1275.42 + 8624.6 – 894.54 – 24.71 = ? a) 8620.27 b) 8738.57 c) 8890.93 d) 8980.77 e) 9012.17

1275.42 + 8624.6 – 894.54 – 24.71 = ?
a) 8620.27
b) 8738.57
c) 8890.93
d) 8980.77
e) 9012.17
by

1 Answer

Answer :

d) 8980.77
by

Related questions

5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Description : 5, 8, 12, 18, 24, 30, 36, 42, ____ a) 52 b) 46 c) 48 d) 54 e) 56

Last Answer : Each term in the series is the addition of successive prime numbers. Like Prime numbers are2, 3, 5, 7, 11, 13, 17, 19, 23, 29 and so on. So first term is addition of (2 + 3). Ie 5, then second term is (3 + 5) ie ... +17)ie. 30, then (17+19)ie.36, then (19+23)ie., 42, then (23+29)i.e. 52. Answer: a)

Total literate population of city E is what percentage of total population of city D? 1) 67.5% 2) 71.5% 3) 74.5% 4) 77.5% 5) 82.5%

Description : Total literate population of city E is what percentage of total population of city D? 1) 67.5% 2) 71.5% 3) 74.5% 4) 77.5% 5) 82.5%

Last Answer : 2) 71.5%

The average weight of four boys A, B, C, and D is 75 kg. The fifth boy E is included and the average weight decreases by 4 kg. A is replaced by F. The weight of F is 6 kg more than E. Average weight decreases because of the replacement of A and now the average weight is 72 kg. Find the weight of A. 1) 57 kg 2) 54 kg 3) 56 kg 4) 60 kg 5) 58 kg

Description : The average weight of four boys A, B, C, and D is 75 kg. The fifth boy E is included and the average weight decreases by 4 kg. A is replaced by F. The weight of F is 6 kg more than E. Average weight decreases because of ... . Find the weight of A. 1) 57 kg 2) 54 kg 3) 56 kg 4) 60 kg 5) 58 kg

Last Answer : 3) 56 kg

7% of 77 + 77% of 777 + 777% of 7777 a) 58090.54 b) 60457.25 c) 68709.16 d) 71000.01 e) None of these

Description : 7% of 77 + 77% of 777 + 777% of 7777 a) 58090.54 b) 60457.25 c) 68709.16 d) 71000.01 e) None of these

Last Answer : 7% of 77 + 77% of 777 + 777% of 7777 = 0.07 × 77 + 0.77 × 777 + 7.77 × 7777 = 61030.97 Answer: e)

In what ratio must a person mix three kinds of Oats costing him Rs 1.20,Rs 1.44 and Rs 1.74 per Kg so that the mixture may be worth Rs 1.41 per Kg? A)11:77:7 B) 11:45:7 C)25:45:8 D) 27:23:6

Description : In what ratio must a person mix three kinds of Oats costing him Rs 1.20,Rs 1.44 and Rs 1.74 per Kg so that the mixture may be worth Rs 1.41 per Kg? A)11:77:7 B) 11:45:7 C)25:45:8 D) 27:23:6

Last Answer : A)11:77:7

15 17 21 29 45 77 ? a) 109 b) 125 c) 141 d) 173 e) None of these

Description : 15 17 21 29 45 77 ? a) 109 b) 125 c) 141 d) 173 e) None of these

Last Answer : 15 + 2 = 17 17 + 4 = 21 21 + 8 = 29 29 + 16 = 45 45 + 32 = 77 77 + 64 = 141 Answer: c)

12 17 32 57 ? 137 a) 98 b) 95 c) 37 d) 92 e) none of these

Description : 12 17 32 57 ? 137 a) 98 b) 95 c) 37 d) 92 e) none of these

Last Answer : The pattern of the number series is 12+5×1=17, 17+5×3=32, 32+5×5=57 57+5×7=92, 92+5×9=137 Answer: d)

Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Description : Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Last Answer : Let the age of Ram be R, brother be B R=3B And (R + 9 ) =1.5(B + 9) 3B + 9 =1.5B + 13.5 1.5B =4.5 or B = 3 years R= 9 years. Father current age = 4R(Since father is 3 times older than Ram, his ... R + 3 R, and not 3R) Father age when Ram is 1.5 times the age of his brother = 4R + 9 = 45. Answer : c

Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Description : Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Last Answer : Let the age of Ram be R, brother be B R=3B And (R + 9 ) =1.5(B + 9) 3B + 9 =1.5B + 13.5 1.5B =4.5 or B = 3 years R= 9 years. Father current age = 4R(Since father is 3 times older than Ram, his ... R + 3 R, and not 3R) Father age when Ram is 1.5 times the age of his brother = 4R + 9 = 45. Answer : c

18.4 x 17.5 + 27.6 x 13.5 = ? ÷ 4 a) 2778.4 b) 2786.4 c) 2866.4 d) 2986.3 e) 3256.8

Description : 18.4 x 17.5 + 27.6 x 13.5 = ? ÷ 4 a) 2778.4 b) 2786.4 c) 2866.4 d) 2986.3 e) 3256.8

Last Answer : 18.4 x 17.5 + 27.6 x 13.5 = ? ÷ 4 Sol: 322 + 372.6 = ? ÷4 694.6 x 4 = ? ? = 2778.4 Answer: a)

12.28× 1.5 -36÷ 2.4 = ? a) 3.24 b) 7.325 c) 6.42 d) 4.32 e) None of these

Description : 12.28× 1.5 -36÷ 2.4 = ? a) 3.24 b) 7.325 c) 6.42 d) 4.32 e) None of these

Last Answer : 12.28 × 1.5 - 15 = ? 18.42 - 15 = ? ? = 3.42 Answer: e)

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

5 10 17 27 37 50 65 a) 10 b) 17 c) 27 d) 37 e) 50

Description : 5 10 17 27 37 50 65 a) 10 b) 17 c) 27 d) 37 e) 50

Last Answer : The series is +5, +7, +9, +11, .... Answer: c)

3, 9, 17, 27, 39, 53, ? a) 64 b) 69 c) 74 d) 78 e) 81

Description : 3, 9, 17, 27, 39, 53, ? a) 64 b) 69 c) 74 d) 78 e) 81

Last Answer : Series is 1× 2 + 1, 2 × 3 + 3, 3 × 4 + 5, 4 × 5 + 7, 5 × 6 + 9 Answer: b)

5 7.5 11.25 17.5 ? 50 a) 28.75 b) 26.50 c) 27.50 d) 28.25 e) None of these

Description : 5 7.5 11.25 17.5 ? 50 a) 28.75 b) 26.50 c) 27.50 d) 28.25 e) None of these

Last Answer : 7.5 – 5 = 2.5 11.25 – 7.5 = 3.75 => 3.75 – 2.5 = 1.25 11.25 – 7.5 = 3.75 17.5 – 11.25 = 6.25 => 6.25 – 3.75 = 2.5 Answer: a)

Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is: A.1 : 3 B.3 : 4 C.3 : 2 D.Data inadequate E.None of these

Description : Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and  they cross each other in 23 seconds. The ratio of their speeds is: A.1 : 3 B.3 : 4 C.3 : 2 D.Data inadequate E.None of these

Last Answer : Answer - C (3 : 2) Explanation - Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27x metres, and length of the second train = 17y metres. relative speed = total ... 23x + 23y = 27x + 17 y 27x-23x= 23 y-17y 4x=6y x/y=6/4=3/2= 3:2

The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 years hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Description : The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 ... hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Last Answer : 5 : 30 : 31

6, 15, 35, ____, 143, 221, 323 a) 97 b) 112 c) 77 d) 75 e) 128

Description : 6, 15, 35, ____, 143, 221, 323 a) 97 b) 112 c) 77 d) 75 e) 128

Last Answer : Number in each term is the product of the successive prime numbers starting from two, for first term 2×3 = 6, for second term 3×5 = 15, for third term 5×7 = 35, so missing term is 7×11 = 77. Answer: c)

In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage of water in the final mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Description : In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage ... mixture? 1) 29.35% 2) 28. 57% 3) 24. 57% 4) 27. 75% 5) 26. 57%

Last Answer : 2) 28. 57%

5 6 16 57 ? 1245 7506 a) 240 b) 248 c) 244 d) 250 e) 260

Description : 5 6 16 57 ? 1245 7506 a) 240 b) 248 c) 244 d) 250 e) 260

Last Answer : Answer: b)

24 14 26 ? 28 16 30 a) 13 b) 17 c) 15 d) 11 e) 20

Description : 24 14 26 ? 28 16 30 a) 13 b) 17 c) 15 d) 11 e) 20

Last Answer : The series consists of two series 1 and 2: Series 1 : 24 26 28 30 +2 +2 +2 Series 2 : 14 15 16 +1 +1 Answer: c)

P, Q, R invested in the ratio of 15:16:17. After the end of the business teram they receives the profit in the ratio 9:10:11. Find the ratio of time in which they invested in the business. A) 934:1699:1578 B)1224:1275:1320 C)1578:1668:8096. D) None

Description : P, Q, R invested in the ratio of 15:16:17. After the end of the business teram they receives the profit in the ratio 9:10:11. Find the ratio of time in which they invested in the business. A) 934:1699:1578 B)1224:1275:1320 C)1578:1668:8096. D) None

Last Answer : Answer: B)  P, Q, R invest the amount in the ratio 15:16:17  T1, T2, T3 are time for investment profit gained =investment × time  Profit ratio= 9: 10: 11=15 × T1 :16 × T2 : 17 × T3  T1:T2:T3 =1224:1275:1320

A vessel contains 100 litres of milk. From this, 10 litres of milk was taken out and replaced by water. The process was repeated further two times. How much milk is now contained by the vessel? a) 72.9 litres b) 60.4 litres c) 71.6 litres

Description : A vessel contains 100 litres of milk. From this, 10 litres of milk was taken out and replaced by water. The process was repeated further two times. How much milk is now contained by the vessel? a) 72.9 litres b) 60.4 litres c) 71.6 litres d) 81 litres e) None of these

Last Answer : Milk after three replacement =100 × (90/100)3 = 72.9 litres Answer: a)

9837+315 X 6-77 X 13+10% of 1500 (1)10600 (2)10850 (3)11200 (4)10700 (5)11000

Description : 9837+315 X 6-77 X 13+10% of 1500 (1)10600 (2)10850 (3)11200 (4)10700 (5)11000

Last Answer : (2)10850

The terminal value in year 6 is closest to __________. a) Rs.22.57 b) Rs.20.42 c) Rs.24.30 d) Rs.25.70

Description : The terminal value in year 6 is closest to __________. a) Rs.22.57 b) Rs.20.42 c) Rs.24.30 d) Rs.25.70

Last Answer : a) Rs.22.57

A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is: a) 35.55 km/hr b) 36 km/hr c) 71.11 km/hr d) 71 km/hr e) 69.69km/hr

Description : A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is: a) 35.55 km/hr b) 36 km/hr c) 71.11 km/hr d) 71 km/hr e) 69.69km/hr

Last Answer : Total time taken = (160/64) + (160/80) = 9/2 hrs. Avg Speed – 320 × (2/9) km/hr = 71.11km/hr Answer: c)

108 54 36 18 9 6 4 a) 54 b) 36 c) 18 d) 9 e) 6

Description : 108 54 36 18 9 6 4 a) 54 b) 36 c) 18 d) 9 e) 6

Last Answer : The series is ÷2, ÷1.5 alternately. Answer: d)

Deepa decided to donate 16% of her monthly salary to an NGO. On the day of donation she changed her mind and donated Rs. 6,567/- which was 75%of what she had decided earlier. How much is Deepa’s monthly salary? a) Rs. 54,725/- b) Rs. 58,756/- c) Rs. 56,700/- d) Rs. 55,696/- e) Rs. 52,696/-

Description : Deepa decided to donate 16% of her monthly salary to an NGO. On the day of donation she changed her mind and donated Rs. 6,567/- which was 75%of what she had decided earlier. How much is Deepa’s monthly salary? a) Rs. 54,725/- b) Rs. 58,756/- c) Rs. 56,700/- d) Rs. 55,696/- e) Rs. 52,696/-

Last Answer : Let the Deepa Monthly Salary = x Deepa decided to donate 16% of her monthly salary. On the day of donation she changed. So, 75%of she had decided earlier of 16% 16 × 75/100 = 12% Therefore = 12%= Rs. 6567 100% = Rs .6567 × 100 / 12 x = Rs. 54725 Answer: a)

260 g of wet soil was taken in a pycnometer jar of weight 400 g in order to find the moisture content in the soil, with specific gravity of soil particles 2.75. The weight of soil and remaining water filled in pycnometer without air bubbles was 1415 g and the weight of pycnometer filled with water alone was 1275 g. The moisture content in the soil is (A) 24.2 % (B) 18.2 % (C) 53.8 % (D) None of these

Description : 260 g of wet soil was taken in a pycnometer jar of weight 400 g in order to find the moisture content in the soil, with specific gravity of soil particles 2.75. The weight of soil and remaining water filled in pycnometer without air ... is (A) 24.2 % (B) 18.2 % (C) 53.8 % (D) None of these

Last Answer : Answer: Option B

Evaluate: 48×52 + 61×59 + 77×83 a) 12486 b) 10996 c) 13406 d) 13206 e) None of these

Description : Evaluate: 48×52 + 61×59 + 77×83 a) 12486 b) 10996 c) 13406 d) 13206 e) None of these

Last Answer : 48×52 = (50 - 2) × (50 + 2) = 502 – 22 = 2496 61 × 59 = (60 + 1) × (60 - 1) = 602 – 12 = 3599 77 × 83 = (80 - 3) × (80 + 3) = 802 – 32 = 6391 Sum = 2496 + 3599 + 6391 = 12486 Answer: a)

All the words of OLIVE are arranged in dictionary order. Find the position of the word LIVEO. a) 49 b) 55 c) 57 d) 59 e) 61

Description : All the words of OLIVE are arranged in dictionary order. Find the position of the word LIVEO. a) 49 b) 55 c) 57 d) 59 e) 61

Last Answer : words starting with E = 4! = 24 words starting with I = 4! = 24 words starting with LE = 3! = 6 words starting with LIE = 2! = 2, LIO = 2! = 2 the first word with starting with LIV will be LIVEO so rank = 24 + 24 + 6 + 2 + 2 + 1 = 59 Answer: d)

Number of girls enrolled in only Dancing classes is what per cent of the boys enrolled in the same? (Rounded off to two digits after decimal) (1) 38•67 (2) 35•71 (3) 41•83 (4) 28•62 (5) None of these

Description : Number of girls enrolled in only Dancing classes is what per cent of the boys enrolled in the same? (Rounded off to two digits after decimal) (1) 38•67 (2) 35•71 (3) 41•83 (4) 28•62 (5) None of these

Last Answer : (2) 35•71

The quantity of Orange available at vendor A is approximately what percent more than that of Apple available at vendor B? 1) 61.52% 2) 68.4% 3) 82% 4) 90% 5) 71.43%

Description : The quantity of Orange available at vendor A is approximately what percent more than that of Apple available at vendor B? 1) 61.52% 2) 68.4% 3) 82% 4) 90% 5) 71.43%

Last Answer : 5) 71.43%

8 1/4 ×5 2/3 – 4 1/6 × 4 1/5 = ? a) 31 b) 18 c) 14 d) 27 e) 23

Description : 8 1/4 ×5 2/3 – 4 1/6 × 4 1/5 = ? a) 31 b) 18 c) 14 d) 27 e) 23

Last Answer : ? = (33/4) × (27/5) – (25/6) × (21/5) =891/20 -35/2 ≈ 44.5 – 17.5 =27 Answer: d)

What is the respective ratio of the number of girls enrolled in only Painting classes to the number of boys enrolled in the same ? (1) 77 : 26 (2) 21 : 73 (3) 26 : 77 (4) 73 : 21 (5) None of these

Description : What is the respective ratio of the number of girls enrolled in only Painting classes to the number of boys enrolled in the same ? (1) 77 : 26 (2) 21 : 73 (3) 26 : 77 (4) 73 : 21 (5) None of these

Last Answer : (3) 26 : 77

What is the total number of illiterate people in city B & C together? 1) 57.34 lakh 2) 58.12 lakh 3) 59.64 lakh 4) 60.62 lakh 5) 61.32 lakh

Description : What is the total number of illiterate people in city B & C together? 1) 57.34 lakh 2) 58.12 lakh 3) 59.64 lakh 4) 60.62 lakh 5) 61.32 lakh

Last Answer : 4) 60.62 lakh

The ratio of two specific heats of air is equal to  (a) 0.17  (b) 0.24  (c) 0.1  (d) 1.41  (e) 2.71.

Description : The ratio of two specific heats of air is equal to  (a) 0.17  (b) 0.24  (c) 0.1  (d) 1.41  (e) 2.71.

Last Answer : Answer : d

10 years ago the average age of all the 25 teachers of a college was 45 years. 4 years ago, a teacher retired from the post at the age of 60 years, and was replaced by a new teacher whose age was 54 years. What is the present average age of all the teachers? a) Between 52 and 53 b) Between 53 and 54 c) Between 54 and 55 d) Between 55 and 56 e) None of the above

Description : 10 years ago the average age of all the 25 teachers of a college was 45 years. 4 years ago, a teacher retired from the post at the age of 60 years, and was replaced by a new teacher whose age was 54 years. ... 53 b) Between 53 and 54 c) Between 54 and 55 d) Between 55 and 56 e) None of the above

Last Answer : Let current year be 2015 In 2005, sum of all ages = 25 45 = 1125 In 2015, sum of all ages = 1125 + (25 10) = 1375 Now 60 year old teacher was replaced by a 54 year old teacher. So we need ... all ages in 2015 considering the replacement teacher = 1375 - 6 = 1369 Average = 1369/25 = 54.76 Answer: c)

A train travelling at 36 kmph completely crosses another train having half its length and travelling in the opposite direction at 54 kmph, in 12 seconds. If it also passes a railway platform in 112 minutes, the length of the platform is : a) 560 metres b) 620 metres c) 700 meres d) 750 metres e) 720 meters

Description : A train travelling at 36 kmph completely crosses another train having half its length and travelling in the opposite direction at 54 kmph, in 12 seconds. If it also passes a railway platform in 112 minutes, the length ... is : a) 560 metres b) 620 metres c) 700 meres d) 750 metres e) 720 meters

Last Answer : Answer: c)

Three-fourth of two-third of one-sixth of a number is 15.What is 30 percent of that number? a) 54 b) 48 c) 72 d) 64 e) None of these

Description : Three-fourth of two-third of one-sixth of a number is 15.What is 30 percent of that number? a) 54 b) 48 c) 72 d) 64 e) None of these

Last Answer : Suppose no. is x 3x/4 ×2/3 ×1/6 x/12 = 15/1 x = 180, 30% of 180 = 54 Answer: a)

The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: A.534 B.486 C.544 D.548 E.None of these

Description : The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: A.534 B.486 C.544 D.548 E.None of these

Last Answer : Answer – D (548) Explanation – Required number = (L.C.M. of 12, 15, 20, 54) + 8 = 540 + 8 = 548.

A man in a train notices that he can count 21 telephone posts in one minute. If they are known to be 50 meters apart, then at what speed is the train travelling? A.50 kmph B.54 kmph C.60 kmph D.62 kmph E.None of these

Description : A man in a train notices that he can count 21 telephone posts in one minute. If they are known to be 50 meters apart, then at what speed is the train travelling? A.50 kmph B.54 kmph C.60 kmph D.62 kmph E.None of these

Last Answer : Answer – C (60 kmph) Explanation – Number of gaps between 21 telephone posts = 20 Distance traveled in 1 minute = (50 x 20) m = 1000 m = 1 km Speed = 60 km/hr

Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour? A.10 min B.12 min C.18 min D.15 min E.None of these

Description : Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour? A.10 min B.12 min C.18 min D.15 min E.None of these

Last Answer : Answer – A (10 min) Explanation – Due to stoppages, it covers 9 km less.Time taken to cover 9 km = (9/54 x 60) min = 10 min

Nishu is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the speed of the train? A.35 kmph B.54 kmph C.62 kmph D.70 kmph E.None of these

Description : Nishu is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the speed of the train? A.35 kmph B.54 kmph C.62 kmph D.70 kmph E.None of these

Last Answer : Answer - B (54 kmph) Explanation - Let the length of the train be x metres. Then, the train covers x metres in 8 seconds (train is actually covering itself because length of man is very less compartable to train)and (x + ... /8]m/sec (convert to km/hr i.e x 18/5) =[120/8] x 18/5kmph = 54 kmph.

In a bag there arc coins of 25 paise and 10 paise in the ratio of 6 : 17. If the bag contains Rs. 16 then the number of 10-paise coins is a) 30 b) 40 c) 70 d) 85 e) 65

Description : In a bag there arc coins of 25 paise and 10 paise in the ratio of 6 : 17. If the bag contains Rs. 16 then the number of 10-paise coins is a) 30 b) 40 c) 70 d) 85 e) 65

Last Answer : d) 85

Three pipes P, Q and R can fill a tank from empty to full in 40 minutes, 15 minutes, and 30 minutes respectively. When the tank is empty, all the three pipes are opened. P, Q and R discharge chemical solutions X, Y and Z respectively. What is the proportion of the solution Y in the liquid in the tank after 5 minutes? a) 8 / 15 b) 7 / 15 c) 8 / 17 d) 6 / 13 e) 8 / 13

Description : Three pipes P, Q and R can fill a tank from empty to full in 40 minutes, 15 minutes, and 30 minutes respectively. When the tank is empty, all the three pipes are opened. P, Q and R discharge chemical solutions X, Y and Z respectively. ... 5 minutes? a) 8 / 15 b) 7 / 15 c) 8 / 17 d) 6 / 13 e) 8 / 13

Last Answer : a Part of the tank filled by pipe P in 1 minute = 1 / 40 Part of the tank filled by pipe Q in 1 minute = 1 / 15 Part of the tank filled by pipe R in 1 minute = 1/ 30 Here we have to find the proportion of ... together in 5 minute = 5 1/8 = 5/ 8 Required proportion = (1/3) / ( 5/8) = 8 / 15

Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a total simple interest of 19,550 at the end of 7 years, how much money did he borrow? a) 39,500 b) 42,500 c) 41,900 d) 43,000 e) None of these

Description : Ravi borrowed some money at the rate of 4 p.c.p.a. for the first three years, at the rate of 8 p.c.p.a. for the next two years and at the rate of 9 p.c.p.a. for the period beyond 5 years. If he pays a ... 7 years, how much money did he borrow? a) 39,500 b) 42,500 c) 41,900 d) 43,000 e) None of these

Last Answer : Let the amount borrowed be Rs P Total amount of simple interest = (P×3×4)/100 + (p×2×8)/100 + (p×2×9)/100 = 19550 0.12P + 0.16P + 0.18P = 19550 0.46p= 19550 P = Rs. 42500 Answer: b)

28, 42, 84, 210, 630, ? a) 2675 b) 2515 c) 2445 d) 2375 e) 2205

Description : 28, 42, 84, 210, 630, ? a) 2675 b) 2515 c) 2445 d) 2375 e) 2205

Last Answer : Series is × 1.5, ×2, ×2.5, ×3, ×3.5 Answer: e)

Anjana walked at 4 kmph for a certain part of his journey and took an auto, travelling at 25 kmph for the rest of the journey. If he took 42 minutes for the entire journey, what part of the journey did he walk given that his average speed for the entire journey was 10 kmph? a) 2 km b) 1.5 km c) 3.5 km d) 4 km e) 1 km

Description : Anjana walked at 4 kmph for a certain part of his journey and took an auto, travelling at 25 kmph for the rest of the journey. If he took 42 minutes for the entire journey, what part of the journey did he walk given that his ... journey was 10 kmph? a) 2 km b) 1.5 km c) 3.5 km d) 4 km e) 1 km

Last Answer : Total time = 42 minutes = 0.7 hours. Average speed = 10 kmph Total distance = 0.7×10 = 7 km Let distance walked = W W/4 + (7-W)/25 = 0.7 Solving W = 2 Answer: a)

A person sold an item for Rs. 14280 after giving 15% discount on the labelled price and earned 19% profit on the cost price. What would have been the percentage profit, had he not given the discount? a) 30% b) 34% c) 40% d) 42.5% e) None of these

Description : A person sold an item for Rs. 14280 after giving 15% discount on the labelled price and earned 19% profit on the cost price. What would have been the percentage profit, had he not given the discount? a) 30% b) 34% c) 40% d) 42.5% e) None of these

Last Answer : Labelled price = [(14280×100)/85] = Rs. 16800 Or, 23X/120 = 69/5 Or, X= [(69×120)/(23×5)] = 72km. Answer is: c)