The combined age of a father and daughter is 66. The daughter is the same age as the father. But with the digits reversed. What are their ages? -Riddles

The combined age of a father and daughter is 66. The daughter is the same age as the father. But with the digits reversed. What are their ages? -Riddles
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Answer :

There are three correct answers 51 and 15, 42 and 24, or 60 and 6.
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The ages of a father and son add up to 66. The father's age is the son's age reversed. How old could they be? (3 possible solutions). -Riddles

Description : The ages of a father and son add up to 66. The father's age is the son's age reversed. How old could they be? (3 possible solutions). -Riddles

Last Answer : 51 and 15. 42 and 24. 60 and 06.

Shyam is younger than Sharuk by 22 years. If the ratio of their ages is 5:7, find the age of Shyam a) 55 b) 77 c) 66 d) 88

Description : Shyam is younger than Sharuk by 22 years. If the ratio of their ages is 5:7, find the age of Shyam a) 55 b) 77 c) 66 d) 88

Last Answer : A If sharuk age is x, then Shyam age is x-22, so (x-22)/x = 5/7 => 7x-154 = 5x => 2x = 154 => x = 77 So shyam age is 77 - 22 = 55

A two digit number is such that the sum of the digits is 11.When the number with the same digits is reversed is subtracted from this number, the difference is 9.What is the number? 1. 23 2. 24 3. 65 4. 14 5. 32

Description : A two digit number is such that the sum of the digits is 11.When the number with the same digits is reversed is  subtracted from this number, the difference is 9.What is the number? 1. 23 2. 24 3. 65 4. 14 5. 32

Last Answer : Answer- 3(65) Explanation:- let the number be written as xy x-ten’s place y units place x+y=11…………………1 (10x+y)-(10y+x)=9 10x+y-10y-x=9 9x-9y=9 x-y=1………………….2 Add (1) & (2) 2x=12 x=6 y=5 the number is 65

The ratio of the present ages of Rupa and her daughter is ` 7 : 3`. When Rupa was 26 years old, her daughter was 6 years old . Find the present age of

Description : The ratio of the present ages of Rupa and her daughter is ` 7 : 3`. When Rupa was 26 years old, her daughter was 6 years old . Find the present age of

Last Answer : The ratio of the present ages of Rupa and her daughter is ` 7 : 3`. When Rupa was 26 years old, ... old . Find the present age of Rupa. (in years)

In a two-digit number, the sum of the digits is 9. If 9 is subtracted from the number, then the digits get reversed. Find the product of the digits

Description : In a two-digit number, the sum of the digits is 9. If 9 is subtracted from the number, then the digits get reversed. Find the product of the digits

Last Answer : In a two-digit number, the sum of the digits is 9. If 9 is subtracted from the number, then the digits get reversed. Find the product of the digits

The 2 digit number which becomes (5/6)th of itself when its digits are reversed. The difference in the digits of the number being 1, then the two digits number is (a) 45 (b) 54 (c) 36 (d) None of these

Description : The 2 digit number which becomes (5/6)th of itself when its digits are reversed. The difference in the digits of the number being 1, then the two digits number is (a) 45 (b) 54 (c) 36 (d) None of these

Last Answer : (b) 54

The 2 digit number which becomes (5/6)th of itself when its digits are reversed. The difference in the digits of the number being 1, then the two digits number is (a) 45 (b) 54 (c) 36 (d) None of these

Description : The 2 digit number which becomes (5/6)th of itself when its digits are reversed. The difference in the digits of the number being 1, then the two digits number is (a) 45 (b) 54 (c) 36 (d) None of these

Last Answer : (b) 54

In an examination mahi scores 64% of marks, nitesh scores 52% of marks and ritesh scores 48% of marks. The maximum mark of the exam is a three digit number, whose sum is 10 and the middle digit is equal to the sum of the other two digits. The number will decreased by 297, if its digit are reversed. approximately what is the average mark obtained by mahi, nitesh and ritesh? A) 247 B) 248 C) 264 D) 284

Description : In an examination mahi scores 64% of marks, nitesh scores 52% of marks and ritesh scores 48% of marks. The maximum mark of the exam is a three digit number, whose sum is 10 and the middle digit is equal to ... what is the average mark obtained by mahi, nitesh and ritesh? A) 247 B) 248 C) 264 D) 284

Last Answer : A) Maximum mark consist of a three digit number let's consider Unit digit place is Z,ten's place digit is Y and hundred's place digit is X. According to the question, Y=x+z---------1 X+Y ... Total number of Mahi, Nitesh and Ritesh =164/100 451=739.61 Required average =739.64/3=246.54~247.

Suresh and Ramesh are twins. In a form by mistake, Suresh reverses the last 2 digits of his year of birth, and this makes him 9 years older than Ramesh. With this mistake, the sum of their ages in 2015 becomes 43. How old will Ramesh be 2021? a) 17 b) 19 c) 21 d) 23 e) 25

Description : Suresh and Ramesh are twins. In a form by mistake, Suresh reverses the last 2 digits of his year of birth, and this makes him 9 years older than Ramesh. With this mistake, the sum of their ages in 2015 becomes 43. How old will Ramesh be 2021? a) 17 b) 19 c) 21 d) 23 e) 25

Last Answer : Let the correct ages of Ramesh and Suresh be X in 2015 (since they are twins, they will have the same age) Given: 2x + 9 = 43 Or x = 17 years in 2015. Age in 2021 = 17 + 6 = 23 Note: year of birth = 2015 – 17 = 1998. Reversing, Suresh = 1989 or 9 year older. Answer: d)

A man has nine children, born at regular intervals. The sum of their squares of their ages is equal to the square of his own age.What are the ages of the children? -Riddles

Description : A man has nine children, born at regular intervals. The sum of their squares of their ages is equal to the square of his own age.What are the ages of the children? -Riddles

Last Answer : 2 - 5 - 8 - 11 - 14 - 17 - 20 - 23 - 26

How many strings of 5 digits have the property that the sum of their digits is 7 ? (A) 66 (B) 330 (C) 495 (D) 99

Description : How many strings of 5 digits have the property that the sum of their digits is 7 ? (A) 66 (B) 330 (C) 495 (D) 99

Last Answer : (B) 330

The sum of present ages of a father and his son is 36 years. When the son reaches father’s present age, the sum of their ages will be 80 years. What is the present age of the son? a) 4 years b) 7 years c) 9 years d) 12 years e) None of these

Description : The sum of present ages of a father and his son is 36 years. When the son reaches father’s present age, the sum of their ages will be 80 years. What is the present age of the son? a) 4 years b) 7 years c) 9 years d) 12 years e) None of these

Last Answer : Difference in two sums = 80- 36 = 44 Age of both are increased by 44/2 = 22 years Difference in ages of father and son = 22 years sum of present ages of father and son = 36 years Son’s present age = 1/2 × (36 - 22) = 7 years Answer: b)

The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these

Description : The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these

Last Answer : Sum of present ages = 35 years sum of their ages will be 85 years after (85-35) / 2 = 25 years from now. the father is 25 years older than his son. Present age of father = (35 + 25)/2 = 30 years. Answer: c)

Age of father 30 years ago was 9 times the age of her son. After 30 years, father’s age will be thrice that of his son. Find the ratio of their present ages. a) 21 : 5 b) 29 : 5 c) 27 : 4 d) 21 : 3

Description : Age of father 30 years ago was 9 times the age of her son. After 30 years, father’s age will be thrice that of his son. Find the ratio of their present ages. a) 21 : 5 b) 29 : 5 c) 27 : 4 d) 21 : 3

Last Answer : A At age of son be x and as father's age is 9 times the age of her son, let it be 9x, nine years ago. At present: father's age will be (9x + 30) and son's age will be (x + 30) After 30 years: father's age ... x = 20 We are asked to find the present ratio. (9x + 30) : (x + 30) = 210 : 50 = 21:5

The digits of a two-digit number are in the ratio of 2 : 3 and the number obtained by interchanging the digits is bigger than the original number by 27.What is the original number? 1. 63 2. 48 3. 96 4. 69 5. 66

Description : The digits of a two-digit number are in the ratio of 2 : 3 and the number obtained by interchanging the digits is bigger than the original number by 27.What is the original number? 1. 63 2. 48 3. 96 4. 69 5. 66

Last Answer : Answer- 4 (69) Explanation:- lets digit at tens and ones place be 2x and 3x So,number is 2x*10 + 3x After interchanging number will be 3x*10 +2x so, [3x*10 +2x] – [2x*10 + 3x]27 we get,x=3 so number =69

A and B are 3 years and 2 years old respectively. Their father is 40 years. After how many years, father’s age would be twice of combined age of A and B? a) 5 years b) 10 years c) 15 years d) 20 years e) None of these

Description : A and B are 3 years and 2 years old respectively. Their father is 40 years. After how many years, father’s age would be twice of combined age of A and B? a) 5 years b) 10 years c) 15 years d) 20 years e) None of these

Last Answer : Father’s age = 40 years. Children’s combined age = 3 + 2= 5 years Double of their ages = 2 × 5 = 10 years Difference between father’s age and combined age = 40 – 10 = 30 years required time = 1/ (2 + 1) × 30 = 10 years Answer: b)

I am a two-digit number. All my digits are even. No two digits are the same. None of my digits are prime numbers. I am not a multiple of ten. My tens digit is bigger than my other numbers. If you followed all the previous steps, there should be three options remaining the number is the option where if you add all the digits it’s exactly in the middle (in how big the number is) of all the other options with their digits added together. What number am I? -Riddles

Description : I am a two-digit number. All my digits are even. No two digits are the same. None of my digits are prime numbers. I am not a multiple of ten. My tens digit is bigger than my other numbers. ... big the number is) of all the other options with their digits added together. What number am I? -Riddles

Last Answer : If you followed all the steps apart from the last one there will be three options remaining: 64, 84, and 86. You then had to add up the digits, 64=6+4=10, 84=8+4=12, and 86=8+6=14. ... biggest number (12) and put it back as it was before the digits were added together and your answer should be 84.

Father offered a gift to his Daughter and told ......... i. If you feel hungry, you may eat it. ii. If you feel thirsty, you may drink it. iii. If you feel coldish, you may burn it. So, what is that gift that father presented to the daughter? -Riddles

Description : Father offered a gift to his Daughter and told ......... i. If you feel hungry, you may eat it. ii. If you feel thirsty, you may drink it. iii. If you feel coldish, you may burn it. So, what is that gift that father presented to the daughter? -Riddles

Last Answer : A coconut.

A girl is twice as old as her brother and half as old as her father. In 50 years, her brother will be half as old as his father. How old is the daughter now? -Riddles

Description : A girl is twice as old as her brother and half as old as her father. In 50 years, her brother will be half as old as his father. How old is the daughter now? -Riddles

Last Answer : 50 years old.

Once upon a time there was a beautiful princess named Anna. Anna's father, the King, wanted to be sure his daughter married an intelligent man. To test his daughter's suitors the King hid Anna's picture in one of three boxes. The suitor had to be able to select the box with Anna's picture on one try and within twenty seconds. On the gold box was the message 'Anna's picture is in this box'. The silver box had the message 'Anna's picture is not in this box.' 'Anna's picture is not in the gold box' was written on the bronze box. The King would tell each suitor 'Only one of the three messages is correct.' Which box contained Anna's picture? -Riddles

Description : Once upon a time there was a beautiful princess named Anna. Anna's father, the King, wanted to be sure his daughter married an intelligent man. To test his daughter's suitors the King hid Anna's ... each suitor 'Only one of the three messages is correct.' Which box contained Anna's picture? -Riddles

Last Answer : The silver box contained Anna's picture. If her picture had been in the gold box, two statements would have been true. (The messages on both the gold box and the silver box.) If her picture had ... bronze box, two statements would have been true. (The messages on the bronze box and the silver box.)

Four people are sitting around a campfire after a long day of recreation, when one man comments: 'Do you realize that around this campfire, the four of us include a mother, father, brother, sister, son, daughter, niece, nephew, aunt, uncle and a couple cousins'?. If everyone is related by blood (with no unusual marriages) how is this possible? -Riddles

Description : Four people are sitting around a campfire after a long day of recreation, when one man comments: 'Do you realize that around this campfire, the four of us include a mother, father, brother, sister, ... '?. If everyone is related by blood (with no unusual marriages) how is this possible? -Riddles

Last Answer : The campfire circle includes a woman and her brother. The woman's daughter and the man's son are also present.

A cloud was my mother, the wind is my father, my son is the cool stream, and my daughter is the fruit of the land. A rainbow is my bed, the earth my final resting place, and I'm the torment of man. Who Am I? -Riddles

Description : A cloud was my mother, the wind is my father, my son is the cool stream, and my daughter is the fruit of the land. A rainbow is my bed, the earth my final resting place, and I'm the torment of man. Who Am I? -Riddles

Last Answer : Rain.

The sum of two children is ‘a’. The age of the father is twice the ‘a’. After twenty years, his age will be equal to the addition of the ages of his children. Find the age of father. -Maths 10th

Description : The sum of two children is ‘a’. The age of the father is twice the ‘a’. After twenty years, his age will be equal to the addition of the ages of his children. Find the age of father. -Maths 10th

Last Answer : Let the sum of the ages of two children will be x and age of father will be y. A.T.Q. , y = 2x ----------(i) and , After 20 years, x+40=y+20 ==> ... i), x-2x = -20 ==> x = 20 Now, put x= 20 in (i), y = 2 x 20 = 40 Hence age of father will be 40 years.

The sum of ages of Sunil and his father is 46 years. 3 years back, father’s age was 4 times sunil’s age. find present age of Sunil. a) 7 years b) 8 years c) 11 years d) 12 years e) None of these

Description : The sum of ages of Sunil and his father is 46 years. 3 years back, father’s age was 4 times sunil’s age. find present age of Sunil. a) 7 years b) 8 years c) 11 years d) 12 years e) None of these

Last Answer : Sum of their ages, 3 years ago = 46 – (2 × 3) = 40 years sunil’s age, 3 years ago = 1/5 × 40 = 8 years sunil’s present age = 8 + 3 = 11 years Answer: c)

Fathima's father was 76 years of age when she was born while her mother was 72years old when her brother 8 years younger to her was born. What is the difference between the ages of her parents? a)12 years b)14 years c)16 years d)18 years

Description : Fathima's father was 76 years of age when she was born while her mother was 72years old when her brother 8 years younger to her was born. What is the difference between the ages of her parents? a)12 years b)14 years c)16 years d)18 years

Last Answer : A Mother's age when Fathima 's brother was born = 72 years. Father's age when Fathima 's brother was born = (76+8) years = 84 years. Required difference = (84-72) years = 12 years

The sum of the current ages of a father and his son is 84 years. 7 years ago, father's age was 3 times the age of the son. After 7 years, son's age will be a) 35 years b) 28 years c) 56years d) 53 years

Description : The sum of the current ages of a father and his son is 84 years. 7 years ago, father's age was 3 times the age of the son. After 7 years, son's age will be a) 35 years b) 28 years c) 56years d) 53 years

Last Answer : A Son’s current age = x years. Then father’s age = (84 - x)years (84 - x) - 7 = 3(x - 7) 2x=56 x =28; after 7years it will be turn on 35 

In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these

Description : In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these

Last Answer : Let current age of Ram and his son be R,S (R + 10) = 3(S + 10) [2 times older = 3 times the age] R = 3S + 20 (R - 5) = 9(S - 5) 3S + 20 – 5= 9S – 45 3S + 15 = 9S – 45 or S = 10., R = 50 sum of ages 3 years from now = 10 + 3 + 50 + 3 = 66. Answer: b)

John is talking to Mary while working on a deal book at 2AM. Mary learns that John's sister has three children. 'How old are the children?' asks Mark.'Well,' replies John, 'the product of their ages is 36.' 'Hmmm, the sum of their ages is the same as this figure right here,' says John pointing at the spreadsheet. 'Still not enough information' says Mary after thinking for a minute. 'The eldest is dyslexic' says John. How old are the children? -Riddles

Description : John is talking to Mary while working on a deal book at 2AM. Mary learns that John's sister has three children. 'How old are the children?' asks Mark.'Well,' replies John, 'the product of their ... after thinking for a minute. 'The eldest is dyslexic' says John. How old are the children? -Riddles

Last Answer : This answer was deleted by moderators

I am a five-digit whole number, read the same forward, backward and upside down. My second digit is half my third digit; my fifth digit is the product of my first and last digits; and the sum of my whole is ten. What am I? -Riddles

Description : I am a five-digit whole number, read the same forward, backward and upside down. My second digit is half my third digit; my fifth digit is the product of my first and last digits; and the sum of my whole is ten. What am I? -Riddles

Last Answer : 10801

In the same way you can make four fives in an equation to equal 100, (5+5)X(5+5)=100, can you make an equation with only four sevens and no other digits to make 100? -Riddles

Description : In the same way you can make four fives in an equation to equal 100, (5+5)X(5+5)=100, can you make an equation with only four sevens and no other digits to make 100? -Riddles

Last Answer : (7/.7)X(7/.7)=100 As 7/.7 = 10 The equation becames equivalent to 10X10

When `PtE_(6)` vapour mixed with an equal volume of Xe, the gases combined immediatedly at room temperature and produces a yellow solid X at `66^(@)C`

Description : When `PtE_(6)` vapour mixed with an equal volume of Xe, the gases combined immediatedly at room temperature and produces a yellow solid X at `66^(@)C`

Last Answer : When `PtE_(6)` vapour mixed with an equal volume of Xe, the gases combined immediatedly at room temperature and produces ... ]^(+) [Pt_(2)F_(11)]^(-)`

When the average age of a father, mother and their son was 90 years, the son got married and a child was born just 6 year after the marriage when child turned 14 years the average age of the family is 80yrs. Find the age of daughter - in - law at present? A) 55 B) 56 C) 57 D) 58

Description : When the average age of a father, mother and their son was 90 years, the son got married and a child was born just 6 year after the marriage when child turned 14 years the average age of the family is 80yrs. Find the age of daughter - in - law at present? A) 55 B) 56 C) 57 D) 58

Last Answer : B) total age of father, mother and son at the time of son's marriage = 90*3 =270 present age of family father, mother, son, daughter-in-law, child = (father, mother, son age at the time of marriage ... 60)+ daughter-in-law present age + 14 = 80*5 =400 daughter-in-law present age= 400-344 = 56yrs

I have four digits, I own a lot of cash money money, I'm kept a secret, but used on the daily. What am I? -Riddles

Description : I have four digits, I own a lot of cash money money, I'm kept a secret, but used on the daily. What am I? -Riddles

Last Answer : Pin number.

Four letters form me quite complete, As all who breathe do show; Reversed, you'll find I am the seat Of infamy and woe. Transposed, you'll see I'm base and mean, Again of Jewish race; Transposed once more, I oft am seen To hide a lovely face.What are the five words? -Riddles

Description : Four letters form me quite complete, As all who breathe do show; Reversed, you'll find I am the seat Of infamy and woe. Transposed, you'll see I'm base and mean, Again of Jewish race; Transposed once more, I oft am seen To hide a lovely face.What are the five words? -Riddles

Last Answer : Live, evil, vile, Levi, veil.

If a couple is 5 years or more apart in age, and they both experienced the same social changing events, but at different ages, can you spot the nuances that display this?

Description : If a couple is 5 years or more apart in age, and they both experienced the same social changing events, but at different ages, can you spot the nuances that display this?

Last Answer : My step mom is 15years younger than my dad. They both experienced things at different ages that is true but they both see things pretty much eye to eye. Also know another couple where she is ... upbringing might have totally debunked by the time they come around for the younger one type thing??

I am a three-digit number. All of my digits are prime. One of the numbers is even. Each of my numbers are used only once. The total of my first and last digits equals 10. The total of my first two digits equals 5. -Riddles

Description : I am a three-digit number. All of my digits are prime. One of the numbers is even. Each of my numbers are used only once. The total of my first and last digits equals 10. The total of my first two digits equals 5. -Riddles

Last Answer : This one is fairly easy if you use elimination if you follow all the first 5 steps you get three options: 525, 327, and 723 but if you followed the last step you would reach your answer. The answer was 327.

What is the smallest whole number that is equal to seven times the sum of its digits? -Riddles

Description : What is the smallest whole number that is equal to seven times the sum of its digits? -Riddles

Last Answer : The answer to this math riddle is 21. You probably just guessed to answer this math riddle, which is fine, but you can also work it out algebraically. The two-digit number ab stands for 10a + b since the ... a = 2b. That is, the second digit must be twice the first. The smallest such number is 21.

I have 3 digits. The tens place is 3 more than the ones place the hundrends place is 2 more than the tens place. What number am I? -Riddles

Description : I have 3 digits. The tens place is 3 more than the ones place the hundrends place is 2 more than the tens place. What number am I? -Riddles

Last Answer : 863!

What four digit positive, whole number has its last and first digits equal, addition of its last two digits is equal to its second digit. And the product of the squares of its last two digits is equal to four two noughts. -Riddles

Description : What four digit positive, whole number has its last and first digits equal, addition of its last two digits is equal to its second digit. And the product of the squares of its last two digits is equal to four two noughts. -Riddles

Last Answer : 5945. 5=5. 4+5=9=second digit 4^2 x 5^2 = 400 = four two noughts

What is the highest number that can be written with three digits? -Riddles

Description : What is the highest number that can be written with three digits? -Riddles

Last Answer : (9⁹)⁹ = 9³⁸⁷⁴²⁰⁴⁸⁹, which is a number with more than 369 million digits.

What two-digit number equals two times the result of multiplying its digits? -Riddles

Description : What two-digit number equals two times the result of multiplying its digits? -Riddles

Last Answer : 36 = 2 x 3 x 6.

What is the 4 digit number in which the first digit is one-fifth of the last, and the second and third digits are the last digit multiplied by 3? -Riddles

Description : What is the 4 digit number in which the first digit is one-fifth of the last, and the second and third digits are the last digit multiplied by 3? -Riddles

Last Answer : 1155

This number added to it's square, and the digits of that summation added together, bring it back to itself. What is it? -Riddles

Description : This number added to it's square, and the digits of that summation added together, bring it back to itself. What is it? -Riddles

Last Answer : 3. 3 squared is 9. 3+9=12. Take the two digits of the summation and add them; 1+2=3. In short; 3-9-12-3. This can also work with the number 0 and 9.

0,1,2,3,4,5,6,7,8,9 Use the digits above once each only to compose two fractions which when added togeather equal 1. -Riddles

Description : 0,1,2,3,4,5,6,7,8,9 Use the digits above once each only to compose two fractions which when added togeather equal 1. -Riddles

Last Answer : 35/70 + 148/296 = 1

(A) Use two digits to make the smallest possible positve intiger.(B) Five 3s can express 37: 37=33+3+3/3Find another way to do it.(C) Use six identical dgits to make 100. (Several solutions are possible.)(D) Use five 4s to make 55.(E) Use four 9s to make 20. -Riddles

Description : (A) Use two digits to make the smallest possible positve intiger.(B) Five 3s can express 37: 37=33+3+3/3Find another way to do it.(C) Use six identical dgits to make 100. (Several solutions are possible.)(D) Use five 4s to make 55.(E) Use four 9s to make 20. -Riddles

Last Answer : (A) 1 X 1; 1/1;2/2;ect....;1-0;2-1;and many others. (B) 37=333/3X3; 37=3 X 3 X 3 + 3/.3 (C) 99 + 99/99; 55+55- 5- 5; (666-66)/6 (D) 44 + 44/4=55. (E) 9 + 99/9=20.

When the celebrated German mathematician Karl Friedrich Gauss (1777-1855) was nine he was asked to add all the integers from 1 through 100. He quickly added 1 to 100, 2 to 99, and so on for 50 pairs of numbers each adding to 101. 50 X 101=5,050.Now find the sum of all the digits in integers from 1 through 1,000,000,000.That's all the digits in all the numbers, not all the numbers themselves. -Riddles

Description : When the celebrated German mathematician Karl Friedrich Gauss (1777-1855) was nine he was asked to add all the integers from 1 through 100. He quickly added 1 to 100, 2 to 99, and so on for 50 pairs ... 1,000,000,000.That's all the digits in all the numbers, not all the numbers themselves. -Riddles

Last Answer : The numbers can be grouped by pairs: 999,999,999 and 0; 999,999,998 and 1' 999,999,997 and 2; and so on.... There are half a billion pairs, and the sum of the digits in each pair is 81. The digits in the unpaired number, 1,000,000,000, add to 1. Then: (500,000,000 X 81) + 1= 40,500,000,001.

How many pluses should we put between the digits of 987,654,321 to get a total of 99, and where? -Riddles

Description : How many pluses should we put between the digits of 987,654,321 to get a total of 99, and where? -Riddles

Last Answer : (6) 9 + 8 + 7 + 6 + 5 + 43 + 21= 99 (7) 9 + 8 + 7 + 65 + 4 + 3 + 2 + 1= 99