -Maths 9th

Last Answer : (c) We know that, if a point is of the form (x, 0)i.e., its y-coordinate is zero, then it will lie on X-axis otherwise not. Here, y-coordinates of points P(0, 3), R (0, -1) and T (1,2) are not zero, so these points do not lie on the X-axis.

Description : Which of the following points lie on the x-axis ? -Maths 9th

Last Answer : B (1,0) , D(0,0), E(-1,0) and G(4,0) lies on the x - axis .

Description : Which of the points P(0, 3), Q(l, 0), R(0, – 1), S(-5, 0) and T(1, 2) do not lie on the X-axis ? -Maths 9th

Last Answer : (c) We know that, if a point is of the form (x, 0)i.e., its y-coordinate is zero, then it will lie on X-axis otherwise not. Here, y-coordinates of points P(0, 3), R (0, -1) and T (1,2) are not zero, so these points do not lie on the X-axis.

Description : In which quadrant or on which axis each of the following points lie ? -Maths 9th

Last Answer : (i) In point (-3, 5), x-coordinate is negative and y-coordinate is positive, so it lies in II quadrant. (ii) In point (4,-1), x-coordinate is positive and y-coordinate is negative, so it lies in ... v) In point (-3, - 6), x-coordinate and y-coordinate both are negative, so it lies in III quadrant.

Description : In which quadrant or on which axis each of the following points lie ? -Maths 9th

Last Answer : (i) In point (-3, 5), x-coordinate is negative and y-coordinate is positive, so it lies in II quadrant. (ii) In point (4,-1), x-coordinate is positive and y-coordinate is negative, so it lies in ... v) In point (-3, - 6), x-coordinate and y-coordinate both are negative, so it lies in III quadrant.

Description : Which axis is parallel to the line on which the two points with coordinates (4, 3) and (4,–2) lie? -Maths 9th

Last Answer : Solution :- As x-coordinate of both points is 4. So, both points lie on the line x = 4 which is parallel to y-axis.

Description : Two points with coordinates (3, 4) and (–5, 4) lie on a line parallel to which axis? Justify your answer. -Maths 9th

Last Answer : Solution :- y-coordinate of both the points is 4. So, both points lie on the line y = 4 which is parallel to x-axis.

Description : If y-coordinate of a point is zero, then where will this point lie in the coordinate plane? On the x-axis. -Maths 9th

Last Answer : Solution :- On the x-axis.

Description : Abscissa of all the points on the X-axis is -Maths 9th

Last Answer : (d) Abscissa of all the points on the X-axis is any number because X-axis is a number line which contains many real numbers on it.

Description : Ordinate of all points on the X-axis is -Maths 9th

Last Answer : (a) Ordinate of all points on the X-axis is zero. Because ordinate (or y-coordinate) of a point is perpendicular distance of this point from the X-axis measured along the Y-axis. If point lies on X- axis, then the perpendicular distance of point from X- axis will be zero, so ordinate will be zero.

Description : If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Last Answer : (d) We know that, a point lies on X-axis, if its y-coordinate is zero. So, on plotting the given points on graph paper, we get Q and O lie on the X-axis.

Description : Abscissa of all the points on the X-axis is -Maths 9th

Last Answer : (d) Abscissa of all the points on the X-axis is any number because X-axis is a number line which contains many real numbers on it.

Description : Ordinate of all points on the X-axis is -Maths 9th

Last Answer : (a) Ordinate of all points on the X-axis is zero. Because ordinate (or y-coordinate) of a point is perpendicular distance of this point from the X-axis measured along the Y-axis. If point lies on X- axis, then the perpendicular distance of point from X- axis will be zero, so ordinate will be zero.

Description : If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Last Answer : (d) We know that, a point lies on X-axis, if its y-coordinate is zero. So, on plotting the given points on graph paper, we get Q and O lie on the X-axis.

Description : Draw the graph of the linear equation 3x + 4y = 6. At what points, does the graph cut the x-axis and the y-axis? -Maths 9th

Last Answer : hope it helps

Description : Find the co-ordinates of the points on the x-axis which are at a distance of 10 units from the point (– 4, 8)? -Maths 9th

Last Answer : (a) Internal division: If P(x, y) divides the line segment formed by the joining of the points A (x1, y1) and B (x2, y2) internally in the ratio m1 : m2. Then\(x=rac{m_1x_2+m_2x_1}{m_1+m_2}\) and \(y=rac ... : 1, the co-ordinates of the mid-point are \(\bigg(rac{x_1+x_2}{2},rac{y_1+y_2}{2}\bigg)\).

Description : In what ratio is the line joining the points (2, –3) and (5, 6) divided by the x-axis. -Maths 9th

Last Answer : (b) (2, 1) (- 2, 1)Let PQRS be the required square and P(0, -1) and R(0, 3) be its two opposite vertices. Length of diagonal PR = \(\sqrt{(0-0)^2+(3+1)^2}\) = \(\sqrt{16}\) = 4∴ Length of each side = \( ... + 4 = 8 ⇒ a2 = 4 ⇒ a = 2. ∴ The other two vertices of the square are (+2, 1) and (-2, 1).

Description : Write the coordinates of two points on X-axis and two points on Y-axis which are at equal distances from the origin. Connect all these points and make them as vertices of quadrilateral. Name the quadrilateral thus formed. -Maths 9th

Last Answer : Let a be the equal distance from origin on both axes. Now, the coordinates of two points on equal distance 'a'on x-axis are Pla, 0) and R(-a, 0). Also, the coordinates of two points on equal distance 'a' on Y-axis are Q(0, a) and S(0, -a). Join all the four points on the graph.

Description : Find distances of points C(-3, -2) and D(5, 2) from x-axis and y-axis -Maths 9th

Last Answer : answer:

Description : The points (- 5, 2) and (2, -5) lie in the -Maths 9th

Last Answer : (c) In point (-5,2), x-coordinate is negative and y-coordinate is positive, so it lies in II quadrant and in point (2, – 5), x- coordinate is positive and y-coordinate is negative, so it lies in IV quadrant.

Description : The points whose abscissa and ordinate have different signs will lie in -Maths 9th

Last Answer : (d) The points whose abscissa and ordinate have different signs will be of the form (-x, y) or (x, – y)and these points will lie in II and IV quadrants.

Description : Without plotting the points indicate the quadrant in which they will lie, if -Maths 9th

Last Answer : (i) The given point is (- 3, 5). Here, abscissa is negative and ordinate is positive, so it lies in II quadrant. (ii) The given point is (-5, - 3). Here, abscissa and ordinate both are negative ... ) The given point is (3, 5). Here, abscissa and ordinate both are positive, so it lies in I quadrant.

Description : The points (- 5, 2) and (2, -5) lie in the -Maths 9th

Last Answer : (c) In point (-5,2), x-coordinate is negative and y-coordinate is positive, so it lies in II quadrant and in point (2, – 5), x- coordinate is positive and y-coordinate is negative, so it lies in IV quadrant.

Description : The points whose abscissa and ordinate have different signs will lie in -Maths 9th

Last Answer : (d) The points whose abscissa and ordinate have different signs will be of the form (-x, y) or (x, – y)and these points will lie in II and IV quadrants.

Description : Without plotting the points indicate the quadrant in which they will lie, if -Maths 9th

Last Answer : (i) The given point is (- 3, 5). Here, abscissa is negative and ordinate is positive, so it lies in II quadrant. (ii) The given point is (-5, - 3). Here, abscissa and ordinate both are negative ... ) The given point is (3, 5). Here, abscissa and ordinate both are positive, so it lies in I quadrant.

Description : Without plotting the points indicate the quadrant in which they will lie, if: -Maths 9th

Last Answer : Solution :- (i) III quadrant (iii) IV quadrant

Description : If two circles intersect at two points, prove that their centres lie on the perpendicular bisector of the common chord. -Maths 9th

Last Answer : Given: Two circles, with centres O and O' intersect at two points A and B. A AB is the common chord of the two circles and OO' is the line segment joining the centres of the two circles. Let OO' intersect ... 0° Thus, AP = BP and ∠APO = ∠BPO = 9 0° Hence, OO' is the perpendicular bisector of AB.

Description : In the adjoining figure, points A, B, C and D lie on a circle. AD = 24 and BC = 12. -Maths 9th

Last Answer : AD = 24, BC = 12. In ΔCBE and ΔADE, ∠CBA = ∠CDA, ∠BCE = ∠DAE (Angles in the same segment are equal) ∠BEC = ∠DEA (vertical opposite angles are equal) ⇒ ΔBCE and ΔDEA are similar Δs with sides in the ratio 1 : 2. ∴ Ratio of areas = Ratio of square of sides = 12 : 22 = 1 : 4

Description : Without plotting the points indicate the quadrant in which they lie, if : (i) ordinate is 5 and abscissa is – 3 (ii) abscissa is -5 and ordinate is – 3 -Maths 9th

Last Answer : answer:

Description : Without plotting the points indicate the quadrant in which they will lie, if (i) the ordinate is 5 and abscissa is – 3 -Maths 9th

Last Answer : (i) In the point (−3,5) abscissa is negative and ordinate is positive, so it lies in the second quadrant. (ii) In the point (−5,−3) abscissa and ordinate both are negative, so it lies in the ... . (iv) In the point (3,5) abscissa and ordinate both are positive, so it lies in the first quadrant

Description : Which of the following points lies on Y-axis ? -Maths 9th

Last Answer : We know that, a point lies on the Y-axis, if its x-coordinate is zero. Here, x-coordinate of points C(0, 1), D(0, 0), E(0,-1) and G(0, 5) are zero. So, these points lie on Y-axis. Also ... 0) is the intersection point of both.the axes, so we can consider that it lies on Y-axis as well as on X-axis.

Description : Which of the following points lies on Y-axis ? -Maths 9th

Last Answer : We know that, a point lies on the Y-axis, if its x-coordinate is zero. Here, x-coordinate of points C(0, 1), D(0, 0), E(0,-1) and G(0, 5) are zero. So, these points lie on Y-axis. Also ... 0) is the intersection point of both.the axes, so we can consider that it lies on Y-axis as well as on X-axis.

Description : If the perpendicular distance of a point P from the X-axis is 5 units and the foot of the perpendicular lies on the negative direction of X-axis, then the point P has -Maths 9th

Last Answer : (d) We know that, the perpendicular distance of a point from the X-axis gives y-coordinate of that point. Here, foot of perpendicular lies on the negative direction of X-axis, so perpendicular distance can be measure in II quadrant or III quadrant. Hence, the point P has y-coordinate = 5 or -5.

Description : A point lies on positive direction of X-axis at a distance of 7 units from the Y-axis. What are its coordinates ? -Maths 9th

Last Answer : Given, point lies on the positive direction of X-axis, so its y-coordinate will be zero and it is at a distance of 7 units from the X-axis, so its coordinates are (7, 0). If it lies on negative ... x-coordinate will be zero and its distance from X-axis is 7 units, so its coordinates are (0, -7).

Description : Any point on the X-axis is of the form -Maths 9th

Last Answer : (c) Every point on the X-axis has its y-coordinate equal to zero. i.e., y = 0 Hence, the general form of every point on X-axis is (x, 0).

Description : The equation of X-axis is of the form x = 0 -Maths 9th

Last Answer : (b) The equation of X-axis is of the form y = 0.

Description : The graph of the linear equation 2x+ 3y = 6 is a line which meets the X-axis at the point. -Maths 9th

Last Answer : (c) Since, the graph of linear equation 2x + 3y = 6 meets the X-axis. So, we put y = 0 in 2x + 3y = 6 ⇒ 2x + 3(0) = 6 = 2x + 0 = 6 ⇒ x = 6/2 ⇒ x = 3 Hence, the coordinate on X-axis is (3, 0).

Description : Draw the graph of the equation represented by a straight Line which is parallel to the X-axis and at a distance 3 units below it. -Maths 9th

Last Answer : Any straight line parallel to X-axis in negative direction of Y-axis is given by y = - k, where k is the distance of the line from the X-axis. Here, k = 3. Therefore, the equation of the line is y = -3. To ... , plot the points (1,-3), (2, -3) and (3, -3) and join them. This is the required graph.

Description : If the perpendicular distance of a point P from the X-axis is 5 units and the foot of the perpendicular lies on the negative direction of X-axis, then the point P has -Maths 9th

Last Answer : (d) We know that, the perpendicular distance of a point from the X-axis gives y-coordinate of that point. Here, foot of perpendicular lies on the negative direction of X-axis, so perpendicular distance can be measure in II quadrant or III quadrant. Hence, the point P has y-coordinate = 5 or -5.

Description : A point lies on positive direction of X-axis at a distance of 7 units from the Y-axis. What are its coordinates ? -Maths 9th

Last Answer : Given, point lies on the positive direction of X-axis, so its y-coordinate will be zero and it is at a distance of 7 units from the X-axis, so its coordinates are (7, 0). If it lies on negative ... x-coordinate will be zero and its distance from X-axis is 7 units, so its coordinates are (0, -7).

Description : Any point on the X-axis is of the form -Maths 9th

Last Answer : (c) Every point on the X-axis has its y-coordinate equal to zero. i.e., y = 0 Hence, the general form of every point on X-axis is (x, 0).

Description : The equation of X-axis is of the form x = 0 -Maths 9th

Last Answer : (b) The equation of X-axis is of the form y = 0.

Description : The graph of the linear equation 2x+ 3y = 6 is a line which meets the X-axis at the point. -Maths 9th

Last Answer : (c) Since, the graph of linear equation 2x + 3y = 6 meets the X-axis. So, we put y = 0 in 2x + 3y = 6 ⇒ 2x + 3(0) = 6 = 2x + 0 = 6 ⇒ x = 6/2 ⇒ x = 3 Hence, the coordinate on X-axis is (3, 0).

Description : Draw the graph of the equation represented by a straight Line which is parallel to the X-axis and at a distance 3 units below it. -Maths 9th

Last Answer : Any straight line parallel to X-axis in negative direction of Y-axis is given by y = - k, where k is the distance of the line from the X-axis. Here, k = 3. Therefore, the equation of the line is y = -3. To ... , plot the points (1,-3), (2, -3) and (3, -3) and join them. This is the required graph.

Description : Is (x, 0) a point on the x–axis? Give reason. -Maths 9th

Last Answer : Solution :-

Description : Write the equation representing x-axis. -Maths 9th

Last Answer : Solution:- y=0

Description : Write the equation of a line parallel to x-axis and passing through the point (–3, –4). -Maths 9th

Last Answer : Solution :- y = -4

Description : Write the equation of the line parallel to the x-axis at distance 3 units above x-axis. -Maths 9th

Last Answer : Solution :-

Description : Find the co-ordinate where the equation 2x + 3y = 6 intersects x-axis. -Maths 9th

Last Answer : Solution :-

Description : Draw the graph of the equation represented by the straight line which is parallel to the x-axis and 3 units above it. -Maths 9th

Last Answer : Solution :- Any straight line parallel to x-axis is given by y = a, where a is the distance of the line from the x-axis. Here a = 3. Therefore the equation of the line is y = 3. To draw the graph of this equation plot the points (0, 3) and (3, 3) and join them.