400 gm spirit solution has 30 % spirit in it , what is the ratio of spirit should be added to make it 80 % in the solution ? A)2:5 B)4:3 C)5:2 D)2:7

400 gm spirit solution has 30 % spirit in it , what is the ratio of spirit should be added to make it 80 % in the solution ? A)2:5 B)4:3 C)5:2 D)2:7
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Answer :

A)2:5

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Box A contains wheat worth Rs.30 per kg and box B contains wheat worth Rs.40 per kg.If both A and B are mixed in the the ratio 4:7 then the price of mixture per kg is A)36.36 B)35.80 C)42.50 D)31.30

Description : Box A contains wheat worth Rs.30 per kg and box B contains wheat worth Rs.40 per kg.If both A and B are mixed in the the ratio 4:7 then the price of mixture per kg is A)36.36 B)35.80 C)42.50 D)31.30

Last Answer : A)36.36

Some amount out of Rs. 10000 was lent at 6 % p.a. and the remaining at 4% p.a. If the total simple interest from both the fractions in 5 years was Rs. 1500, then the ratio of the 2 different amount is A)1:3 B)3:1 C)1:4 D)3:2

Description : Some amount out of Rs. 10000 was lent at 6 % p.a. and the remaining at 4% p.a. If the total simple interest from both the fractions in 5 years was Rs. 1500, then the ratio of the 2 different amount is A)1:3 B)3:1 C)1:4 D)3:2

Last Answer : A)1:3

Sum of Rs.118 was shared among 50 boys and girls,each girl receive Rs.2.60 and boy receive Rs.1.80.Find the number of girls. A) 15 B)25 C)30 D)35

Description : Sum of Rs.118 was shared among 50 boys and girls,each girl receive Rs.2.60 and boy receive Rs.1.80.Find the number of girls. A) 15 B)25 C)30 D)35

Last Answer : D)35

In what proportion must water be mixed with milk to gain 40 % by selling it at cost price ? A) 3:5 B)5:3 C)2:5 D)3:2

Description : In what proportion must water be mixed with milk to gain 40 % by selling it at cost price ? A) 3:5 B)5:3 C)2:5 D)3:2

Last Answer : C)2:5 Solution: 40 : 100 2 : 5

One alloy contains silver and copper in the ratio 5:1 and the other contains in the ratio 7:2 respectively. What weights of the 2 must be melted together, so as to make a 5 lb mass with 80% silver? A)5:3 B)3:2 C)2:3 D)2:5

Description : One alloy contains silver and copper in the ratio 5:1 and the other contains in the ratio 7:2 respectively. What weights of the 2 must be melted together, so as to make a 5 lb mass with 80% silver? A)5:3 B)3:2 C)2:3 D)2:5

Last Answer : B)3:2

A Mixture contain 88% of sulphur,another mixture contain 70% of sulphur.In order to get 84% of sulphur,in what ratio these two must be mixed. A) 2:7 B)7:2 C)7:4 D)4:5

Description : A Mixture contain 88% of sulphur,another mixture contain 70% of sulphur.In order to get 84% of sulphur,in what ratio these two must be mixed. A) 2:7 B)7:2 C)7:4 D)4:5

Last Answer : B)7:2

In what ratio must a person mix three kinds of Oats costing him Rs 1.20,Rs 1.44 and Rs 1.74 per Kg so that the mixture may be worth Rs 1.41 per Kg? A)11:77:7 B) 11:45:7 C)25:45:8 D) 27:23:6

Description : In what ratio must a person mix three kinds of Oats costing him Rs 1.20,Rs 1.44 and Rs 1.74 per Kg so that the mixture may be worth Rs 1.41 per Kg? A)11:77:7 B) 11:45:7 C)25:45:8 D) 27:23:6

Last Answer : A)11:77:7

In what proportion must sugar at Price 4.10 per kg must be mixed with weat at Price 4.60 per kg, so that the mixture be worth Rs 4.30 a Kg ? A)3:2 B)2:3 C)5:3 D)None of these

Description : In what proportion must sugar at Price 4.10 per kg must be mixed with weat at Price 4.60 per kg, so that the mixture be worth Rs 4.30 a Kg ? A)3:2 B)2:3 C)5:3 D)None of these

Last Answer : A)3:2

In what ratio water be mixed with juice costing Rs.12 per liter to obtain a mixture worth of Rs.8 per litre? A)2:3 B)2:1 C)1:2 D)3:2

Description : In what ratio water be mixed with juice costing Rs.12 per liter to obtain a mixture worth of Rs.8 per litre? A)2:3 B)2:1 C)1:2 D)3:2

Last Answer : C)1:2

From a vessel containing 100 litres of ****,10 litres are drawn out and an equal amount of water is added. From the mixture,10 litres is again drawn out and same quantity of water is added. What is the final ratio of **** and water? a) 91 : 9 b) 81 : 19 c) 80 : 20 d) 90 : 10 e) None of these

Description : From a vessel containing 100 litres of wine,10 litres are drawn out and an equal amount of water is added. From the mixture,10 litres is again drawn out and same quantity of water is added. What is the final ratio of wine and water? a) 91 : 9 b) 81 : 19 c) 80 : 20 d) 90 : 10 e) None of these

Last Answer : Quantity of wine after two replacements = 100 l × (90/100)2 =81 l Required ratio = 81 : ( 100 – 81 )= 81 : 19 Answer: b)

185% of 400 + 35% of 240 = ?% of 1648 a) 85 b) 75 c) 125 d) 50 e) None of these

Description : 185% of 400 + 35% of 240 = ?% of 1648 a) 85 b) 75 c) 125 d) 50 e) None of these

Last Answer : 740 + 84 = 16.48 × ? 824 = 16.48 × ? ? = 50 Answer: d)

?% of 725 + 14% of 2100 = 700 a) 64 b) 80 c) 72 d) 56 e) 48

Description : ?% of 725 + 14% of 2100 = 700 a) 64 b) 80 c) 72 d) 56 e) 48

Last Answer : ?% × 725 +14 × 21=700 =>?% × 725 +294 =700 => ?% × 725 =406 =>?=406/725 × 100 =56 Answer: d)

A person, by selling an article at half of the list price incurs a loss of 20%. Find the profit percentage if he sells at the list price? A. 25% B. 60% C. 5% D. 30 %

Description : A person, by selling an article at half of the list price incurs a loss of 20%. Find the profit percentage if he sells at the list price? A. 25% B. 60% C. 5% D. 30 %

Last Answer : Answer – B (60 %) Explanation – 0.50 MP = 0.8 CP (since 20% loss) So, MP = 160CP ⇒ 60% gain.

Three pipes P, Q and R can fill a tank from empty to full in 40 minutes, 15 minutes, and 30 minutes respectively. When the tank is empty, all the three pipes are opened. P, Q and R discharge chemical solutions X, Y and Z respectively. What is the proportion of the solution Y in the liquid in the tank after 5 minutes? a) 8 / 15 b) 7 / 15 c) 8 / 17 d) 6 / 13 e) 8 / 13

Description : Three pipes P, Q and R can fill a tank from empty to full in 40 minutes, 15 minutes, and 30 minutes respectively. When the tank is empty, all the three pipes are opened. P, Q and R discharge chemical solutions X, Y and Z respectively. ... 5 minutes? a) 8 / 15 b) 7 / 15 c) 8 / 17 d) 6 / 13 e) 8 / 13

Last Answer : a Part of the tank filled by pipe P in 1 minute = 1 / 40 Part of the tank filled by pipe Q in 1 minute = 1 / 15 Part of the tank filled by pipe R in 1 minute = 1/ 30 Here we have to find the proportion of ... together in 5 minute = 5 1/8 = 5/ 8 Required proportion = (1/3) / ( 5/8) = 8 / 15

12833 + 133 % of 1655 -7/5 of 3533 (1)9000 (2)10000 (3)10500 (4)11000 (5) 9500

Description : 12833 + 133 % of 1655 -7/5 of 3533 (1)9000 (2)10000 (3)10500 (4)11000 (5) 9500

Last Answer : 2)10000

A, B and C enter into a partnership and their shares are in ratio 1/2 : 1/3 : 1/4, after 2 months, A withdraws half of his capital and after 12 months, a profit of Rs 1050 is divided among them. What is B’s share ? A.Rs.420 B.Rs. 300 C.Rs.400 D.Rs.350

Description : A, B and C enter into a partnership and their shares are in ratio 1/2 : 1/3 : 1/4, after 2 months, A withdraws half of his capital and after 12 months, a profit of Rs 1050 is divided among them. What is B’s share ? A.Rs.420 B.Rs. 300 C.Rs.400 D.Rs.350

Last Answer : Answer- C(Rs.400) Explanation : Ratio of investments =1/2 : 1/3 : 1/4 , LCM of 2, 3, 4 = 12 ,multiply ratios with 12 we get 6 : 4 : 3 , so,initial investment be 6x, 2x and 3x so, we can write: A : B :C =(6x X 2 + 3x X 10 ) : (4x X 12) :(3x X 12) = 7:8:6 B’s share= (8/21) x 1050 = 400

A sum of Rs. 1550 was lent partly at 5% and partly at 8% per annum simple interest. The total interest received after 4 yr was Rs. 400. The ratio of the money lent at 8% to that lent at 5% is? (a) 15:16 (b) 16:17 (c) 19:17 (d) 21:26 (e) 20:17

Description : A sum of Rs. 1550 was lent partly at 5% and partly at 8% per annum simple interest. The total interest received after 4 yr was Rs. 400. The ratio of the money lent at 8% to that lent at 5% is? (a) 15:16 (b) 16:17 (c) 19:17 (d) 21:26 (e) 20:17

Last Answer : (a) 15:16

The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: A.10 B.14 C.23 D.30 E.None of these

Description : The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: A.10 B.14 C.23 D.30 E.None of these

Last Answer : Answer – C (23) Explanation – L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37. Number to be added = (60 – 37) = 23

In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage of water in the final mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Description : In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage ... mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Last Answer : 2) 28. 57%

vIf the price of Mango is Rs. 130 per kg, Apple is Rs. 140 per kg and Orange is Rs. 80 per kg, then what is the ratio of their cost at vendor A? 1) 11 : 14 : 16 2) 39 : 28: 20 3) 39 : 28 : 21 4) 15 : 14 : 11 5) 39 : 26 : 20

Description : If the price of Mango is Rs. 130 per kg, Apple is Rs. 140 per kg and Orange is Rs. 80 per kg, then what is the ratio of their cost at vendor A? 1) 11 : 14 : 16 2) 39 : 28: 20 3) 39 : 28 : 21 4) 15 : 14 : 11 5) 39 : 26 : 20

Last Answer : 2) 39 : 28: 20

The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 years hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Description : The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 ... hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Last Answer : 5 : 30 : 31

A,B are start walking around a Circular park of radius 70m. They start at the same point, and A goes clockwise at 10m/s, while b goes anti-clockwise at 20m/s.How many times will they cross each other at the starting point if they walk for 30 minutes? a) 20 b) 40 c) 60 d) 80 e) None of the above

Description : A,B are start walking around a Circular park of radius 70m. They start at the same point, and A goes clockwise at 10m/s, while b goes anti-clockwise at 20m/s.How many times will they cross each other at the starting point if they walk for 30 minutes? a) 20 b) 40 c) 60 d) 80 e) None of the above

Last Answer : Radius = 70m, So circumference = 2 (22/7) 70 =440m Relative speed = 10 +20 = 30m/s They will meet everytime at the starting point when the distance covered by both put together is a multiple of 440 ... =1800/44 =40.9 So they will meet 40 times (we need to ignore the decimal part). Answer : b

A,B are start walking around a Circular park of radius 70m. They start at the same point, and A goes clockwise at 10m/s, while b goes anti-clockwise at 20m/s.How many times will they cross each other at the starting point if they walk for 30 minutes? a) 20 b) 40 c) 60 d) 80 e) None of the above

Description : A,B are start walking around a Circular park of radius 70m. They start at the same point, and A goes clockwise at 10m/s, while b goes anti-clockwise at 20m/s. How many times will they cross each other at the starting point if they walk for 30 minutes? a) 20 b) 40 c) 60 d) 80 e) None of the above

Last Answer : Radius = 70m, So circumference = 2 (22/7) 70 =440m Relative speed = 10 +20 = 30m/s They will meet everytime at the starting point when the distance covered by both put together is a multiple of 440 ... =1800/44 =40.9 So they will meet 40 times (we need to ignore the decimal part). Answer : b

A discount of 25% on one article is same as a discount of 50% on another article .The costs of two article can be: A. Rs 30, Rs 20 B. Rs 90, Rs 40 C. Rs 80, Rs 40 D. Rs 50, Rs 40

Description : A discount of 25% on one article is same as a discount of 50% on another article .The costs of two article can be: A. Rs 30, Rs 20 B. Rs 90, Rs 40 C. Rs 80, Rs 40 D. Rs 50, Rs 40

Last Answer : Answer – C. Rs 80, Rs 40 Explanation – Let the costs of the two articles be x and y. Then, 25% of x = 50% of y => x/y = 50/25 = 2/1 So,x and y must be in the ratio of 2:1

A merchant claims to sell goods at his cost price. But by using false weights, he give only 600 gm of goods for every 1 kg that he buys.What is his profit percentage? a)40% b)100% c)60% d)66 2/3%

Description : A merchant claims to sell goods at his cost price. But by using false weights, he give only 600 gm of goods for every 1 kg that he buys.What is his profit percentage? a)40% b)100% c)60% d)66 2/3%

Last Answer : d)66 2/3%

A mixture contains milk and water in the ratio of 3:2 litter of water is added to the mixture, milk, milk and water in the mixture become equal find the quantities of milk and water in the mixture . a) 12, 8 litter b) 4,3 litter c) 12, 6 litres d) 10,8 litres e) None of these

Description : A mixture contains milk and water in the ratio of 3:2 litter of water is added to the mixture, milk, milk and water in the mixture become equal find the quantities of milk and water in the mixture . a) 12, 8 litter b) 4,3 litter c) 12, 6 litres d) 10,8 litres e) None of these

Last Answer : Let quantities of milk and water in the mixture be 3x and 2x. Then if 4 litres of water is added to the mixture the ratio of milk and water become 1:1. It can be written as (3x): (2x + 4) = 1 ... Therefore, the milk in the mixture is 4x3 = 12 litres and quantity of water = 4x2 = 8 liters Answer: a)

60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio of 3 : 2 and alloy B has tin and copper in the ratio of I : 4 the amount of tin in the new alloy is a) 36 kg b) 44 kg c) 80 kg d) 53 kg e) 45 kg

Description : 60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio of 3 : 2 and alloy B has tin and copper in the ratio of I : 4 the amount of tin in the new alloy is a) 36 kg b) 44 kg c) 80 kg d) 53 kg e) 45 kg

Last Answer : b) 44 kg

75%of a number is equal to four-fifth of another number. What is the ratio between first number and the second number? a) 4:3 b) 30:32 c) 7:9 d) 16:15 e) None of these

Description : 75%of a number is equal to four-fifth of another number. What is the ratio between first number and the second number? a) 4:3 b) 30:32 c) 7:9 d) 16:15 e) None of these

Last Answer : Let the two number be x & y. According to question, 75/100 x : 4/5 y 3/4 x : 4/5 y 15x = 16y x /y = 16/15 Answer: d)

The price of two dozens of oranges is Rs.120/-more than the price of one kg. of mango. The price of one dozen of apple is Rs.80/- more than the price of one kg of mango. Which of the following represents the ratios of the price of one orange and one apple respectively? a) 4 : 5 b) 3 : 2 c) 7 : 9 d) Cannot be determined

Description : The price of two dozens of oranges is Rs.120/-more than the price of one kg. of mango. The price of one dozen of apple is Rs.80/- more than the price of one kg of mango. Which of the following represents the ... apple respectively? a) 4 : 5 b) 3 : 2 c) 7 : 9 d) Cannot be determined e) None of these

Last Answer : Because no. of mangoes is unknown. So ratio cannot be calculated. Answer: d)

A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days, 4/7 of the work completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day? a) 79 b) 80 c) 81 d) 82 e) 83

Description : A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days, 4/7 of the work completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day? a) 79 b) 80 c) 81 d) 82 e) 83

Last Answer : work finished by 33 days = 33 117 8 = 30888 man hours 4/7th of the job is finished. remaining work = 1-(4/7) = 3/7 if 4/7th of the work is 30888 hours, then 3/7th of the work = [30888 ... 9 number of men = 198 since, 117 men are already working, additional men required = 198 - 117 = 81 Answer: c)

The sum of present ages of a father and his son is 36 years. When the son reaches father’s present age, the sum of their ages will be 80 years. What is the present age of the son? a) 4 years b) 7 years c) 9 years d) 12 years e) None of these

Description : The sum of present ages of a father and his son is 36 years. When the son reaches father’s present age, the sum of their ages will be 80 years. What is the present age of the son? a) 4 years b) 7 years c) 9 years d) 12 years e) None of these

Last Answer : Difference in two sums = 80- 36 = 44 Age of both are increased by 44/2 = 22 years Difference in ages of father and son = 22 years sum of present ages of father and son = 36 years Son’s present age = 1/2 × (36 - 22) = 7 years Answer: b)

Two equal sums are lent at the same time at 6% and 5 % simple interest respectively. The former is recovered 24 months earlier than the latter. And the amount in each case is Rs. 2400. Find the sum of money lent initially. a) 1500 b) 2000 c) 2400 d) 3000 e) 3600

Description : Two equal sums are lent at the same time at 6% and 5 % simple interest respectively. The former is recovered 24 months earlier than the latter. And the amount in each case is Rs. 2400. Find the sum of money lent initially. a) 1500 b) 2000 c) 2400 d) 3000 e) 3600

Last Answer : Let the sum be S, time be ‘n’ years for 6%. n+2 years for 5% 2400 = S + S ×n × 6/100 2400 = S + S × (n+2) × 5/100 So, 6n = 5(n+2) or n = 10 years. 2400 = S + S × 10 × 6/100 = 1.6S S = 2400/1.6 = 1500 Answer: a)

Nandu purchased a mobile phone and got a discount of 5% from dealer. he sold that mobile phone at a profit of 10% on his purchase price. What is the percentage profit on actual price of the mobile phone? 1. 2% 2. 3% 3. 4% 4. 4.5 %

Description : Nandu purchased a mobile phone and got a discount of 5% from dealer. he sold that mobile phone at a profit of 10% on his purchase price. What is the percentage profit on actual price of the mobile phone? 1. 2% 2. 3% 3. 4% 4. 4.5 %

Last Answer : 4. 4.5 %

(562 % of 816) + 1449 = ? 1) 4145 2) 5675 3) 6035 4) 7325 5) 8885

Description : (562 % of 816) + 1449 = ? 1) 4145 2) 5675 3) 6035 4) 7325 5) 8885

Last Answer : 3) 6035

Rohit sold his bicycle at 4 % profit. If he sold it for Rs.204 less, he would have made a 30% loss. What was his cost price(in Rs.)? a)630 b)640 c)600 d)560

Description : Rohit sold his bicycle at 4 % profit. If he sold it for Rs.204 less, he would have made a 30% loss. What was his cost price(in Rs.)? a)630 b)640 c)600 d)560

Last Answer : c)600 

60% loss on cost price is what percent loss on selling price? A. 28 B. 38 % C. 40 D. 150%

Description : 60% loss on cost price is what percent loss on selling price? A. 28 B. 38 % C. 40 D. 150%

Last Answer : Answer – D (150 %) Explanation – Loss = 60% on CP i.e., 0.6CP ⇒ SP = 0.4CP Loss % on SP = loss/SP x 100 = 0.6CP/0.4CP x 100 = 150%.

A man sells two flats for Rs. 8000 each. neither loosing nor gaining in the deal. If he sold one at a gain of 25%, the other commodity sold at a loss of: A. 50/3 % B. 18 /3% C. 25% D. 32%

Description : A man sells two flats for Rs. 8000 each. neither loosing nor gaining in the deal. If he sold one at a gain of 25%, the other commodity sold at a loss of: A. 50/3 % B. 18 /3% C. 25% D. 32%

Last Answer : Answer – A (50/3 %) Explanation – Total S.P = 16000 Rs. and Total C.P = 16000 Rs. S.P. of Ist = Rs. 8000. Gain on it = 25% C.P of Ist = Rs. (100/125 x 8000) = Rs.6400 C.P of 2nd = Rs, (16000 – 6400) = Rs. 9600. S.P of 2nd = 8000. ∴loss on 2nd commodity = (1600/9600 x 100)% = 50/3%

A man sells two flats at the rate of Rs. 2 lakhs each. On one he gains 3% and on the other, he loses 3%. His gain or loss % in the whole transaction is A. 9% loss B. 2% loss C. 3% loss D. 25% loss

Description : A man sells two flats at the rate of Rs. 2 lakhs each. On one he gains 3% and on the other, he loses 3%. His gain or loss % in the whole transaction is A. 9% loss B. 2% loss C. 3% loss D. 25% loss

Last Answer : Answer – A (0.09% loss) Explanation – Loss% = X^2/100=(3)^2/100 % =0.09%

A man purchased wheat worth Rs. 400. He sold 3/4 at a loss of 10% and the reminder at a gain of 10%. On the whole he gets: A. loss of 5% B. gain of 5 C. loss of 19% D. loss of 6%

Description : A man purchased wheat worth Rs. 400. He sold 3/4 at a loss of 10% and the reminder at a gain of 10%. On the whole he gets: A. loss of 5% B. gain of 5 C. loss of 19% D. loss of 6%

Last Answer : Answer – A (loss of 5%) Explanation – C.P of 3/4th = Rs. (3/4 x 400) = Rs. 300, C.P of 1/4th = Rs. 100 ∴ Total S.P = (90% of Rs. 300 + 110% of Rs. 100) = Rs. 380 Loss = (20/400 x 100)% = 5%

Sum of present ages of A and B is 60 years. 5 years hence, their ages will be in the ratio 3:4. Find A’s present age. a) 25 years b) 30 years c) 35 years d) 40 years e) None of these

Description : Sum of present ages of A and B is 60 years. 5 years hence, their ages will be in the ratio 3:4. Find A’s present age. a) 25 years b) 30 years c) 35 years d) 40 years e) None of these

Last Answer : Sum of their present ages = 60 years sum of their ages, 5 years hence = 60 + (5 × 2) = 70 years. after 5 years, ratio of ages of A and B will be 3 : 4. A’s age after 5 years = (3/7) × 70 = 30 years A’s present age = 30 – 5 = 25 years Answer: a)

151.1% of 151.1 + 151.1 = ? a) 380 b) 400 c) 350 d) 420 e) 440

Description : 151.1% of 151.1 + 151.1 = ? a) 380 b) 400 c) 350 d) 420 e) 440

Last Answer : Answer: a)

57% of 400 + 23% of 700 + 32% of 1100 – 28% of 1300 = ? a) 401 b) 389 c) 377 d) 364 e) 352

Description : 57% of 400 + 23% of 700 + 32% of 1100 – 28% of 1300 = ? a) 401 b) 389 c) 377 d) 364 e) 352

Last Answer : ? = 57×4 + 23×7 + 32×11 - 28×13 = 228 + 161 + 352 – 364 = 377 Answer: c)

676, 400, 196, 64, 4, ? a) 4 b) 36 c) 16 d) -4 e) -16

Description : 676, 400, 196, 64, 4, ? a) 4 b) 36 c) 16 d) -4 e) -16

Last Answer : Answer: c)

The profit made by David in selling his calculator for Rs.400 would be the same as the loss he would have made in selling it at a 25% loss. If he sold his calculator after offering a discount of Rs.100, find the percentage at which he marked it above the cost price. a)56.25% b)62.5% c)60% d)50%

Description : The profit made by David in selling his calculator for Rs.400 would be the same as the loss he would have made in selling it at a 25% loss. If he sold his calculator after offering a discount of Rs.100, find the percentage at which he marked it above the cost price. a)56.25% b)62.5% c)60% d)50%

Last Answer : a)56.25%

A shopkeeper marked a suit at Rs.400. He sold it after allowing a discount, and still made at a profit of 25%. At what percentage above its cost price did he marked the suit, if he sold it for Rs.320? a)50% b)66 2/3% c)62 1/2% d)56 1/4%

Description : A shopkeeper marked a suit at Rs.400. He sold it after allowing a discount, and still made at a profit of 25%. At what percentage above its cost price did he marked the suit, if he sold it for Rs.320? a)50% b)66 2/3% c)62 1/2% d)56 1/4%

Last Answer : d)56 1/4%

In a bag there arc coins of 25 paise and 10 paise in the ratio of 6 : 17. If the bag contains Rs. 16 then the number of 10-paise coins is a) 30 b) 40 c) 70 d) 85 e) 65

Description : In a bag there arc coins of 25 paise and 10 paise in the ratio of 6 : 17. If the bag contains Rs. 16 then the number of 10-paise coins is a) 30 b) 40 c) 70 d) 85 e) 65

Last Answer : d) 85

The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: A.30 B.22 C.40 D.60 E.None of these

Description : The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: A.30 B.22 C.40 D.60 E.None of these

Last Answer : Answer – C (40) Explanation – Let the numbers be 2x and 3x. Then, their L.C.M. = 6x. So, 6x = 48 or x = 8. The numbers are 16 and 24. Hence, required sum = (16 + 24) = 40.

A modified amino acid solution with increased equimolar branched-chain amino acids and decreased aromatic amino acids has been proposed for patients with hepatic insufficiency. Which of the following statements is/are true? A. This formulation is proposed for the use of patients with fulminant hepatitis. B. Nitrogen balance is achieved in such patients with amounts of 40 gm. of amino acids per 24 hours. C. The use of 80 to 100 gm. of such solutions is associated with hepatic encephalopathy. D. In some studies of surgical patients, improvements in mortality have been reported.

Description : A modified amino acid solution with increased equimolar branched-chain amino acids and decreased aromatic amino acids has been proposed for patients with hepatic insufficiency. Which of the following ... D. In some studies of surgical patients, improvements in mortality have been reported.

Last Answer : Answer: D DISCUSSION: The use of modified amino acid solutions is based on the false neurotransmitter hypothesis of the cause of hepatic coma. According to this hypothesis, the imbalance ... in a group of patients with cirrhosis, decreasing morbidity and showing a trend toward decreased mortality

One-fifth of a number is equal to 5/8th of another number. If 35 is added to the first number, it becomes four times of the second number. Find the second number. 1. 39 2. 70 3. 40 4. 25 5. None of these

Description : One-fifth of a number is equal to 5/8th of another number. If 35 is added to the first number, it becomes four times of the second number. Find the second number. 1. 39 2. 70 3. 40 4. 25 5. None of these

Last Answer : Answer- 3(40) Explanation:- (1/5)x =(5/8)y………..1 if 35 is added to first no. , x + 35= 4y so,x= 4y -35 put in eq 1… (1/5)( 4y-35) = (5/8)y y=40 =second number