In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these

In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now?
a) 46
b) 66
c) 86
d) 76
e) None of these
by

1 Answer

Answer :

Let current age of Ram and his son be R,S
(R + 10) = 3(S + 10) [2 times older = 3 times the age]
R = 3S + 20
(R - 5) = 9(S - 5)
3S + 20 – 5= 9S – 45
3S + 15 = 9S – 45
or S = 10., R = 50
sum of ages 3 years from now = 10 + 3 + 50 + 3 = 66.
Answer: b)
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Description : Suresh and Ramesh are twins. In a form by mistake, Suresh reverses the last 2 digits of his year of birth, and this makes him 9 years older than Ramesh. With this mistake, the sum of their ages in 2015 becomes 43. How old will Ramesh be 2021? a) 17 b) 19 c) 21 d) 23 e) 25

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Three year ago, ratio of Tom and Ram age’s was 5 : 6 respectively. After 12 years, this ratio becomes 6 : 7. How old is Ram at present? a) 39years b) 93 years c) 78 years d) 87 years

Description : Three year ago, ratio of Tom and Ram age’s was 5 : 6 respectively. After 12 years, this ratio becomes 6 : 7. How old is Ram at present? a) 39years b) 93 years c) 78 years d) 87 years

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if the ratio of the ages (in years) of A and B, 5 years ago was 5:7, then which of the following can be the sum of their ages 5 years from now?

Description : if the ratio of the ages (in years) of A and B, 5 years ago was 5:7, then which of the following can be the sum of their ages 5 years from now?

Last Answer : if the ratio of the ages (in years) of A and B, 5 years ago was 5:7, then which of the following can be ... years from now? A. 90 B. 98 C. 92 D. 87

A man distributed 43 chocolates to his children. How many of his children are more than five years old? I. A child older than five years gets 5 chocolates II. A child 5 years or younger in age gets 6 chocolates. If the question can be answered with the help of statement I alone, If the question can be answered with the help of statement II alone, If both,statement I and statement II are needed to answer the question If the question cannot be answered even with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Description : A man distributed 43 chocolates to his children. How many of his children are more than five years old? I. A child older than five years gets 5 chocolates II. A child 5 years or younger ... the statements. If the data in either statement I or statement II alone is sufficient to answer the question

Last Answer : From both statement I and II: Let the number of chocolates received by child older than 5 years be x and that of for child than 5 years or younger be y Therefore, 5x + 6 y = 43 Since x and y has to ... for the above equation will be x=5 and y=3 Hence, 5 children are older than 5 years Answer : c

15 years ago, vaishali age was 15 times the age of her brother and the sum of present ages of vaishali and brother is 94years. What will be the age of her brother after 18 years? a) 32 years b) 33.5 years c) 37 years d) 30 years

Description : 15 years ago, vaishali age was 15 times the age of her brother and the sum of present ages of vaishali and brother is 94years. What will be the age of her brother after 18 years? a) 32 years b) 33.5 years c) 37 years d) 30 years

Last Answer : C

Present ages of A and B are 50 years and 18 years respectively. In how many years will A be twice as old as B? a) 14 years b) 15 years c) 16 years d) 18 years e) None of these

Description : Present ages of A and B are 50 years and 18 years respectively. In how many years will A be twice as old as B? a) 14 years b) 15 years c) 16 years d) 18 years e) None of these

Last Answer : Let the required time be x years. then (50+x) = 2 (18 + x) = 50 + x = 36 + 2x  x = 14 years. Alternative method : Double of B’s age = 2 × 18 = 36 years difference between A’s present age and double of B’s age = 50 – 36= 14 years. A will be twice of B’s age after 14 years. Answer: a)

if the ratio of the ages (in years) of x and y, 8 years ago is 7:6, then which of the following can be the sum of their ages 8 years from now?

Description : if the ratio of the ages (in years) of x and y, 8 years ago is 7:6, then which of the following can be the sum of their ages 8 years from now?

Last Answer : if the ratio of the ages (in years) of x and y, 8 years ago is 7:6, then which of the following can be ... years from now? A. 82 B. 97 C. 75 D. 94

Four years ago, the average of a 4 member family was 40 years. 3 years ago, a boy got married to a 23 years old girl, and they had a baby boy last year. what is the average of the family 2 years from now assuming no one joins or leaves from the family in the next 2 years.

Description : Four years ago, the average of a 4 member family was 40 years. 3 years ago, a boy got married to a 23 years old girl, and they had a baby boy last year. what is the average of the family 2 years from now assuming no ... leaves from the family in the next 2 years. a) 40 b) 42.5 c) 36.5 d) 34 e) 35.8

Last Answer : Four years ago, sum of all the family members age = 4× 40 = 160 three years ago, sum of all the family members age = 164 + 23 = 187 last year, sum = 197 (187 + 5 + 5) two years from now, sum = 197 + 18 = 215 hence, average = 215/6 = 35.8 Answer: e)

Vasu said to his son, "I was as old as you at the time of your birth". If vasu’s age is 76 years now, the son's age ten years back was: a)14 years b)19 years c)33 years d)28 years

Description : Vasu said to his son, "I was as old as you at the time of your birth". If vasu’s age is 76 years now, the son's age ten years back was: a)14 years b)19 years c)33 years d)28 years

Last Answer : D Let the son's present age be x years. Then, (76 - x) = x 2x = 76 x = 38 Son's age 10 years back (38-10) = 28 years

34.8% x 950 – 33.2% of 850 = ? a) 58.4 b) 48.4 c) 56.4 d) 68.9 e) 76.3

Description : 34.8% x 950 – 33.2% of 850 = ? a) 58.4 b) 48.4 c) 56.4 d) 68.9 e) 76.3

Last Answer : 34.8% x 950 – 33.2% of 850 = ? Sol: 0.348 x 950 – 0.332 x 850=? 330.6 – 282.2=? ?= 48.4 Answer: b)

The ratio of the present ages of a father and his son is ` 3 : 1` . The sum of their ages after five years is 58. Find the ratio of their ages 3 years

Description : The ratio of the present ages of a father and his son is ` 3 : 1` . The sum of their ages after five years is 58. Find the ratio of their ages 3 years

Last Answer : The ratio of the present ages of a father and his son is ` 3 : 1` . The sum of their ages after ... is 58. Find the ratio of their ages 3 years ago.

Two concentric circles have radii of 23 cm and 9 cm. A rectangle has an area equal to the annular space between the above two circles. If the breadth of the rectangle is 22 cm then find its length. 1 : 32 cm 2 : 48 cm 3 : 76 cm 4 : 64 cm 5 : None of these

Description : Two concentric circles have radii of 23 cm and 9 cm. A rectangle has an area equal to the annular space between the above two circles. If the breadth of the rectangle is 22 cm then find its length. 1 : 32 cm 2 : 48 cm 3 : 76 cm 4 : 64 cm 5 : None of these

Last Answer : 4 : 64 cm

The ages of a father and son add up to 66. The father's age is the son's age reversed. How old could they be? (3 possible solutions). -Riddles

Description : The ages of a father and son add up to 66. The father's age is the son's age reversed. How old could they be? (3 possible solutions). -Riddles

Last Answer : 51 and 15. 42 and 24. 60 and 06.

The sum of the ages of two persons A and B is 50. 5 years ago, the ratio of their ages was 5/3. The present age of A and B are (A) 30, 20 (B) 35, 15 (C) 38, 12 (D) 40, 10

Description : The sum of the ages of two persons A and B is 50. 5 years ago, the ratio of their ages was 5/3. The present age of A and B are (A) 30, 20 (B) 35, 15 (C) 38, 12 (D) 40, 10

Last Answer : Answer: A

Ratio of ages of three girls are 5:8:10, six years ago, the sum of their ages was 28. Find their present ages. a) 16,10,20 b) 12,28,36 c) 10,16,20 d) 16,28,36

Description : Ratio of ages of three girls are 5:8:10, six years ago, the sum of their ages was 28. Find their present ages. a) 16,10,20 b) 12,28,36 c) 10,16,20 d) 16,28,36

Last Answer : C Let the present ages are 5x, 8x, 10x. => (5x-6) + (8x-6) + (10x-6) = 28 => 23x = 46 => x = 2 So their present ages are: 10,16,20