A container contains 55 litres of milk. From this container 5.5 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container? a) 32 b) 29.16 c) 43 d) 27.12 e) 40.09
E
Where x is the initial quantity of milk in the cask y is the quantity of milk withdrawn in each process and n is
the number of processes.
Initial quantity:55
Withdrawn quantity=5.5 number of times repeated=3
Hence from the above rule it can be say that,
Formula,=[a(1-b/a)n
]
Quantity of milk left after the 3rd operation =55*((55-5.5)/55) ^3
=40.09litres.