A father runs after his son, who is 1000 meters ahead. The father runs at a speed of 1 kilometre every 8 minutes, and the son runs at a speed of 1 kilometer every 12 minutes. How much distance has the son covered at the point when the father overtakes him? a) 2500 meters b) 2000 meters c) 1500 meters d) 1000 meters e) 1200 meters

A father runs after his son, who is 1000 meters ahead. The father runs at a speed of 1 kilometre every 8 minutes, and the son runs at a speed of 1 kilometer every 12 minutes. How much distance has the son covered at the point when the father overtakes him?
a) 2500 meters
b) 2000 meters
c) 1500 meters
d) 1000 meters
e) 1200 meters
by

1 Answer

Answer :

Time taken is same for both father and son
Let x be the distance son travelled before being overtaken by his father
Time taken by son = x/5 km/hour
Time taken by father = (1000 + x) / 7.5 km/hr
Since, time taken is same
x/5 = (1000 + x) / 7.5 or x = 2000m
Answer: b)
by

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Last Answer : Answer: c)

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Description : If a train runs at 40 km/hour, it reaches its destination late by 11 minutes. But if it runs at 50 km/hour, it is late by 5 minutes only. The correct time (in minutes) for the train to complete the journey is? a) 13 b) 15 c) 19 d) 21 e) None of these

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Last Answer : (A) 1080

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.12 X 13+105% of 993 +879/18 +15 (1)1150 (2)1170 (3)1185 (4)1200 (5) 1215 .12 X 13+105% of 993 +879/18 +15 (1)1150 (2)1170 (3)1185 (4)1200 (5) 1215

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Last Answer : (4)1200

The sum of ages of Sunil and his father is 46 years. 3 years back, father’s age was 4 times sunil’s age. find present age of Sunil. a) 7 years b) 8 years c) 11 years d) 12 years e) None of these

Description : The sum of ages of Sunil and his father is 46 years. 3 years back, father’s age was 4 times sunil’s age. find present age of Sunil. a) 7 years b) 8 years c) 11 years d) 12 years e) None of these

Last Answer : Sum of their ages, 3 years ago = 46 – (2 × 3) = 40 years sunil’s age, 3 years ago = 1/5 × 40 = 8 years sunil’s present age = 8 + 3 = 11 years Answer: c)

At what distance is VHF propagation normally limited? A. Around 500 miles B. Around 1500 miles C. Around 2000 miles D. Around 1000 miles

Description : At what distance is VHF propagation normally limited? A. Around 500 miles B. Around 1500 miles C. Around 2000 miles D. Around 1000 miles

Last Answer : A. Around 500 miles

At what distance is VHF propagation normally limited? A. Around 500 miles B. Around 1500 miles C. Around 2000 miles D. Around 1000 miles

Description : At what distance is VHF propagation normally limited? A. Around 500 miles B. Around 1500 miles C. Around 2000 miles D. Around 1000 miles

Last Answer : A. Around 500 miles

he auto-rickshaw fare in a city is charged as ₹10 for the first kilometre and @ ₹4 per kilometre for subsequent distance covered. Write the linear equation to express the above statement. Draw the graph of linear equation. -Maths 9th

Description : he auto-rickshaw fare in a city is charged as ₹10 for the first kilometre and @ ₹4 per kilometre for subsequent distance covered. Write the linear equation to express the above statement. Draw the graph of linear equation. -Maths 9th

Last Answer : Solution :- Fig. 3.12 represents the graph of the linear equation y = 4x+6.

A manufacture undertakes to supply 2000 pieces of a particular component at Rs.25 per piece. According to his estimates, even if 5% fail to pass the quality tests, then he will make a profit of 25%. However as it turned out, 50% of the components were rejected. What is the loss to the manufacture? [TCS recruitment exam question] A. Rs 12,000 B. Rs 13,000 C. Rs 14,000 D. Rs 15,000 E. None f these

Description : A manufacture undertakes to supply 2000 pieces of a particular component at Rs.25 per piece. According to his estimates, even if 5% fail to pass the quality tests, then he will make a profit of 25%. However as it turned out, ... A. Rs 12,000 B. Rs 13,000 C. Rs 14,000 D. Rs 15,000 E. None f these

Last Answer : Answer - B. Rs 13,000 Explanation: 5% of 2000=100 so 2000-100=1900 so,if he sells 1900 he will get 25% profit cost per piece rs 25 so 25x 1900 don't solve here if 125% . ... /125=38000=CP if 50% rejected,only 1000 pieces sold so 1000 25=25000=SP loss=cp-sp= 38000-25000=13000

If 25 toys cost 500, what would be the cost of 75 toys? A. 2000 B. 1500 101 C. 1200 D. 1700

Description : If 25 toys cost 500, what would be the cost of 75 toys? A. 2000 B. 1500 101 C. 1200 D. 1700

Last Answer : ANSWER: B

If 25 toys cost 500, what would be the cost of 75 toys? A. 2000 B. 1500 C. 1200 D. 1700

Description : If 25 toys cost 500, what would be the cost of 75 toys? A. 2000 B. 1500 C. 1200 D. 1700

Last Answer : ANSWER: B