Description : 10, 221, ____, 44443, 555554 a) 3333 b) 3321 c) 3332 d) 3341 e) 332
Last Answer : This series is formed by subtracting 1 from the series of 11, 222, 3333, 44444, 555555 and so on. So the missing tam is 3333-1 = 3332. Answer: c)
Description : 15 17 21 29 45 77 ? a) 109 b) 125 c) 141 d) 173 e) None of these
Last Answer : 15 + 2 = 17 17 + 4 = 21 21 + 8 = 29 29 + 16 = 45 45 + 32 = 77 77 + 64 = 141 Answer: c)
Description : Consider a disk queue with I/O requests on the following cylinders in their arriving order: 6,10,12,54,97,73,128,15,44,110,34,45 The disk head is assumed to be at cylinder 23 and moving in the direction ... . The disk head movement using SCAN-scheduling algorithm is: (1) 172 (2) 173 (3) 227 (4) 228
Last Answer : (2) 173
Description : A box contains 15bolts of which 5 are defective. If 5 bolts are selected at random from the box, what is the probability that at least one of them is defective? a) 91/143 b) 101/143 c) 111/143 d) 121/143 e) 131/143
Last Answer : Probability that at least one is defective = 1 – probability that none is defective Probability that none is defective = 10C5 / 15C5 = 12/143 Required Probability = 1-12/143 = 131/143 Answer: e)
Description : 3 7 6 28 9 112 12 ? a) 112 b) 448 c) 28 d) 38 e) None of these
Last Answer : First series: 3, 6, 9 (increased by 3) Second Series: 7, 28, 112, 448 (multiplied by 4) Answer: d)
Description : 3.25 × 16 + 7.25 × 8 = ? + 75 a) 83 b) 75 c) 61 d) 53 e) 35
Last Answer : ? + 75 = 52 + 58 = 110 ? = 110 – 75 = 35 Answer: e)
Description : The average age of the whole class is 12.05 years. The average age of all girls is 12.5 years and the average age of boys is 11.75 years. If the total number of boys is 45 then what is the total number of girls in the class? a) 20 b) 25 c) 30 d) 35 e) 40
Last Answer : Let the number of girls be x. The number of boys is 45. :. Total age of boys and girls in the class = (x+45) × 12.05 or, (x+45) × 12.05 = 45 × 11.75 + x × 12.5 or, 12.05x + 542.25 = 528.75 + 12.5x or, 13.5 = 0.45x or, x = 13.5/0.45 = 30 Answer is: c)
Description : 1275.42 + 8624.6 – 894.54 – 24.71 = ? a) 8620.27 b) 8738.57 c) 8890.93 d) 8980.77 e) 9012.17
Last Answer : d) 8980.77
Description : 112 111 119 92 156 31 ? a) 375 b) 287 c) 387 d) 247 e) None of these
Last Answer : Answer: d)
Description : 1/9, 4/9, 1 7/9, 7 1/9, 28 4/9, ? a) 112(1/9) b) 113(7/9) c) 115(4/9) d) 140(5/9) e) 142(2/9)
Last Answer : The pattern is 1/9,4/9,16/9,64/9,256/9,1024/9. 1024/9 = 113 7/9 Answer: b)
Description : A train travelling at 36 kmph completely crosses another train having half its length and travelling in the opposite direction at 54 kmph, in 12 seconds. If it also passes a railway platform in 112 minutes, the length ... is : a) 560 metres b) 620 metres c) 700 meres d) 750 metres e) 720 meters
Last Answer : Answer: c)
Description : 1 3 9 31 ? 651 a) 97 b) 127 c) 129 d) 109 e) None of these
Last Answer : The series is ×1 + 2, ×2 + 3, ×3 + 4, ... Answer: c)
Description : 23.98 × 62.49 × 12.03 = ? × 29.97 a) 500 b) 600 c) 900 d) 450 e) 750
Last Answer : 24× 62.5× 12 = ? × 30 24× 750 = ? × 30 ? = (24× 750) / 30 = 600 Answer: b)
Description : 97,122,?,307,503,792 a) 171 b) 158 c) 186 d) 203 e) 178
Description : 256 128 ? 192 96 240 80 a) 64 b) 156 c) 96 d) 128 e) 176
Last Answer : The series is ×0.5, ÷1, ×1.5, ÷2, ×2.5.... Answer: d)
Description : √6889+√3721+√1024-√2401=? a) 129 b) 128 c) 127 d) 124 e) 123
Last Answer : √6889 + √3721 +√1024 - √2401 = ? Or,?= √(83)2 + √(61)2 + √(32)2 - √(49)2 =83+61+32 – 49 =127 Answer: c)
Description : In what ratio must a person mix three kinds of Oats costing him Rs 1.20,Rs 1.44 and Rs 1.74 per Kg so that the mixture may be worth Rs 1.41 per Kg? A)11:77:7 B) 11:45:7 C)25:45:8 D) 27:23:6
Last Answer : A)11:77:7
Description : 9837+315 X 6-77 X 13+10% of 1500 (1)10600 (2)10850 (3)11200 (4)10700 (5)11000
Last Answer : (2)10850
Description : In how many ways can a team of 6 persons be formed out of a total of 12 persons such that 3 particular persons should not be included in any team? A) 56 B) 112 C) 84 D) 128
Last Answer : Answer: C) Three particular persons should not be included in each team. i.e., we have to select remaining 6- 3= 3 persons from 12-3 = 9 persons. Hence, required number of ways = 9C3 = {9×8 × 7} / {3 × 2 × 1} = 504 / 6 = 84
Description : 3 9 15 ? 35 49 a) 25 b) 30 c) 24 d) 20 e) None of these
Last Answer : Answer: a)
Description : The Average of marks obtained by 120 candidates in a certain examination is 35. If the average marks of passed candidates is 39 and that of failed candidates is 15, what is the number of candidates who passed the examination? A.90 B.100 C.108 D.115 E.None of these
Last Answer : Answer – B (100) Explanation – Let the number of passed candidates be a Then total marks =>120 x 35 = 39 a + (120 – a) x 15 4200 = 39 a + 1800 – 15 a a = 100
Description : Evaluate: 48×52 + 61×59 + 77×83 a) 12486 b) 10996 c) 13406 d) 13206 e) None of these
Last Answer : 48×52 = (50 - 2) × (50 + 2) = 502 – 22 = 2496 61 × 59 = (60 + 1) × (60 - 1) = 602 – 12 = 3599 77 × 83 = (80 - 3) × (80 + 3) = 802 – 32 = 6391 Sum = 2496 + 3599 + 6391 = 12486 Answer: a)
Description : 7% of 77 + 77% of 777 + 777% of 7777 a) 58090.54 b) 60457.25 c) 68709.16 d) 71000.01 e) None of these
Last Answer : 7% of 77 + 77% of 777 + 777% of 7777 = 0.07 × 77 + 0.77 × 777 + 7.77 × 7777 = 61030.97 Answer: e)
Description : Total literate population of city E is what percentage of total population of city D? 1) 67.5% 2) 71.5% 3) 74.5% 4) 77.5% 5) 82.5%
Last Answer : 2) 71.5%
Description : 3 7.5 15 37.5 75 167.5 375 a) 167.5 b) 75 c) 37.5 d) 15 e) 7.5
Last Answer : The series is ×2.5, ×2 alternately Answer: a)
Description : What is is the GCF of 55 77 and 143?
Last Answer : GCF(55, 77, 143) = 11.
Description : I. 32a^2 + 52a + 15 = 0 II. 8b^2 + 38b + 35 = 0 1 : if a > b 2 : if a < b 3 : if a ≥ b 4 : if a ≤ b 5 : if a = b or the relation between a and b cannot be established.
Last Answer : 3 : if a ≥ b
Description : Sum of Rs.118 was shared among 50 boys and girls,each girl receive Rs.2.60 and boy receive Rs.1.80.Find the number of girls. A) 15 B)25 C)30 D)35
Last Answer : D)35
Description : What is the respective ratio of the number of girls enrolled in only Painting classes to the number of boys enrolled in the same ? (1) 77 : 26 (2) 21 : 73 (3) 26 : 77 (4) 73 : 21 (5) None of these
Last Answer : (3) 26 : 77
Description : 5, 5, 15, 75, 525, 4725, _____. 1 : 51795 2 : 50135 3 : 51025 4 : 50175 5 : 51975
Last Answer : Answer- 5(51975) Explanation- multiply by consecutive odd numbers 5×1=5 5×3=15 15×5=75 75×9=4725 4725×11=51975
Description : √80 × (35/6) × (21)2 +343 =? a) 21125 b) 22981 c) 20781 d) 23159 e) 21230
Last Answer : ?= √80 × (35/6) × (21)2 + 343 =√(16×5) × (35/6) × 441 + 343 =4√5 × (35/6) × 441 + 343 =2√5 ×35 ×147 + 343 =2 ×2.2 ×35 × 147 +343 = 22981 Answer: b)
Description : Ages of DEEPA and Subha are presently in the ratio of 5 : 6 respectively. Six years hence this ratio will become 6 : 7 respectively. What was Subha’s age 5 years ago? a) 33 years b) 32 years c) 35 years d) 31 years e) None of these
Last Answer : Present ratio of Deepa&Subha = 5 : 6 Six year hence ratio of Deepa&Subha = 6 : 7 Difference between ratio = 1 Difference in ages between present & future = 6 year. 1 ratio=6 yrs & SUBHA's age = 6 6 =36 year 5 year ago ... = 7 6 = 42 year B's age 5 year ago = 42-6-5 = 42-11 = 31 year Answer: d)
Description : Two stations X and Y are 170 km apart on a straight line. One train starts from X at 6 a.m. and travels towards Y at 25 kmph. Another train starts from Y at 8 a.m. and travels towards X at a speed of 35 kmph. At what time will they meet? a) 11. 30 a.m b) 10.30 a.m c) 11 a.m d) 9 a.m e) 10 am
Last Answer : e Suppose they meet z hours after 6 a.m. Distance covered by X in z hours = 25× z km. Distance covered by Y in (z - 2) hours = 35(z - 2) km. Therefore 25z + 35(z- 2) = 170 60z = 240 x = 4. So, they meet at 10 a.m.
Description : 2/3 part of the sum is lent out at 3%, 1/6 part is lent out at 6% and remaining part at 12%. All the three parts are lent out at simple interest. If the annual income is Rs. 35, what is the sum? (a) Rs.500 (b) Rs.600 (c) Rs.700 (d) Rs.850 (e) Rs.950
Last Answer : (c) Rs.700
Description : Two coin are tossed 400 times and we get a. Two Heads : 112 times b. One Head : 160 times c. No Head : 128 times. When two coins are tossed at random, what is the probability of getting a. Two Heads b. One Head c. No Head -Maths 9th
Last Answer : Given, Total number of events = 400 (a) No. of times two heads occur = 112 Probability of getting two heads = 112/400 = 7/25 (b) No. of times one heads occur = 160 Probability of getting one heads = 160/400 = 2/5 (c) No. of times no heads occur = 128 Probability of getting no heads = 128/400 = 8/25
Description : From a total of six men and four ladies, a committee of three is to be formed. If Mrs.X is not willing to join the committee in which Mr.Y is a member, whereas Mr.Y is willing to join the committee only if Mrs.Z is included. How many such committees are possible? a) 138 b) 128 c) 112 d) 91
Last Answer : d) 91
Description : Triple DES uses a. 168 bit keys on 64-bit blocks of plain text b. Working on 64-bit blocks of plain text and 56 bit keys by applying DES algorithm for three rounds. c. Works with 144 bit ... algorithm once. d. Uses 128 bit blocks of plain text and 112 bit keys and apply DES algorithm thrice.
Last Answer : b. Working on 64-bit blocks of plain text and 56 bit keys by applying DES algorithm for three rounds.
Description : Evaluate: (4 + 4×18 – 6 - 8) / (123×6 - 146×5) a) 7.5 b) 7.75 c) 8 d) 8.25 e) 8.5
Last Answer : Numerator = 4 + 72 – 14 = 62 Denominator = 738 – 730 = 8 Required value = 62/8 = 7.75 Answer: b)
Description : A train travelling at a speed of 75 mph enters a tunnel 7/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges? A.1 min B.3 min C.5 min D.6 min E.None of these
Last Answer : Answer – B (3 min) Explanation – Actually train is covering length of tunnel + its own length here so total distance = 7/2 + 1/4= 15/4 miles time= distance /speed time= (15/4) / 75 = 1/20 hour (1/20)x60 = 3 min
Description : Mr. Xavier invested a certain amount in Debit and Equity funds in the ratio of 4 : 5 respectively. At the end of one year, he earned a total dividend of 30% on his investment. After one year he reinvested the amount including ... . 81,000/- (c) Rs. 60,000/- (d) Rs. 65,000/- (e) None of these
Last Answer : (a) Rs. 75,000/-
Description : The average weight of four boys A, B, C, and D is 75 kg. The fifth boy E is included and the average weight decreases by 4 kg. A is replaced by F. The weight of F is 6 kg more than E. Average weight decreases because of ... . Find the weight of A. 1) 57 kg 2) 54 kg 3) 56 kg 4) 60 kg 5) 58 kg
Last Answer : 3) 56 kg
Description : Six equal point charges Q = 10nC are located at 2,3,4,5,6,7m. Find the potential at origin. a) 140.35 b) 141.35 c) 142.35 d) 143.35
Last Answer : d) 143.35
Description : If Q is discharge is cubic metres per sec and D is the economical diameter of the pipe. According to Lea (A) D = 0.67 to 0.87 Q (B) D = 0.77 to 0.97 Q (C) D = 0.97 to 1.22 Q (D) D = 1.22 to 1.33 Q
Last Answer : (C) D = 0.97 to 1.22 Q
Description : My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, ... father when my brother was born? a) 35 years b) 34 years c) 33 years d) 32 years e) 30 years
Last Answer : Let my age = x Then My brother's age = x + 3 My mother's age = x + 26 My sister's age = (x + 3) + 4 = x + 7 My Father's age = (x + 7) + 28 = x + 35 => age my father when my brother was born = x + 35 – (x + 3) = 32. Answer: d)
Description : 1824 ÷ 32 + 5040 ÷ ? – 5600 ÷ 35 = 37 a) 36 b) 48 c) 60 d) 72 e) 84
Last Answer : 57 + 5040 ÷ ? – 160 = 37 5040 ÷ ? = 37 – 57 + 160 = 140 = 5040 ÷ 140 = 36 Answer: a)
Description : [(3/8) + (8/3)] – [(4/9) + (9/4)] = ? a) 0.5 b) 0.65 c) 0.9 d) 1.25 e) 0.35
Last Answer : ? = [(64+9) / 24] – [(81+16)/36] = (73/24) – (97/36) = (219 - 194)/72 = 25/72 = 0.347 = 0.35 Answer: e)
Description : 25,?,45,58,73,90,109 a) 33 b) 34 c) 35 d) 38 e) 36
Last Answer : The series is 3×5+10=25,4×6+10=34,5×7+10=45,6×8+10=58,7×9+10=73,8× 10+10=90,9×11+10=109 Hence missing term=34 Answer: b)
Description : Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these
Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)