3 9 15 ? 35 49 a) 25 b) 30 c) 24 d) 20 e) None of these

3 9 15 ? 35 49

a) 25

b) 30

c) 24

d) 20

e) None of these


by

1 Answer

Answer :

Answer: a) 
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Related questions

5, 10, 35, 160, 785, _____. 1 : 2010 2 : 3910 3 : 2525 4 : 2860 5 : None of these

Description : 5, 10, 35, 160, 785, _____. 1 : 2010 2 : 3910 3 : 2525 4 : 2860 5 : None of these

Last Answer : Answer- 2 (3910) Explanationadd 5^1,5^2,5^3,5^4,5^5 and so on in each step.

16, 32, 35, 140, 145, 870, 877, _____ 1 : 7016 2 : 885 3 : 5020 4 : 6018 5 : None of these

Description : 16, 32, 35, 140, 145, 870, 877, _____ 1 : 7016 2 : 885 3 : 5020 4 : 6018 5 : None of these

Last Answer : Answer- 1(7016) Explanation16×2 =32 32+3=35 35×4=140 140+5=145 145×6=870 870+7=877 877×8=7016

4 8 24 ? 124 224 a) 60 b) 65 c) 59 d) 62 e) None of these

Description : 4 8 24 ? 124 224 a) 60 b) 65 c) 59 d) 62 e) None of these 

Last Answer : Answer: a)

24,48,144,576,2880,? 1 : 17280 2 : 16640 3 : 14400 4 : 20160 5 : 14240

Description : 24,48,144,576,2880,? 1 : 17280 2 : 16640 3 : 14400 4 : 20160 5 : 14240

Last Answer : Answer- 1 (17280) Explanation- 24 x 2=48 48×3=144 144×4=576 576×5=2880

2.5 x 0.08 ÷ (1.9)^2= ? a) 2.5 b) 1.2 c) 0.008 d) 0.06 e) 0.03

Description : 2.5 x 0.08 ÷ (1.9)^2= ? a) 2.5 b) 1.2 c) 0.008 d) 0.06 e) 0.03

Last Answer : 2.5 × 0.08 ÷ (1.9)^2 = ? = 2.5 × 0.08/3.61 = ? = 0.0554 = 0.06 (approx) Answer: d)

3,25,255,2545,25455, ? 1 : 254550 2 : 254555 3 : 254545 4 : 254555 5 : 254556

Description : 3,25,255,2545,25455, ? 1 : 254550 2 : 254555 3 : 254545 4 : 254555 5 : 254556

Last Answer : Answer-3 (254545) Explanation25=(3×10)-5 255=(25×10)+5 2545=(255×10)-5 25455=(2545×10)+5 ?=(2545×10)-5 = 254545

5, 5, 15, 75, 525, 4725, _____. 1 : 51795 2 : 50135 3 : 51025 4 : 50175 5 : 51975

Description : 5, 5, 15, 75, 525, 4725, _____. 1 : 51795 2 : 50135 3 : 51025 4 : 50175 5 : 51975

Last Answer : Answer- 5(51975) Explanation- multiply by consecutive odd numbers 5×1=5 5×3=15 15×5=75 75×9=4725 4725×11=51975

4 32 ? 2048 16348 a) 250 b) 286 c) 256 d) 225 e) None of these

Description : 4 32 ? 2048 16348 a) 250 b) 286 c) 256 d) 225 e) None of these

Last Answer : Multiply by 8. Answer: c)

729 656 595 ? 494 a) 540 b) 530 c) 500 d) 529 e) 541

Description : 729 656 595 ? 494 a) 540 b) 530 c) 500 d) 529 e) 541

Last Answer : Difference of Difference 9. Answer: a)

259 256 ? 244 235 224 a) 250 b) 251 c) 253 d) 249 e) None of these

Description : 259 256 ? 244 235 224 a) 250 b) 251 c) 253 d) 249 e) None of these

Last Answer : Difference of odd numbers 3, 5, 7, 9, 11. Answer: b)

9654 ÷ 21 +7638 ÷ 44 = ? a) 633 b) 600 c) 643 d) 621 e) 598

Description : 9654 ÷ 21 +7638 ÷ 44 = ? a) 633 b) 600 c) 643 d) 621 e) 598

Last Answer : 9654 ÷ 21 + 7338 ÷ 44 = ? = 459.714 + 173.59 = 633.304 = 633 (approx) Answer: a)

1/8 × 3/5 × 4/7 x 7897 = ? a) 310 b) 325 c) 375 d) 275 e) 338

Description : 1/8 × 3/5 × 4/7 x 7897 = ? a) 310 b) 325 c) 375 d) 275 e) 338

Last Answer : ? = 7897 × 4 × 3 / 8 × 5 × 7 = 338.31 = 338 (approx.) Answer: e)

3√7469 x √668 = ? a) 450 b) 300 c) 505 d) 465 e) 555

Description : 3√7469 x √668 = ? a) 450 b) 300 c) 505 d) 465 e) 555

Last Answer : 3√7469 × √668 = ? = 19.5 × 25.9 = 505.05 = 505 (approx) Answer: c)

(4.36)^2 x 66.5 - 371 = ? a) 850 b) 893 c) 910 d) 875 e) 885

Description : (4.36)^2 x 66.5 - 371 = ? a) 850 b) 893 c) 910 d) 875 e) 885

Last Answer : (4.36)^2 × 66.5 - 371 = ? = 19.0096 × 66.5 - 371 = ? = 1264.1384 - 371 = 893.1384 = 893 (approx.) Answer: b)

196, 200, 209, 234, 283, 404, 573, _____ 1 : 872 2 : 840 3 : 884 4 : 878 5 : 862

Description : 196, 200, 209, 234, 283, 404, 573, _____ 1 : 872 2 : 840 3 : 884 4 : 878 5 : 862

Last Answer : Answer-5 (862) Explanation- add square of prime no. in each step 4,9,25,49,121,so on

5, 13, 29, 61, 125, 253, _____ 1 : 512 2 : 521 3 : 509 4 : 552 5 : None of these

Description : 5, 13, 29, 61, 125, 253, _____ 1 : 512 2 : 521 3 : 509 4 : 552 5 : None of these

Last Answer : Answer-3(509) Explanation5 x2 +3 =13 13×2 +3=29 29×2+3=61 and so on..

363,795,1227,1659,2091, ? 1 : 2423 2 : 2613 3 : 2813 4 : 2513 5 : 2523

Description : 363,795,1227,1659,2091, ? 1 : 2423 2 : 2613 3 : 2813 4 : 2513 5 : 2523

Last Answer : Answer- 5 (2523) Explanation- +432 in every step

4725,1050,300,120,80,? 1 : 40 2 : 160 3 : 120 4 : 110 5 : 60

Description : 4725,1050,300,120,80,? 1 : 40 2 : 160 3 : 120 4 : 110 5 : 60

Last Answer : Answer-2 (160) Explanation- 4725 / 4.5=1050 1050/3.5=300 300/2.5=120 120/1.5=80 80/0.5=160

3,14,58,234,938,? 1 : 4152 2 : 4110 3 : 3754 4 : 4154 5 : 4624

Description : 3,14,58,234,938,? 1 : 4152 2 : 4110 3 : 3754 4 : 4154 5 : 4624

Last Answer : Answer- 3 (3754) Explanation- x4+2

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

Present ages of Simmi and Anu are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively, What is Anu’s present age in years? A.20 B.24 C.28 D.35 E.None of these

Description : Present ages of Simmi and Anu are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively, What is Anu’s present age in years? A.20 B.24 C.28 D.35 E.None of these

Last Answer : Answer – B (24) Explanation – Let the present ages of Simmi and Anu be 5x years and 4x years respectively Then, [5X + 3] / [4X + 3] =11/9 x=6 Anu’s present age = 4X = 24 years

Ajay reads at an average rate of 30 pages per hour, while Vikram reads at an average rate of 40 pages per hour. If Ajay starts reading a novel at 4:30 PM and Vikram begins reading an identical copy of the same book at 5:20 PM, at what time will they be reading the same page? a) 7:50 PM b) 8:15 PM c) 8:40 PM d) 9:00 PM e) 9:25 PM

Description : Ajay reads at an average rate of 30 pages per hour, while Vikram reads at an average rate of 40 pages per hour. If Ajay starts reading a novel at 4:30 PM and Vikram begins reading an identical copy of the same book at 5:20 PM, at ... same page? a) 7:50 PM b) 8:15 PM c) 8:40 PM d) 9:00 PM e) 9:25 PM

Last Answer : Ajay reads at average rate of 30 pages per hour ie. 1 page in every two minutes. Therefore, by 5:20 PM, he would have covered 25 pages By 6:20 PM, Ajay would have read 25+30 pages and Vikram would have ... and he will also finish 100 pages Hence, both of them will be on same page at 7:50 Answer: a)

Two stations X and Y are 170 km apart on a straight line. One train starts from X at 6 a.m. and travels towards Y at 25 kmph. Another train starts from Y at 8 a.m. and travels towards X at a speed of 35 kmph. At what time will they meet? a) 11. 30 a.m b) 10.30 a.m c) 11 a.m d) 9 a.m e) 10 am

Description : Two stations X and Y are 170 km apart on a straight line. One train starts from X at 6 a.m. and travels towards Y at 25 kmph. Another train starts from Y at 8 a.m. and travels towards X at a speed of 35 kmph. At what time will they meet? a) 11. 30 a.m b) 10.30 a.m c) 11 a.m d) 9 a.m e) 10 am

Last Answer : e Suppose they meet z hours after 6 a.m. Distance covered by X in z hours = 25× z km. Distance covered by Y in (z - 2) hours = 35(z - 2) km. Therefore 25z + 35(z- 2) = 170 60z = 240 x = 4. So, they meet at 10 a.m.

The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these

Description : The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these

Last Answer : Sum of present ages = 35 years sum of their ages will be 85 years after (85-35) / 2 = 25 years from now. the father is 25 years older than his son. Present age of father = (35 + 25)/2 = 30 years. Answer: c)

The average age of the whole class is 12.05 years. The average age of all girls is 12.5 years and the average age of boys is 11.75 years. If the total number of boys is 45 then what is the total number of girls in the class? a) 20 b) 25 c) 30 d) 35 e) 40

Description : The average age of the whole class is 12.05 years. The average age of all girls is 12.5 years and the average age of boys is 11.75 years. If the total number of boys is 45 then what is the total number of girls in the class? a) 20 b) 25 c) 30 d) 35 e) 40

Last Answer : Let the number of girls be x. The number of boys is 45. :. Total age of boys and girls in the class = (x+45) × 12.05 or, (x+45) × 12.05 = 45 × 11.75 + x × 12.5 or, 12.05x + 542.25 = 528.75 + 12.5x or, 13.5 = 0.45x or, x = 13.5/0.45 = 30 Answer is: c)

1:1, 8:4, 9:27, 64:16, 25:125, ?:?, 49:343, a) 36:316 b) 216:36 c) 316:16 d) 32:316 e) None of these

Description : 1:1, 8:4, 9:27, 64:16, 25:125, ?:?, 49:343, a) 36:316 b) 216:36 c) 316:16 d) 32:316 e) None of these

Last Answer : Its alternatively ratio of n2 and n3 Now, after 25:125, it would be 63 : 62  216:36 Answer: b)

Sum of Rs.118 was shared among 50 boys and girls,each girl receive Rs.2.60 and boy receive Rs.1.80.Find the number of girls. A) 15 B)25 C)30 D)35

Description : Sum of Rs.118 was shared among 50 boys and girls,each girl receive Rs.2.60 and boy receive Rs.1.80.Find the number of girls. A) 15 B)25 C)30 D)35

Last Answer : D)35

24 14 26 ? 28 16 30 a) 13 b) 17 c) 15 d) 11 e) 20

Description : 24 14 26 ? 28 16 30 a) 13 b) 17 c) 15 d) 11 e) 20

Last Answer : The series consists of two series 1 and 2: Series 1 : 24 26 28 30 +2 +2 +2 Series 2 : 14 15 16 +1 +1 Answer: c)

. What is the ratio of the total investment in Metals to that in Machinery? a) 135 : 302 b) 24 : 49 c) 2 : 4 d) 197 : 226 e) 123 : 233

Description : . What is the ratio of the total investment in Metals to that in Machinery? a) 135 : 302 b) 24 : 49 c) 2 : 4 d) 197 : 226 e) 123 : 233

Last Answer : d) 197 : 226

Sum of present ages of A and B is 60 years. 5 years hence, their ages will be in the ratio 3:4. Find A’s present age. a) 25 years b) 30 years c) 35 years d) 40 years e) None of these

Description : Sum of present ages of A and B is 60 years. 5 years hence, their ages will be in the ratio 3:4. Find A’s present age. a) 25 years b) 30 years c) 35 years d) 40 years e) None of these

Last Answer : Sum of their present ages = 60 years sum of their ages, 5 years hence = 60 + (5 × 2) = 70 years. after 5 years, ratio of ages of A and B will be 3 : 4. A’s age after 5 years = (3/7) × 70 = 30 years A’s present age = 30 – 5 = 25 years Answer: a)

[(3/8) + (8/3)] – [(4/9) + (9/4)] = ? a) 0.5 b) 0.65 c) 0.9 d) 1.25 e) 0.35

Description : [(3/8) + (8/3)] – [(4/9) + (9/4)] = ? a) 0.5 b) 0.65 c) 0.9 d) 1.25 e) 0.35

Last Answer : ? = [(64+9) / 24] – [(81+16)/36] = (73/24) – (97/36) = (219 - 194)/72 = 25/72 = 0.347 = 0.35 Answer: e)

Manish purchased 25 kg of rice @ Rs32 per kg and 15 kg of rice @ Rs 36 per kg. He mixed the two varieties of rice and sold it @ Rs 40.20 per kg. What is the percent profit earned? 1. 25 2. 40 3. 30 4. 20

Description : Manish purchased 25 kg of rice @ Rs32 per kg and 15 kg of rice @ Rs 36 per kg. He mixed the two varieties of rice and sold it @ Rs 40.20 per kg. What is the percent profit earned? 1. 25 2. 40 3. 30 4. 20

Last Answer : 4. 20

15 17 32 49 81 130 ? a) 179 b) 211 c) 194 d) 226 e) None of these

Description : 15 17 32 49 81 130 ? a) 179 b) 211 c) 194 d) 226 e) None of these

Last Answer : 15 + 17 = 32 17 + 32 = 49 32 + 49 = 81 49 + 81 = 130 81 + 130 = 211 Answer: b)

√(4.9 − 0.49) = ? a) 10.42 b) 5.84 c) 12.84 d) 2.1 e) None of these

Description : √(4.9 − 0.49) = ? a) 10.42 b) 5.84 c) 12.84 d) 2.1 e) None of these

Last Answer : Answer: d)

Of the four numbers, the first is twice the second, the second is one-third of the third and the third is 5 times the fourth. The average of the numbers is 24.75. The largest of these numbers is: A.45 B.25 C.30 D.45 E.None of these

Description : Of the four numbers, the first is twice the second, the second is one-third of the third and the third is 5 times the fourth. The average of the numbers is 24.75. The largest of these numbers is: A.45 B.25 C.30 D.45 E.None of these

Last Answer : Answer – D (45) Explanation – Let the fourth number be a then hen, third number = 5a, second number= 5a/3 and first=10a/3 a+ 5a+ 5a/3 + 10/3 = 24.75 x 4 so,a=9 So, the numbers are 9, 45, 15 and 30

P and Q can do a piece of job in 24 days; Q and R can do it in 30 days while R and P can finish it in 40 days. If P, Q, Rworks together, in how many days will they finish the job? In how many days will each one of them finish it, working alone? A) 15,25,35,45 B) 20,30,40,120 C) 20,30,40,50 D) 20,25,30,60

Description : P and Q can do a piece of job in 24 days; Q and R can do it in 30 days while R and P can finish it in 40 days. If P, Q, Rworks together, in how many days will they finish the job? In how many days will each ... finish it, working alone? A) 15,25,35,45 B) 20,30,40,120 C) 20,30,40,50 D) 20,25,30,60 

Last Answer : B Time taken by (P + Q) to finish the job = 24days. (P + Q)'s 1 day's job = 1/24 Time taken by (Q +R) to finish the job = 30days. (Q + R)'s 1 day's job = 1/30 Time taken by (R + P) to finish the ... - {(P + Q)'s 1 day's job } = (1/20 -1/24)=1/120 Hence, R alone can finish the job in 120 days.

P, Q and R can do a piece of work in 18,24 and 36 days on the second day and P on the third day, again R on the fourth day and so on. Then in how, many days will the work be completed? 1. 25 2. 24 3. 22 4. 20 5. 26

Description : P, Q and R can do a piece of work in 18,24 and 36 days on the second day and P on the third day, again R on the fourth day and so on. Then in how, many days will the work be completed? 1. 25 2. 24 3. 22 4. 20 5. 26

Last Answer : 2;

15, 18, 21.6, 25.92, ? a) 31.104 b) 31.014 c) 31.114 d) 30.114 e) 30.004

Description : 15, 18, 21.6, 25.92, ? a) 31.104 b) 31.014 c) 31.114 d) 30.114 e) 30.004

Last Answer : The series is a geometric progression with a common ratio 1.2. Hence the next term is 25.92 × 1.2 = 31.104 Answer: a)

The average age of four boys, five years ago was 9 of all the five is 15 years. The present age of the new boy is 1. 22 years 2. 24 years 3. 21 years 4. 18 years 5. 19 years

Description : The average age of four boys, five years ago was 9 of all the five is 15 years. The present age of the new boy is 1. 22 years 2. 24 years 3. 21 years 4. 18 years 5. 19 years

Last Answer : 5; Five years ago the average age of 4 boys = 9 years The present average age of 4 boys = 9+5 = 14 So the present age of new boys = 15 + 4 x 1 = 19 years

2 9 ? 105 436 2195 13182 a) 32 b) 45 c) 40 d) 30 e) 25

Description : 2 9 ? 105 436 2195 13182 a) 32 b) 45 c) 40 d) 30 e) 25

Last Answer : The series is (2 + 7) × 1 = 9; (9 + 6) × 2 = 30; (30 + 5) × 3 = 105; (105 + 4) × 4 = 436; (436 + 3) × 5 = 2195; (2195 + 2) × 6 = 13182 Answer: d)

The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

Description : The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

Last Answer : Answer – C (11 am) Explanation – Suppose they meet x hrs after 8 a.m. Then, (Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs] = 330 60x + 75(x – 1) = 330 x = 3 So, they meet at (8 + 3), i.e. 11 a.m

The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

Description : The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet? A.10:30 am B.10:45 am C.11 am D.11:25 am E.None of these

Last Answer : Answer – C (11 am) Explanation – Suppose they meet x hrs after 8 a.m. Then, (Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs] = 330 60x + 75(x – 1) = 330 x = 3 So, they meet at (8 + 3), i.e. 11 a.m

Speed of a boat in standing water is 9kmph and the speed of the stream is 1.5kmph. A man rows to a place at a distance of 10.5 km and comes back to the starting point. Find the total time taken by him. A.24 hours B.16 hours C.20 hours D.15 hours

Description : Speed of a boat in standing water is 9kmph and the speed of the stream is 1.5kmph. A man rows to a place at a distance of 10.5 km and comes back to the starting point. Find the total time taken by him. A.24 hours B.16 hours C.20 hours D.15 hours

Last Answer : Answer- A Basic Formula: i. speed = distance traveled / time taken ii. speed of the stream = ½ (a-b) km/hr iii. speed in still water = ½ (a+b) km/hr Explanation: Speed in still water= ½ (a+b) = 9km ... gives a = 10.5km/hr ; b=7.5 kmphr Total time taken by him = 105/10.5 + 105/7.5 = 24 hours

Two taps A and B are opened together to fill a tank. Both the taps fill the tank in time “x” If B separately took 25 minutes more time than “x” to fill the tank and B took 49 minutes more time than “x” to fill the tank, then find out the value of x? A) 48 minutes B) 24 minutes C) 54 minutes D) 35 minutes

Description : Two taps A and B are opened together to fill a tank. Both the taps fill the tank in time x If B separately took 25 minutes more time than x to fill the tank and B took 49 minutes more time than x ... the tank, then find out the value of x? A) 48 minutes B) 24 minutes C) 54 minutes D) 35 minutes

Last Answer : D Time is taken to fill the tank by both taps x = √a*b x = √25*49 => 5*7 => 35

Kathir and Anand can do a work in 20 days and 30 days respectively. Kathir started the work and left after 4 days. Anand took over and completed the work. In how many days was the total work completed? a) 28 days b) 20 days c) 23 days d) 25 days e) 26 days

Description : Kathir and Anand can do a work in 20 days and 30 days respectively. Kathir started the work and left after 4 days. Anand took over and completed the work. In how many days was the total work completed? a) 28 days b) 20 days c) 23 days d) 25 days e) 26 days 

Last Answer : a Kathir’s one day’s work= 1/20 Kathir’s 4 day’s work =4* (1/20) = 1/5 Work left= 1-1/5 = 4 /5 Anand’s one day’s work= 1/30 Anand can do work in = (4/5) *(30/ 1) = 24 days So total days = 24+4 = 28 days

Ishath bought 15 pieces of [email protected],500/- each and sold all of them at the total price of Rs.81, 000/-. What is the percent profit earned in the deal? a) 18.66 b) 20 c) 25 d) 36 e) None of these

Description : Ishath bought 15 pieces of [email protected],500/- each and sold all of them at the total price of Rs.81, 000/-. What is the percent profit earned in the deal? a) 18.66 b) 20 c) 25 d) 36 e) None of these

Last Answer : Total cost of 15 pieces of Mobiles= 15×4500 = Rs. 67500 Total Sales prices of 15 pieces of Mobiles= Rs. 81000 Profit% = 81000 – 67500 / 67500 × 100 = 13500/67500 × 100 = 20% Answer: b)

A shopkeeper declares that he sells rice at the cost price. However he uses a weight of 425 grams. Instead of 500 grams, what is his percentage of profit? a) a) 16 5/6 b) 15 c) c) 20 7/23 d) 25 e) None of these

Description : A shopkeeper declares that he sells rice at the cost price. However he uses a weight of 425 grams. Instead of 500 grams, what is his percentage of profit? a) a) 16 5/6 b) 15 c) c) 20 7/23 d) 25 e) None of these

Last Answer : % profit = Loss/Actual Weight x 100 = 500 – 425/500 × 100 = 75/500 x 100 = 15% Answer: b)

75%of a number is equal to four-fifth of another number. What is the ratio between first number and the second number? a) 4:3 b) 30:32 c) 7:9 d) 16:15 e) None of these

Description : 75%of a number is equal to four-fifth of another number. What is the ratio between first number and the second number? a) 4:3 b) 30:32 c) 7:9 d) 16:15 e) None of these

Last Answer : Let the two number be x & y. According to question, 75/100 x : 4/5 y 3/4 x : 4/5 y 15x = 16y x /y = 16/15 Answer: d)

A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m.? A.15 B.8 C.7 D.10 E.None of these

Description : A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m.? A.15 B.8 C.7 D.10 E.None of these

Last Answer : Answer – C (7) Explanation – Relative speed = (2 + 3) = 5 rounds per hourSo, they cross each other 5 times in an hour and 2 times in half an hourHence, they cross each other 7 times before 9.30 a.m.