A can hit a target three times in five shots, B two times in five shots and C three times in four shots. They fire a volley. -Maths 9th

A can hit a target three times in five shots, B two times in five shots and C three times in four shots. They fire a volley. -Maths 9th
by

1 Answer

Answer :

P(A) = \(rac{3}{5}\), P(B) = \(rac{2}{5}\), P(C) = \(rac{3}{4}\). In order that two shots may hit the target the following three mutually exclusive events are possible,(i) A and B hit the target and not C. (ii) B and C hit the target and not A. (iii) A and C hit the target and not B.If p1, p2, p3 are the probabilities of these three events thenp1 = P (A). P (B) . P (not C) = \(rac{3}{5}\) x \(rac{2}{5}\) x \(\big(1-rac{3}{4}\big)\) = \(rac{3}{5}\) x \(rac{2}{5}\) x \(rac{1}{4}\) = \(rac{6}{100}\) p2 = P (B). P (C) . P (not A) = \(rac{2}{5}\) x \(rac{3}{4}\) x \(\big(1-rac{3}{5}\big)\) = \(rac{2}{5}\) x \(rac{3}{4}\) x \(rac{2}{5}\) = \(rac{12}{100}\)p3 = P (A) × P (C) × P (not B) = \(rac{3}{5}\) x \(rac{3}{4}\) x \(\big(1-rac{2}{5}\big)\) = \(rac{3}{5}\)x \(rac{3}{4}\) x \(rac{3}{5}\) = \(rac{27}{100}\)∴ Required probability = p1 + p2 + p3 = \(rac{6}{100}\) + \(rac{12}{100}\) + \(rac{27}{100}\) = \(rac{45}{100}\) = \(rac{9}{20}.\)
by

Related questions

A man can hit a target once in 4shots. If he fires 4 shots in succession, what is the probability that he will hit his target? a) 175/256 b) 81/256 c) 1/256 d) 1/256

Description : A man can hit a target once in 4shots. If he fires 4 shots in succession, what is the probability that he will hit his target? a) 175/256 b) 81/256 c) 1/256 d) 1/256

Last Answer : a) 175/256

An anti-aircraft gun can take a maximum of four shots at any plane moving away from it. The probabilities of hitting the plane at 1st, 2nd, 3rd -Maths 9th

Description : An anti-aircraft gun can take a maximum of four shots at any plane moving away from it. The probabilities of hitting the plane at 1st, 2nd, 3rd -Maths 9th

Last Answer : (c) 0.6976Let A, B, C, D be the events that 1st, 2nd, 3rd and 4th shots hits the plane respectively. Then, P(A) = 0.4, P(B) = 0.3, P(C) = 0.2, P(D) = 0.1 ⇒ P(not A) = 1 - P(A),= ... and D are independent events) P(At least one shot hits the plane) = 1 - P(None hits the plane) = 1 - 0.3024 = 0.6976

Will and Jim were practicing shooting, and each scored seventy-five hits out of a hundred. After a little break, Will tried again and hit thirty-five out of fifty shots. Jim did not do any more shooting. Who had the best average for the day? -Riddles

Description : Will and Jim were practicing shooting, and each scored seventy-five hits out of a hundred. After a little break, Will tried again and hit thirty-five out of fifty shots. Jim did not do any more shooting. Who had the best average for the day? -Riddles

Last Answer : Jim's average is higher.

An anti-air craft gun can take a maximum of four shots at an enemy plane moving away from it. The probability of hitting the plane at the first, second, third and fourth shots are 0.4, 0.3, 0.2 and 0.1 respectively. What is the probability that the plane is hit when all the four shots are fired? a) 0.6872 b) 0.4379 c) 0.6976 d) 0.3452

Description : An anti-air craft gun can take a maximum of four shots at an enemy plane moving away from it. The probability of hitting the plane at the first, second, third and fourth shots are 0.4, 0.3, 0.2 and 0.1 ... is hit when all the four shots are fired? a) 0.6872 b) 0.4379 c) 0.6976 d) 0.3452

Last Answer : c) 0.6976

The probability that A hits a target is 1/3 and the probability that B hits it is 2/5 . -Maths 9th

Description : The probability that A hits a target is 1/3 and the probability that B hits it is 2/5 . -Maths 9th

Last Answer : (b) \(rac{3}{5}\)Let A : Event that A hits the target B : Event that B hits the target Given,P(A) = \(rac{1}{3}\) ⇒ P(A not hitting the target) = P(\(\bar{A}\)) = 1 - \(rac{1}{3}\) = \(rac{2}{3}\)P(B) = \(rac{ ... = \(rac{3}{15}\) + \(rac{4}{15}\) + \(rac{2}{15}\) = \(rac{9}{15}\) = \(rac{3}{5}\).

What happened to the other USA Womens Beach Volley Ball team?

Description : What happened to the other USA Womens Beach Volley Ball team?

Last Answer : I Found it. It wasn’t clear on Yahoo Sports. They lost to China.

Are there any suggestions out there for a new volley ball coach?

Description : Are there any suggestions out there for a new volley ball coach?

Last Answer : answer:Let me suggest that you consider aligning yourself with the American Volleyball Coaches Association They should be able to supply you with any ideas you might need. Volleyball is the national ... very excited watching a bunch of gals playing volleyball, without wearing any team uniforms.

What is the name of the skill used to begin each point in volley ball?

Description : What is the name of the skill used to begin each point in volley ball?

Last Answer : The serve initiates play and any points earned.

What is the height of Volley ball pole?

Description : What is the height of Volley ball pole?

Last Answer : Need answer

Did people fire shots where you live on ********* Eve at midnight?

Description : Did people fire shots where you live on Christmas Eve at midnight?

Last Answer : No. There are laws here that you can’t fire guns within a certain distance from residences.

There are 18 points in a plane such that no three of them are in the same line except five points which are collinear. -Maths 9th

Description : There are 18 points in a plane such that no three of them are in the same line except five points which are collinear. -Maths 9th

Last Answer : answer:

Five balls of different colours are to be placed in three boxes of different sizes. Each box can hold all five. In how many different ways -Maths 9th

Description : Five balls of different colours are to be placed in three boxes of different sizes. Each box can hold all five. In how many different ways -Maths 9th

Last Answer : According to the question, we have 5 balls to be placed in 3 boxes where no box remains emptyHence, we can have the following kinds of distribution firstly, where the distribution will be (3,1,1) that is, one box gets three ... go in second box is = 4 C 2 . Total no. of ways =90 Total:60+90=150.

The weight of a man is four times the weight of a child. Write an equation in two variables for this situation. -Maths 9th

Description : The weight of a man is four times the weight of a child. Write an equation in two variables for this situation. -Maths 9th

Last Answer : Solution :-

Find the condition that one root of ax^2 + bx + c = 0 may be four times the other. -Maths 9th

Description : Find the condition that one root of ax^2 + bx + c = 0 may be four times the other. -Maths 9th

Last Answer : answer:

Why does he break down in tears after the fire? -Maths 9th

Description : Why does he break down in tears after the fire? -Maths 9th

Last Answer : The author’s house was completely burned down. Five hours later when the fire was finally put out, he realised at once that his cat was nowhere. He had to face the loss of old school, his house and cat. In such a state, he cried and broke down in tears.

Four boys and three girls stand in a queue for an interview. What is the probability that they will be in alternate positions ? -Maths 9th

Description : Four boys and three girls stand in a queue for an interview. What is the probability that they will be in alternate positions ? -Maths 9th

Last Answer : Total number of ways of arranging 4 boys and 3 girls, i.e., 7 people in a queue (row) = n(S) = 7! Let A : Event in which the 4 boys and 3 girls occupy alternate position. This is possible when the ... {4 imes3 imes2 imes1 imes3 imes2 imes1}{7 imes6 imes5 imes4 imes3 imes2 imes1}\) = \(rac{1}{35}.\)

If two additional arrows are shot and both hit the target describe the set of all possible final scores.?

Description : If two additional arrows are shot and both hit the target describe the set of all possible final scores.?

Last Answer : if two additional arrows are shot and both hit the target,describe the set of all possible final scores.

If two additional arrows are shot and both hit the target describe the set of all possible final scores.?

Description : If two additional arrows are shot and both hit the target describe the set of all possible final scores.?

Last Answer : if two additional arrows are shot and both hit the target,describe the set of all possible final scores.

When I was playing Cowboys and Indians, with my neighborhood friends, in the seventies, all our bullets and arrows hit their target. So I, until now, never really questioned the aiming a problem. Here's my question >>?

Description : When I was playing Cowboys and Indians, with my neighborhood friends, in the seventies, all our bullets and arrows hit their target. So I, until now, never really questioned the aiming a problem. Here's my question >>?

Last Answer : The single-bullet theory is fascinating to me. Let alone the accuracy. Thank goodness for the Zapruder Film. It still leaves questions. I am certain there have been many Cowboy and indian like shots fired from ... person. I think the precautions now are far to great for it to happen again in the US

Is there a specific way to hit in American football that will give the target a concussion?

Description : Is there a specific way to hit in American football that will give the target a concussion?

Last Answer : A concussion generally occurs when the head either accelerates rapidly and then is stopped, or is spun rapidly. Any hit that does this is likely to cause a concussion but I wouldn’t say it was guaranteed.

Awlaki and the CIA Hit List -- Should US Presidents have the right to target US Citizens for assassination without any judicial review?

Description : Awlaki and the CIA Hit List -- Should US Presidents have the right to target US Citizens for assassination without any judicial review?

Last Answer : No.

A pilot has to release the bomb to hit a target – (1) right above the target (2) beyond the target (3) before the target (4) None of these

Description : A pilot has to release the bomb to hit a target – (1) right above the target (2) beyond the target (3) before the target (4) None of these

Last Answer : (3) before the target Explanation: According to Newton's first law, an object that is at rest will stay at rest unless an unbalanced force acts upon it and an object that is in motion will not change its velocity unless an unbalanced force acts upon it.

The probability that a man can hit a target is 2/3. The probability that he misses the target is ........ a. 1/2b. 1/4 c. 1/3 d. 3/4

Description : The probability that a man can hit a target is 2/3. The probability that he misses the target is ........ a. 1/2b. 1/4 c. 1/3 d. 3/4

Last Answer : c. 1/3

A pilot has to release the bomb to hit a target (1) right above the target (2) beyond the target (3) before the target (4) None of these

Description : A pilot has to release the bomb to hit a target (1) right above the target (2) beyond the target (3) before the target (4) None of these

Last Answer : before the target

An urn contains nine balls, of which three are red, four are blue and two are green. -Maths 9th

Description : An urn contains nine balls, of which three are red, four are blue and two are green. -Maths 9th

Last Answer : (b) \(rac{2}{7}\)Let S be the sample space having 9 balls (3R + 4B + 2G) Then n(S) = Total number of ways in which 3 balls can be drawn out of the 9 balls= \(rac{9 imes8 imes7}{3 imes2}\) = 84Let A : Event of drawing three ... 2 = 24.∴ P(A) = \(rac{n(A)}{n(S)}\) = \(rac{24}{84}\) = \(rac{2}{7}\).

A management institute has six senior professors and four junior professors. Three professors are selected at random -Maths 9th

Description : A management institute has six senior professors and four junior professors. Three professors are selected at random -Maths 9th

Last Answer : (a) \(rac{5}{6}\)P(At least one junior professor is selected) = P(Selecting 1 Junior) P(Selecting 2 Seniors) + P(Selecting 2 Junior) P(Selecting 1 Senior) + P(Selecting all 3 Juniors)∴ Required probability = \(rac{^4C_1 imes^ ... }{30}\) = \(rac{15+9+1}{30}\) = \(rac{25}{30}\) = \(rac{5}{6}\).

Two coins are tossed simultaneously for 360 times. The number of times ‘2 Tails’ appeared was three times ‘No Tail’ appeared and number of times ‘1 tail’ appeared is double the number of times ‘No Tail’ appeared. -Maths 9th

Description : Two coins are tossed simultaneously for 360 times. The number of times ‘2 Tails’ appeared was three times ‘No Tail’ appeared and number of times ‘1 tail’ appeared is double the number of times ‘No Tail’ appeared. -Maths 9th

Last Answer : Total number of outcomes = 360 Let the number of times ‘No Tail’ appeared be x Then, number of times ‘2 Tails’ appeared =3x Number of times ‘1 Tail’ appeared =2x Now, x + 2x + 3x =360 ⇒ 6x =360 ⇒ x= 60 P(of getting two tails)=(3 x 60) / 360 =1 / 2

Two coins are tossed simultaneously for 360 times. The number of times ‘2 Tails’ appeared was three times ‘No Tail’ appeared and number of times ‘1 tail’ appeared is double the number of times ‘No Tail’ appeared. -Maths 9th

Description : Two coins are tossed simultaneously for 360 times. The number of times ‘2 Tails’ appeared was three times ‘No Tail’ appeared and number of times ‘1 tail’ appeared is double the number of times ‘No Tail’ appeared. -Maths 9th

Last Answer : Total number of outcomes = 360 Let the number of times ‘No Tail’ appeared be x Then, number of times ‘2 Tails’ appeared =3x Number of times ‘1 Tail’ appeared =2x Now, x + 2x + 3x =360 ⇒ 6x =360 ⇒ x= 60 P(of getting two tails)=(3 x 60) / 360 =1 / 2

Five years hence , the age of Ram will be 10 more than the two thirds of Ravi’s age . Assume the present ages of Ram and Ravi as x and y respectively . Express the statement in the form of a linear equation in two variables. -Maths 9th

Description : Five years hence , the age of Ram will be 10 more than the two thirds of Ravi’s age . Assume the present ages of Ram and Ravi as x and y respectively . Express the statement in the form of a linear equation in two variables. -Maths 9th

Last Answer : answer:

Hari has some two rupee and five rupee coins .The total amount with him is rs. 43. Express the given information as a linear equation in two variables. -Maths 9th

Description : Hari has some two rupee and five rupee coins .The total amount with him is rs. 43. Express the given information as a linear equation in two variables. -Maths 9th

Last Answer : answer:

Five horses are in a race. Mr A. Selects two of the horses at random and bets on them. The probability that Mr A selected the winning horse is -Maths 9th

Description : Five horses are in a race. Mr A. Selects two of the horses at random and bets on them. The probability that Mr A selected the winning horse is -Maths 9th

Last Answer : (b) \(rac{2}{5}\)As each horse has equal chance of winning the race, Number of ways in which one of the five horses wins the race = 5C1 ∴ n(S) =5C1 = \(rac{|\underline5}{|\underline4|\underline1}\) 5To find the chance ... n(E) = 2C1 = 2 ∴ Required probability = \(rac{n(E)}{n(S)}\) = \(rac{2}{5}\).

the curved surface area of a cylinder is 154 cm. the total surface area of the cylinder is three times its curved surface area. find the volume of the cylinder. -Maths 9th

Description : the curved surface area of a cylinder is 154 cm. the total surface area of the cylinder is three times its curved surface area. find the volume of the cylinder. -Maths 9th

Last Answer : T.S.A = 3*154 = 462 cm² C.S.A = 154 cm² C.S.A = 2πrh T.S.A = 2πr(r+h) Now, In T.S.A = 2πrr + 2πrh 462 = 2πrr + 2πrh 462 = 2*22/7*r*r + 154 462 - 154 = 2*22/7*r*r 308*7/2*22 = r*r 49 = r*r R = 7 cm ... 7*h 154/44 = h 7/2 =h H = 3.5 cm or 7/2 cm Now volume = πrrh = 22/7 * 7* 7 *7/2 = 11*49 = 539 cm³

Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes ; -Maths 9th

Description : Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes ; -Maths 9th

Last Answer : Total number of chances = 23 + 72 + 77 + 28 = 200 Number of chances of coming 2 heads = 72 therefore P( coming 2 heads)= 514 / 642 = 9 / 25

Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes -Maths 9th

Description : Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes -Maths 9th

Last Answer : It is given that coin is tossed 200 times Total number of trials = 200 Number of events for getting less than three tails = 68 + 82 + 30 = 180 Probability of getting less than 3 tails =180 / 200 =9 / 10

Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes ; -Maths 9th

Description : Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes ; -Maths 9th

Last Answer : Total number of chances = 23 + 72 + 77 + 28 = 200 Number of chances of coming 2 heads = 72 therefore P( coming 2 heads)= 514 / 642 = 9 / 25

Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes -Maths 9th

Description : Three coins are tossed simultaneously 200 times with the following frequencies of different outcomes -Maths 9th

Last Answer : It is given that coin is tossed 200 times Total number of trials = 200 Number of events for getting less than three tails = 68 + 82 + 30 = 180 Probability of getting less than 3 tails =180 / 200 =9 / 10

Three coins were tossed 30 times simultaneously. -Maths 9th

Description : Three coins were tossed 30 times simultaneously. -Maths 9th

Last Answer : Frequency disribution of above data in tabular form is given as:

A fair coin is tossed three times. Let A, B and C be defined as follows: -Maths 9th

Description : A fair coin is tossed three times. Let A, B and C be defined as follows: -Maths 9th

Last Answer : The sample space is S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT} A = {HHH, HHT, HTH, HTT}, B = {HHH, HHT, THH, THT} and C = {HHT, THH} Also, A ∩ B = {HHH, HHT}, B ∩ C = {HHT, THH}, C ∩ A = {HHT}P (A ... (C), i.e., if the events are pairwise independent and (ii) P (A ∩ B ∩ C) = P (A) . P (B) . P (C)

A die is rolled three times. The probability of getting a larger number than the previous number each time is: -Maths 9th

Description : A die is rolled three times. The probability of getting a larger number than the previous number each time is: -Maths 9th

Last Answer : (b) \(rac{5}{24}\)Total number of ways three die can be rolled = 6 6 6 = 216 A larger number than the previous number can be got in the three throws as (1, 2, 3), (1, 2, 4), (1, 2, 5) ( ... , 5, 6). ∴ Total number of favourable cases = 20∴ Required probability =\(rac{20}{216}\) = \(rac{5}{24}\).

Which one of the following is the equation whose roots are respectively three times the roots of the equation ax^2 + bx + c = 0 ? -Maths 9th

Description : Which one of the following is the equation whose roots are respectively three times the roots of the equation ax^2 + bx + c = 0 ? -Maths 9th

Last Answer : answer:

The quadratic equation whose roots are three times the roots of 3ax^2 + 3bx + c = 0 is -Maths 9th

Description : The quadratic equation whose roots are three times the roots of 3ax^2 + 3bx + c = 0 is -Maths 9th

Last Answer : answer:

find the mean of first five multiples of 10 -Maths 9th

Description : find the mean of first five multiples of 10 -Maths 9th

Last Answer : This is the correct one...

Find the five rational no. Between5/7 and9/11 -Maths 9th

Description : Find the five rational no. Between5/7 and9/11 -Maths 9th

Last Answer : 5/7 and 9/11 find the lcm of 7 and 11 lcm =77. 5/7 *11/11=55/77 , 9/11*7/7=63/77 therefore five rational no are 56/77 57/77 58/77 59/77 60/77

If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th

Description : If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th

Last Answer : x + x + 2 + x + 4 + x + 6 + x + 8 / 5 = 11 5x + 20 = 55 5x = 35 ⇒ x = 7

Books are packed in piles each containing 20 books. Thirty five piles were examined for defective books and the results are given in the following table : -Maths 9th

Description : Books are packed in piles each containing 20 books. Thirty five piles were examined for defective books and the results are given in the following table : -Maths 9th

Last Answer : Total number of books = 700 (i) P(no defective books) = 400 / 700 = 4 / 7 (ii) P(more than 0 but less than 4 defective books) = 269 / 700 (iii) P(more than 4 defective books) = 13 / 700

find the mean of first five multiples of 10 -Maths 9th

Description : find the mean of first five multiples of 10 -Maths 9th

Last Answer : This is the correct one...

Find the five rational no. Between5/7 and9/11 -Maths 9th

Description : Find the five rational no. Between5/7 and9/11 -Maths 9th

Last Answer : 5/7 and 9/11 find the lcm of 7 and 11 lcm =77. 5/7 *11/11=55/77 , 9/11*7/7=63/77 therefore five rational no are 56/77 57/77 58/77 59/77 60/77

If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th

Description : If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th

Last Answer : x + x + 2 + x + 4 + x + 6 + x + 8 / 5 = 11 5x + 20 = 55 5x = 35 ⇒ x = 7

Books are packed in piles each containing 20 books. Thirty five piles were examined for defective books and the results are given in the following table : -Maths 9th

Description : Books are packed in piles each containing 20 books. Thirty five piles were examined for defective books and the results are given in the following table : -Maths 9th

Last Answer : Total number of books = 700 (i) P(no defective books) = 400 / 700 = 4 / 7 (ii) P(more than 0 but less than 4 defective books) = 269 / 700 (iii) P(more than 4 defective books) = 13 / 700

The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. -Maths 9th

Description : The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. -Maths 9th

Last Answer : NEED ANSWER