Description : A car starts from rest and moves on a straight road with a uniform acceleration of 10 m/s2 for the first 10 s. During the next 10 s, the car move s with the velocity it has attained. What is the total distance covered by the car in 20 s? (a) 500 m (b) 1000 m (c) 1,500 m (d) 2,000 m
Last Answer : Ans:(c)
Description : A 2 m long shaft rotates about one end at 20 rad/s. It begins to accelerate with ? = 10 rads/s2. After how long, in seconds, will the velocity of the free end reach 100 m/s? a.3 b.107 dynes c.5 d.6 e.7
Last Answer : a. 3
Description : A flywheel starting from rest and accelerating uniformly performs 25 revolutions in 5 sec. Its angular velocity in rpm after 10 seconds would be a.50 rpm b.20 rpm c.25 rpm d.60 rpm e.45 rpm
Last Answer : b. 20 rpm
Description : A ball moving with uniform velocity comes to rest in a distance of 72 m in 6 s. Its initial velocity and retardation are (a) 12 m/s and 2 m/s2 (b) 12 m/s and 4 m/s2 (c) 24 m/s and 8 m/s2 (d) 24 m/s and 4 m/s2
Last Answer : Ans:(d)
Description : A roller coaster reaches a velocity of 20 m/s at a location where the radius of curvature is 40 m. Calculate the acceleration in m/s2? a.10 b.9 c.11 d.8 e.107 dynes
Last Answer : a. 10
Description : A particle starts from rest and moves in a straight line whose equation of motion is given by S = 2t3 - t2 - 1. The acceleration of the particle after one sec will be a.6 m/sec2 b.4 m/sec2 c.12 m/sec2 d.10 m/sec2 e.8 m/sec2
Last Answer : d. 10 m/sec2
Description : The number of revolutions through which a pulley will rotate from rest if its angular acceleration is increased uniformly from zero to 12 rad per sec2 during 4 sec and then uniformly decreased to 0 rad per sec2 during the next 3 sec would be a.46.4 b.26.74 c.11.6 d.3.2 e.17.7
Last Answer : b. 26.74
Description : How much force is needed to accelerate a 15 kg bowling ball at 2m/s2?
Last Answer : 34
Description : A locomotive of weight 100 tonnes is attached to train of wagons weighing 1000 tonnes. The locomotive pulls the wagons with a constant velocity of 36 km/hour. When the coupling between the train and wagons breaks, the wagons roll on 95 m in ... would be a.0.36 m b.0.44 m c.0.77 m. d.0.5 m e.0.66 m
Last Answer : d. 0.5 m
Description : The angular acceleration of a flywheel decreases uniformly from 8 rad/sec2 to 2 rad sec2 in 6 sec at which time its angular velocity is 42 rad/sec. The initial angular velocity was a.12 rad/sec b.24 rad/sec c.30 rad/sec d.3 rad/sec e.6 rad/sec
Last Answer : a. 12 rad/sec
Description : A ball of mass 1 kg moving with a velocity of 2 m/sec collides directly with a stationary ball of mass 2 kg. If the first ball comes to rest after the impact the velocity of second ball after impact will be a.1.5 m/sec b.0.5 m/sec c.Zero d.2 m/sec e.1.0 m/sec
Last Answer : e. 1.0 m/sec
Description : The average person passes out at an acceleration of 7g (that is, seven times the gravitational acceleration on Earth). Suppose a car is designed to accelerate at this rate. How much time (in seconds) would be required for the car to accelerate from rest to 56.3 miles per hour?
Last Answer : I think the Fluther policy is not to help students with their homework, but I always hate this kind of problem and it seems to me that the g is just in there to provide some background and to confuse you.
Description : I just need to know a formula, or a lot more formulas, but there are always both unknowns in a formula.
Last Answer : I don't know how to fix it ... you have to do it yourself
Description : As the train starts moving, a man sitting inside leans backwards because of (a) Inertia of rest (b) Inertia of motion (c) Moment of inertia (d) Conservation of mass
Last Answer : Ans:(a)
Description : Stopping distance of vehicles : When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on ... the brake with the deceleration of 5m/s2. Find the stopping distance of the car -Science
Last Answer : Here u=72 km/hr = 72×10003600m/s=2072×10003600m/s=20 m/s , v=0 a= -5 m/s2 Now using the relation v2=u2+2asv2=u2+2as 0=(20)2+2×(−5)×s0=(20)2+2×(−5)×s s=40ms=40m
Description : An object dropped from a cliff falls with a constant acceleration of 10 m/s2. Find its speed 5 s after it was dropped. -Science
Last Answer : v=u+atv=u+at u=0u=0 v=10×5=50m/sv=10×5=50m/s
Description : A train 100 m long is moving with the velocity of 72 km/hr. Find the time it takes to cross the bridge which is 2 km long? -Science
Last Answer : Given Lenght of Train = 100m , velocity = 72 km/hr = 20 m/s, Lenght of the Bridge =2 Km. Total distance covered by the train to fully pass the bridge = 2000 + 100 = 2100 m So, time taken time=distancevelocity=210020=105sectime=distancevelocity=210020=105sec
Description : A ball tied with a string to a rotating shaft revolves at uniform speed. As the shaft is suddenly brought to rest, the string starts getting round the shaft with the angular velocity of the ball (a) increasing (b) decreasing (c) remaining constant (d) becoming zero
Description : A train accelerates from 36 km/h to 54 km/h in 10 sec. (i) Acceleration (ii) The distance travelled by car. -Science
Last Answer : a. Acceleration is given by a=ΔvΔta=ΔvΔt Δv=54−36=18km/hr=18×10003600m/s=5m/sΔv=54−36=18km/hr=18×10003600m/s=5m/s So a=.5 m/s2 b. Distance is given by S=ut+12at2S=ut+12at2 Now u=36 km/hr =10m/s s=10×10+12×.5×102s=10×10+12×.5×102 So s=125m
Description : An object starting from rest travels 20 m in first 2 s and 160 m in next 4 s.What will be the velocity after 7 s from the start. -Science
Last Answer : Total distance travelled by the object =20 m + 16 m = 36 m Total time taken = 4 s + 2 s = 6 s Average Speed=total Distance travelledtotal time taken Average Speed=total Distance travelledtotal time taken Average Speed=366=6Average Speed=366=6 m/s
Description : A car traveling at a constant velocity of 20 meters per second passes a second car which is initially at rest. The car which was at rest starts accelerating at 10 meters per second squared the instant it is passed ... car. They will meet again in: w) 2 seconds x) 4 seconds y) 6 seconds z) 8 seconds
Last Answer : ANSWER: X -- 4 SECONDS
Description : An object moves along a straight line with an acceleration of 2 m/s2. If its initial speed is 10 m/s, what will be its speed 2 s later? -Science
Last Answer : u=10 m/s,t=2 s, a=2 m/s2 v=u+atv=u+at v=10+2×2=14v=10+2×2=14 m/s
Description : In a 2280 m race Dinesh beats Aarav by 360 m or 6 seconds. In another race on the same track at the same speeds. Aarav and karthick start at one end while Dinesh starts at the opposite end. How many metres would Aarav ... is 16 m/sec more than that of karthick a) 1140 m b) 2280 m c) 2460 m d) 1180 m
Last Answer : B Aarav 's speed =360/6 =60 m/s Time taken by Aarav to cover 2280 m =2280/60= 38 seconds Dinesh 's speed = 2280/60=38 m/s karthick 's speed = 22m/s Time taken by Dinesh to meet karthick in ... direction: Distance covered by Aarav: =2280/(38+22) =2280/60 =38 seconds =(38*60)m =2280 m
Description : A car whose mass is 2 metric tons is accelerated uniformly from stand hill to 100 kmph in 5 sec. Find the driving force in Newton’s. a. 11,120 N b. 11,320 N c. 11,420 N d. 11520 N formula: F= ma / k
Last Answer : 11,120N
Description : A train 170 m long is running at a speed of 22.5 km/hr. what time will it take to cross a 80m long bridge? A) 20 sec B) 40 sec C) 15 sec D) 30sec
Last Answer : ANSWER:B Explanation: Length of the train = 170 m Length of the bridge = 80 m Therefore, length of the train + length of the bridge = (170 + 80) m = 250m Speed of the train = 22.5 km/hr Speed ... .25m/sec Therefore, time taken by the train to cross the bridge = 250 m/6.25 m/sec. = 40 seconds.
Description : A body moves, from rest with a constant acceleration of 5 m per sec. The distance covered in 5 sec is most nearly (A) 38 m (B) 62.5 m (C) 96 m (D) 124 m
Last Answer : (B) 62.5 m
Description : A train moving at 60 kilometers per hour is struck by a bullet moving 1000 m/sec at right angles to the train. The direction with which the bullet appears to strike the train would be a.75? b.60? c.22 d.30? e.45?
Last Answer : e. 45?
Description : A train is moving eastward at 10 m/sec. A waiter is walking eastward at 1.2m/sec; and a fly is flying toward the north across the waiter’s tray
Last Answer : A train is moving eastward at 10 m/sec. A waiter is walking eastward at 1.2m/sec; and a fly ... . What is the velocity of the fly relative to Earth.
Description : A passenger train 165 m long which is running at a speed of 30km/hr. In what time will it pass a man who is running at a speed of 3 km/hr in the opposite direction. In which the train is moving. A)14 sec B) 17sec C)16sec D)18sec
Last Answer : ANSWER: D Explanation: Speed of the train = 30 km/hr Speed of man = 3 km/hr Length of the train = 165m If direction is given in opposite direction then we add both speed. That is (30 + 3 )= 33 km/hr ... can easily get the distance of m/s So it cover 165 m i.e., 165 * 6 /55 = 18 sec.
Description : Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 -3 m 3. Natural frequency of the system = 60 rad/sec ... /m B. 80 x 10 3 N-s/m C. 42 x 10 3 N-s/m D. None of the above
Last Answer : C. 42 x 10 3 N-s/m
Description : Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 -3 m 3. Natural frequency of the system = 60 rad/sec ... /m b. 80 x 10 3 N-s/m c. 42 x 10 3 N-s/m d. None of the above
Last Answer : c. 42 x 10 3 N-s/m
Description : A lake starts freezing because of the cold atmosphere. It will first freeze A. At the bottom B. ln the middle pan C. At the top surface (Answer) D. Uniformly throughout the water body
Last Answer : C. At the top surface (Answer)
Description : It takes 60 sec for a train running at 162 km/hr to cross a bridge. And it takes 36 sec for the same speed to cross a boy walking at the rate of 18km/hr in the same direction in which the train is ... the train and length of the platform. A) 1440 &1260m B) 1220 &60m C) 1000 & 1460m D) 1260 &1450m
Last Answer : ANSWER: A Explanation: Relative speed of the train to man = (162 - 18) = 144km/hr Convert km/hr into m/s 144km/hr = (144 * 5 /18) m/s = 40 m/s When the train passes ... of bridge = 2700 length of bridge = 1260 m the length of the bridge & train are 1260 and 1440m
Description : Two metro train 360 meters and 360 meters in length respectively and running in same directions, one at the rate of 116 km and other at the rate of 100 km an hours. What time will they be cross of each other? A) 100 sec B) 162sec C) 132sec D) 126sec
Last Answer : ANSWER: B Explanation: Length of the 1st metro train = 360m Length of the 2nd metro train = 360m Total length of the both metro train = 360 + 360 = 720 m speed of the 1st metro train = 116 km/hr ... Required time = distance / speed = (720/(40/9))sec = 720 * 9 /40 = 162sec.
Description : A lake starts freezing because of the cold atmosphere, It will first freeze A. At the bottom B. In the middle part C. At the top surface D. Uniformly throughout the water body
Last Answer : ANSWER: C
Description : Calculate the value of critical damping coefficient if a vibrating system has mass of 4kg and stiffness of 100N/m A 20 N-sec/m B 40 N-sec/m C 60 N-sec/m D 80 N-sec/m
Last Answer : B 40 N-sec/m
Description : Calculate: a. Mass flow rate in lb/hr. b. The velocity at section 2 in fps a. 800,000lb/hr;625ft/s b. 900,000lb/hr;625 ft/s c. 888,000lb/hr;269 ft/s d. 700,000lb/hr;269 ft/s m = A1V!/V1
Last Answer : 900,000 lb/hr;625 ft/s
Description : A train starts its journey from a stationary position and after running for 1 minute in parallel, 30 m / s speed is obtained. Determine the speed of the train in 1 minute ?
Last Answer : Here , the initial velocity , u = 0 m / s end velocity , v = 30 m / s time , t = 1 min = 60 sec we know , acceleration , a = (v- u) / t = (30- 0) / 60 = 0.5 m / s ^ 2 Acceleration = 0.5 m / s ^ 2
Description : The distance between two cities A and B is 330km. A train starts from A at 8 (a)m. and travels towards B at 60 km/hr. Another train starts from B at 9 (a)m. and travels towards A at 75 km/hr. At what time do they meet? a) 10 am. b) 10 : 30 am. c) 11 am. d) 11 : 30 am. e) None of these
Last Answer : Distance travelled by first train in one hour = 60 x 1 = 60 km Therefore, distance between two train at 9 a.m. = 330 – 60 = 270 km Now, Relative speed of two trains = 60 + 75 = 135 km/hr Time of meeting of two trains =270/135=2 hrs. Therefore, both the trains will meet at 9 + 2 = 11 A.M. Answer: c)
Description : Two stations X and Y are 170 km apart on a straight line. One train starts from X at 6 a.m. and travels towards Y at 25 kmph. Another train starts from Y at 8 a.m. and travels towards X at a speed of 35 kmph. At what time will they meet? a) 11. 30 a.m b) 10.30 a.m c) 11 a.m d) 9 a.m e) 10 am
Last Answer : e Suppose they meet z hours after 6 a.m. Distance covered by X in z hours = 25× z km. Distance covered by Y in (z - 2) hours = 35(z - 2) km. Therefore 25z + 35(z- 2) = 170 60z = 240 x = 4. So, they meet at 10 a.m.
Description : The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these
Last Answer : Answer – C (11 am) Explanation – Suppose they meet x hrs after 8 a.m. Then, (Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs] = 330 60x + 75(x – 1) = 330 x = 3 So, they meet at (8 + 3), i.e. 11 a.m
Description : A mail train 220 m long is running with a sped of 120 km/hr. What is the time in which it will pass a man who starts from the engine running at the speed of 12km/hr in the direction opposite to that of the train. A) 6sec B) 5sec C) 4sec D) 3sec
Last Answer : ANSWER: A Explanation: We know as the train and the running person are moving in opposite direction,therir speed values are added to find the relative speed. Relative speed = speed of mail train + speed of running ... [ from the length of the mail train is the distance] = 220 / 36.66 = 6 sec.
Description : Calculate the emf when a coil of 100 turns is subjected to a flux rate of 0.3 tesla/sec. a) 3 b) 30 c) -30 d) -300
Last Answer : c) -30
Description : An aeroplane has a run of 500 m to take off from the runway. It starts from rest and moves with constant acceleration
Last Answer : An aeroplane has a run of 500 m to take off from the runway. It starts from rest and moves with ... is the velocity of the aeroplane at the take off ?
Description : A train travels between two stations 15 km apart in 18 minutes. If the train accelerates for a part of journey uniformly followed by uniform retardation, the maximum speed attained by the train during the journey will by a.125 km/hr b.107 dynes c.80 km/hr d.100 km/hr e.60 km/hr
Last Answer : d. 100 km/hr
Description : A train travels between two stations 15 km, apart in 18 minutes. If the train accelerates for a part of journey uniformly followed by uniform relardation, the maximum speed attained by the train, during, the journey, will be a.60 km/hr b.80 km/hr c.125 km/hr d.100 km/hr e.107 dynes
Description : Please ripley me due to emergency
Last Answer : To calculate the flux density in the ring, you need to use the following formula: B = (μ * I * N) / (2 * π * r) where: B is the flux density in the ring (in teslas) μ is the relative permeability ... 2 * π * 0.127 m) = 0.53 T So the flux density in the ring would be approximately 0.53 teslas.
Description : What is the total acceleration of a point on the rim of a flywheel 4 mts in diameter 0.6 see after it has started from rest if it accelarates uniformly from rest to 2000 rpm in 20 secs. a.68.9 mts/sec2 b.102.6 mts/sec2 c.78.94 mts/sec2 d.107 dynes e.33.2 mts/sec2
Last Answer : c. 78.94 mts/sec2
Description : A cannon of weight 10 tonnes fires a shell of 50 kg with a muzzle velocity of 900 m/sec at an angle of 30?. The time taken for the shell to emerge from the barrel is 0.004 sec. The velocity of the cannon would be a.3.9 m/sec b.7.8 m/sec c.8.95 m/sec d.1.95 m/sec e.5.85 m/sec
Last Answer : a. 3.9 m/sec