The points (- 5, 2) and (2, -5) lie in the -Maths 9th

1 Answer

Answer :

(c) In point (-5,2), x-coordinate is negative and y-coordinate is positive, so it lies in II quadrant and in point (2, – 5), x- coordinate is positive and y-coordinate is negative, so it lies in IV quadrant.

Related questions

Description : Which of the points P(0, 3), Q(l, 0), R(0, – 1), S(-5, 0) and T(1, 2) do not lie on the X-axis ? -Maths 9th

Last Answer : (c) We know that, if a point is of the form (x, 0)i.e., its y-coordinate is zero, then it will lie on X-axis otherwise not. Here, y-coordinates of points P(0, 3), R (0, -1) and T (1,2) are not zero, so these points do not lie on the X-axis.

Description : The points (- 5, 2) and (2, -5) lie in the -Maths 9th

Last Answer : (c) In point (-5,2), x-coordinate is negative and y-coordinate is positive, so it lies in II quadrant and in point (2, – 5), x- coordinate is positive and y-coordinate is negative, so it lies in IV quadrant.

Description : Which of the points P(0, 3), Q(l, 0), R(0, – 1), S(-5, 0) and T(1, 2) do not lie on the X-axis ? -Maths 9th

Last Answer : (c) We know that, if a point is of the form (x, 0)i.e., its y-coordinate is zero, then it will lie on X-axis otherwise not. Here, y-coordinates of points P(0, 3), R (0, -1) and T (1,2) are not zero, so these points do not lie on the X-axis.

Description : Two points with coordinates (3, 4) and (–5, 4) lie on a line parallel to which axis? Justify your answer. -Maths 9th

Last Answer : Solution :- y-coordinate of both the points is 4. So, both points lie on the line y = 4 which is parallel to x-axis.

Description : Without plotting the points indicate the quadrant in which they lie, if : (i) ordinate is 5 and abscissa is – 3 (ii) abscissa is -5 and ordinate is – 3 -Maths 9th

Last Answer : answer:

Description : Without plotting the points indicate the quadrant in which they will lie, if (i) the ordinate is 5 and abscissa is – 3 -Maths 9th

Last Answer : (i) In the point (−3,5) abscissa is negative and ordinate is positive, so it lies in the second quadrant. (ii) In the point (−5,−3) abscissa and ordinate both are negative, so it lies in the ... . (iv) In the point (3,5) abscissa and ordinate both are positive, so it lies in the first quadrant

Description : Which of the following points lie on the x-axis ? -Maths 9th

Last Answer : B (1,0) , D(0,0), E(-1,0) and G(4,0) lies on the x - axis .

Description : The points whose abscissa and ordinate have different signs will lie in -Maths 9th

Last Answer : (d) The points whose abscissa and ordinate have different signs will be of the form (-x, y) or (x, – y)and these points will lie in II and IV quadrants.

Description : Without plotting the points indicate the quadrant in which they will lie, if -Maths 9th

Last Answer : (i) The given point is (- 3, 5). Here, abscissa is negative and ordinate is positive, so it lies in II quadrant. (ii) The given point is (-5, - 3). Here, abscissa and ordinate both are negative ... ) The given point is (3, 5). Here, abscissa and ordinate both are positive, so it lies in I quadrant.

Description : In which quadrant or on which axis each of the following points lie ? -Maths 9th

Last Answer : (i) In point (-3, 5), x-coordinate is negative and y-coordinate is positive, so it lies in II quadrant. (ii) In point (4,-1), x-coordinate is positive and y-coordinate is negative, so it lies in ... v) In point (-3, - 6), x-coordinate and y-coordinate both are negative, so it lies in III quadrant.

Description : Which of the following points lie on the x-axis ? -Maths 9th

Last Answer : B (1,0) , D(0,0), E(-1,0) and G(4,0) lies on the x - axis .

Description : The points whose abscissa and ordinate have different signs will lie in -Maths 9th

Last Answer : (d) The points whose abscissa and ordinate have different signs will be of the form (-x, y) or (x, – y)and these points will lie in II and IV quadrants.

Description : Without plotting the points indicate the quadrant in which they will lie, if -Maths 9th

Last Answer : (i) The given point is (- 3, 5). Here, abscissa is negative and ordinate is positive, so it lies in II quadrant. (ii) The given point is (-5, - 3). Here, abscissa and ordinate both are negative ... ) The given point is (3, 5). Here, abscissa and ordinate both are positive, so it lies in I quadrant.

Description : In which quadrant or on which axis each of the following points lie ? -Maths 9th

Last Answer : (i) In point (-3, 5), x-coordinate is negative and y-coordinate is positive, so it lies in II quadrant. (ii) In point (4,-1), x-coordinate is positive and y-coordinate is negative, so it lies in ... v) In point (-3, - 6), x-coordinate and y-coordinate both are negative, so it lies in III quadrant.

Description : Which axis is parallel to the line on which the two points with coordinates (4, 3) and (4,–2) lie? -Maths 9th

Last Answer : Solution :- As x-coordinate of both points is 4. So, both points lie on the line x = 4 which is parallel to y-axis.

Description : Without plotting the points indicate the quadrant in which they will lie, if: -Maths 9th

Last Answer : Solution :- (i) III quadrant (iii) IV quadrant

Description : If two circles intersect at two points, prove that their centres lie on the perpendicular bisector of the common chord. -Maths 9th

Last Answer : Given: Two circles, with centres O and O' intersect at two points A and B. A AB is the common chord of the two circles and OO' is the line segment joining the centres of the two circles. Let OO' intersect ... 0° Thus, AP = BP and ∠APO = ∠BPO = 9 0° Hence, OO' is the perpendicular bisector of AB.

Description : In the adjoining figure, points A, B, C and D lie on a circle. AD = 24 and BC = 12. -Maths 9th

Last Answer : AD = 24, BC = 12. In ΔCBE and ΔADE, ∠CBA = ∠CDA, ∠BCE = ∠DAE (Angles in the same segment are equal) ∠BEC = ∠DEA (vertical opposite angles are equal) ⇒ ΔBCE and ΔDEA are similar Δs with sides in the ratio 1 : 2. ∴ Ratio of areas = Ratio of square of sides = 12 : 22 = 1 : 4

Description : A point both of whose coordinates are negative will lie in -Maths 9th

Last Answer : (c) A point both of whose coordinates are negative will lie in III quadrant because, in III quadrant x-coordinate and y-coordinate both are negative.

Description : The positive solutions of the equation ax + by + c = 0 always lie in the -Maths 9th

Last Answer : (a) We know that, if a line passes through the Ist quadrant, then all solution lying on the line in first quadrant must be positive because the coordinate of all points in the Ist quadrant are positive.

Description : A point both of whose coordinates are negative will lie in -Maths 9th

Last Answer : (c) A point both of whose coordinates are negative will lie in III quadrant because, in III quadrant x-coordinate and y-coordinate both are negative.

Description : The positive solutions of the equation ax + by + c = 0 always lie in the -Maths 9th

Last Answer : (a) We know that, if a line passes through the Ist quadrant, then all solution lying on the line in first quadrant must be positive because the coordinate of all points in the Ist quadrant are positive.

Description : If y-coordinate of a point is zero, then where will this point lie in the coordinate plane? On the x-axis. -Maths 9th

Last Answer : Solution :- On the x-axis.

Description : Where does the point (–2, 4) lie in the coordinate plane? -Maths 9th

Last Answer : Solution :- II quadrant

Description : In which quadrant does a point both of whose coordinates are positive lie? -Maths 9th

Last Answer : Solution :- I quadrant.

Description : The point in which abscissa and ordinate have different signs will lie in which quadrant (s)? -Maths 9th

Last Answer : Solution :- II and IV quadrants.

Description : ABC and DBC are two triangles on the same BC such that A and D lie on the opposite sides of BC,AB=AC and DB = DC.Show that AD is the perpendicular bisector of BC. -Maths 9th

Last Answer : Solution :-

Description : If circles are drawn taking two sides of a triangle as diameter, prove that the point of intersection of these circles lie on the third side. -Maths 9th

Last Answer : Solution :- Given: Two circles are drawn on sides AB and AC of a △ABC as diameters. The circles intersects at D. To prove: D lies on BC Construction: Join A and D Proof: ∠ADB = 90° (Angle in the semi-circle ... + 90° => ∠ADB + ∠ADC = 180° => BDC is a straight line. Hence, D lies On third side BC.

Description : Two congruent circles intersect each other at point A and B.Through A any line segment PAQ is drawn so that P,Q lie on the two circles.Prove that BP = BQ. -Maths 9th

Last Answer : Solution :- Let, O and O' be the centres of two congruent circles. As, AB is the common chord of these circles. ∴ ACB = ADB As congruent arcs subtent equal angles at the centre. ∠AOB = ∠AO'B ⇒ 1/2∠AOB = 1/2∠AO'B ⇒ ∠BPA = ∠BQA ⇒ BP = BQ (Sides opposite to equal angles)

Description : The product of the abscissa and the ordinate of a point P is negative. In which quadrants can the point lie ? -Maths 9th

Last Answer : answer:

Description : 7. Between which two whole numbers on the number line are the given numbers lie? Which of these whole numbers is nearer the number? -Maths 9th

Last Answer : (a) 0.8 lies between 0 and 1 0.8 is nearer to 1 (b) 5.1 lies between 5 and 6 5.1 is nearer to 5 (c) 2.6 lies between 2 and 3 2.6 is nearer to 3 (d) 6.4 lies between 6 and 7 6.4 is nearer to 6 (e) 9.1 lies between 9 and 10 9.1 is nearer to 9 (f) 4.9 lies between 4 and 5 4.9 is nearer to 5

Description : In which quadrant does the point (-1, 2) lie ? -Maths 9th

Last Answer : answer:

Description : If in coordinates of a point B(3, -2), signs of both coordinates are interchanged, then it will lie in which quadrant ? -Maths 9th

Last Answer : answer:

Description : 5. In a parallelogram ABCD, E and F are the mid-points of sides AB and CD respectively (see Fig. 8.31). Show that the line segments AF and EC trisect the diagonal BD. -Maths 9th

Last Answer : . Solution: Given that, ABCD is a parallelogram. E and F are the mid-points of sides AB and CD respectively. To show, AF and EC trisect the diagonal BD. Proof, ABCD is a parallelogram , AB || CD also, ... (i), DP = PQ = BQ Hence, the line segments AF and EC trisect the diagonal BD. Hence Proved.

Description : Points (1, -1), (2, – 2), (4, – 5) and (-3, – 4) -Maths 9th

Last Answer : (d) In points (1, -1), (2, -2) and (4, -5) x-coordinate is positive and y-coordinate is negative, So, they all lie in IV quadrant. In point (-3, – 4) x-coordinate is negative and y-coordinate is negative. So, it lies in III quadrant So, given points do not lie in the same quadrant.

Description : On plotting the points 0(0, 0), A(3, 0), 5(3, 4), C(0, 4) and joining OA, AB, BC and CO. -Maths 9th

Last Answer : (b) Here, point 0 (0, 0) is the origin. A(3, 0) lies on positive direction of X-axis, B (3, 4) lies in 1st quadrant and C (0, 4) lines on positive direction of Y-axis. On joining OA AB, BC and CO the figure obtained is a rectangle.

Description : If the coordinates of the two points are P(-2, 3) and Q(-3, 5), then (Abscissa of P) – (Abscissa of Q) is -Maths 9th

Last Answer : (b) We have, points P(- 2, 3) and Q(- 3, 5) Here, abscissa of Pi.e., x-coordinate of Pis -2 and abscissa of Q i.e., x-coordinate of Q is -3. So, (Abscissa of P) – (Abscissa of Q) = - 2 - (-3) = -2 + 3 =1.

Description : If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Last Answer : (d) We know that, a point lies on X-axis, if its y-coordinate is zero. So, on plotting the given points on graph paper, we get Q and O lie on the X-axis.

Description : Taking 0.5 cm as 1 unit, plot the following points on the graph paper. -Maths 9th

Last Answer : Here, in point 4(1, 3) both x and y-coordinates are positive, so it lies in I quadrant. In point 8(-3, -1),both x and y-coordinates are negative, so it lies in III quadrant. In point C(1, -4), x- ... is zero, so it lies on Y-axis and in point F(1,0) y-coordinate is zero, so it lies on X-axis.

Description : Plot the points P(1, 0), Q(4, 0) and 5(1, 3). Find the coordinates of the point R such that PQRS is a square. -Maths 9th

Last Answer : see the below answer

Description : Points A(5, 3), B(-2, 3) and 0(5, – 4) are three vertices of a square ABCD. -Maths 9th

Last Answer : The graph obtained by plotting the points A, B and C and D is given below. Take a point C on the graph such that ABCD is a square i.e., all sides AB, BC, CD, and AD are equal. So, abscissa of C should be ... of C should be equal to ordinate of D i.e., -4. Hence, the coordinates of C are (-2, - 4).

Description : Plot the points A (1, – 1) and B (4, 5). -Maths 9th

Last Answer : In point A(1, -1), x-coordinate is positive and y-coordinate is negative, so it lies in IV quadrant. In point B(4, 5), both coordinates are positive, so it lies in I quadrant. On plotting these point, we ... Y-axis at y = 7. Thus, we get the point Q(5,7) which lies outside the line segment AB.

Description : Points (1, -1), (2, – 2), (4, – 5) and (-3, – 4) -Maths 9th

Last Answer : (d) In points (1, -1), (2, -2) and (4, -5) x-coordinate is positive and y-coordinate is negative, So, they all lie in IV quadrant. In point (-3, – 4) x-coordinate is negative and y-coordinate is negative. So, it lies in III quadrant So, given points do not lie in the same quadrant.

Description : On plotting the points 0(0, 0), A(3, 0), 5(3, 4), C(0, 4) and joining OA, AB, BC and CO. -Maths 9th

Last Answer : (b) Here, point 0 (0, 0) is the origin. A(3, 0) lies on positive direction of X-axis, B (3, 4) lies in 1st quadrant and C (0, 4) lines on positive direction of Y-axis. On joining OA AB, BC and CO the figure obtained is a rectangle.

Description : If the coordinates of the two points are P(-2, 3) and Q(-3, 5), then (Abscissa of P) – (Abscissa of Q) is -Maths 9th

Last Answer : (b) We have, points P(- 2, 3) and Q(- 3, 5) Here, abscissa of Pi.e., x-coordinate of Pis -2 and abscissa of Q i.e., x-coordinate of Q is -3. So, (Abscissa of P) – (Abscissa of Q) = - 2 - (-3) = -2 + 3 =1.

Description : If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Last Answer : (d) We know that, a point lies on X-axis, if its y-coordinate is zero. So, on plotting the given points on graph paper, we get Q and O lie on the X-axis.

Description : Taking 0.5 cm as 1 unit, plot the following points on the graph paper. -Maths 9th

Last Answer : Here, in point 4(1, 3) both x and y-coordinates are positive, so it lies in I quadrant. In point 8(-3, -1),both x and y-coordinates are negative, so it lies in III quadrant. In point C(1, -4), x- ... is zero, so it lies on Y-axis and in point F(1,0) y-coordinate is zero, so it lies on X-axis.

Description : Points A(5, 3), B(-2, 3) and 0(5, – 4) are three vertices of a square ABCD. -Maths 9th

Last Answer : The graph obtained by plotting the points A, B and C and D is given below. Take a point C on the graph such that ABCD is a square i.e., all sides AB, BC, CD, and AD are equal. So, abscissa of C should be ... of C should be equal to ordinate of D i.e., -4. Hence, the coordinates of C are (-2, - 4).

Description : Plot the points A (1, – 1) and B (4, 5). -Maths 9th

Last Answer : In point A(1, -1), x-coordinate is positive and y-coordinate is negative, so it lies in IV quadrant. In point B(4, 5), both coordinates are positive, so it lies in I quadrant. On plotting these point, we ... Y-axis at y = 7. Thus, we get the point Q(5,7) which lies outside the line segment AB.

Description : Plot the points P(1, 0), Q(4, 0) and 5(1, 3). Find the coordinates of the point R such that PQRS is a square. -Maths 9th

Last Answer : see the below answer