Description : The sum of the ages of the 4 members of Sinha family is 172 years. 8 years ago the ages of the 4 members Nishu, Vicky, Mrs.Sinha and Sinha were in the ratio of 2:3:7:8. After how many years would Nishu be ... present age of his mother? a) 33 years b) 35 years c) 36 years d) 37 years e) None of these
Last Answer : Answer: B Let their ages 8 years ago be 2x, 3x, 7x, and 8x. Their ages now 2x+8, 3x+8, 7x+8, 8x+8. According to the question, =2x+8+3x+8+7x+8+8x+8=172 20x+32=172 =>x=140/20=7 Present age of Nishu=2×7+8=22 years Present age of mother=7×7+8=57 years Hence, required years (57-22)=35 years
Description : The ratio of kabil’s age 6 years ago and sahul’s age after 6 years is 3 : 3. If at present, the ratio of their ages is 7: 5, then find the ratio between kabil’s age 6 years hence and sahul’s age 6 years ago. a) 1 : 3 b) 2 : 1 c) 4 : 3 d) 3 : 4
Last Answer : B At present: Ratio of their ages = 7 : 5. Therefore, 7: 5 will be 7x and 5x. kabil's age 6 years ago = 7x - 6 sahul's age after 6years = 5x + 6 Ratio of kabil's age 6years ago and sahul's age after 6 ... Ratio of sahul's age and kabil's age (7x + 6) / (5x - 6) = 48/24 =2/1 =2:1
Description : Age of father 30 years ago was 9 times the age of her son. After 30 years, father’s age will be thrice that of his son. Find the ratio of their present ages. a) 21 : 5 b) 29 : 5 c) 27 : 4 d) 21 : 3
Last Answer : A At age of son be x and as father's age is 9 times the age of her son, let it be 9x, nine years ago. At present: father's age will be (9x + 30) and son's age will be (x + 30) After 30 years: father's age ... x = 20 We are asked to find the present ratio. (9x + 30) : (x + 30) = 210 : 50 = 21:5
Description : The ratio between the present ages of A and B is 6:7. If B is 4 years old than A. What will be the ratio of the ages of A and B after 4 years? A.5 : 7 B.7 : 8 C.8 : 7 D.Data inadequate E.None of these
Last Answer : Answer – B (7 : 8) Explanation – Let A’s age and B’s age be 6X years and 7X years respectively Then, 7X – 6X = 4 X = 4 Required ratio = (6X + 4) : (7X + 4) = (6*4+4) : (7*4 +4) =28 : 32 = 7 : 8
Description : The ratio between the present ages of M and N is 8:9. If N is 6 years old than M, what will be the ratio of the ages of M and N after 6 years a) 9:10 b) 7:9 c) 9:8 d) 11:10
Last Answer : A Let M age and N age be 8x years and 9x years. Then 9x - 8x = 6 <=> x = 6 So required ratio will be (8x+6): (9x+6) 54:60 9:10
Description : Three year ago, ratio of Tom and Ram age’s was 5 : 6 respectively. After 12 years, this ratio becomes 6 : 7. How old is Ram at present? a) 39years b) 93 years c) 78 years d) 87 years
Last Answer : B We are given that age ratio of tom and ram = 5 : 6 Tom's age = 5x and Ram's age = 6x 3 years ago, their age was 5x and 6x. Hence at present, Tom's age = 5x +3 and Ram's age = 6x +3 After 12years, Tom's ... = 6 / 7 7 (5x + 15) = 6 (6x + 15) X = 15 Ram's present age = (6x + 3) = 93years
Description : Sum of present age of A, B and C is 72 years. If 4 years ago, their ages were in the ratio 1 : 2 : 3, find A’s present age. a) 7 years b) 10 years c) 12 years d) 14 years e) None of these
Last Answer : Sum of present ages of A, B and C is 72 years. sum of their ages (4 years ago) = 72 – (3 × 4) = 60 years 4 years ago, ratio of ages of A, B and C was 1 : 2 :3. A’s age, 4 years ago = (1/6) ×60 = 10 years A’s present age = 10 + 4 = 14 years Answer: d)
Description : Total of the ages of P, Q and R at present is 99 years. Eight years ago, the ratio of their ages was 4: 5: 6. What is the age of Q at present a) 44 b) 30 c) 45 d) 33
Last Answer : D Let their ages 8 years ago is4x, 5x and 6x years. 4x+8+5x + 8 + 6x + 8= 99 hence x= 5 Q’s present age = (5x + 8) =33 years
Description : Eight years ago, the ratio of the ages of micky and Donald was 6:5, 12years hence, the ratio of their ages will be 11:10. What is Donald age at present a) 30 years b) 28 years c) 34 years d) 36 years
Last Answer : B Let 8 years ago the age of Micky and Donald be 6x and 5x resp. then, ((6x+8)+12) / ((5x+8)+12) = 11/10 10(6x+20) = 11(5x+20) 5x = 20 => x = 4 So Donald age is (5x+8) = 28
Description : Ages of DEEPA and Subha are presently in the ratio of 5 : 6 respectively. Six years hence this ratio will become 6 : 7 respectively. What was Subha’s age 5 years ago? a) 33 years b) 32 years c) 35 years d) 31 years e) None of these
Last Answer : Present ratio of Deepa&Subha = 5 : 6 Six year hence ratio of Deepa&Subha = 6 : 7 Difference between ratio = 1 Difference in ages between present & future = 6 year. 1 ratio=6 yrs & SUBHA's age = 6 6 =36 year 5 year ago ... = 7 6 = 42 year B's age 5 year ago = 42-6-5 = 42-11 = 31 year Answer: d)
Description : At present, a mother is 3 times older than her son. After 5 years, the sum of their ages will be 70 years. The age of the mother after 10 years will be (A) 40 (B) 55 (C) 45 (D) 60
Last Answer : 45
Description : 15 years ago, vaishali age was 15 times the age of her brother and the sum of present ages of vaishali and brother is 94years. What will be the age of her brother after 18 years? a) 32 years b) 33.5 years c) 37 years d) 30 years
Last Answer : C
Description : Keerthi's grandfather was 16 times older to her 32 years ago. He would be 6times of her age 16 years from now. What was ratio of ages of keerthi and her grandfather 16 years ago. a) 1:10 b) 11:10 c) 10:11 d) 10:1
Last Answer : A Let, keerthi’s age 32 years ago = x, Grandfather's age 32 years ago = 16x. 16 years from now, 6(x+32+16) = (16x+32+16) => x = 24 16 years ago ratio was: (x+16)/ (16x+16) = (24+16) / (16*24+16) 40 /400 = >1 / 10
Description : The ratio of the ages of Bala and Babu is 13: 11. The total of their ages is 3.6decades. The proportion of their ages after 0.95decades will be [1 Decade = 10 years] a) 24:23 b) 12:11 c) 27:24 d) 29:26
Last Answer : D Let, Bala’s age = 13A and babu’s age = 11A Then 13A + 11A = 36 A = 1.5 Bala’s age = 19.5years and Babu’s age = 16.5 years Proportion of their ages after 9.5 is = (19.5+9.5) : (16.5 + 9.5) = 29 : 26
Description : Sum of present ages of A and B is 60 years. 5 years hence, their ages will be in the ratio 3:4. Find A’s present age. a) 25 years b) 30 years c) 35 years d) 40 years e) None of these
Last Answer : Sum of their present ages = 60 years sum of their ages, 5 years hence = 60 + (5 × 2) = 70 years. after 5 years, ratio of ages of A and B will be 3 : 4. A’s age after 5 years = (3/7) × 70 = 30 years A’s present age = 30 – 5 = 25 years Answer: a)
Description : One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these
Last Answer : Answer - B (16) Explanation - Let one year ago Sam's age be 4X years And, Ash's age be 3X years Present age of Sam = (4X + 1) years Present age of Ash= (3X + 1) years One year hence Sam's age = (4X + 2) ... = 2 Sum of their present ages = 4X + 1 + 3X + 1 = 7X + 2 = 7 x 2 + 2 = 16 years.
Description : Present ages of Simmi and Anu are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively, What is Anu’s present age in years? A.20 B.24 C.28 D.35 E.None of these
Last Answer : Answer – B (24) Explanation – Let the present ages of Simmi and Anu be 5x years and 4x years respectively Then, [5X + 3] / [4X + 3] =11/9 x=6 Anu’s present age = 4X = 24 years
Description : The average age of two persons is 46 years. 16 years back the ratio between their ages were 1 : 2, then what is the difference between present ages of these two persons? 1) 16 years 2) 20 years 3) 24 years 4) 12 years 5) 8 years
Last Answer : 2) 20 years
Description : The sum of the ages of two persons A and B is 50. 5 years ago, the ratio of their ages was 5/3. The present age of A and B are (A) 30, 20 (B) 35, 15 (C) 38, 12 (D) 40, 10
Last Answer : Answer: A
Description : 12 years ago M was half of N in age. If the ratio of their present ages is 4 : 5, what will be the total of their present ages a) 30 b) 35 c) 36 d) 32
Last Answer : C Let M's age 12 years ago = x years. Then, N's age 12 years ago = 2x years. (x + 12) / (2x+ l2) = 4/5 => x = 4. So, the total of their present ages =(x + 12 + 2x + 12) = (3x + 24) = 36 years.
Description : Fathima's father was 76 years of age when she was born while her mother was 72years old when her brother 8 years younger to her was born. What is the difference between the ages of her parents? a)12 years b)14 years c)16 years d)18 years
Last Answer : A Mother's age when Fathima 's brother was born = 72 years. Father's age when Fathima 's brother was born = (76+8) years = 84 years. Required difference = (84-72) years = 12 years
Description : The sum of present ages of a father and his son is 36 years. When the son reaches father’s present age, the sum of their ages will be 80 years. What is the present age of the son? a) 4 years b) 7 years c) 9 years d) 12 years e) None of these
Last Answer : Difference in two sums = 80- 36 = 44 Age of both are increased by 44/2 = 22 years Difference in ages of father and son = 22 years sum of present ages of father and son = 36 years Son’s present age = 1/2 × (36 - 22) = 7 years Answer: b)
Description : The sum of ages of Sunil and his father is 46 years. 3 years back, father’s age was 4 times sunil’s age. find present age of Sunil. a) 7 years b) 8 years c) 11 years d) 12 years e) None of these
Last Answer : Sum of their ages, 3 years ago = 46 – (2 × 3) = 40 years sunil’s age, 3 years ago = 1/5 × 40 = 8 years sunil’s present age = 8 + 3 = 11 years Answer: c)
Description : The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70
Last Answer : Answer : D (70) ExplanationSum of ages is 360 years.The ratio of children and parents ages is 2:1. Total age of parents = 360 x 1 / 3 = 120 years Ratio of wife and husband age is 5:7. Therefore, the age of husband = 120 x 7 / 12 = 70 Hence the age of husband is 70 years.
Description : Shyam is younger than Sharuk by 22 years. If the ratio of their ages is 5:7, find the age of Shyam a) 55 b) 77 c) 66 d) 88
Last Answer : A If sharuk age is x, then Shyam age is x-22, so (x-22)/x = 5/7 => 7x-154 = 5x => 2x = 154 => x = 77 So shyam age is 77 - 22 = 55
Description : Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these
Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)
Description : Present ages of A and B are in the ratio 7:4, which of the following can be the difference between their ages after 8 years?
Last Answer : Present ages of A and B are in the ratio 7:4, which of the following can be the difference between their ... B. 10 years C. 15 years D. All of these
Description : The sum of the ages of a Mother and son is 54 years. Eight years ago, the product of their ages was 6 times the mother’s age at that time. The present age of mother and son a) 34,17 b) 14,40 c) 40,14 d) 50,17
Last Answer : C Let sons age = x years. Then mothers age = (54 - x)years. (x-8)(54-x-8) = 6(54- x - 8) hence (x-8) = 6 so x = 14 Their ages are 40 years and 14 years.
Description : A is 2 years older than B who is twice as old as C. If sum of ages of A, B and C is 37 years, find the age of A. a) 7 years b) 9 years c) 14 years d) 16 years e) None of these
Last Answer : Let the age of C be x years. Then age of B = 2x and age of A = 2x + 2 sum of ages of A, B and C = (2x + 2) + (2x) + x = 37 (5x + 2) = 37 x = 7 Age of A = 2x + 2 = 16 years Answer: d)
Description : The combined age of a father and daughter is 66. The daughter is the same age as the father. But with the digits reversed. What are their ages? -Riddles
Last Answer : There are three correct answers 51 and 15, 42 and 24, or 60 and 6.
Description : The ages of two sisters differ by 32 years. 12 years ago, the elder one was 7 times as old as the younger one. What are their present ages of the elder person a) 46.9 b) 49.3 c) 42.7 d) 45.4
Last Answer : B Let's take the present age of the elder person = x and the present age of the younger person = x – 32 (x – 12) = 7*(x-32-12) => x – 12 = 7x – 308 => 6x = 296 => x = 49years 3months
Description : What is the meaning of the name Rupa ?
Last Answer : The name Rupa means metal.
Description : After replacing an old person by a new person, it was found that the average age of five persons of a assembly is the same as it was 6 years ago. What is the difference between the ages of the replaced and the new persons? A) 24 B) 36 C) 30 D) 15
Last Answer : C) Let the ages of the five persons at present be a, b, c, d & e years. And the age of the new persons be f years. So the new average of five members' age = (a + b + c + d + f)/5 - ... - e + f) = 5x Solving e - f = 30 years. Thus the difference of ages between replaced and new person = 30years.
Description : if the ratio of the ages (in years) of x and y, 8 years ago is 7:6, then which of the following can be the sum of their ages 8 years from now?
Last Answer : if the ratio of the ages (in years) of x and y, 8 years ago is 7:6, then which of the following can be ... years from now? A. 82 B. 97 C. 75 D. 94
Description : Seven years ago the ratio of the ages of P and Q (in years) was ` 7 : 6` . Which of the following cannot be the ratio of their ages 6 years from now ?
Last Answer : Seven years ago the ratio of the ages of P and Q (in years) was ` 7 : 6` . Which of the following cannot be the ... : 14` C. ` 13 : 12` D. ` 16 : 15`
Description : What is the right age for ear piercing in kids? My daughter is 5 years old, and her ear is still not pierced.?
Last Answer : I am sorry to hear that. I have a daughter. She just turned 9 years old. But she had her ear piercing in her newborn days. She was probably 4 days old when she had it.
Description : Madhan was 3 times as old as his daughter 10 years ago. After 10 years, Madhan will be twice as old as his daughter. Find out the present age of Madhan. a) 68 years b) 70 years c) 40 years d) 55 years e) 80 years
Last Answer : b Let age of the daughter before 10 years = x Then, age of Madhan before 10 years = 3x After 10 years, Madhan will be twice as old as his daughter. ⇒ 3x + 20 = 2( x+20) ⇒ x = 20 ⇒ Present age of Madhan = 3x + 10 = 3× 20+ 10 = 70 years.
Description : Five years hence , the age of Ram will be 10 more than the two thirds of Ravi’s age . Assume the present ages of Ram and Ravi as x and y respectively . Express the statement in the form of a linear equation in two variables. -Maths 9th
Last Answer : answer:
Description : The present age of A is twice that of B. The sum of their present ages is 33 years. Find the present age of A (in years)
Last Answer : The present age of A is twice that of B. The sum of their present ages is 33 years. Find the present age of A (in years)
Description : The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these
Last Answer : Sum of present ages = 35 years sum of their ages will be 85 years after (85-35) / 2 = 25 years from now. the father is 25 years older than his son. Present age of father = (35 + 25)/2 = 30 years. Answer: c)
Description : When the average age of a father, mother and their son was 90 years, the son got married and a child was born just 6 year after the marriage when child turned 14 years the average age of the family is 80yrs. Find the age of daughter - in - law at present? A) 55 B) 56 C) 57 D) 58
Last Answer : B) total age of father, mother and son at the time of son's marriage = 90*3 =270 present age of family father, mother, son, daughter-in-law, child = (father, mother, son age at the time of marriage ... 60)+ daughter-in-law present age + 14 = 80*5 =400 daughter-in-law present age= 400-344 = 56yrs
Description : The ratio of the present ages of a father and his son is ` 3 : 1` . The sum of their ages after five years is 58. Find the ratio of their ages 3 years
Last Answer : The ratio of the present ages of a father and his son is ` 3 : 1` . The sum of their ages after ... is 58. Find the ratio of their ages 3 years ago.
Description : The ratio of the present ages of Raju and his wife is ` 5 : 4`. Which of the following cannot be the ratio of their ages 20 years hence ?
Last Answer : The ratio of the present ages of Raju and his wife is ` 5 : 4`. Which of the following cannot be the ratio of their ... 5` C. ` 23 : 20` D. ` 13 : 10`
Description : Ratio of ages of three girls are 5:8:10, six years ago, the sum of their ages was 28. Find their present ages. a) 16,10,20 b) 12,28,36 c) 10,16,20 d) 16,28,36
Last Answer : C Let the present ages are 5x, 8x, 10x. => (5x-6) + (8x-6) + (10x-6) = 28 => 23x = 46 => x = 2 So their present ages are: 10,16,20
Description : The sum of the current ages of a father and his son is 84 years. 7 years ago, father's age was 3 times the age of the son. After 7 years, son's age will be a) 35 years b) 28 years c) 56years d) 53 years
Last Answer : A Son’s current age = x years. Then father’s age = (84 - x)years (84 - x) - 7 = 3(x - 7) 2x=56 x =28; after 7years it will be turn on 35
Description : if the ratio of the ages (in years) of A and B, 5 years ago was 5:7, then which of the following can be the sum of their ages 5 years from now?
Last Answer : if the ratio of the ages (in years) of A and B, 5 years ago was 5:7, then which of the following can be ... years from now? A. 90 B. 98 C. 92 D. 87
Description : The ages of A and B are in the ratio 8 : 5. If the sum of their ages is 39 years, what will be the ratio of their ages after 9 years? a) 3 : 2 b) 8 : 7 c) 10: 7 d) 11 : 8 e) None of these
Last Answer : Sum of ratios = 8 +5 = 13. Sum of ages = 39 years 13 ratio = 39 years 1 ratio = 3 years 9 years = 3 ratio new ratio = (8+3) : (5+3) = 11 : 8 Answer: d)
Description : The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 ... hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31
Last Answer : 5 : 30 : 31
Description : Present ages of A and B are 50 years and 18 years respectively. In how many years will A be twice as old as B? a) 14 years b) 15 years c) 16 years d) 18 years e) None of these
Last Answer : Let the required time be x years. then (50+x) = 2 (18 + x) = 50 + x = 36 + 2x x = 14 years. Alternative method : Double of B’s age = 2 × 18 = 36 years difference between A’s present age and double of B’s age = 50 – 36= 14 years. A will be twice of B’s age after 14 years. Answer: a)