The moment of a force is a.Equivalent to the algebraic sum of the moments acting on a body b.Equivalent to the sum of horizontal as well as vertical components of the moments on a body c.Equivalent to the sum of the moments acting on a body d.Equivalent to the sum of horizontal components of the moments on a body e.Equivalent to the vertical sum of the moments acting on a body

The moment of a force is a.Equivalent to the algebraic sum of the moments acting on a body b.Equivalent to the sum of horizontal as well as vertical components of the moments on a body c.Equivalent to the sum of the moments acting on a body d.Equivalent to the sum of horizontal components of the moments on a body e.Equivalent to the vertical sum of the moments acting on a body
by

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Answer :

a. Equivalent to the algebraic sum of the moments acting on a body
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The necessary condition of equilibrium of a body is a.The algebraic sum of horizontal components of all forces must be zero b.The algebraic sum of vertical components of all forces must be zero c.The algebraic sum of forces about a point must be zero d.All the above e.None of the above

Description : The necessary condition of equilibrium of a body is a.The algebraic sum of horizontal components of all forces must be zero b.The algebraic sum of vertical components of all forces must be zero c.The algebraic sum of forces about a point must be zero d.All the above e.None of the above

Last Answer : d. All the above

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Last Answer : d. None of the above

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If the positive and negative shear force diagram areas are not equal, it can be concluded that a.shear force diagram has been wrongly drawn b.there is at least one couple acting on the beam c.107 dynes d.there are at least two maxima for bending moment e.bending moment does not change sign

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A horizontal load of 120 kg/mt is to be carried by a cable suspended between supports at same level and 60 mts apart. If the maximum permissible tension is 36,000 kg the required length of cable is a.63.3 mets b.62.5 mts c.60.8 mts d.107 dynes e.60.1 mts

Description : A horizontal load of 120 kg/mt is to be carried by a cable suspended between supports at same level and 60 mts apart. If the maximum permissible tension is 36,000 kg the required length of cable is a.63.3 mets b.62.5 mts c.60.8 mts d.107 dynes e.60.1 mts

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If four turms of rope around a horizontal post will hold a 100 kg weight with a pull of 1 kg, then a.107 dynes b.0.25 c.0.18 d.0.3 e.0.11

Description : If four turms of rope around a horizontal post will hold a 100 kg weight with a pull of 1 kg, then a.107 dynes b.0.25 c.0.18 d.0.3 e.0.11

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A particle moves along a rough plane inclined at 30? to the horizontal. The co-efficient of friction between the particle and the plane is 0.1. Its initial velocity is 15 m/sec. The ratio of the velocity of the particle when it move down the plane to that when it move up the plane would be in the regions a.8 ? 10 b.5 ? 7 c.2 ? 3 d.4 ? 6 e.10 ? 13

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Last Answer : b. 5 ? 7