A mixture contains milk and water in the ratio of 3:2 litter of water is added to the
mixture, milk, milk and water in the mixture become equal find the quantities of milk and
water in the mixture .
a) 12, 8 litter
b) 4,3 litter
c) 12, 6 litres
d) 10,8 litres
e) None of these

1 Answer

Answer :

Let quantities of milk and water in the mixture be 3x and 2x. Then if 4 litres of water
is added to the mixture the ratio of milk and water become 1:1.
It can be written as (3x): (2x + 4) = 1/1
Thus, 3x = 2x +4
 x = 4
Therefore, the milk in the mixture is 4x3 = 12 litres and quantity of water = 4x2 = 8 liters
Answer: a)

Related questions

Description : From a vessel containing 100 litres of wine,10 litres are drawn out and an equal amount of water is added. From the mixture,10 litres is again drawn out and same quantity of water is added. What is the final ratio of wine and water? a) 91 : 9 b) 81 : 19 c) 80 : 20 d) 90 : 10 e) None of these

Last Answer : Quantity of wine after two replacements = 100 l × (90/100)2 =81 l Required ratio = 81 : ( 100 – 81 )= 81 : 19 Answer: b)

Description : In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage ... mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Last Answer : 2) 28. 57%

Description : A vessel contains 100 litres of milk. From this, 10 litres of milk was taken out and replaced by water. The process was repeated further two times. How much milk is now contained by the vessel? a) 72.9 litres b) 60.4 litres c) 71.6 litres d) 81 litres e) None of these

Last Answer : Milk after three replacement =100 × (90/100)3 = 72.9 litres Answer: a)

Description : A milkman mixes 20 litres of water with 80 litres of milk. After selling one-fourth of this mixture, he adds water to replenish the quantity he has sold, what is the current proportion of water to milk? a) 1 : 3 b) 2 : 3 c) 3 : 4 d) 4 : 3 e) None of these

Last Answer : Milk remaining after selling 1/4 of mixture = 80 ×(1- 1/4)=60 litres =>water =100-60 = 40 litres => Required ratio = 40 : 60 =2 : 3 Answer: b)

Description : How many litres of a 36 litre mixture containing milk and water in the ratio of 4 : 6 be replaced with pure milk so that the resultant mixture contains milk and water in equal proportion? a) 3 b) 2 c) 4 d) 7 e) 6 

Last Answer :  E  The mixture contains 40% milk and 60% water in it.  That is 14.4 litres of milk and 21.6 litres of water.  Now we are replacing the mixture with pure milk so that the amount of milk and water in the ... containing 60% water,  we need to remove ={3.6}/{0.6} litres of the mixture  = 6 litres

Description : Vessel A contains milk and water in the ratio 3:2. Vessel B contains milk and water in the proportion 4:5.In what proportion should quantities be taken from A & B to form a mixture in which milk and water are in the ratio 7:2? a) 3:2 b) 15:2 c) 4:3 d) 8:15 e) 6:18

Last Answer : D For this question, we will consider the proportion of milk in each mixture. In Vessel A, the proportion of milk in 3/((3+2) )=3/5. vessel B, the proportion of milk is 4/(4+5) = 4/9

Description : A sample of x litres from a container having a 60 litre mixture of milk and water containing milk and water in the ratio of 2 : 3 is replaced with pure milk so that the container will have milk and water in equal ... . What is the value of x? a) 6 litres b) 10 litres c) 30 litres d) None of these

Last Answer : C Another way for solving this sum is by choice The mixture of 60 litres has in it 24 litres of milk and 36 litres of water. (2 : 3 :: milk water) When you remove x litres from it, you ... have 30 litres of milk and 30 litres of water - i.e. milk and water are in equal proportion.

Description : A vessel contains milk and water in the ratio of 4:3. If 14 litres of the mixture is drawn and filled with water, the ratio changes to 3:4. How much milk was there in the vessel initially? a) 24 b) 32 c) 40 d) 48 e) None of these

Last Answer : Answer: B milk = 4x and water = 3x milk = 4x – 14*4/7 and water = 3x – 14*3/7 + 14 4x – 8: 3x + 8 = 3:4 X = 8, so milk = 8*4 = 32 litres

Description : A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5? a) 2 b) 3 c) 4 d) 7 e) 6 

Last Answer : E Let cost of 1 litre milk be Rs.1 Milk in 1 litre mix in 1st can =3/4 litre Cost Price(CP) of 1 litre mix in 1st can = Rs. 3/4 Milk in 1 litre mix in 2nd can 1/2 litre. Cost Price(CP) of 1 ... 2nd can :mix in 1st can =1/8:1/8=1:1 ie, from each can,1/2* 12 = 6 litre should be taken.

Description : A shopkeeper has 2 cans of milk. The first contains 30% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the cans so as to get 12 litres of milk such that the ratio of water to milk ... 7 lit. 2) 9 lit, 3 lit. 3) 7.5 lit, 4.5 lit. 4) 4 lit, 8 lit.

Last Answer : 3) 7.5 lit, 4.5 lit.

Description : In a solution of 45 litres of milk and water, ` 40%` is water. How many litres of milk must be added to become the ratio of milk and water ` 5 : 3` ?

Last Answer : In a solution of 45 litres of milk and water, ` 40%` is water. How many litres of milk must be added to become the ... : 3` ? A. 8 B. 3 C. 7 D. 6

Description : A container contains a mixture of two liquids P and Q in the ratio 7 : 5. When 9 litres of mixture are drawn off and the container is filled with Q, the ratio of P and Q becomes 7 : 9. How many litres of liquid P was contained in the container initially? a) 12 b) 21 c) 93 d)17 e) None 

Last Answer : B Let initial quantity of P in the container be 7x and initial quantity of Q in the container be 5x Now 9 litres of mixture is drawn off from the container. Quantity of P in 9 litres of the mixture drawn off ... = 7 : 9 x=16* 21/4*28 Litres of P contained in the container initially =7x = 21

Description : Equal quantities of 3 mixtures of milk and water are mixed in the ratio 1:3, 2:3 and 3:4.The ratio of water and milk in the new mixture is A) 45:76 B) 151:269 C) 123:154 D) 145:245 E) None of these

Last Answer : Answer: B Milk = 1/4 : 2/5 :3/7 = 35/140 :56/140 : 60/140 Quantity of milk in new mix = 35+56+60 = 151 Quantity of water in new mix = 140*3 = 420-151 = 269 M:W = 151:269

Description : In what ratio water be mixed with juice costing Rs.12 per liter to obtain a mixture worth of Rs.8 per litre? A)2:3 B)2:1 C)1:2 D)3:2

Last Answer : C)1:2

Description : In 20 litres of a mixture, the ratio of sugar syrub to honey syrub is 5:1. In order to make the ratio of sugar syrub to honey syrub as 3:1, the quantity of honey syrub that should be added to the mixture will be A) 5 2/3 B) 4 1/3 C) 6 2/3 D) 2 2/9

Last Answer : D By the rule of alligation Quantity of honey : Quantity of mixture =1/12:3/4}=1:9 Given that quantity of mixture = 20 litre =>Quantity of honey : 20 = 1 : 9 => Quantity of honey = 20 x1/9  = 2 2/9 litre

Description : 175 litres of a solution contains `88%` of acid and the rest water. How many liters of water must be added such that the resulting mixture contains `2

Last Answer : 175 litres of a solution contains `88%` of acid and the rest water. How many liters of water ... that the resulting mixture contains `23%` of water ?

Description : Box A contains wheat worth Rs.30 per kg and box B contains wheat worth Rs.40 per kg.If both A and B are mixed in the the ratio 4:7 then the price of mixture per kg is A)36.36 B)35.80 C)42.50 D)31.30

Last Answer : A)36.36

Description : In what ratio must a person mix three kinds of Oats costing him Rs 1.20,Rs 1.44 and Rs 1.74 per Kg so that the mixture may be worth Rs 1.41 per Kg? A)11:77:7 B) 11:45:7 C)25:45:8 D) 27:23:6

Last Answer : A)11:77:7

Description : A man buys milk at Rs. 2.40 per litre. He adds one-third water to it and sells the mixture at Rs. 2.88 per litre. Find his profit percentage. (Assume water is free). a) 21% b) 30% c) 40% d) 50% e) 60%

Last Answer : Let say he purchases 3 litres of milk whose cost is Rs. 7.20 He adds 1 litre of water and the mixture of 4 litres is sold at Rs 2.88 × 4 = Rs11.52 Profit percentage = (11.52 – 7.20) × 100.0/7.20 = 4.32 × 100.0/7.2 = 60% Answer: e)

Description : In a bag there arc coins of 25 paise and 10 paise in the ratio of 6 : 17. If the bag contains Rs. 16 then the number of 10-paise coins is a) 30 b) 40 c) 70 d) 85 e) 65

Last Answer : d) 85

Description : A container contains 55 litres of milk. From this container 5.5 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container? a) 32 b) 29.16 c) 43 d) 27.12 e) 40.09 

Last Answer : E  Where x is the initial quantity of milk in the cask y is the quantity of milk withdrawn in each process and n is the number of processes. Initial quantity:55 Withdrawn quantity=5.5 number of times repeated ... of milk left after the 3rd operation =55*((55-5.5)/55) ^3  =40.09litres.

Description : P and Q started a partnership business investing some amount in the ratio of 3:5. R joined them after six months with an amount equal to that of Q. In what proportion should the profit at the end of one year be distributed among P, Qand R? A.5 : 8 : 10 B.6 : 10 : 5 C.6 : 4 : 10 D.10 : 6 : 3

Last Answer : Answer – B (6 : 10 : 5) Explanation – Let the initial investments of P and Q be 3a amd 5a. P : Q : R = (3a x 12) : (5a x 12) : (5a x 6) = 36 : 60 : 30 = 6 : 10 : 5.

Description : A and B enter into a partnership. A contributes Rs. 16,000 and B Rs. 12,000. At the end of 6 months C joins them with a capital of Rs. 20,000. In what ratio should they divide their annual profit? a) 8:6:5 b) 4 :3 :5 c) 5:6:8 d) 5:3:4 e) 5:7:8

Last Answer : a) 8:6:5

Description : Two jars having a capacity of 3 and 5 litres respectively are filled with mixtures of milk and water. In the smaller jar 25% of the mixture is milk and in the larger 25% of the mixture is water. The jars are emptied ... the percentage of milk in the cask. a) 55% b) 50% c) 45% d) 25% e) None of these

Last Answer : Answer: D 0.75+3.75=4.5/10+8*100=4.5/18*100=25%

Description : The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: A.10 B.14 C.23 D.30 E.None of these

Last Answer : Answer – C (23) Explanation – L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37. Number to be added = (60 – 37) = 23

Description : 6 pens and 14 exercise books cost Rs.162. 5pens and 8 exercise books cost Rs.102. The ratio of cost of 1 pen to that of 1 exercise book is : a) 10 : 3 b) 2 : 3 c) 3 : 2 d) 5 : 6 e) None of these

Last Answer : Let cost of 1 pen be Rs.x and that of 1 exercise book be Rs.y. Then 6x +14 y = 162 =>3x + 7y =81……..(1) 5x + 8y =102…………………………………………..(2) (1)× 5 – (2) × 3 =>11y=99=>y=9.Putting y=9 in equation (1),we get : x = 6 x : y =6 : 9 =2 : 3 Answer: b)

Description : A sum of money is divided among Suresh, Ganesh, Vignesh and Mahesh in the ratio of 3 : 4 : 9 : 10 respectively. If the share of Vignesh is Rs.2,580/-more than the share of Ganesh, then what is the total amount of money of Suresh ... ,985/- b) Rs. 6,487/- c) Rs. 6,708/- d) Rs. 7,156/- e) Rs. 8,457/-

Last Answer : According to the question, difference of ratio of Ganesh and Vignesh is 5 so, 1 ratio = 2580/5 = 516 Now, total ratio of Suresh + Mahesh = 13 So, total money = 13 × 516 = Rs. 6708 Answer: c)

Description : Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together? A.8 B.11 C.13 D.16 E.None of these

Last Answer : Answer – D (16) Explanation – L.C.M. of 2, 4, 6, 8, 10, 12 is 120.So, the bells will toll together after every 120 seconds, i.e, 2 minutes.In 30 minutes, they will toll together 30/2 + 1 = 16

Description : 400 gm spirit solution has 30 % spirit in it , what is the ratio of spirit should be added to make it 80 % in the solution ? A)2:5 B)4:3 C)5:2 D)2:7

Last Answer : A)2:5

Description : Ages of DEEPA and Subha are presently in the ratio of 5 : 6 respectively. Six years hence this ratio will become 6 : 7 respectively. What was Subha’s age 5 years ago? a) 33 years b) 32 years c) 35 years d) 31 years e) None of these

Last Answer : Present ratio of Deepa&Subha = 5 : 6 Six year hence ratio of Deepa&Subha = 6 : 7 Difference between ratio = 1 Difference in ages between present & future = 6 year. 1 ratio=6 yrs & SUBHA's age = 6 6 =36 year 5 year ago ... = 7 6 = 42 year B's age 5 year ago = 42-6-5 = 42-11 = 31 year Answer: d)

Description : A Mixture contain 88% of sulphur,another mixture contain 70% of sulphur.In order to get 84% of sulphur,in what ratio these two must be mixed. A) 2:7 B)7:2 C)7:4 D)4:5

Last Answer : B)7:2

Description : A grocer bought two kinds of rice at Rs. 38 and Rs. 32 per kg respectively. In what ratio should these two be mixed, so that by selling the mixture at Rs.42.5 per kg, 25% may be gained? a) 2:1 b) 3:2 c) 3:4 d) 1:2

Last Answer : d) 1:2

Description : A solution of 30 litres of milk and water, has ` 70%` milk. How many litres of water must be added so that the volumes of milk and water will be in th

Last Answer : A solution of 30 litres of milk and water, has ` 70%` milk. How many litres of water must be added so that the volumes ... : 2`? A. 6 B. 3 C. 5 D. 4

Description : One-fifth of a number is equal to 5/8th of another number. If 35 is added to the first number, it becomes four times of the second number. Find the second number. 1. 39 2. 70 3. 40 4. 25 5. None of these

Last Answer : Answer- 3(40) Explanation:- (1/5)x =(5/8)y………..1 if 35 is added to first no. , x + 35= 4y so,x= 4y -35 put in eq 1… (1/5)( 4y-35) = (5/8)y y=40 =second number

Description : Shan bought 30 liters of milk at the rate of Rs.8 per liter. He got it churned after spending Rs.10 and 5kg of cream and 30 liter of toned milk were obtained. If he sold the cream at Rs.30 per kg and toned milk at Rs.4 per liter, his profit in the transaction is: A. 20% B. 8% C. 30% D. 40%

Last Answer : Answer – B .8% Explanation: CP =Rs.(30 x 8 + 10) = Rs.250 SP = Rs. (30 x 5 + 30 x 4) = Rs.270 Gain% = (20/250 x 100)% = 8%

Description : Sum of present age of A, B and C is 72 years. If 4 years ago, their ages were in the ratio 1 : 2 : 3, find A’s present age. a) 7 years b) 10 years c) 12 years d) 14 years e) None of these

Last Answer : Sum of present ages of A, B and C is 72 years. sum of their ages (4 years ago) = 72 – (3 × 4) = 60 years 4 years ago, ratio of ages of A, B and C was 1 : 2 :3. A’s age, 4 years ago = (1/6) ×60 = 10 years A’s present age = 10 + 4 = 14 years Answer: d)

Description : The shares of A, B and C are in the ratio 4 : 5 : 8. If each of the shares is increased by 75%, 20% and 25% respectively, what will be the ratio of their new shares? 1 : 5 : 3 : 5 2 : 7 : 6 : 9 3 : 7 : 6 : 10 4 : 5 : 6 : 10 5 : None of these

Last Answer : 3 : 7 : 6 : 10

Description : The average age of two persons is 46 years. 16 years back the ratio between their ages were 1 : 2, then what is the difference between present ages of these two persons? 1) 16 years 2) 20 years 3) 24 years 4) 12 years 5) 8 years

Last Answer : 2) 20 years

Description : Ashwin borrowed a sum of Rs.6, 300 from Mishra at the rate of 14% for 3 years. He then added some more money to the borrowed sum and lent it to Ramesh at the rate of 16% of simple interest for the same time. If ... sum did he lend to Ramesh? a) Rs.6600 b) Rs.6800 c) Rs.4800 d) Rs.9800 e) Rs.8500

Last Answer : Suppose Ashwin lend Rs. x to Ramesh then, Xx16x3/100 - (X – 6300) × 14 × 3/100 = 618......(1) From equation I , x = Rs. 6800 Answer: b)

Description : The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs.4000. The total price of 12 chairs and 3 tables is: a) Rs.3750 b) Rs.3840 c) Rs.3500 d) Rs.3900 e) None of these

Last Answer : Cost of 4 tables =Cost of 10 chairs => Cost of 1 table =10 4=2.5 chairs =>15 chairs + 2 tables = Rs.4000 => 15 chairs + 2 2.5 chairs = Rs.4000 =>20 chairs =Rs.4000 => 1 chair = Rs.4000 20 = Rs ... of 12 chairs + cost of 3 tables =12 Rs.200 + 3 Rs.500 = Rs.2400 + Rs.1500=Rs.3900 Answer: d)

Description : Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction? A.12 sec B.18 sec C.14 sec D.25 sec E.None of these

Last Answer : Answer – A (12 sec) Explanation – Speed of the first train = [120 / 10] m/sec = 12 m/sec. Speed of the second train = [120 / 15] m/sec = 8 m/sec. Relative speed = (12 + 8) = m/sec = 20 m/sec. ∴ Required time = (120 + 120) / 20 secc = 12 sec

Description : Pipe A can fill a water tank in 8 hours, Pipe B can fill the same tank in 12 hours and Pipe C can empty the tank in 24 hours. If all three pipes are opened together, in how many hours will the tank be completely filled or empty? a) 4.8 hours b) 5 hours c) 5.4 hours d) 6 hours e) 7.2 hours

Last Answer : If all the three pipes are opened together, in one hour they will fill 1/8 + 1/12 – 1/24 = (3+2-1)/24 = 1/6 part of tank. So, to fill it completely it will take 6 hours. Answer is: d)

Description : One alloy contains silver and copper in the ratio 5:1 and the other contains in the ratio 7:2 respectively. What weights of the 2 must be melted together, so as to make a 5 lb mass with 80% silver? A)5:3 B)3:2 C)2:3 D)2:5

Last Answer : B)3:2

Description : The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 ... hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Last Answer : 5 : 30 : 31

Description : Francis and George started a business with investments of Rs.7000 and Rs.10000. After x months, Francis left. After two more months David joined the business with an investment of Rs.10000. If the annual profit is shared among David, ... which they stayed that year. a)5:5:12 b)1:1:3 c)1:1:4 d)1:1:2

Last Answer : a)5:5:12

Description : The ratio between the present ages of A and B is 6:7. If B is 4 years old than A. What will be the ratio of the ages of A and B after 4 years? A.5 : 7 B.7 : 8 C.8 : 7 D.Data inadequate E.None of these

Last Answer : Answer – B (7 : 8) Explanation – Let A’s age and B’s age be 6X years and 7X years respectively Then, 7X – 6X = 4 X = 4 Required ratio = (6X + 4) : (7X + 4) = (6*4+4) : (7*4 +4) =28 : 32 = 7 : 8

Description : A box contains 2 black, 3 orange and 4 pink ribbons. If two ribbons are drawn at random. What is the probability that both are orange? 1) 5/12 2) 1/13 3) 1/14 4) 1/12 5) 1/24

Last Answer : 4) 1/12

Description : Is X divisible by 12? a. X leaves a remainder 2 when divided by 8 b. X is divisible by 3. c. X is divisible by 6. a) If the data in statement a is sufficient to answer the question, while ... the question. e) If the data in statement a, b and c together are not sufficient to answer the question.

Last Answer : From (a), we notice that the number is of the form 8n+2, which means it also leaves a remainder 2 on being divided by 4. So, its not divisible by 12. From (b) and (c) together, the number can be any multiple of 6, from which we cant conclusively say if number is divisible by 12. Answer: a)

Description : 19 + (12 ÷ 4 × (240 × 1 ÷ 180)) × 6 ÷ (101 + 98 ÷ 7 - 113) – (7 ÷ 2 + 14 – 3.5 – 9 × 8.5) × 4 a) 201 b) 241 c) -241 d) -281 e) 281

Last Answer : 240 1 180 = 4/3 12 4 (240 1 180) = 3 (4/3) = 4 101 + 98 7 - 113 = 101 + 14 - 113 = 2 19 + (12 4 (240 1 180)) 6 (101 + 98 7 - 113) = 19 + 4 6 2 = 19 + 4 3 = 31 7 2 ... 180)) 6 (101 + 98 7 - 113) - (7 2 + 14 - 3.5 - 9 8.5) 4 = 31 - (-250) = 281 Answer: e)

Description : The ages of A and B are in the ratio 8 : 5. If the sum of their ages is 39 years, what will be the ratio of their ages after 9 years? a) 3 : 2 b) 8 : 7 c) 10: 7 d) 11 : 8 e) None of these

Last Answer : Sum of ratios = 8 +5 = 13. Sum of ages = 39 years 13 ratio = 39 years  1 ratio = 3 years 9 years = 3 ratio new ratio = (8+3) : (5+3) = 11 : 8 Answer: d)