?% of 725 + 14% of 2100 = 700 a) 64 b) 80 c) 72 d) 56 e) 48

?% of 725 + 14% of 2100 = 700
a) 64
b) 80
c) 72
d) 56
e) 48
by

1 Answer

Answer :

?% × 725 +14 × 21=700
=>?% × 725 +294 =700
=> ?% × 725 =406
=>?=406/725 × 100 =56
Answer: d)
by

Related questions

Deepa decided to donate 16% of her monthly salary to an NGO. On the day of donation she changed her mind and donated Rs. 6,567/- which was 75%of what she had decided earlier. How much is Deepa’s monthly salary? a) Rs. 54,725/- b) Rs. 58,756/- c) Rs. 56,700/- d) Rs. 55,696/- e) Rs. 52,696/-

Description : Deepa decided to donate 16% of her monthly salary to an NGO. On the day of donation she changed her mind and donated Rs. 6,567/- which was 75%of what she had decided earlier. How much is Deepa’s monthly salary? a) Rs. 54,725/- b) Rs. 58,756/- c) Rs. 56,700/- d) Rs. 55,696/- e) Rs. 52,696/-

Last Answer : Let the Deepa Monthly Salary = x Deepa decided to donate 16% of her monthly salary. On the day of donation she changed. So, 75%of she had decided earlier of 16% 16 × 75/100 = 12% Therefore = 12%= Rs. 6567 100% = Rs .6567 × 100 / 12 x = Rs. 54725 Answer: a)

53 × 47 + 64 × 56 -72 × 68 = ? a) 1221 b) 1403 c) 1249 d) 1337 e) 1179

Description : 53 × 47 + 64 × 56 -72 × 68 = ? a) 1221 b) 1403 c) 1249 d) 1337 e) 1179

Last Answer : Answer: e)

Three-fourth of two-third of one-sixth of a number is 15.What is 30 percent of that number? a) 54 b) 48 c) 72 d) 64 e) None of these

Description : Three-fourth of two-third of one-sixth of a number is 15.What is 30 percent of that number? a) 54 b) 48 c) 72 d) 64 e) None of these

Last Answer : Suppose no. is x 3x/4 ×2/3 ×1/6 x/12 = 15/1 x = 180, 30% of 180 = 54 Answer: a)

A person covered a certain distance by bus at the rate of 40 kmph and walked back to the initial point at the rate of 6 kmph. The whole journey took 13 hours and 48 minutes. What distance did he walk? a) 60km b) 64 km c) 70km d) 72km e) 80 km

Description : A person covered a certain distance by bus at the rate of 40 kmph and walked back to the initial point at the rate of 6 kmph. The whole journey took 13 hours and 48 minutes. What distance did he walk? a) 60km b) 64 km c) 70km d) 72km e) 80 km

Last Answer : Let the distance be x km. then (x/40) + (x/6) = 13 + (48/60) = 69/5 Answer is: d)

The marked price of a watch was Rs. 720.A man brought the same for Rs.550.80 after getting two successive discounts the first being 10% .What was the second discount rate? A. 12% B. 14% C. 15% D. 18%

Description : The marked price of a watch was Rs. 720.A man brought the same for Rs.550.80 after getting two successive discounts the first being 10% .What was the second discount rate? A. 12% B. 14% C. 15% D. 18%

Last Answer : Answer – C. 15% Explanation – Let the second discount rate be x% Then, (100 – x)% of 90% of 720 = 550.80 => (100 – x)/100 x 90/100 x 720 = 550.80 = (100-x) = [55080/(9 x 72) = 85 => x= 15 second discount rate =15%

19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)

The average weight of four boys A, B, C, and D is 75 kg. The fifth boy E is included and the average weight decreases by 4 kg. A is replaced by F. The weight of F is 6 kg more than E. Average weight decreases because of the replacement of A and now the average weight is 72 kg. Find the weight of A. 1) 57 kg 2) 54 kg 3) 56 kg 4) 60 kg 5) 58 kg

Description : The average weight of four boys A, B, C, and D is 75 kg. The fifth boy E is included and the average weight decreases by 4 kg. A is replaced by F. The weight of F is 6 kg more than E. Average weight decreases because of ... . Find the weight of A. 1) 57 kg 2) 54 kg 3) 56 kg 4) 60 kg 5) 58 kg

Last Answer : 3) 56 kg

A sum was invested for 4 yr at a certain rate of simple interest. If it had been invested at 2% more annual rate of interest, then Rs. 64 more would have been obtained. What is the sum? (a) Rs.600 (b) Rs.700 (c) Rs.800 (d) Rs.900

Description : A sum was invested for 4 yr at a certain rate of simple interest. If it had been invested at 2% more annual rate of interest, then Rs. 64 more would have been obtained. What is the sum? (a) Rs.600 (b) Rs.700 (c) Rs.800 (d) Rs.900

Last Answer : (c) Rs.800

Avinash, Bala and Chandran invested Rs.45,000/-, Rs. 70, 000/- and Rs. 90,000/- respectively to start a business. At the end of two years, they earned a profit of Rs.1,64,000/-. What will be Bala’s share in the profit? a) Rs.56, 000/- b) Rs.46, 000/- c) Rs. 50, 000/- d) Rs.75, 000/- e) None of these

Description : Avinash, Bala and Chandran invested Rs.45,000/-, Rs. 70, 000/- and Rs. 90,000/- respectively to start a business. At the end of two years, they earned a profit of Rs.1,64,000/-. What will be Bala’s share in the profit? a) Rs.56, 000/- b) Rs.46, 000/- c) Rs. 50, 000/- d) Rs.75, 000/- e) None of these

Last Answer : Profit sharing ratio of Avinash,Bala & Chandran = 45000 : 70000 : 90,000 = 45 : 70 : 90 = 9 : 14 : 18 Bala's share of profit after two year =Rs.164000 × 14 × 41 = Rs. 4000 ×14 = Rs. 56000 Answer: a)

5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Description : 5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Last Answer : Each term in the series is the addition of successive prime numbers. Like Prime numbers are2, 3, 5, 7, 11, 13, 17, 19, 23, 29 and so on. So first term is addition of (2 + 3). Ie 5, then second term is (3 + 5) ie ... +17)ie. 30, then (17+19)ie.36, then (19+23)ie., 42, then (23+29)i.e. 52. Answer: a)

34.8% x 950 – 33.2% of 850 = ? a) 58.4 b) 48.4 c) 56.4 d) 68.9 e) 76.3

Description : 34.8% x 950 – 33.2% of 850 = ? a) 58.4 b) 48.4 c) 56.4 d) 68.9 e) 76.3

Last Answer : 34.8% x 950 – 33.2% of 850 = ? Sol: 0.348 x 950 – 0.332 x 850=? 330.6 – 282.2=? ?= 48.4 Answer: b)

Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: A.58 sec B.50 sec C.48 sec D.56 sec E.None of these

Description : Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is: A.58 sec B.50 sec C.48 sec D.56 sec E.None of these

Last Answer : Answer – C (48 sec) Explanation – Relative speed = all lengths/time [60+90] = [1.10 +0.9 ]/time [ PLUS when opposite direction] time=2/150 = 1/75 h 1 hour______3600 sec 1/75 hr______? ?= 3600/75=48 sec

24+(72 ÷ 48×8+14) × 36 ÷ (3×4) + 36 ÷ 3 ×4 a) 120 b) 140 c) 160 d) 180 e) None of these

Description : 24+(72 ÷ 48×8+14) × 36 ÷ (3×4) + 36 ÷ 3 ×4 a) 120 b) 140 c) 160 d) 180 e) None of these

Last Answer : 72÷48×8+14 = (72/48) × 8 + 14 = (3/2) × 8 + 14 = 12 +14 = 26 24 + (72 ÷ 48 × 8 + 14) ×36 ÷ (3 × 4) + 36 ÷ 3 × 4 = 24 + 26 × 36÷12 + 36 ÷ 3 × 4 = 24 + 26 × 3 + 12 × 4 = 24 + 78 + 48 = 150 Answer: e)

1824 ÷ 32 + 5040 ÷ ? – 5600 ÷ 35 = 37 a) 36 b) 48 c) 60 d) 72 e) 84

Description : 1824 ÷ 32 + 5040 ÷ ? – 5600 ÷ 35 = 37 a) 36 b) 48 c) 60 d) 72 e) 84

Last Answer : 57 + 5040 ÷ ? – 160 = 37 5040 ÷ ? = 37 – 57 + 160 = 140 = 5040 ÷ 140 = 36 Answer: a)

In how many different ways can the letters of the word DESIGN be arranged so that the vowels are at the two ends? a) 48 b) 66 c) 12 d) 72 e) 96

Description : In how many different ways can the letters of the word DESIGN be arranged so that the vowels are at the two ends? a) 48 b) 66 c) 12 d) 72 e) 96

Last Answer : Total ways = 4 ! x 2 ! = 4 × 3 × 2 x 2= 48 Answer: a)

The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: A.11115 B.15110 C.15130 D.15310 E.None of these

Description : The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: A.11115 B.15110 C.15130 D.15310 E.None of these

Last Answer : Answer – B (15110) Explanation – Here (48 – 38) = 10, (60 – 50) = 10, (72 – 62) = 10, (108 – 98) = 10 & (140 – 130) = 10. Required number = (L.C.M. of 48, 60, 72, 108, 140) – 10 = 15120 – 10 = 15110

The average of weight of three men A,B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E, whose weight is 3 kg.more than that of D, replaces A, then the average weight of B,C,D and E becomes 79 kg. The weight of A is : a) 70 kg b) 72 kg c) 75 kg d) 80 kg e) 78 kg

Description : The average of weight of three men A,B and C is 84 kg. Another man D joins the group and the average now becomes 80 kg. If another man E, whose weight is 3 kg.more than that of D, replaces A, then the average weight of B,C ... 79 kg. The weight of A is : a) 70 kg b) 72 kg c) 75 kg d) 80 kg e) 78 kg

Last Answer : A+B+C = 3×84=252 A+B+C+D= (4×80)=320 D = (320-252)=68 and E = (68+3)=71 Now, B+C+D+E = (4×79)=316 B+C+D=(316-71)=245 kg So, A = (320-245)=75 kg Answer: c)

Two concentric circles have radii of 23 cm and 9 cm. A rectangle has an area equal to the annular space between the above two circles. If the breadth of the rectangle is 22 cm then find its length. 1 : 32 cm 2 : 48 cm 3 : 76 cm 4 : 64 cm 5 : None of these

Description : Two concentric circles have radii of 23 cm and 9 cm. A rectangle has an area equal to the annular space between the above two circles. If the breadth of the rectangle is 22 cm then find its length. 1 : 32 cm 2 : 48 cm 3 : 76 cm 4 : 64 cm 5 : None of these

Last Answer : 4 : 64 cm

A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is: a) 35.55 km/hr b) 36 km/hr c) 71.11 km/hr d) 71 km/hr e) 69.69km/hr

Description : A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is: a) 35.55 km/hr b) 36 km/hr c) 71.11 km/hr d) 71 km/hr e) 69.69km/hr

Last Answer : Total time taken = (160/64) + (160/80) = 9/2 hrs. Avg Speed – 320 × (2/9) km/hr = 71.11km/hr Answer: c)

256 128 ? 192 96 240 80 a) 64 b) 156 c) 96 d) 128 e) 176

Description : 256 128 ? 192 96 240 80 a) 64 b) 156 c) 96 d) 128 e) 176

Last Answer : The series is ×0.5, ÷1, ×1.5, ÷2, ×2.5.... Answer: d)

A merchant dealer gives successive discounts of 10% and 20% in that order and makes a profit of 20%. what will be the profit if he offers a single flat discount of 30%? a) 20% b) 16.67% c) 18% d) 14% e) None of these

Description : A merchant dealer gives successive discounts of 10% and 20% in that order and makes a profit of 20%. what will be the profit if he offers a single flat discount of 30%? a) 20% b) 16.67% c) 18% d) 14% e) None of these

Last Answer : let marked price be 100. SP with 10%, 20% = 80% of (90% of 100) = 72. profit = 20% so CP = 72/1.20 = Rs. 60 by offering a flat discount of 30%, sales price = 70% of 100 = 70 profit = (70 - 60) ×100 / 60 = 16.67% Answer: b)

Ashwin borrowed a sum of Rs.6, 300 from Mishra at the rate of 14% for 3 years. He then added some more money to the borrowed sum and lent it to Ramesh at the rate of 16% of simple interest for the same time. If Ashwin gained Rs.618/- in the whole transaction, then what sum did he lend to Ramesh? a) Rs.6600 b) Rs.6800 c) Rs.4800 d) Rs.9800 e) Rs.8500

Description : Ashwin borrowed a sum of Rs.6, 300 from Mishra at the rate of 14% for 3 years. He then added some more money to the borrowed sum and lent it to Ramesh at the rate of 16% of simple interest for the same time. If ... sum did he lend to Ramesh? a) Rs.6600 b) Rs.6800 c) Rs.4800 d) Rs.9800 e) Rs.8500

Last Answer : Suppose Ashwin lend Rs. x to Ramesh then, Xx16x3/100 - (X – 6300) × 14 × 3/100 = 618......(1) From equation I , x = Rs. 6800 Answer: b)

400 gm spirit solution has 30 % spirit in it , what is the ratio of spirit should be added to make it 80 % in the solution ? A)2:5 B)4:3 C)5:2 D)2:7

Description : 400 gm spirit solution has 30 % spirit in it , what is the ratio of spirit should be added to make it 80 % in the solution ? A)2:5 B)4:3 C)5:2 D)2:7

Last Answer : A)2:5

39.98 × 85.01 – 79.9 × 34.9 + 175.03 × 12.08 = ? a) 4800 b) 4300 c) 2700 d) 2100 e) 3400

Description : 39.98 × 85.01 – 79.9 × 34.9 + 175.03 × 12.08 = ? a) 4800 b) 4300 c) 2700 d) 2100 e) 3400

Last Answer : ? = 40 × 85 – 80 × 35 + 175 × 12 = 3400 – 2800 + 2100 = 2700 Answer: c)

Difference between the compound interest and the simple interest accrued on an amount of Rs. 18000 in two year is Rs. 405. What was the rate of interest? 1) 14% 2) 16% 3) 12.5% 4) 15% 5) 15.5%

Description : Difference between the compound interest and the simple interest accrued on an amount of Rs. 18000 in two year is Rs. 405. What was the rate of interest? 1) 14% 2) 16% 3) 12.5% 4) 15% 5) 15.5%

Last Answer : 4) 15%

Ganesha, Harish and Raghu started a business with investments of Rs.15000, Rs.18000 and Rs.21000. At the end of the one year, they earned a total profit of Rs.5400. Find the respective shares of Ganesh, Harish and Raghu in the profit (in Rs.) a)1500,1800,2100 b)1360,1800,2240 c)1750,2100,2450 d)1890,2100,2310

Description : Ganesha, Harish and Raghu started a business with investments of Rs.15000, Rs.18000 and Rs.21000. At the end of the one year, they earned a total profit of Rs.5400. Find the respective shares of Ganesh, Harish ... profit (in Rs.) a)1500,1800,2100 b)1360,1800,2240 c)1750,2100,2450 d)1890,2100,2310 

Last Answer : a)1500,1800,2100

A sample of natural gas containing 80% methane (CH4 ) and rest nitrogen (N2 ) is burnt with 20% excess air. With 80% of the combustibles producing CO2 and the remainder going to CO, the Orsat analysis in volume percent is (A) CO2 : 6.26, CO : 1.56, O2 : 3.91, H2O :15.66, N2 : 72.60 (B) CO2 : 7.42, CO : 1.86, O2 : 4.64, N2 :86.02 (C) CO2 : 6.39, CO : 1.60, O2 : 3.99, H2O:25.96, N2 :72.06 (D) CO2 : 7.60, CO : 1.90, O2 : 4.75, N2 : 85.74

Description : A sample of natural gas containing 80% methane (CH4 ) and rest nitrogen (N2 ) is burnt with 20% excess air. With 80% of the combustibles producing CO2 and the remainder going to CO, the Orsat analysis in volume percent is (A) CO2 : 6 ... 96, N2 :72.06 (D) CO2 : 7.60, CO : 1.90, O2 : 4.75, N2 : 85.74

Last Answer : (B) CO2 : 7.42, CO : 1.86, O2 : 4.64, N2 :86.02

The population of a city in 2000 is 50,000. The average per decade of the previous records of population is 5000 and average percentage per decade is 20%. The population of the city based on geometrical increase method, in the year 2020 will be (A) 56,000 (B) 60,000 (C) 64,000 (D) 72,000

Description : The population of a city in 2000 is 50,000. The average per decade of the previous records of population is 5000 and average percentage per decade is 20%. The population of the city based on geometrical increase method, in the year 2020 will be (A) 56,000 (B) 60,000 (C) 64,000 (D) 72,000

Last Answer : (D) 72,000

Which is the number that comes next in the following sequence? 2, 6, 12, 20, 30, 42, 56, ………… (A) 60 (B) 64 (C) 72 (D) 70

Description : Which is the number that comes next in the following sequence? 2, 6, 12, 20, 30, 42, 56, ………… (A) 60 (B) 64 (C) 72 (D) 70

Last Answer : (C) 72

A bus can travel 25% faster than a jeep. Both start from point P at the same time and reach point Q, 225 kms away from P, at the same time. On the way, however, the bus lost about 37.5 minutes while stopping at the certain place. What is the speed of the jeep? a) 64 km/hr b) 72 km/hr c) 68 km/hr d) 56 km/hr

Description : A bus can travel 25% faster than a jeep. Both start from point P at the same time and reach point Q, 225 kms away from P, at the same time. On the way, however, the bus lost about 37.5 minutes while stopping at the ... is the speed of the jeep? a) 64 km/hr b) 72 km/hr c) 68 km/hr d) 56 km/hr

Last Answer : B Let speed of the jeep =x kmph Then, speed of the bus =(100+25)x/100 =125x/100 =5x/4 kmph Time taken by the jeep to travel from P to Q =225/x hours Time taken by the bus to travel from p to Q =225/(5x/4) + ... 225/x=900/5x+37.5/60 225/x=180/x+37.5/60 45/x =37.5/60 37.5x=45*60 X=72 km/hr

The population of city S increased from 650,000 in 2000 to 700,000 in 2010, and it is projected that the population will increase by the same number from 2010 to 2020. Approximately what is the projected percent increase in population from 2010 to 2020 ? a) 7.1% b) 7.7% c) 8.3% d) 14.3% e) 15.3%

Description : The population of city S increased from 650,000 in 2000 to 700,000 in 2010, and it is projected that the population will increase by the same number from 2010 to 2020. Approximately what is the projected percent increase in population from 2010 to 2020 ? a) 7.1% b) 7.7% c) 8.3% d) 14.3% e) 15.3%

Last Answer : Required percentage = (750000 - 700000)/700000 * 100 = 7.14% Answer: a)

57% of 400 + 23% of 700 + 32% of 1100 – 28% of 1300 = ? a) 401 b) 389 c) 377 d) 364 e) 352

Description : 57% of 400 + 23% of 700 + 32% of 1100 – 28% of 1300 = ? a) 401 b) 389 c) 377 d) 364 e) 352

Last Answer : ? = 57×4 + 23×7 + 32×11 - 28×13 = 228 + 161 + 352 – 364 = 377 Answer: c)

A train travelling at 36 kmph completely crosses another train having half its length and travelling in the opposite direction at 54 kmph, in 12 seconds. If it also passes a railway platform in 112 minutes, the length of the platform is : a) 560 metres b) 620 metres c) 700 meres d) 750 metres e) 720 meters

Description : A train travelling at 36 kmph completely crosses another train having half its length and travelling in the opposite direction at 54 kmph, in 12 seconds. If it also passes a railway platform in 112 minutes, the length ... is : a) 560 metres b) 620 metres c) 700 meres d) 750 metres e) 720 meters

Last Answer : Answer: c)

720% of 40 + 520 = x – 28 a) 800 b) 700 c) 820 d) 840 e) 500

Description : 720% of 40 + 520 = x – 28 a) 800 b) 700 c) 820 d) 840 e) 500

Last Answer : Answer: a) 

2/3 part of the sum is lent out at 3%, 1/6 part is lent out at 6% and remaining part at 12%. All the three parts are lent out at simple interest. If the annual income is Rs. 35, what is the sum? (a) Rs.500 (b) Rs.600 (c) Rs.700 (d) Rs.850 (e) Rs.950

Description : 2/3 part of the sum is lent out at 3%, 1/6 part is lent out at 6% and remaining part at 12%. All the three parts are lent out at simple interest. If the annual income is Rs. 35, what is the sum? (a) Rs.500 (b) Rs.600 (c) Rs.700 (d) Rs.850 (e) Rs.950

Last Answer : (c) Rs.700

Insert the missing number: 36/62, 39/63, 43/61, 48/64, ? (A) 51/65 (B) 56/60 (C) 54/60 (D) 33/60

Description : Insert the missing number: 36/62, 39/63, 43/61, 48/64, ? (A) 51/65 (B) 56/60 (C) 54/60 (D) 33/60

Last Answer : Answer: C Observer 36/62, 39/63, 43/61, 48/64, ? series Upper part is increase by 3, 4, 5, 6 i.e 36+3= 39, 39+4 = 43, 43+5 = 48, 48 + 6 = 54.

The correct readback of the frequency 123.725 on 25 kHz spacing is: a. 123.725 b. 123.7 c. 12372 d. 123.72

Description : The correct readback of the frequency 123.725 on 25 kHz spacing is: a. 123.725 b. 123.7 c. 12372 d. 123.72

Last Answer : a. 123.725

The correct readback of the frequency 123.725 on 25 kHz spacing is: a. 123.725 b. 123.7 c. 12372 d. 123.72

Description : The correct readback of the frequency 123.725 on 25 kHz spacing is: a. 123.725 b. 123.7 c. 12372 d. 123.72

Last Answer : a. 123.725

What is the average score in an exam taken by 500 students where the minimum score is 200? a. Half the students scored above 700. b. Half the students scored below 700. c. The maximum score in the exam was 850, scored by exactly 42 students.

Description : What is the average score in an exam taken by 500 students where the minimum score is 200? a. Half the students scored above 700. b. Half the students scored below 700. c. The maximum score in the ... . e) If the data in statement a, b and c together are not sufficient to answer the question.

Last Answer : The fact that half scored above 700, and other half less than 700 does not tell the actual distribution of scores to calculate the average. Statement (c) also does not help us determine the average. Answer: e)

An electric field is given as E = 6y 2 z i + 12xyz j + 6xy 2 k. An incremental path is given by dl = -3 i + 5 j – 2 k mm. The work done in moving a 2mC charge along the path if the location of the path is at p(0,2,5) is (in Joule) a) 0.64 b) 0.72 c) 0.78 d) 0.80

Description : An electric field is given as E = 6y 2 z i + 12xyz j + 6xy 2 k. An incremental path is given by dl = -3 i + 5 j – 2 k mm. The work done in moving a 2mC charge along the path if the location of the path is at p(0,2,5) is (in Joule) a) 0.64 b) 0.72 c) 0.78 d) 0.80

Last Answer : b) 0.72

A fluid (µ/ρ) = 0.01 cm2 /sec is moving at critical flow condition (NRe = 2100) through a pipe of dia 3 cms. Velocity of flow is __________ cm/sec. (A) 7 (B) 700 (C) 7000 (D) 630

Description : A fluid (µ/ρ) = 0.01 cm2 /sec is moving at critical flow condition (NRe = 2100) through a pipe of dia 3 cms. Velocity of flow is __________ cm/sec. (A) 7 (B) 700 (C) 7000 (D) 630

Last Answer : (A) 7

Stoke's law is valid, when NRe, p is less than (A) 2 (B) 100 (C) 2100 (D) 700

Description : Stoke's law is valid, when NRe, p is less than (A) 2 (B) 100 (C) 2100 (D) 700

Last Answer : (A) 2

A wire can be bent to form a circle of radius 56 cm. if it is instead bent in the form of a square, then its area will be: a) 6400 sq.cm b) 2025 sq.cm c) 7744 sq.cm d) 6561 sq.cm e) none of these

Description : A wire can be bent to form a circle of radius 56 cm. if it is instead bent in the form of a square, then its area will be: a) 6400 sq.cm b) 2025 sq.cm c) 7744 sq.cm d) 6561 sq.cm e) none of these

Last Answer : Length of the wire = circumference of the circle 2 × (22/7) × 56 = 2 × 22 × 8 = 352 cm side of square = 352/4 = 88cm area of square = 88 × 88 = 7744 sq.cm Answer: c)

10 years ago the average age of all the 25 teachers of a college was 45 years. 4 years ago, a teacher retired from the post at the age of 60 years, and was replaced by a new teacher whose age was 54 years. What is the present average age of all the teachers? a) Between 52 and 53 b) Between 53 and 54 c) Between 54 and 55 d) Between 55 and 56 e) None of the above

Description : 10 years ago the average age of all the 25 teachers of a college was 45 years. 4 years ago, a teacher retired from the post at the age of 60 years, and was replaced by a new teacher whose age was 54 years. ... 53 b) Between 53 and 54 c) Between 54 and 55 d) Between 55 and 56 e) None of the above

Last Answer : Let current year be 2015 In 2005, sum of all ages = 25 45 = 1125 In 2015, sum of all ages = 1125 + (25 10) = 1375 Now 60 year old teacher was replaced by a 54 year old teacher. So we need ... all ages in 2015 considering the replacement teacher = 1375 - 6 = 1369 Average = 1369/25 = 54.76 Answer: c)

Saina spent Rs. 44,668/- on her air tickets, Rs.56,732 on buying gifts to the family members and the remaining 22% of the total amount she had as cash with her. What was the total amount ? a) Rs. 1,25,800/- b) Rs. 1,30,000/- c) Rs. 1,10,500/- d) Rs. 1,68,300/- e) Rs. 1,50,000/-

Description : Saina spent Rs. 44,668/- on her air tickets, Rs.56,732 on buying gifts to the family members and the remaining 22% of the total amount she had as cash with her. What was the total amount ? a) Rs. 1,25,800/- b) Rs. 1,30,000/- c) Rs. 1,10,500/- d) Rs. 1,68,300/- e) Rs. 1,50,000/- 

Last Answer : Saving = 22% Spent = a00 - 22) = 78% Spending money = 44668 + 56732 = 101400 78%- 101400 100% = 101400 100/78 = 130000 Answer: b)

The average of 11 results is 50. If the average of first 6 results is 49 and that of last 6is 52, find the sixth result? A.55 B.56 C.65 D.62 E.None of these

Description : The average of 11 results is 50. If the average of first 6 results is 49 and that of last 6is 52, find the sixth result? A.55 B.56 C.65 D.62 E.None of these

Last Answer : Answer – B (56) Explanation – The total of 11 results = 11 x 50 = 550 The total of first 6 results = 6 x 49 = 294 The total of last 6 results = 6 x 52 = 312 The sixth result is common to both: Sixth result = 294 + 312 – 550 = 56

In a 100 quadrat study of 1 sqm each Cyperus rotundus was found in 80 quadrats with overall of 5640 individuals. The frequency (%), abun dance and density (m2) would be a). 70.5, 80.0 and 56.4 b). 56.4, 70.5 and 80.0 c). 80.0, 70.5 and 56.4 d). 80.0, 56.4 and 70.5

Description : In a 100 quadrat study of 1 sqm each Cyperus rotundus was found in 80 quadrats with overall of 5640 individuals. The frequency (%), abun dance and density (m2) would be a). 70.5, 80.0 and 56.4 b). 56.4, 70.5 and 80.0 c). 80.0, 70.5 and 56.4 d). 80.0, 56.4 and 70.5

Last Answer : c). 80.0, 70.5 and 56.4

187.5, 182, 171, ?, 132.5, 105, 72 a) 145.5 b) 155.5 c) 154.5 d) 144.5 e) None of these

Description : 187.5, 182, 171, ?, 132.5, 105, 72 a) 145.5 b) 155.5 c) 154.5 d) 144.5 e) None of these

Last Answer : The pattern is -5.5, -11, -16.5, -22 and so on. Answer: c)

72× 25 + 45× 96 = 163 + ? a) 1912 b) 2024 c) 1844 d) 1908 e) 1960

Description : 72× 25 + 45× 96 = 163 + ? a) 1912 b) 2024 c) 1844 d) 1908 e) 1960

Last Answer : 1800 + 4320 = 4096 + ? ? = 1800 + 4320 – 4096 = 2024 Answer: b)

72, 115, 244, ?, 760, 1147 a) 501 b) 431 c) 473 d) 459 e) 445

Description : 72, 115, 244, ?, 760, 1147 a) 501 b) 431 c) 473 d) 459 e) 445

Last Answer : The pattern is: 72+43×1=115, 115+43×3=244, 244+43×5=459, 459+43×7=760, 760+43×9=1147 Answer: d)