Simple interest on a certain sum of money for 4 years at 5% per annum is half the compound interest on Rs. 8000 for 2 years at 10% per annum. The sum placed on simple interest is: a) Rs.4200 b) b)Rs.4250 c) Rs.5250 d) Rs.5200 e) Rs.4000

1 Answer

Answer :

a

C.I = 8000 * (1+(10/100))2 –8000

 = 8000 *110/100 * 110/100 – 8000 = 9680 – 8000 = Rs.1680

Therefore, S.I = C.I / 2 = 1680 / 2=Rs. 840

840 = sum * 4 * 5 / 100

:. Sum = Rs.(840 * 100)/ (4 *5) = Rs.4200

Related questions

Description : A sum of Rs. 1550 was lent partly at 5% and partly at 8% per annum simple interest. The total interest received after 4 yr was Rs. 400. The ratio of the money lent at 8% to that lent at 5% is? (a) 15:16 (b) 16:17 (c) 19:17 (d) 21:26 (e) 20:17

Last Answer : (a) 15:16

Description : The annual payment of Rs. 200 in 5 yr at 5% per annum simple interest will discharge a debt of? (a) Rs. 950 (b) Rs. 800 (c) Rs. 1000 (d) Rs. 1250 (e) None of the above

Last Answer : e) None of the above

Description : Arun started a business with Rs. 40,000 and is joined afterwards by Arul with Rs.60, 000. After how many months did Arul join if the profits at the end of the year are divided equally? a) 3 b) 4 c) 5 d) 6 e) 2

Last Answer : b Suppose, Arul joined after x months.  Then, 40000 * 12 = 60000 * (12 – x) => 48 = 72 - 6x => 6x = 24 → x = 4

Description : On selling 25 balls at Rs. 1015, there is a profit equal to the cost price of 10 balls. What is the cost price of a ball? a) Rs. 31 b) Rs. 29 c) Rs. 35 d) Rs. 27 e) Rs. 39

Last Answer : b Profit = (S.P of 25 balls) - (C.P of 25 balls) = 1015 - (C.P of 25 balls) Given that Profit = (C.P of 10 balls) => 1015 - (C.P of 25 balls) = (C.P of 10 balls) => (C.P of 25 balls) + (C.P of 10 balls) = 1015 => C.P of 35 balls = 1015 => C.P of 1 ball=1015 / 35 = Rs. 29

Description : Some amount out of Rs.8500 was lent at 5% per annum and the remaining was lent at 3% per annum. If the total simple interest from both the fractions in4 years was Rs.1500, the sum lent at 5% per annum was a) Rs. 2400 b) Rs. 2200 c) Rs. 2000 d) Rs. 6000

Last Answer : D Total simple interest received , I = Rs.1500 Principal , p = 8500 period, n = 4 years Rate of interest, r = ? Simple Interest, I=PNR/100 1500 = ( 8500 4 r )/ 100  = ... total amount is Rs.8500.  Therefore, the amount lent at 5% per annum (part1 amount) = 8500x12/17  = 6000 

Description : Shweta deposits a certain amount on 1st January and 1st July (Same amount on both days) in a bank that offers 5% compound interest, compounded half-yearly. Shweta gains interest of Rs.121 at the end of the year. How much money did Shweta deposit? a) 1200 b) 1300 c) 1400 d) 1500 e) 1600

Last Answer : Let the amount be P Half yearly rate = 5/2 = 2.5% For the deposit on January, Amount = P (1 + 2.5 / 100)2 For the deposit on July, Amount = P (1 + 2.5 /100) We can solve the question by ... Amount in July = 1600 1.025 = 1640 So total interest = 81 + 40 = 121 Required answer is 1600 Answer: e)

Description : Accumulated sum at the end of 5 years, if Rs. 10000 is invested now at 10% interest per annum on a compound basis is Rs. (A) 15000 (B) 16105 (C) 18105 (D) 12500

Last Answer : (B) 16105

Description : P walks around a circular field at the rate of two rounds per hour while Q runs around it at the rate of eight rounds per hour. They start in the opposite direction from the same point at 6.45 a.m. They shall first cross each other at? a) 6.45 a.m b) 6.50 a.m c) 7.51 a.m d) 6.51 a.m e) 7.45 am

Last Answer : d Since P and Q move in the opposite direction along the circular field, so they will first meet each other when there is a difference of one round between the two. Relative speed of P and Q = 8+2 = 10 rounds per hour. Time ... 1/10 hr = 6 min. 6 Hrs 45 min + 6 min = 6 hrs 51 min i.e, 6.51 a.m

Description : Madhan was 3 times as old as his daughter 10 years ago. After 10 years, Madhan will be twice as old as his daughter. Find out the present age of Madhan. a) 68 years b) 70 years c) 40 years d) 55 years e) 80 years

Last Answer : b Let age of the daughter before 10 years = x Then, age of Madhan before 10 years = 3x After 10 years, Madhan will be twice as old as his daughter. ⇒ 3x + 20 = 2( x+20) ⇒ x = 20 ⇒ Present age of Madhan = 3x + 10 = 3× 20+ 10 = 70 years.

Description : The monthly incomes of two persons are in the ratio 5 : 4 and their monthly expenditures are in the ratio 9 : 7. If each person saves Rs. 500 per month, then what are their monthly incomes? a) Rs 8000 and Rs ... Rs 3750 and Rs 3000 c) Rs 5000 and Rs 4000 d) Rs 4500 and Rs 4000 e) None of the above

Last Answer : Let the incomes of two persons be 5x and 4x let the expenditures of them be 9y and 7y Each person saves Rs. 500 Therefore, 5x - 9y = 500 4x - 7y = 500 Solving the above equations, 20x - 36y = 2000 20x - ... = 500 + 9(500) = 5000 X = 1000 Hence, their salaries are Rs. 5000 and Rs. 4000 Answer: c)

Description : Kathir and Anand can do a work in 20 days and 30 days respectively. Kathir started the work and left after 4 days. Anand took over and completed the work. In how many days was the total work completed? a) 28 days b) 20 days c) 23 days d) 25 days e) 26 days 

Last Answer : a Kathir’s one day’s work= 1/20 Kathir’s 4 day’s work =4* (1/20) = 1/5 Work left= 1-1/5 = 4 /5 Anand’s one day’s work= 1/30 Anand can do work in = (4/5) *(30/ 1) = 24 days So total days = 24+4 = 28 days

Description : A letter lock consists of four rings each marked with five different letters. The number of distinct unsuccessful attempts to open the lock is at the most -. a) 625 b) 676 c) 576 d) 624 e) 575

Last Answer : d Since each ring consists of five different letters, the total number of attempts possible with the four rings is =5 * 5 * 5 * 5 = 625. Of these attempts, one of them is a successful attempt. Maximum number of unsuccessful attempts = 625 - 1 = 624.

Description : Two stations X and Y are 170 km apart on a straight line. One train starts from X at 6 a.m. and travels towards Y at 25 kmph. Another train starts from Y at 8 a.m. and travels towards X at a speed of 35 kmph. At what time will they meet? a) 11. 30 a.m b) 10.30 a.m c) 11 a.m d) 9 a.m e) 10 am

Last Answer : e Suppose they meet z hours after 6 a.m. Distance covered by X in z hours = 25× z km. Distance covered by Y in (z - 2) hours = 35(z - 2) km. Therefore 25z + 35(z- 2) = 170 60z = 240 x = 4. So, they meet at 10 a.m.

Description : A boat running downstream covers a distance of 20 km in 5 hours while for covering the same distance upstream, it takes 10 hours. What is the speed of the stream? a) 2km/hr b) 4km/hr c) 1km/hr d) 1.5 km/hr e) None of these

Last Answer : c Rate of downstream=(20 / 5 ) kmph= 4kmph Rate of upstream =( 20/10) kmph= 2kmph Therefore Speed of the stream= (1/2)(4 - 2) kmph= 1 kmph

Description : Three pipes P, Q and R can fill a tank from empty to full in 40 minutes, 15 minutes, and 30 minutes respectively. When the tank is empty, all the three pipes are opened. P, Q and R discharge chemical solutions X, Y and Z respectively. ... 5 minutes? a) 8 / 15 b) 7 / 15 c) 8 / 17 d) 6 / 13 e) 8 / 13

Last Answer : a Part of the tank filled by pipe P in 1 minute = 1 / 40 Part of the tank filled by pipe Q in 1 minute = 1 / 15 Part of the tank filled by pipe R in 1 minute = 1/ 30 Here we have to find the proportion of ... together in 5 minute = 5 1/8 = 5/ 8 Required proportion = (1/3) / ( 5/8) = 8 / 15

Description : A portion of Rs.6600 is invested at a 5% per annum, while the remainder is invested at a 3% per annum. If the annual income from the portion earning a 5% per annum is twice that of the other portion, what is the ... investments after one year? a) Rs.270 b) Rs.370 c) Rs.250 d) Rs.280 e) None of these

Last Answer : 5x + 3y = z (Total Income) x + y = 6600 -(1) 5x= 2(3y) 5x – 6y = 0 -(2) By solving (1) and (2) we get, x = 3600 so y = 3000 (3600*5*1)/100 + (3000*3*1)/100 = 180 + 90 = 270 Answer: a)

Description : Difference between the compound interest and the simple interest accrued on an amount of Rs. 18000 in two year is Rs. 405. What was the rate of interest? 1) 14% 2) 16% 3) 12.5% 4) 15% 5) 15.5%

Last Answer : 4) 15%

Description : Ashwin borrowed a sum of Rs.6, 300 from Mishra at the rate of 14% for 3 years. He then added some more money to the borrowed sum and lent it to Ramesh at the rate of 16% of simple interest for the same time. If ... sum did he lend to Ramesh? a) Rs.6600 b) Rs.6800 c) Rs.4800 d) Rs.9800 e) Rs.8500

Last Answer : Suppose Ashwin lend Rs. x to Ramesh then, Xx16x3/100 - (X – 6300) × 14 × 3/100 = 618......(1) From equation I , x = Rs. 6800 Answer: b)

Description : A sum was invested for 4 yr at a certain rate of simple interest. If it had been invested at 2% more annual rate of interest, then Rs. 64 more would have been obtained. What is the sum? (a) Rs.600 (b) Rs.700 (c) Rs.800 (d) Rs.900

Last Answer : (c) Rs.800

Description : A sum of Rs. 1521 is lent out in two parts in such a way that the interest on one part at 10% for 5 yr is equal to that of another part at 8% for 10 yr. What will be the two parts of sum? (a) Rs.946 and ... ) Rs.986 and Rs.515 (c) Rs.956 and Rs.505 (d) Rs.936 and Rs.585 (e) None of the above

Last Answer : (d) Rs.936 and Rs.585

Description : Two equal sums are lent at the same time at 6% and 5 % simple interest respectively. The former is recovered 24 months earlier than the latter. And the amount in each case is Rs. 2400. Find the sum of money lent initially. a) 1500 b) 2000 c) 2400 d) 3000 e) 3600

Last Answer : Let the sum be S, time be ‘n’ years for 6%. n+2 years for 5% 2400 = S + S ×n × 6/100 2400 = S + S × (n+2) × 5/100 So, 6n = 5(n+2) or n = 10 years. 2400 = S + S × 10 × 6/100 = 1.6S S = 2400/1.6 = 1500 Answer: a)

Description : The compound interest accrued on an amount of Rs. 25,500 at the end of three years is Rs. 8,440.5.What would be the simple interest accrued on the same amount at the same rate in the same period? a) Rs. 5,450/- b) Rs. 8,750/- c) Rs. 4,350/- d) Rs. 3,650/- e) Rs. 7,650/- 

Last Answer : A = P + Interest = 25500 + 8440.5 = 33940.5 A = P + 1 + (R/100)^3 33940.5 = 25500 a + R/100)^3 a + R/100)^3 = 33940.5 / 25500 a + R/100)^3 = 1.331 a + R/100)^3 = ... R = 10% Simple Interest = Principle Rate Time / 100 = 25500 10 3/100 = 7650 Answer: e)

Description : Randeep invests Rs. 25,200 in buying shares of face value of Rs. 40 each at 5% premium. The dividend on these shares is 10% per annum. Find the divide

Last Answer : Randeep invests Rs. 25,200 in buying shares of face value of Rs. 40 each at 5% premium. The dividend on these ... B. Rs. 2400 C. Rs. 4200 D. Rs. 3680

Description : 2/3 part of the sum is lent out at 3%, 1/6 part is lent out at 6% and remaining part at 12%. All the three parts are lent out at simple interest. If the annual income is Rs. 35, what is the sum? (a) Rs.500 (b) Rs.600 (c) Rs.700 (d) Rs.850 (e) Rs.950

Last Answer : (c) Rs.700

Description : By selling a telephone for Rs. 2400, a shopkeeper make a profit of 25%. Then, his profit percentage, if he had sold it for Rs. 2016, is ? (a) 10% (b) 6.25% (c) 6.5% (d) 5% (e) 12%

Last Answer : (d) 5%

Description : Mark the correct option a) Interest at 10% per annum is charged on the loan compounded half yearly b) Second loan is not admissible until first loan is cleared. c) Loan are not available on AEA policies ... policy by dept only from the date of acceptance of the proposal by the CPMG e) All the above

Last Answer : e) All the above

Description : A man purchased wheat worth Rs. 400. He sold 3/4 at a loss of 10% and the reminder at a gain of 10%. On the whole he gets: A. loss of 5% B. gain of 5 C. loss of 19% D. loss of 6%

Last Answer : Answer – A (loss of 5%) Explanation – C.P of 3/4th = Rs. (3/4 x 400) = Rs. 300, C.P of 1/4th = Rs. 100 ∴ Total S.P = (90% of Rs. 300 + 110% of Rs. 100) = Rs. 380 Loss = (20/400 x 100)% = 5%

Description : A article is listed at Rs. 2000 and a discount of 20% is offered on the list price .What additional discount must be offered to the customer bring the net price to Rs. 1400? A. 12.5% B. 10% C. 12% D. 15%

Last Answer : Answer – A. 12.5% Explanation – S.P after 1st discount, 100%………2000 80%………? ?=2000×80/100=1600 Net S.P = Rs. 1400. Discount on Rs. 1600 = Rs. 200. ∴Required discount = (200/1600 x 100)% =12.5%

Description : Rahul invested a certain amount in buying Rs. 25 shares of a company, which pays a dividend of 12%. If the earns 10% per annum on his investment, then

Last Answer : Rahul invested a certain amount in buying Rs. 25 shares of a company, which pays a dividend of ... , then find the market value of each share.

Description : If the compound interest accrued on an amount of Rs.15,000/- in two years is Rs.2,496/-.What is the rate of interest p.c.p.a.? a) 8 b) 12 c) 7.5 d) Cannot be determined e) None of these

Last Answer : Let the rate of interest p.c.p.a. be x. 2496 =15000 * x /100 x = 16.64 16.64 is the rate of interest compounded for two year & for one year = 8% 8% C.I. table for two year. I year = 8% II year = 8.64 Total =16.64% Answer: a)

Description : A machine costs Rs. 20000 and its useful life is 8 years. The money is borrowed at 8% interest per annum. The capital recovery factor at 8% interest per annum for 8 years is 0.174. The annual equipment cost of the machine will be (A) Rs. 1740 (B) Rs. 3480 (C) Rs. 5220 (D) Rs. 6960

Last Answer : (B) Rs. 3480

Description : An amount becomes 160% of itself in 5 years through simple interest. At the same rate of interest, how long will it take for the amount to more than double itself if we use compound interest? a) 7 b) 8 c) 9 d) 10 e) cannot be determined

Last Answer : Answer: a)

Description : The value of a machine depriciates at the rate of 10% per annum. If its present value is Rs 10000, what will be its value after 2 years? -Maths

Last Answer : answer:

Description : Some amount out of Rs. 10000 was lent at 6 % p.a. and the remaining at 4% p.a. If the total simple interest from both the fractions in 5 years was Rs. 1500, then the ratio of the 2 different amount is A)1:3 B)3:1 C)1:4 D)3:2

Last Answer : A)1:3

Description : Mr. Sathyan invested Rs.20, 000/- with rate of interest@20 p.c.p.a. The interest was compounded half yearly for first one year and in the next year it was compounded yearly. What will be the total interest earned at the end of two years? a) Rs.7600 b) Rs. 9040 c) Rs. 8750 d) Rs. 6900

Last Answer : Total interest = 20000 × 110/100 × 110/100 × 120/100 - 20000 = 29040 - 20000= Rs. 9040 Answer: b)

Description : How do I compute the financial advantages and disadvantages of taking Social Security as soon as I'm eligible?

Last Answer : I receive a statement every year from Social Security 2 months before my birthday. It tells me what my payment will be at age 62 if I stop working then. It tells me what the payment will be at full ... It also tells me what I would make if I became disabled at this time. Is this what you mean?

Description : In the 8085A Microprocessor, arithmetic and logical operations are performed through which of the following? A) Stack B) ALU C) I/O D) Register 

Last Answer : In the 8085A Microprocessor, arithmetic and logical operations are performed through which of the following? A) Stack B) ALU C) I/O D) Register 

Description : A man sells two houses at the rate of Rs.1.995 lakh each. On one he gains 5% and on the other he loses 5%. His gain or loss per cent in the whole transaction is a) 0.25% loss b) 0.25% gain c) 2.5% loss d) 2.5% gain e) 1.25% loss

Last Answer : a) 0.25% loss

Description : A manufacture undertakes to supply 2000 pieces of a particular component at Rs.25 per piece. According to his estimates, even if 5% fail to pass the quality tests, then he will make a profit of 25%. However as it turned out, ... A. Rs 12,000 B. Rs 13,000 C. Rs 14,000 D. Rs 15,000 E. None f these

Last Answer : Answer - B. Rs 13,000 Explanation: 5% of 2000=100 so 2000-100=1900 so,if he sells 1900 he will get 25% profit cost per piece rs 25 so 25x 1900 don't solve here if 125% . ... /125=38000=CP if 50% rejected,only 1000 pieces sold so 1000 25=25000=SP loss=cp-sp= 38000-25000=13000

Description : Ram and Shyam started a business with investments of Rs.40000 and Rs.60000. At the end of one year, out of the total Ram got Rs.2000 less profit than Shyam. Find the total profit (in Rs.) a)12000 b)10000 c)8000 d)16000

Last Answer : b)10000

Description : A man sells two flats for Rs. 8000 each. neither loosing nor gaining in the deal. If he sold one at a gain of 25%, the other commodity sold at a loss of: A. 50/3 % B. 18 /3% C. 25% D. 32%

Last Answer : Answer – A (50/3 %) Explanation – Total S.P = 16000 Rs. and Total C.P = 16000 Rs. S.P. of Ist = Rs. 8000. Gain on it = 25% C.P of Ist = Rs. (100/125 x 8000) = Rs.6400 C.P of 2nd = Rs, (16000 – 6400) = Rs. 9600. S.P of 2nd = 8000. ∴loss on 2nd commodity = (1600/9600 x 100)% = 50/3%

Description : P,Q, R enter into a partnership.P initially invests Rs 54 lakh and withdraws Rs 18 lakhs after 4 years. Q initially Rs 72 lakh ans adds another Rs 18 lakhs after 6 years and R invests Rs 108 lakh and adds another ... Then for how many years did R invests Rs 126 lakh per annum A) 5 B) 7 C) 8 D) 11 

Last Answer : Answer: C) Ratio of their profit P, Q, R is 54*4+36*6:72*6+90*4:108*x+126*(10-x) =12:22:35 - 0.5x Profit of R=profit of P +profit of Q 35-0.5x=12+22 X=2 year The number of years for R invests Rs 126 lakh =10-2=8years

Description : An earth moving equipment costs Rs. 5,00,000 and has an estimated life of 10 years and a salvage value of Rs. 50,000. What uniform annual amount must be set aside at the end of each of the 10 years for replacement if ... years is 0.069? (A) Rs. 31050 (B) Rs. 34500 (C) Rs. 37950 (D) Rs. 5000

Last Answer : (A) Rs. 31050

Description : What is the rate of interest in PPF wef 01 Apr 12 ? a) 8.8% per annum compounded yearly b) 8.5% per annum compounded yearly c) 8.6 % per annum compounded yearly d) None of these

Last Answer : a) 8.8% per annum compounded yearly

Description : A and B started a business jointly. A’s investment was thrice the investment of B and the period of his investment was two times the period of investment of B. If B received Rs.4000 as profit, then their total profit is : a) Rs.16,000 b) Rs.20,000 c) Rs.24,000 d) Rs.28,000 e) None of these

Last Answer : Suppose B invested Rs. x for y months. Then, A invested Rs.3x for 2y months. So, A : B = (3x × 2y) : (x × y) = 6xy : xy = 6 : 1 So, B’s profit : total profit = 1 : 7 Let the total profit be Rs. x. Then, 1 / 7 = 40000 / x Or x = 28000. Answer: d)

Description : The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs.4000. The total price of 12 chairs and 3 tables is: a) Rs.3750 b) Rs.3840 c) Rs.3500 d) Rs.3900 e) None of these

Last Answer : Cost of 4 tables =Cost of 10 chairs => Cost of 1 table =10 4=2.5 chairs =>15 chairs + 2 tables = Rs.4000 => 15 chairs + 2 2.5 chairs = Rs.4000 =>20 chairs =Rs.4000 => 1 chair = Rs.4000 20 = Rs ... of 12 chairs + cost of 3 tables =12 Rs.200 + 3 Rs.500 = Rs.2400 + Rs.1500=Rs.3900 Answer: d)

Description : Sanki purchased 20 dozen notebook at Rs. 48 per dozen. He sold 8 dozen at 10% profit and remaining 12 dozen with 20% profit. What is his profit percentage in the transaction? A. 8% B. 15% C. 16% D. 19% 

Last Answer : Answer – C (16%) Explanation – C.P of 20 dozen = Rs.(48 x 20) = Rs.960 C.P of 8 dozen = Rs. (48 x8) = Rs. 384. C.P of 12 dozen =Rs. (960 – 384) = Rs. 576 Total S.P = Rs. (110/100 x 384 +120/100 x 576) = Rs.1113.60 ∴ Profit % = (153.60/960 x 100)% =16%

Description : From the following information, calculate the extra cost of material by following EOQ: Annual consumption: = 45000 units Ordering cost per order: = Rs. 10  Carrying cost per unit per annum: = Rs. 10  Purchase price per unit = Rs. ... ) No saving (b) Rs. 2,00,000 (c) Rs. 2,22,010 (d) Rs. 2,990

Last Answer : (d) Rs. 2,990

Description : Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a ... 7 years, how much money did he borrow? a) 39,500 b) 42,500 c) 41,900 d) 43,000 e) None of these

Last Answer : Let the amount borrowed be Rs P Total amount of simple interest = (P×3×4)/100 + (p×2×8)/100 + (p×2×9)/100 = 19550 0.12P + 0.16P + 0.18P = 19550 0.46p= 19550 P = Rs. 42500 Answer: b)